UNIX sort ignores whitespaces - linux

Question

Given a file txt:
ab
a c
a a
When calling sort txt, I obtain:
a a
ab
a c
In other words, it is not proper sorting, it kind of deletes/ignores the whitespaces! I expected this to be the behavior of sort -i but it happens with or without the -i flag.
I would like to obtain "correct" sorting:
a a
a c
ab
How should I do that?

Answer 1

Solved by:
export LC_ALL=C
From the sort() documentation:
WARNING: The locale specified by the environment affects sort order. Set LC_ALL=C to get the traditional sort order that uses native byte values.
(works for ASCII at least, no idea for UTF8)

Answer 2

Like mentioned before, LC_ALL=C sort does the trick. This is simply because different languages have different rules for sorting characters, which are often laid out by senior linguists instead of CS experts. And these rules, in the case of your locale, seem to say that spaces ought to be ignored in sorting.
By prefixing LC_ALL=C (or, when LC_ALL is unset, LC_COLLATE=C suffices), you explicitely declare language-agnostic sorting (and, with LC_ALL, number-formatting and stuff), which is what you want in this context. If you want to make this your default, export LC_COLLATE in your environment.
The default is chosen in this way to keep consistency with the "normal", real-world sorting schemes (like the white pages), which often ignored spaces.

Answer 3

Using the C locale i.e. sorting just by byte values is not a good solution in languages where some letters are outside the range [A-Za-z]. Such letters are represented as multiple bytes in UTF-8 and then the byte value collating order is not what one desires. (Some characters may have two equivalent representations (pre-composed and de-composed)).
Nevertheless, the treatment of spaces is a problem. I tried the following:
$ cat stest
a b
a c
ab
a d
$ sort stest
ab
a b
a c
a d
$ sort -k 1,1 stest
a b
a c
a d
ab
For my needs, the -k 1,1 did the trick. Another but clumsier solution I tried, was to change spaces to some auxiliary character, then sort, then change the auxiliaries back into blanks.

Answer 4

You could use the 'env' program to temporarily change your LC_COLLATE for the duration of the sort; e.g.
/usr/bin/env LC_COLLATE=POSIX /bin/sort file1 file2
It's a little cumbersome on the command line but if you're using it in a script should be transparent.

Answer 5

I have been looking at this for a little while, wanting to optimize a shell script I maintain that has a heavy international userbase. (heavy as in percentage, not quantity).
Most of the options I saw around the web and SO seem to recommend what I see here, setting the locale globally (overkill)
export LC_ALL=C
or piping it into each individual command like this from gnu.org (tedious)
$ echo abcdefghijklmnopqrstuvwxyz | LC_ALL=C /usr/xpg4/bin/tr 'a-z' 'A-Z' ABCDEFGHIJKLMNOPQRSTUVWXYZ
I wanted to avoid clobbering the user's locale as a unseen side effect of running my program. This turned out to be easily accomplished just as you would expect, by leaving off the globalization. No need to export this variable past your program.
I had to set LANG instead of LC_ALL for some reason, but all the individual locales were set which is functionally enough for me.
Here is the test, simple as can be
#!/bin/bash
# locale_checker.sh
#Check and set locale to LC_ALL to optimize character sort and search.
echo "locale was $LANG"
LANG=C
locale
and output + proof that it is temporary and can be restricted to my script's process.
mateor#:~/snippets$ ./locale_checker.sh
locale was en_US.UTF-8
LANG=C
LANGUAGE=en_US:en
LC_CTYPE="C"
LC_NUMERIC="C"
LC_TIME="C"
LC_COLLATE="C"
LC_MONETARY="C"
LC_MESSAGES="C"
LC_PAPER="C"
LC_NAME="C"
LC_ADDRESS="C"
LC_TELEPHONE="C"
LC_MEASUREMENT="C"
LC_IDENTIFICATION="C"
LC_ALL=
mateor#:~/snippets$ locale
LANG=en_US.UTF-8
LANGUAGE=en_US:en
LC_CTYPE="en_US.UTF-8"
LC_NUMERIC="en_US.UTF-8"
LC_TIME="en_US.UTF-8"
LC_COLLATE="en_US.UTF-8"
LC_MONETARY="en_US.UTF-8"
LC_MESSAGES="en_US.UTF-8"
LC_PAPER="en_US.UTF-8"
LC_NAME="en_US.UTF-8"
LC_ADDRESS="en_US.UTF-8"
LC_TELEPHONE="en_US.UTF-8"
LC_MEASUREMENT="en_US.UTF-8"
LC_IDENTIFICATION="en_US.UTF-8"
LC_ALL=
There you go. You get the optimized locale without clobbering another person's innocent environment as well as avoid the tedium of piping it everywhere you think it may help.

Answer 6

Weird, works here (cygwin).
Try sort -d txt.

Answer 7

Actually for me
$ cat txt
ab
a c
a a
$ sort txt
a a
a c
ab
I'll bet between your a and c you have a non-breaking space or an enspace or an empspace or other high-codepoint space!
EDIT
Just ran it on Linux. I should have looked at the tags. Yes I get the same output you do! My first run was on the Mac. Looks like a difference between GNU and BSD. I will investigate further.
EDIT 2:
Linux uses a field-based sort.... still looking for how to suppress it. Tried
sort -t, txt
hoping to trick GNU into thinking the whole line was one field, but it still used the current locale to sort.
EDIT 3:
The OP solved the problem by setting the locale to C with
export LC_ALL=C
There seems to be no other approach. The sort command will use the current locale, and although it often says the C (or its alias POSIX) is the default locale, if you have Linux it has probably been set for you. Enter locale -a to see the available locales. On my system:
$ locale -a
C
POSIX
en_AG
en_AU.utf8
en_BW.utf8
en_CA.utf8
en_DK.utf8
en_GB.utf8
en_HK.utf8
en_IE.utf8
en_IN
en_NG
en_NZ.utf8
en_PH.utf8
en_SG.utf8
en_US.utf8
en_ZA.utf8
en_ZW.utf8
It seems like setting the locale to C (or its alias POSIX) is the only way to break the field-based behavior of sort and treat the whole line as one field. It is rather odd IMHO that this is how to do it. I would think the -t or -k options, or perhaps some new option would be a more sensible way to make this happen.
BTW, it looks like this question has been asked before on SO: unexpected result from gnu sort.