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VBA: Convert Text to Number
(11 answers)
Closed 4 years ago.
For some reason Excel is converting my number into text and adding a preceding apostrophe in every cell in column E3 and F3.
I need to convert columns E3:F3 back to numbers and format them to currency. How do I do that?
A1:K2 is the header.
The code below is not working:
Set wb = objApp.Workbooks.Open("aFile.xls", True, False)
wb.Sheets(1).Rows(2).Delete
wb.Sheets(1).Range("E3:F3") = Mid(wb.Sheets(1).Range("E3:F3"), 2,
Len(wb.Sheets(1).Range("E3:F3")) - 2)
wb.Sheets(1).Range("E3:F3").NumberFormat = "$#,##0.00"
If your text is only a number, the answer is simple. Multiply it by 1.
Say cell A1= '00001234 or a formula or macro returns a piece of text, multiply the answer by 1.
"00001234" * 1 = 1234.
I want to extract the value of a Label or a txtBox on a VBA form.
Num = lblText * 1
Another example:
If .txtLevel10 * 1 > 50 Then...etc.
Also works with some other data types "16-Jan-15" *1 = 16/1/15
Works in Excel & VBA but only if there are no other characters in the original text.
Cheers
Assuming you want the same currency formatting you get from the toolbar, this works:
wb.Sheets(1).Range("E3:F3").Formula = wb.Sheets(1).Range("E3:F3").Value
wb.Sheets(1).Range("E3:F3").Style = "Currency"
Just using worksheet.Range() with no properties forces Excel to guess exactly which property you actually mean (this is called the "default property"), and you get inconsistent results.
Try:
Range("E3:F3").Style = "Currency"
Try highlighting that column and doing Data->Text To Columns (Excel 2003; in 2007+ Text to columns is on one of the ribbons). Click 'Delimited', then 'Next', Next again, then select General as the format. This should convert the whole column into a number.
If this works, it is easily automated. Let me know if you need code.
EDIT - you have to do one column at a time.
Len(wb.Sheets(1).Range("E3:F3"))
For me this just (as expected) throws an error. You'll have to process each cell individually to use your approach.
Dim c as Range
Set wb = objApp.Workbooks.Open("aFile.xls", True, False)
With wb.Sheets(1)
.Rows(2).Delete
For each c in .Range("E3:F3").cells
c.Value = Mid(c.value, 2, Len(c.value)-2)
c.NumberFormat = "$#,##0.00"
next c
End With
This, actually, works. The key is to apply format before setting the value:
Set wb = objApp.Workbooks.Open("aFile.xls", True, False)
wb.Sheets(1).Rows(2).Delete
wb.Sheets(1).Range("E3:F3").NumberFormat = "$#,##0.00"
For Row = 3 To 3 'your rows range in case you need iterate through (1 row only in your case)
For Column = 5 To 6 'E3:F3
wb.Sheets(1).Cells(Row, Column) = Mid(wb.Sheets(1).Cells(Row, Column), 2, Len(wb.Sheets(1).Cells(Row, Column)) - 2)
Next Column
Next Row
Related
I tried using the OFFSET function to no avail. Essentially, I have a few cells and I need to move them by a user-specified amount in the x and y direction. How would I do this?
In excel, a function like this one will populate multiple cells
Function populate()
Evaluate "eventFinal(" & Application.Caller.Offset(0, 1).Address(False, False) & ")"
populate = "result here >>"
End Function
Private Sub eventFinal(CellToChange As Range)
Dim numbers(2, 1) As Integer
numbers(0, 0) = 25
numbers(0, 1) = 21
numbers(1, 0) = 3
numbers(2, 0) = 4
numbers(1, 1) = 2
numbers(2, 1) = 6
CellToChange.Resize(3, 2) = numbers
End Sub
I'm afraid VB is the only way unless you 'cheat' a little...
I only illustrate the concept re: 'cheating' with this google sheet.
Google sheets "equivalent" with colour placement: here.
