I'm trying to figure out how to get cloud-init to execute a script. At the moment I have a file called myscript which reads
!/bin/sh
echo 'Hello world - I just executed user-data!' > /root/helloworld
sudo mkdir scripttest
Then in my Java code I have
String usrdata = new String();
usrdata= "myscript";
req.setUserData(usrdata);
req.setUserData(org.apache.commons.codec.binary.Base64.encodeBase64String(usrdata.getBytes()));
result= client.runInstances(req);
This doesn't seem to be working when I ssh into the instance I'm running. Any thoughts why?
The question has some formatting issues, so I hope I am understanding correctly...
I have never used cloud-init from java, but I can see some issues:
the scripts will run as root. So the sudo mkdir scripttest should just be mkdir scripttest
usrdata seems to be a string with value myscript. I expect it should rather be the base64 encoded contents of myscript.
Related
I am very new to linux and shell scriprting.
I am trying to run a shellscript from secure shell (ssh) on linux using following commands:
chmod +x path/to/mynewshell.sh
sh path/to/mynewshell.sh
I get this error:
path/to/mynewshell.sh: path/to/mynewshell.sh: cannot execute binary file.
Tried using this command:
bash path/to/mynewshell.sh
I get the same error.
Tried with this command: su - myusername sh path/to/mynewshell.sh
It is asking for my password and giving me this error: no such file or directory.
1.The result of cat -v path/to/mynewshell.sh is:
^#^#^#^#^#^#^#^#Rscript "$dir"/diver_script.R
done
2.When tried 'less path/to/mynewshell.sh' i got this on my terminal:
#!/bin/bash/Rscript^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#
^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#^#
for dir in /path/to/* ; do
^#^#^#^#^#^#^#^#Rscript "$dir"/myRscript.R
done
3.When i ran file path/to/mynewshell.sh : i got this "Bourne-Again shell script text executable"
Please give any advice on how I can try executing the shellscript.
chmod -x removes execution permission from a file. Do this:
chmod +x path/to/mynewshell.sh
And run it with
/path/to/mynewshell.sh
As the error report says, you script is not actually a script, it's a binary file.
I was getting the same error running my shell script through a bash interpreter in PowerShell. I ran dos2unix myscript.sh on the shell script, and now it runs ok.
From a proposed duplicate:
run_me.sh.xz: run_me.sh.xz: cannot execute binary file
This is because the file is compressed, as indicated by the .xz extension. You need to remove the compression before the file can be used.
xz -d ./run_me.sh.xz
chmod +x ./run_me.sh # probably not necessary if you already did that before
./run_me.sh
Other compression schemes like gzip (.gz extension), bzip2 (.bz2 extension) etc behave similarly; you just have to know the name of the command to uncompress it, which is of course usually easy to google.
To anyone else having the problem i had.
i was trying to run a 16 bit unicode text file converted to a shell script, this doesn't work as all 16 bit unicode text files have a 0xFFFE marker at the start making mac os not like the file and this gives the “cannot execute binary file” error.
open the text file click on "Format" at the top, go down to "Make Plain Text" click it.
open your terminal type chmod 777 /path/to/file.sh
put in terminal: /path/to/file.sh to run it
That script is simply not a shell script.
A shell script is usually readable and contains shell code.
The output your cat command shows looks indeed like it's a binary of some sort.
As some note, it might be because of a file conversion issue when copying but it looks more like an actual binary to me.
You can check what it is identified as with the file command so:
file path/to/mynewshell.sh
Just start with a clean script and rewrite the code, it looks like you just want to run some R scripts in a directory?
Make sure the R scripts point to the right R script executioner.
In my case I had a bash script that would not execute. The file was originally generated from a find ... -print0 command. Leaving a \0 character the script, removing that character solved my problem.
So I'm sure this is written somewhere, and I'm just wording my searches wrong, but I haven't been able to find it.
I write shell scripts. Many of those scripts require superuser permissions. Rather than putting the sudo command inside the script, I want to invoke the entire script from the start with sudo.
So instead of:
#!/bin/bash
# Sample Script 1
sudo mkdir /usr/tempDir
It would be:
#!/bin/bash
# Sample Script 2
mkdir /usr/tempDir
And I would just invoke it like this: sudo ./sampleScript.sh
My problem is that when I write a script, I simlink it to my bin, so I don't need to worry about the path to the script when I execute it.
If I have the file simlinked to my bin, and I run it as just: sampleScript.sh, it is recognized (and will fail). However, if I do: sudo sampleScript.sh, I get a "sudo: sampleScript.sh: command not found" message.
This happens if it's in both /home/myName/bin and /usr/local/bin.
I know there has to be a trick to making this work that I'm missing. And I also know I'm probably just not wording my google searches properly. Just looking for some guidance to figure this part out.
Thanks.
When you call sudo the PATH changes ie it's not using yours. Look here
sudo changes PATH - why?
It does this because it's now running as root, not as your user.
I'm using Lua script with ngnix to generate ISO file.
Lua script is parsing request and it should pass it to genisoimage command.
