I was wondering if there is a way to get Linux commands with a perl script. I am talking about commands such as cd ls ll clear cp
You can execute system commands in a variety of ways, some better than others.
Using system();, which prints the output of the command, but does not return the output to the Perl script.
Using backticks (``), which don't print anything, but return the output to the Perl script. An alternative to using actual backticks is to use the qx(); function, which is easier to read and accomplishes the same thing.
Using exec();, which does the same thing as system();, but does not return to the Perl script at all, unless the command doesn't exist or fails.
Using open();, which allows you to either pipe input from your script to the command, or read the output of the command into your script.
It's important to mention that the system commands that you listed, like cp and ls are much better done using built-in functions in Perl itself. Any system call is a slow process, so use native functions when the desired result is something simple, like copying a file.
Some examples:
# Prints the output. Don't do this.
system("ls");
# Saves the output to a variable. Don't do this.
$lsResults = `ls`;
# Something like this is more useful.
system("imgcvt", "-f", "sgi", "-t", "tiff", "Image.sgi", "NewImage.tiff");
This page explains in a bit more detail the different ways that you can make system calls.
You can, as voithos says, using either system() or backticks. However, take into account that this is not recommended, and that, for instance, cd won't work (won't actually change the directory). Note that those commands are executed in a new shell, and won't affect the running perl script.
I would not rely on those commands and try to implement your script in Perl (if you're decided to use Perl, anyway). In fact, Perl was designed at first to be a powerful substitute for sh and other UNIX shells for sysadmins.
you can surround the command in back ticks
`command`
The problem is perl is trying to execute the bash builtin (i.e. source, ...) as if they were real files, but perl can't find them as they don't exist. The answer is to tell perl what to execute explicitly. In the case of bash builtins like source, do the following and it works just fine.
my $XYZZY=`bash -c "source SOME-FILE; DO_SOMETHING_ELSE; ..."`;
of for the case of cd do something like the following.
my $LOCATION=`bash -c "cd /etc/init.d; pwd"`;
Related
I am trying to run a Bash command from within my Perl program.
However Perl seems to be confusing my Bash $PWD environment variable as a Perl variable.
How can I make it just read it all as a string?
This is what I'm trying to run
my $path = /first/path;
`ln -s $path $PWD/second/path`
Those backticks runs the second line in Bash. Using System() produces the same problem.
Any ideas?
There are two queries here, on use of Bash variables and on running external commands.
There is the %ENV hash in Perl, with environment variables
perl -wE'say $ENV{PWD}'
However, you are often better off getting the equivalent within the script, as things may have a subtly different meaning for the script or change as the script runs.
More importantly, using shell commands exposes you to all kinds of potential problems with quoting, shell injection, and interpretation. For instance, the command you show is dangerous, as outlined in Charles Duffy comment. It is in principle better to use Perl's rich functionality. See for example
Executing system commands safely while coding in Perl
Using system commands in Perl instead of built in
libraries/functions [duplicate]
for a sober, and detailed, account of advantages.
In case you do need to run external commands, it is best to avoid the shell altogether, for example by using the multi-argument form of system. If you need the output of the command as well there are various modules in Perl that provide that. See links below.
If you also need to use the shell's capabilities, instead of quoting everything just right in order for the shell to receive what it needs better use a ready tool like String::ShellQuote.
Some examples:
How to use both pipes and prevent shell expansion in perl system function?
Perl is respecting '<' as a regular character rather an output redirection
How to pipe the content of a variable as STDIN in a qx{} statement in Perl?
Perl system command with multiple parameters output to file.
Note that qx operator (backticks) uses /bin/sh, which may or may not get relegated to Bash. So if you want Bash you need system('/bin/bash', '-c', $cmd), where $cmd need be built carefully to avoid problems. See the links with examples.
Here is a full example related to the objective behind the question.
Your program's working directory may be other than expected depending on how it's started. For one, it changes after chdir. I don't know your exact intent with PWD, but in Perl there are core Cwd::cwd and FindBin with $RealBin, for the current working directory and for the directory where the script resides (generally different things).