The alternative would be block out a range of cells with functions such as:
=if(and(row(A1) - row(A$1) = row offset value, column(A1)-column(A$1 = column offset value), desired cell to move, "")
The suitability of this depends entirely upon the purpose: if your goal is a visual one where the actual values don't really matter, then google sheets example is one method but the value you place is quite limited (can only use values
First post! Hello everyone :)
Hoping for a bit of help using VBA/Autofilter. I am creating a screening tool that does the following-
1) user inputs a bunch of parameters into the tab "ScreenerOptions" using a combination of dropdowns and numerical inputs
2) selections in "ScreenerOptions" drive VBA code to Autofilter a table, which is in a seperate tab, "Master1"
I want the parameters to be linked dynamically to cells, so whatever option is chosen in a drop down drives the autofilter. I have got everything dynamically linked EXCEPT the operator (eg xlFilterValues, xlTop10Percent etc).
Below is a subset of the parameters in my screener.
Here is code that works:
Sub Test()
With Sheets("Master1")
'FCF Yield, row 14 in screener - if the user leaves the field blank
If Worksheets("ScreenerOptions").Cells(14, 5) = "" Then
'Then all rows in the table are displayed for this column
'Column6 in the screener is pulling in the relevant
'column number in the table based on MATCH formula
Worksheets("Master1").Range("A4").AutoFilter Field:=Sheets("ScreenerOptions").Cells(14, 6)
'If a parameter is entered, filter is applied
'Criteria reference based on inputs in Screener Options Columns C (3) and E (5)
Else
'Formula in screener tool column 8 tells you if dropdown uses a value operator
'e.g. ">", "=" returns 0
'dropdowns containing text 'percent' return a 1
'If 0 is returned, use operator xlOr to return numberical values and blanks
If Worksheets("ScreenerOptions").Cells(14, 8).Value = 0 Then
Worksheets("Master1").Range("A4").AutoFilter _
Field:=Sheets("ScreenerOptions").Cells(14, 6), _
Criteria1:=Sheets("ScreenerOptions").Cells(14, 3).Value & _
Worksheets("ScreenerOptions").Cells(14, 5).Value, _
Operator:=xlOr, Criteria2:=""
Else
'If 1 is returned, use operators xlTop10Percent, xlBottom10Percent as selected
Worksheets("Master1").Range("A4").AutoFilter _
Field:=Sheets("ScreenerOptions").Cells(14, 6), _
Criteria1:=Worksheets("ScreenerOptions").Cells(14, 5).Value, _
**Operator:=xlTop10Percent**
End If
End If
End With
Worksheets("Master1").Activate
End Sub
However, when I change the last operator to link to a cell instead of hard-coding xlTop10Percent:
Operator:=Worksheets("ScreenerOptions").Cells(14, 3).Value
I get the error:
Run-time '1004: Autofilter method of Range class failed.
Can anyone help? It's so closed to being finished!
The string "xlTop10Percent" is just a string - there's no mechanism in VBA to directly convert it to the value of the xlTop10Percent constant.
You can substitute it with the numeric value (5) though and that should work.
https://learn.microsoft.com/en-us/office/vba/api/excel.xlautofilteroperator
If you want to use the "friendly" names in your table then you can create a lookup table on a worksheet to handle the conversion to the numeric values.
Well done for your first post !
About your code, I'm not an expert but i guess it comme from the fact that you assign a string value (like "dog", "hello" or "xlTop10Percent"
Actualy both lines are identical :
Operator:=Worksheets("ScreenerOptions").Cells(14, 3).Value
Operator:="xlTop10Percent"
Which is totally different from that :
Operator:=xlTop10Percent
Operator can take value rather than text, could you try by setting your cell(14,3) at 5 rather than a text ?
Should work, let me know !
take care !
I want to do an INDEX-MATCH-like lookup between two documents, except my MATCH's index array doesn't stay in one column.
In Vague-English: I want a value from a known column that matches another value that may be found in any column.
Refer to the image below. Let's call everything to the left of the bold vertical line on column H doc1, and the right side will be doc2.
Doc2 has a column "Find This", which will be the INDEX's array. It is compared with "ID1" from doc1 (Note that the values in "Find This" will not be in the same order as column ID1, but it's easier to undertsand this way).
The "[Result]" column in doc2 will be the value from doc1's "Want This" column from the row that matches "FIND THIS" ...However, sometimes the value from "FIND THIS" is not in the "ID1" column, and is instead in "ID2","ID3", etc.
So, I'm trying to generate Col K from Col J. This would be like pressing Ctrl+F and searching for a value in Col J, then taking the value from Col D in that row and copying it to Col K.
I made identical values from a column the same color in the other doc to make it easier to visualize where they are coming from.
Note also that in column F of doc1, the same value from doc2's "Find This" can be found after some other text.
