Is it possible to search for a list of strings (100+), for example in a text file and using a command such as findstr to identify which files contain any of the strings? Or is there a better alternative (on Windows) ?
Probably, from the findstr help I found:
/G:file Gets search strings from the specified file(/ stands for console).
and
/S Searches for matching files in the current directory and all
subdirectories.
so:
C:\Temp>copy con strings.txt
test
test1
test2
^Z
1 file(s) copied.
I created (with copy con brings me back) 3 files test.txt test1.txt and test2.txt and placed the strings we have from strings.txt into the respective files and then ran this command:
C:\Temp>findstr /S /G:strings.txt *.txt
strings.txt:test
strings.txt:test1
strings.txt:test2
test.txt:test
test1.txt:test1
test2.txt:test2
It indeed found them, and it even found all three from the source file strings.txt.
Related
Say for example, in the source directory I have the following files:
abc.r
xyz.sh
pqr.fam
lmn.bim
uvw.r
ttt.sh
Now I need to link only the items 1,2 and 5 only (listed above). Most importantly I need to link all the 3 files together (i.e. link all the 3 files at the same time).
I know how to link 1 file at a time (ln -s sourceDirectory/fileName targetDirectory/), but not multiple files at once.
I found ways to do this when the file name prefixes has some pattern (for example, link all the files where the names start with letter "f"), but in my case, I do not have any such pattern. My file names are different.
Try this:
#!/bin/bash
for file in a.txt b.txt c.txt
do
ln -s /sourcedir/"${file}" /targetdir/
done
Since you only have a list, you have to iterate through the list.
I have a folder /home/user/Document/filepath where I have three files namely file1-1.1.0.txt, file2-1.1.1.txt, file3-1.1.2.txt
and another folder named /home/user/Document/backuppath where I have to move files from /home/user/Document/folderpath which has file1-1.0.0.txt, file2-1.0.1.txt and file3-1.0.2.txt
task is to copy the specific files from folder path to backup path.
To summarize:
the below is the files.txt where I listed the files which has to be copied:
file1-*.txt
file2-*.txt
The below is the move.sh script that execute the movements
for file in `cat files.txt`; do cp "/home/user/Document/folderpath/$file" "/home/user/Documents/backuppath/" ; done
for the above script I am getting the error like
cp: cannot stat '/home/user/Document/folderpath/file1-*.txt': No such file or directory found
cp: cannot stat '/home/user/Document/folderpath/file2-*.txt': No such file or directory found
what I would like to accomplish is that I would like to use the script to copy specific files using * in the place of version numbers., since the version number may vary in the future.
You have wildcard characters in your files.txt. In your cp command, you are using quotes. These quotes prevent the wildcards to be expanded, as you can clearly see from the error message.
One obvious possibility is to not use quotes:
cp /home/user/Document/folderpath/$file /home/user/Documents/backuppath/
Or not use a loop at all:
cp $(<files.txt) /home/user/Documents/backuppath/
However, this would of course break if one line in your files.txt is a filename pattern which contains white spaces. Therefore, I would recommend a second loop over the expanded pattern:
while read file # Puts the next line into 'file'
do
for f in $file # This expands the pattern in 'file'
do
cp "/home/user/Document/folderpath/$f" /home/user/Documents/backuppath
done
done < files.txt
Is it possible to search within a directory to scan all files for a particular string, then return the file(s) if the string is found?
For example I am looking to try find files where "120854" is found. If we take the below example using a directory called /users/TCP/ that contains two files called File1 and File2.
File1
-----
Product1:432153
Product2:8614
Product3:975
File2
-----
Product76:87
Product324:684
Product965:120854
The expected outcome would return /users/TCP/File2 as "120854" is found on line 3 in that file. Obviously the directory I'm using has thousands of files and therefore wondering if this is possible. Can't find anything online myself
Thanks!
grep -Ril "120854" /users/TCP/
-- R stands for recursive.
-- i stands for ignore case (optional in your case).
-- l stands for "show the file name, not the result itself".
-- /users/TCP/ stands for directory you are searching in
I have created a test directory structure:
t1.html
t2.php
a/t1.html
a/t2.php
b/t1.html
b/t2.php
All files contain the string "HELLO".
The following commands are run from the root folder above:
> grep -r "HELLO" *
b/t1.html:HELLO
b/t2.php:HELLO
c/t1.html:HELLO
c/t2.php:HELLO
t1.html:HELLO
t2.php:HELLO
> grep -r --include=*.html "HELLO" *
b/t1.html:HELLO
c/t1.html:HELLO
t2.php:HELLO
Why is it including the correct .html files from the sub-directories, but the .php file from the current directory?
If I pop up a level to the directory above my whole structure, then it gives following result:
grep -r --include=*.html "HELLO" *
a/t1.html:HELLO
a/c/t1.html:HELLO
a/b/t1.html:HELLO
This is what I expected when ran from within my structure.
I assume I can achieve the goal using find+grep together, but I thought this was valid usage of grep.
Thanks for any help.
Andy
Use a dot instead of the asterisk:
grep -r HELLO .
Asterisk gets evaluated by the shell and replaced with the list of all the files in the current directory (whose names don't start with a dot). All of them are then grepped recursively.
I have been working on this for quite some time and decided to ask for some help. I'm trying to use a command to find a multiple occurrences of a function (basically a string) within a directory (that has multiple files) and would like to view only the file names which the string is found.
Lets say this was the directory I want to search filled with multiple .h and .cpp files is:
~/Project/Files
and I was looking for occurrences of a function called 'doThis'
So far I have tried:
grep -r doThis ~/Project/Files
But I get the path and where it occurs in the file, I only need the file names.
Also grep -f wont work because I get an error message saying "No such file or directory" and when using just grep I get an error message saying "path is a directory"
Any help would be great: Thanks guys!
Simply use the -l switch ;)
So :
grep -rl foobar dir