To create a symbolic link to $path, with the relative path following the current working directory
use warnings;
use strict;
use Cwd qw(cwd);
my $cwd = cwd;
my $path = '/first/path';
symlink($path, "$cwd/second/path") or die "Can't make a symlink: $!";
If the path is meant to be the script's location use $RealBin from FindBin instead of cwd.
Note that with symlink you cannot pass a directory instead of a link name. See this page.
In the middle of my perl script I want to execute a bash command. The script takes a long time, so at the beginning of the script I want to see if the command exists. This answer says to just try and run it and this other answer suggests some bash commands to test if the program exists.
Is the latter option the best solution? Are there any better ways to do this check in perl?
My best guess is that you want to check for existence of an executable file that you want to run using system or qx//
But if you want your command line to behave the same way as the shell, then you can probably use File::Which
What if we assume that we don't know the command's location?
This means that syck's answer won't work, and zdim's answer is incomplete.
Try this function in perl:
sub check_exists_command {
my $check = `sh -c 'command -v $_[0]'`;
return $check;
}
# two examples
check_exists_command 'pgrep' or die "$0 requires pgrep";
check_exists_command 'readlink' or die "$0 requires readlink";
I just tested it, because I just wrote it.
With perl, you can test files for existence, readability, executability etc., take a look here.
Therefore just use
executeBashStuff() if -x $filename;
or stat it:
stat($filename);
executeBashStuff() if -x _;
To me a better check is to run the program at the beginning of the script (with -V say).
I'd use the same invocation as you use to run the job later (via shell or not, via execvp). Once at it, make sure to see whether it threw errors. This is also discussed in your link but I would in fact get the output back (not send it away) and check that. This is the surest way to see whether the thing actually runs out of your program and whether it is what you expect it to be.
Checking for the executable with -x (if you know the path) is useful, too, but it only tells you that a file with a given name is there and that it is executable.
The system's which seems to be beset with critism for its possible (mis)behavior, it may or may not be a shell-builtin (which complicates how exactly to use it), is an external utility, and its exact behavior is system dependent. The module File::Which pointed out in Borodin's answer would be better -- if it is indeed better than which. (What it may well be, I just don't know.)
Note. I am not sure what "bash command" means: a bash shell built-in, or the fact that you use bash when on terminal? Perl's qx and system use the sh shell, not bash (if they invoke the shell, which depends on how you use them). While sh is mostly a link, and often to bash, it may not be and there are differences, and you cannot rely on your shell configuration.
Can also actually run a shell, qx(/path/bash -c 'cmd args'), if you must. Mind the quotes. You may need to play with it to find the exact syntax on your system. See this page and links.
A predecessor of mine installed a crappy piece of software on an old machine (running Linux) which I've inherited. Said crappy piece of software installed flotsam all over the place, and also is sufficiently bloated that I want it off ASAP -- it no longer has any functional purpose since we've moved on to better software.
Vendor provided an uninstall script. Not trusting the crappy piece of software, I opened the uninstall script in an editor (a 200+ line Bash monster), and it starts off something like this:
SWROOT=`cat /etc/vendor/path.conf`
...
rm -rf $SWROOT/bin
...
It turns out that /etc/vendor/path.conf is missing. Don't know why, don't know how, but it is. If I had run this lovely little script, it would have deleted the /bin folder, which would have had rather amusing implications. Of course this script required root to run!
I've dealt with this issue by just manually running all the install commands (guh) where sensible. This kind of sucked because I had to interpolate all the commands manually. In general, is there some sort of way I can "dry run" a script to have it dump out all the commands it would execute, without it actually executing them?
bash does not offer dry-run functionality (and neither do ksh, zsh, or any other shell I know).
It seems to me that offering such a feature in a shell would be next to impossible: state changes would have to be simulated and any command invoked - whether built in or external - would have to be aware of these simulations.
The closest thing that bash, ksh, and zsh offer is the ability to syntax-check a script without executing it, via option -n:
bash -n someScript # syntax-check a script, without executing it.
If there are no syntax errors, there will be no output, and the exit code will be 0.