Also note that the column headers are only there as examples, the ID columns are not actually numbered.
I would simply hard-code the correct column to search from, but I'm not in control of doc1, and I'm worried that future versions may have new "ID" columns, with other's being removed.
I'd prefer this to be a solution in the form of a formula, but VB will do.
To generate column K based on given values of column J then you could use the following:
=INDEX(doc1!$D$2:$D$14,SUMPRODUCT((doc1!$B$2:$H$14=J2)*ROW(doc1!$B$2:$H$14))-1)
Copy that formula down as far as you need to go.
It basically only returns the row of the where a matching column J is found. we then find that row in the index of your D range to get your value in K.
Proof of concept:
UPDATE:
If you are working with non unique entities n column J. That is the value on its own can be found in multiple rows and columns. Consider using the following to return the Last row where there J value is found:
=INDEX(doc1!$D$2:$D$14,AGGREGATE(14,6,(doc1!$B$2:$H$14=J2)*ROW(doc1!$B$2:$H$14),1)-1)
UPDATE 2:
And to return the first row where what you are looking in column J is found use:
=INDEX($D$2:$D$14,AGGREGATE(15,6,1/($B$2:$H$14=J2)*ROW($B$2:$H$14)-1,1))
Thanks to Scott Craner for the hint on the minimum formula.
To determine if you have UNIQUE data from column J in your range B2:H14 you can enter this array formula. In order to enter an array formula you need to press CTRL+SHFT+ENTER at the same time and not just ENTER. You will know you have done it right when you see {} around your formula in the formula bar. You cannot at the {} manually.
=IF(MAX(COUNTIF($B$2:$H$14,J2:J14))>1,"DUPLICATES","UNIQUE")
UPDATE 3
AGGREGATE - A relatively new function to me but goes back to Excel 2010. Aggregate is 19 functions rolled into 1. It would be nice if they all worked the same way but they do not. I think it is functions numbered 14 and up that will perform the same way an array formula or a CSE formula if you prefer. The nice thing is you do not need to use CSE when entering or editing them. SUMPRODUCT is another example of a regular formula that performs array formula calculations.
The meat of this explanation I believe is what is happening inside of the AGGREGATE brackets. If you click on the link you will get an idea of what the first two arguments are. The first defines which function you are using, and the second tell AGGREGATE how to deal with Errors, hidden rows, and some other nested functions. That is the relatively easy part. What I believe you want to know is what is happening with this:
(doc1!$B$2:$H$14=J2)*ROW(doc1!$B$2:$H$14)
For illustrative purpose lets reduce this formula to something a little smaller in scale that does the same thing. I'll avoid starting in A1 as that can make life a little easier when counting since it the 1st row and first column. So by placing the example range outside of it you can see some more special considerations potentially.
What I want to know is what row each of the items list in Column C occurs in column B
| B | C
3 | DOG | PLATYPUS
4 | CAT | DOG
5 | PLATYPUS |
The full formula for our mini example would be:
{=($B$3:$B$5=C2)*ROW($B$3:$B$5)}
And we are going to look at the following as an array
=INDEX($B$3:$B$5,AGGREGATE(14,6,($B$3:$B$5=C2)*ROW($B$3:$B$5),1)-2)
So the first brackets is going to be a Boolean array as you noted. Every cell that is TRUE will TRUE until its forced into a math calculation. When that happens, True becomes 1 and False becomes 0.I that formula was entered as a CSE formula and place in D2, it would break down as follows:
FALSE X 3
FALSE X 4
TRUE X 5
The 3, 4 and 5 come from ROW() returning the value of the row number that it is dealing with at the time of the array math operation. Little trick, we could have had ROW(1:3). Just need to make sure the size of the array matches! This is not matrix math is just straight across multiplication. And since the Boolean is now experiencing a math operation we are now looking at:
0 X 3 = 0
0 X 4 = 0
1 X 5 = 5
So the array of {0,0,5} gets handed back to the aggregate for more processing. The important thing to note here is that it contains ONLY 0 and the individual row numbers where we had a match. So with the first aggregate formula, formula 14 was chosen which is the LARGE function. And we also told it to ignore errors, which in this particular case does not matter. So after providing the array to the aggregate function, there was a ,1) to finish off the aggregate function. The 1 tells the aggregate function that we want the 1st larges number when the array is sorted from smallest to largest. If that number was 2 it would be the 2nd largest number and so on. So the last row or the only row that something is found on is returned. So in our small example it would be 5.