I've tried with:
local pack_cmd = "genisoimage -V" .. some_other_name
os.execute(pack_cmd)
Command is not successfully executed and as return code I get 3328. I've
tried with absoulte path (/usr/bin/genisoimage and /bin/genisoimage) but
it's not working.
I've tried simple workaround - Execute genisoimage command inside bash script
and in Lua script run it like this:
local pack_cmd = "bash /absoulte/path/script.sh " .. some_other_name
os.execute(pack_cmd)
Still not working and getting same exit code. Also tried to catch what's wrong but it look likes command genisoimage is never executed.
local pack_cmd = "bash /absoulte/path/script.sh " .. some_other_name .." >> error.log"
os.execute(pack_cmd)
Version with handles is not working as well
local handle = io.popen(pack_cmd)
local result = handle:read("*a")
handle:close()
If I execute pack_cmd string manually everything works OK. Executing bash script is also working.
The problem was with permissions for www-data user.
I am trying to create an alias that will execute a script. When i cd into the directory where the script is located... lets say /usr/local/bin/startscript then the script runs as expected and starts the application i want it to.
SO. i went into my bashrc file and added an alias
alias startscript='/usr/local/bin/startscript'
The goal is to be able to run the script by simply typing "startscript" from any directory.
However, when i try to use the alias to run the script, it does not work properly as the application that should start, does not.
My script starts with
#!/bin/sh
and then goes from there
any ideas? Thanks
SCRIPT:
#!/bin/sh
#- Check for user 'user'
if [[ "`whoami`" != "user" ]]; then
echo "This script can only be executed by user 'user'."; exit
fi
. /usr/local/bin/etctrx/startscriptdirectory/startscriptsetup
#- Kill manager to avoid multiple processes
pkill -f 'JavaApp.jar'
#- Start
nohup java -classpath /usr/local/bin/etctrx/startscriptdirectory/RequiredJars/ojdbc5.jar:/usr/local/bin/etctrx/startscriptdirectory/RequiredJars/activation.jar:/usr/local/bin/etctrx/startscriptdirectory/RequiredJars/mail.jar -jar /usr/local/bin/etctrx/startscriptdirectory/JavaApp.jar > ${JAVAAPPLOGS}/startscript.log 2>&1 &
If the script runs as expected while in /usr/local/bin by simply typing startscript, but from another directory the script runs (does not return an error), but doesn't produce the desired results, then the issue is with how you reference the application from within the script.
As others have noted, you shouldn't need an alias for something in /usr/local/bin and if it runs from that directory, obviously your executable permissions are correct too. If the application you're trying to run is also in /usr/local/bin then your script probably assumes it's in the same directory, which wouldn't be the case elsewhere, so you would need to either ad a cd to /usr/local/bin within the script or specify the full application path.
I am able to call the script if i do this, but it still won't give me the
results I want,(application being started) like i do when I run the script from
the directory it lives in
It would appear that the "application" in question is in the same directory as the script, /usr/local/bin, which we have established is already on your PATH. For the script to run correctly but not the application means you might be calling the application wrong, for example
./application
This would fail unless you were calling from /usr/local/bin. Fix would be like this
application
i have very simple shell script
#!/bin/bash
cp -rf /var/www/ksite/app2/* /var/www/ksite/app
echo "----"
echo "done"
but seems cp command fails
if i execute
cp -rf /var/www/ksite/app2/* /var/www/ksite/app
from terminal everything work ok. Can someone tell me how to include cp in shell script?
Thanks
We seem to have doubt as to how this script fails. If there is no error message then this is a strange one. I suggest:
On the command line (which works), do a which cp
Whatever the reply, then copy that and use it as the cp in the script (e.g. /bin/cp)
Check the widcard expansion, run your script with bash -x script-name and see if you get what you expect.
echo $? after the copy in the script - if it is zero then it (thinks it) worked.
Do a ls -ld /var/www/ksite/app from your script, maybe someone set a symbolic link?
If it still fails, source the script from the command-line and see if that works . script-name
Double check that the copy did actually fail! (maybe that should be step 1.)
Make sure you really have bash at /bin/bash. I think a batter hash bang is:
#!/usr/bin/env bash
This uses the env command to locate the bash binary and set the environment.
I had similar problem. What helped me:
I used windows and putty to write script, so I had \r\n at the end of lines. Be sure, you have only \n symbol.
I copied files and the only way it worked for me at script was cp <source_dir>/fileName <dest_dir>/fileName whereas at command line cp <source_dir>/fileName <dest_dir> worked well too.
Just covering all the bases .. do the permissions vary between the excutions .. i.e. do you execute one with sudo/root privileges, the other as user (unlikely, but thought I'd ask since we don't know what the exact error is)
Similar issue to Vladmir where the script was created in Windows. I created a new file "my_bash_script.sh" in the linux environment using VIM, then read the contents of my script into the file:
:r file_made_in_windows.sh
Then I saved, closed, then set the file as executable:
chmod 744 my_bash_script.sh
From there, I ran the script:
./my_bash_script.sh
...and it worked. What a weird issue. I was confounded for a moment.