If there are syntax errors, analysis will stop at the first error, an error message including the line number is written to stderr, and the exit code will be:
2 in bash
3 in ksh
1 in zsh
Separately, bash, ksh, and zsh offer debugging options:
-v to print each raw source code line[1]
to stderr before it is executed.
-x to print each expanded simple command to stderr before it is executed (env. var. PS4 allows tweaking the output format).
Combining -n with -v and/or -x offers little benefit:
With -n specified, -x has no effect at all, because nothing is being executed.
With -n specified, -v will effectively simply print the source code.
If there is a syntax error, there may be benefit in the source code getting print up to the point where the error occurs; keep in mind, though that the error message produced by
-n always includes the offending line number.
[1] Typically, it is individual lines that are printed, but the true unit is however many lines a given command - which may be a compound command such as while or a command list (such as a pipeline) - spans.
You could try running the script under Kornshell. When you execute a script with ksh -D, it reads the commands and checks them for syntax, but doesn't execute them. Combine that with set -xv, and you'll print out the commands that will be executed.
You can also use set -n for the same effect. Kornshell and BASH are fairly compatible with each other. If it's a pure Bourne shell script, both Kornshell and BASH will execute it pretty much the same.
You can also run ksh -u which will cause unset shell variables to cause the script to fail. However, that wouldn't have caught the catless cat of a nonexistent file. In that case, the shell variable was set. It was set to null.
Of course, you could run the script under a restricted shell too, but that's probably not going to uninstall the package.
That's the best you can probably do.
I am trying to create a script that will run a program on each file in a list. I have been trying to do this using a .csh file (I have no clue if this is the best way), and I started with something as simple as hello world
echo "hello world"
The problem is that I cannot execute this script, or verify that it works correctly. (I was trying to do ./testscript.csh which is obviously wrong). I haven't been able to find anything that really explains how to run C Scripts, and I'm guessing there's a better way to do this too. What do I need to change to get this to work?
You need to mark it as executable; Unix doesn't execute things arbitrarily based on extension.
chmod +x testscript.csh
Also, I strongly recommend using sh or bash instead of csh, or you will soon learn about the idiosyncrasies of csh's looping and control flow constructs (some things only work inside them if done a particular way, in particular with the single-line versions things are very limited).
You can use ./testscript.csh. You will however need to make it executable first:
chmod u+x testscript.csh
Which means set testscript to have execute permissions for the user (who ever the file is owned by - which in this case should be yourself!)
Also to tell the OS that this is a csh script you will need put
#! /path/to/csh
on the first line (where /path/to/csh is the full path to csh on your system. You can find that out by issuing the command which csh).
That should give you the behvaiour you want.
EDIT As discussed in some of the comments, you may want to choose an alternative shell to C Shell (csh). It is not the friendliest one for scripting.
You have several options.
You can run the script from within your current shell. If you're running csh or tcsh, the syntax is source testscript.csh. If you're running sh, bash, ksh, etc., the syntax is . ./testscript.sh. Note that I've changed the file name suffix; source or . runs the commands in the named file in your current shell. If you have any shell-specific syntax, this won't work unless your interactive shell matches the one used by the script. If the script is very simple (just a sequence of simple commands), that might not matter.
You can make the script an executable program. (I'm going to repeat some of what others have already written.) Add a "shebang" as the first line. For a csh script, use #!/bin/csh -f. The -f avoids running commands in your own personal startup scripts (.cshrc et al), which saves time and makes it more likely that others will be able to use it. Or, for a sh script (recommended), used #!/bin/sh (no -f, it has a completely different meaning). In either case, run chmod +x the_script, then ./the_script.
There's a trick I often use when I want to perform some moderately complex action. Say I want to delete some, but not all, files in the current directory, but the criterion can't be expressed conveniently in a single command. I might run ls > tmp.sh, then edit tmp.h with my favorite editor (mine happens to be vim). Then I go through the list of files and delete all the ones that I want to leave alone. Once I've done that, I can replace each file name with a command to remove it; in vim, :%s/.*/rm -f &/. I add a #!/bin/sh at the top save it, chmod +x foo.sh, then ./foo.sh. (If some of the file names might have special characters, I can use :%s/.*/rm -f '&'/.)