But wait that 5 was buried inside another function called Index. and in our small example that INDEX formula would be:
=INDEX($B$3:$B$5,AGGREGATE(...)-2)
Well we know that the range is only 3 rows long, so asking for the 5th row, would have excel smacking you up side the head with an error because your index number is out of range. So in comes the header row correction of -1 in the original formula or -2 for the small example and what we really see for the small example is:
=INDEX($B$3:$B$5,5-2)
=INDEX($B$3:$B$5,3)
and here is a weird bit of info, That last one does not become PLATYPUS...it becomes the cell reference to =B5 which pulls PLATYPUS. But that little nuance is a story for another time.
Now in the comments Scott essentially told me to invert for the error to get the first row. And this is important step for the aggregate and it had me running in circles for awhile. So the full equation for the first row option in our mini example is
=INDEX($B$3:$B$5,AGGREGATE(15,6,1/($B$3:$B$5=C2)*ROW($B$3:$B$5),1)-2)
And what Scott Craner was actually suggesting which Skips one math step is:
=INDEX($B$3:$B$5,AGGREGATE(15,6,ROW($B$3:$B$5)/($B$3:$B$5=C2),1)-2)
However since I only realized this after writing this all up the explanation will continue with the first of these two equations
So the important thing to note here is the change from function 14 to function 15 which is SMALL. Think of it a finding the minimum. And this time that 6 plays a huge factor along with the 1/. So our array in the middle this time equates to:
1/FALSE X 3
1/FALSE X 4
1/TRUE X 5
Which then becomes:
1/0 X 3
1/0 X 4
1/1 X 5
Which then has excel slapping you up side the head again because you are trying to divide by 0:
#div/0 X 3
#div/0 X 4
1/1 X 5
But you were smart and you protected yourself from that slap upside the head when you told AGGREGATE to ignore error when you used 6 as the second argument/reference! Therefore what is above becomes:
{5}
Since we are performing a SMALL, and we passed ,1) as the closing part of the AGGREGATE, we have essentially said give me the minimum row number or the 1st smallest number of the resulting array when sorted in ascending order.
The rest plays out the same as it did for the LARGE AGGREGATE method. The pitfall I fell into originally is I did not use the 1/ to force an error. As a result, every time I tried getting the SMALL of the array I was getting 0 from all the false results.
SUMPRODUCT works in a very similar fashion, but only works when your result array in the middle only returns 1 non zero answer. The reason being is the last step of the SUMPRODUCT function is to all the individual elements of the resulting array. So if you only have 1 non zero, you get that non zero number. If you had two rows that matched for instance 12 and 31, then the SUMPRODUCT method would return 43 which is not any of the row numbers you wanted, where as aggregate large would have told you 31 and aggregate small would have told you 12.
Something like this maybe, starting in K2 and copied down:
=IFERROR(INDEX(D:D,MAX(IFERROR(MATCH(J2,B:B,0),-1),IFERROR(MATCH(J2,E:E,0),-1),IFERROR(MATCH(J2,G:G,0),-1),IFERROR(MATCH(J2,H:H,0),-1))),"")
If you want to keep the positions of the columns for the Match variable, consider creating generic range names for each column you want to check, like "Col1", "Col2", "Col3". Create a few more range names than you think you will need and reference them to =$B:$B, =$E:$E etc. Plug all range names into Match functions inside the Max() statement as above.
When columns are added or removed from the table, adjust the range name definitions to the columns you want to check.
For example, if you set up the formula with five Matches inside the Max(), and the table changes so you only want to check three columns, point three of the range names to the same column. The Max() will only return one result and one lookup, even if the same column is matched several times.
