using lwuit UI library I am not destroy j2me application - java-me

Question

I am working with j2me using lwuit I have one problem is that
when I am startApp() inside midlet I first set Display.init(this)
and run application lwuit work good but when I am using Form inside startApp() event in midlet it good work but in this form actionevent I am call new form and in this new form
I put one back command when I pressed it it does not move on main midlet
please help how know lwuit use
import javax.microedition.MIDlet;
import some lwuit UILibrary
public class mainMiddlet extends MIDlet implement ActionListner
{
public mainMiddlet(){
try{
Display.init(this);
//somthing is here
form=new Form();
form.addActionListener(this);
}catch(Exception e){}
}
public void actionperformed(ActionEven ae){
//here i call new form
//in action event of this form
new form().show();
}
//here some middlet default method
}
public class newForm extends Form {
//in this form I am put one command back and when i am pressed it
// I call mainMiddlet but it throw error internal application java.lang.nullpointer
// can I back on mainmiddlet from on form to another form
// my main problem is I am not move on mainmiddlet for exit middlet because destoryall()
// is method of middlet
}

Answer 1

Its just simple. You can call the show() method inside next form back command. For example,
MainMidlet.java
// create the midlet and write inside of the midlet
final Form form = new Form();
form.addCommand(new Command("Next") {
public void actionPerformed(ActionEvent evt) {
new NewForm(form).show();
}
});
NewForm.java
// create the NewForm class and write inside of the class
public NewForm(final Form form) {
// Constructor
addCommand(new Command("Back") {
public void actionPerformed(ActionEvent evt) {
form.show();
}
});
}