I have just started using Linux and I am curious how shell built-in commands such as cd are defined.
Also, I'd appreciate if someone could explain how they are implemented and executed.
If you want to see how bash builtins are defined then you just need to look at Section 4 of The Bash Man Page.
If, however, you want to know how bash bultins are implemented, you'll need to look at the Bash source code because these commands are compiled into the bash executable.
One fast and easy way to see whether or not a command is a bash builtin is to use the help command. Example, help cd will show you how the bash builtin of 'cd' is defined. Similarly for help echo.
The actual set of built-ins varies from shell to shell. There are:
Special built-in utilities, which must be built-in, because they have some special properties
Regular built-in utilities, which are almost always built-in, because of the performance or other considerations
Any standard utility can be also built-in if a shell implementer wishes.
You can find out whether the utility is built in using the type command, which is supported by most shells (although its output is not standardized). An example from dash:
$ type ls
ls is /bin/ls
$ type cd
cd is a shell builtin
$ type exit
exit is a special shell builtin
Re cd utility, theoretically there's nothing preventing a shell implementer to implement it as external command. cd cannot change the shell's current directory directly, but, for instance, cd could communicate new directory to the shell process via a socket. But nobody does so because there's no point. Except very old shells (where there was not a notion of built-ins), where cd used some dirty system hack to do its job.
How is cd implemented inside the shell? The basic algorithm is described here. It can also do some work to support shell's extra features.
Manjari,
Check the source code of bash shell from ftp://ftp.gnu.org/gnu/bash/bash-2.05b.tar.gz
You will find that the definition of shell built-in commands in not in a separate binary executable but its within the shell binary itself (the name shell built-in clearly suggests this).
Every Unix shell has at least some builtin commands. These builtin commands are part of the shell, and are implemented as part of the shell's source code. The shell recognizes that the command that it was asked to execute was one of its builtins, and it performs that action on its own, without calling out to a separate executable. Different shells have different builtins, though there will be a whole lot of overlap in the basic set.
Sometimes, builtins are builtin for performance reasons. In this case, there's often also a version of that command in $PATH (possibly with a different feature set, different set of recognized command line arguments, etc), but the shell decided to implement the command as a builtin as well so that it could save the work of spawning off a short-lived process to do some work that it could do itself. That's the case for bash and printf, for example:
$ type printf
printf is a shell builtin
$ which printf
/usr/bin/printf
$ printf
printf: usage: printf [-v var] format [arguments]
$ /usr/bin/printf
/usr/bin/printf: missing operand
Try `/usr/bin/printf --help' for more information.
Note that in the above example, printf is both a shell builtin (implemented as part of bash itself), as well as an external command (located at /usr/bin/printf). Note that they behave differently as well - when called with no arguments, the builtin version and the command version print different error messages. Note also the -v var option (store the results of this printf into a shell variable named var) can only be done as part of the shell - subprocesses like /usr/bin/printf have no access to the variables of the shell that executed them.
And that brings us to the 2nd part of the story: some commands are builtin because they need to be. Some commands, like chmod, are thin wrappers around system calls. When you run /bin/chmod 777 foo, the shell forks, execs /bin/chmod (passing "777" and "foo") as arguments, and the new chmod process runs the C code chmod("foo", 777); and then returns control to the shell. This wouldn't work for the cd command, though. Even though cd looks like the same case as chmod, it has to behave differently: if the shell spawned another process to execute the chdir system call, it would change the directory only for that newly spawned process, not the shell. Then, when the process returned, the shell would be left sitting in the same directory as it had been in all along - therefore cd needs to be implemented as a shell builtin.
A Shell builtin -- http://linux.about.com/library/cmd/blcmdl1_builtin.htm
for eg. -
which cd
/usr/bin/which: no cd in (/usr/bin:/usr/local/bin......
Not a shell builtin but a binary.
which ls
/bin/ls
http://ss64.com/bash/ this will help you.
and here is shell scripting guide
http://www.freeos.com/guides/lsst/