I came up with a vba solution if I understood correctly:
Sub DisplayActiveRange()
Dim sheetToSearch As Worksheet
Set sheetToSearch = Sheet2
Dim sheetToOutput As Worksheet
Set sheetToOutput = Sheet1
Dim search As Range
Dim output As Range
Dim searchCol As String
searchCol = "J"
Dim outputCol As String
outputCol = "K"
Dim valueCol As String
valueCol = "D"
Dim r As Range
Dim currentRow As Integer
currentRow = 1
Dim maxRow As Integer
maxRow = sheetToOutput.UsedRange.Rows.Count
For currentRow = 1 To maxRow
Set search = Range("J" & currentRow)
For Each r In sheetToSearch.UsedRange
If r.Value <> "" Then
If r.Value = search.Value Then
Set output = sheetToOutput.Range(outputCol & currentRow)
output.Value = sheetToSearch.Range(valueCol & currentRow).Value
currentRow = currentRow + 1
Set search = sheetToOutput.Range(searchCol & currentRow)
End If
End If
Next
Next currentRow
End Sub
There might be better ways of doing it, but this will give you what you want. We assume headers in both "source" and "destination" sheets. You will need to adapt the "Const" declarations according to how your sheets are named. Press Control & G in Excel to bring up the VBA window and copy and paste this code into "This Workbook" under the "VBA Project" group, then select "Run" from the menu:
Option Explicit
Private Const sourceSheet = "Source"
Private Const destSheet = "Destination"
Public Sub FindColumns()
Dim rowCount As Long
Dim foundValue As String
Sheets(destSheet).Select
rowCount = 1 'Assume a header row
Do While Range("J" & rowCount + 1).value <> ""
rowCount = rowCount + 1
foundValue = FncFindText(Range("J" & rowCount).value)
Sheets(destSheet).Select
Range("K" & rowCount).value = foundValue
Loop
End Sub
Private Function FncFindText(value As String) As String
Dim rowLoop As Long
Dim colLoop As Integer
Dim found As Boolean
Dim pos As Long
Sheets(sourceSheet).Select
rowLoop = 1
colLoop = 0
Do While Range(alphaCon(colLoop + 1) & rowLoop + 1).value <> "" And found = False
rowLoop = rowLoop + 1
Do While Range(alphaCon(colLoop + 1) & rowLoop).value <> "" And found = False
colLoop = colLoop + 1
pos = InStr(Range(alphaCon(colLoop) & rowLoop).value, value)
If pos > 0 Then
FncFindText = Mid(Range(alphaCon(colLoop) & rowLoop).value, pos, Len(value))
found = True
End If
Loop
colLoop = 0
Loop
End Function
Private Function alphaCon(aNumber As Integer) As String
Dim letterArray As String
Dim iterations As Integer
letterArray = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
If aNumber <= 26 Then
alphaCon = (Mid$(letterArray, aNumber, 1))
Else
If aNumber Mod 26 = 0 Then
iterations = Int(aNumber / 26)
alphaCon = (Mid$(letterArray, iterations - 1, 1)) & (Mid$(letterArray, 26, 1))
Else
'we deliberately round down using 'Int' as anything with decimal places is not a full iteration.
iterations = Int(aNumber / 26)
alphaCon = (Mid$(letterArray, iterations, 1)) & (Mid$(letterArray, (aNumber - (26 * iterations)), 1))
End If
End If
End Function
I have some fields that need to be split up into different cells. They are in the following format:
Numbers on Mission 21 0 21
Numbers on Mission 5 1 6
The desired output would be 4 separate cells. The first would contain the words in the string "Numbers on Mission" and the subsequent cells would have each number, which is determined by a space. So for the first example the numbers to extract would be 21, 0, 21. Each would be in its own cell next to the string value. And for the second: 5, 1, 6.
I tried using a split function but wasn't sure how to target the numbers specifically, and to identify the numbers based on the spaces separating them.
Pertinent to your first case (Numbers on Mission), the simple solution could be as shown below:
Sub SplitCells()
Const RowHeader As String = "Numbers on Mission"
Dim ArrNum As Variant
ArrNum = Split(Replace(Range("A1"), RowHeader, ""), " ")
For i = 1 To UBound(ArrNum)
Cells(1, i + 2) = ArrNum(i)
Next
Cells(1, 2) = RowHeader
End Sub
The same logic is applicable to your second case. Hope this may help.
Unless I'm overlooking something, you may not need VBA at all. Have you tried the "Text to Columns" option? If you select the cell(s) with the information you would like to split up, and go to Data -> Text to Columns. There, you can choose "delimited" and choose a space as a delimiter, which will split your data into multiple cells, split by where the space is.
edit: Just realized that will also split up your string. In that case, when you are in 3rd part of the Text to Columns, choose a destaination cell that isn't the cell with your data. (I.E. if your data is in A1, choose B1 as destination, and it'll put the split info there. Then just combine the text columns with something like =B1&" "&C1&" "&D1)
I was able to properly split the values using the following:
If i.Value Like "*on Mission*" Then
x = Split(i, " ")
For y = 0 To UBound(x)
i.Offset(0, y + 1).Value = x(y)
Next y
End If
I'm a bit new to trying to program and originally was just trying to improve a spreadsheet but it's gone beyond using a basic function in excel. I have a table that I am having a function look at to find a building number in the first column and then look at start and finish dates in two other respective columns to find out if it should populate specific blocks on a calendar worksheet. The problem occurs because the same building number may appear multiple times with different dates and I need to to find an entry that matches the correct dates.
I was able to create a working though complicated formula to find the first instance and learned I can add a nested if of that formula again in the false statement with a slight change. I can continue doing that but it becomes very large and cumbersome. I'm trying to find a way to make a function for the formula with a variable in it that would look at how many times the it has already been used so it keeps searching down the table for an answer that fits the parameters.
This is currently my formula:
=IFERROR(IF(AND(DATE('IF SHEET (2)'!$F$7,MATCH('IF SHEET (2)'!$C$2,'IF SHEET (2)'!$C$2:'IF SHEET (2)'!$N$2,0),'IF SHEET (2)'!C$4)>=VLOOKUP("2D11"&1,A2:F6,4,0),DATE('IF SHEET (2)'!$F$7,MATCH('IF SHEET (2)'!$C$2,'IF SHEET (2)'!$C$2:'IF SHEET (2)'!$N$2,0),'IF SHEET (2)'!C$4)<=VLOOKUP("2D11"&1,A2:F6,4,0)),IF(VLOOKUP("2D11"&1,A2:F6,3,0)="2D11",VLOOKUP("2D11"&1,A2:F6,6,FALSE)),"NO ANSWER"),"ERROR")
Where you see 2D11&1 is where I need the variable for 1 so it would be "number of times it's been used in the function +1" then I could just loop it so it would keep checking till it ran out of 2D11's or found one that matched. I haven't posted before and I'm doing this through a lot of trial and error so if you need more info please post and say so and I'll try to provide it.
So rather than have someone try to make sense of the rediculous formula I posted I though I would try to make it simpler by just stating what I need to accomplish and trying to see how to turn that into a VBA function. So I'm kinda looking at a few steps:
Matches first instance of building name in column A with
building name for the row of the output cell.
Is date connected with the output cell >= start date of first entry(which is user entered in column D).
Is date connected with the output cell <= end date of first entry(which is user entered in column E).
Enters Unit name(located in column F) for first instance of the building if Parts 1, 2, and 3 are all True.
If parts 1, 2, or 3 are False then loops to look at next instance of the building name down column 1.
Hopefully this makes things clearer than the formula so I'm able to get help as I'm still pretty stuck due to low knowledge of VBA.
Here is a simple solution...
Building_name = ???
Date = ???
Last_Row = Range("A65536").End(xlUp).Row
For i = 1 To Last_Row
if cells(i,1).value = Building_Name Then
if date >= cells(i,4).value Then
if date <= cells(i,5).value Then
first instance = cells(i,6).value
end if
end if
end if
next
you should add a test at the end to avoid the case where there is no first instance in the table
If I understand correctly, you have a Table T1 made of 3 columns: T1.building, T1.start date, T1.end date.
Then you have 3 parameters: P1=building, P2=start date, P3=end date.
You need to find the first entry in table T1 that "fits" within the input parameters dates, that is:
P1=T1.building
P2<=T1.start date
P3>=T1.end date
If so, you can define a custom function like this
Public Function MyLookup(Key As Variant, DateMin As Variant, DateMax As Variant, LookUpTable As Range, ResultColumn As Integer) As Range
Dim iIndx As Integer
Dim KeyValue As Variant
Dim Found As Boolean
On Error GoTo ErrHandler
Found = False
iIndx = 1
Do While (Not Found) And (iIndx <= LookUpTable.Rows.Count)
KeyValue = LookUpTable.Cells(iIndx, 1)
If (KeyValue = Key) And _
(DateMin <= LookUpTable.Cells(iIndx, 2)) And _
(DateMax >= LookUpTable.Cells(iIndx, 3)) Then
Set MyLookup = LookUpTable.Cells(iIndx, ResultColumn)
Found = True
End If
iIndx = iIndx + 1
Loop
Exit Function
ErrHandler:
MsgBox "Error in MyLookup: " & Err.Description
End Function
That may not be the most performant piece of code in the world, but I think it's explanatory.
You can download this working example