I have written a small application on go, which starts 4 threads for doing various things + one main thread. So in total there are 5 threads. But if I'll start activity monitor and monitor the process, this is what I see
First of all why 7 threads. And it is not constant. Sometimes it is 5 and other times it is 7. Also all 4 threads started by main thread ends after doing hat they are suppose to. I verify that threads end by putting a differ statement on the top of thread. Still thread count in Activity monitor stays 7.
Does anyone knows what is going on over here? Are these extra threads started by go runtime? Is there a way to find out how many threads are active my program that are started by my code and not by go runtime.
Yes they are started by the runtime, for example http://play.golang.org/p/c0cIngo_sO it will print 4 goroutines are running.
Goroutines aren't threads, 1 OS thread can handle 100s of goroutines, however if you're doing something heavy or using a blocking system call, the runtime will start a new thread to handle the other goroutines.
I suppose you mean Goroutines when you say threads.
The Go runtime transparently multiplexes lightweight Goroutines onto OS threads. That's also why you don't need to call functions like select()—that's the runtime's job.
If you spawn 7 Go routines and some of them block, the runtime might decide to terminate the idle OS threads. This is why you see less threads than Go routines.
I think you mistake Goroutines for thread.
In your go program, the thread you mean is actually goroutine ，which is a coroutine and is not a real thread , which is implemented by go's runtime(you need to know about go runtime, every go program is running on a runtime, and runtime actually use thread to implement goroutines).Diffrent goroutine may be running in the same thread, or may be not ,but you never know . You can use runtime.GOMAXPROCS for multi-core cpu .
And the threads you see in the monitor are real threads .
Background: I was using Beej's guide and he mentioned forking and ensuring you "get the zombies". An Operating Systems book I grabbed explained how the OS creates "threads" (I always thought it was a more fundamental piece), and by quoting it, I mean it the OS decides nearly everything. Basically they share all external resources, but they split the register and stack spaces (and I think a 3rd thing).
So I get to the waitpid function which http://www.qnx.com's developer docs explain very well. In fact, I read the entire section on threads, minus all the types of conditions after a Processes and Threads google.
The fact that I can split code up and put it back together doesn't confuse me. HOW I can do this is confusing.
In C and C++, your program is a Main() function, which goes forward, calls other functions, maybe loops forever (waiting for input or rendering), and then eventually quits or returns. In this model I see NO reason for it to stop beyond a "I'm waiting for something", in which case it just loops.
Well, it seems it can loop by setting certain things, like "I'm waiting for a semaphore" or "a response" or "an interrupt". Or maybe it gets interrupted without waiting for one. This is what confuses me.
The processor time-slices processes and threads. That's all fine and dandy, but how does it decide when to stop one? I understand that you get to the Polling function and say "Hey I'm waiting for input, clock tick or user do something". Somehow it tells this to the os? I'm not sure. But moreso:
It seems to be able to completely randomly interrupt or interject, even on a single-threaded application. So you're running one thread and suddenly waitpid() says "Hey, I finished a process, let me interrupt this, we both hate zombies, I gotta do this." and you're still looping on some calculation. So, what just happens??? I have no idea, somehow they both run and your computation isn't messed with, 'cause it's single threaded, but that somehow doesn't mean that it won't stop what it's doing to run waitpid() inside the same thread WHILE you're still doing your other app things.
Also confusing, is how you can be notified, like iOSes notifications, and say "Hey, I got some UI changes, get me off of 16 and put me back on 1 so I can change this thing". But same question as last paragraph, how does it interrupt a thread that's running?
I think I understand the splitting, but this joining is utterly confusing. It's like the textbooks have this "rabbit from hat" step I'm supposed to accept. Other SO posts told me they don't share the same stack, but that didn't help, now I'm imagining a slinky (stack) leaning over to another slinky, but unsure how it recombines to change the data.
Thanks for any help, I apologize that this is long, but I know someone's going to misinterpret this and give me the "they are different stacks" answer if I'm too concise here.
Thanks,
OK, I'll have a go, though it's gonna be 'economical with the truth':)
It's sorta like this:
The OS kernel scheduler/dispatcher is a state-machine for managing threads. A thread comprises a stack, (allocated at the time of thread creation), and a Thread Control Block, (TCB), struct in the kernel that holds thread state and can store thread context, (including user registers, especially the stack-pointer). A thread must have code to run, but the code is not dedicated to the thread - many threads can run the same code. Threads have states, eg. blocked on I/O, blocked on an inter-thread signal, sleeping for a timer period, ready, running on a core.
Threads belong to processes - a process must have at least one thread to run its code and has one created for it by the OS loader when the process starts up. The 'main thread' may then create others that will also belong to that process.
The state-machine inputs are software interrupts - system calls from those threads that are already running on cores, and hardware interrupts from perhiperal devices/controllers, (disk, network, mouse, KB etc), that use processor hardware features to stop the processor/s running instructions from the threads and 'immediately' run driver code instead.
The output of the state-machine is a set of threads running on cores. If there are fewer ready threads than cores, the OS will halt the unuseable cores. If there are more ready threads than cores, (ie. the machine is overloaded), the 'sheduling algorithm' that decided with threads to run takes into account several factors - thread and process priority, prority boosts for threads that have just become ready on I/O completion or inter-thread signal, foreground-process boosts and others.
The OS has the ability to stop any running thread on any core. It has an interprocessor hardware-interrupt channel and drivers that can force any thread to enter the OS and be blocked/stopped, (maybe because another thread has just beome ready and the OS scheduling algorithm has decided that a running thread must be immediately preempted).
The software intrrupts from running threads can change the set of running threads by requesting I/O, or by signaling other threads, (the events, mutexes, condition-variables and semaphores). The hardware interrupts from peripheral devices can change the set of running threads by signaling I/O completion.
When the OS gets these inputs, it uses that input, and internal state in containers of Thread Control Block and Process Control Block structs, to decide which set of ready threads to run next. It can block a thread from running by saving its context, (including registers, especially stack pointer), in its TCB and not returning from the interrupt. It can run a thread that was blocked by restoring its context from its TCB to a core and performing an interrupt-return, so allowing the thread to resume from where it left off.
The gain is that no thread that is waiting for I/O gets to run at all and so does not use any CPU and, when I/O becomes avilable, a waiting thread is made ready 'immediately' and, if there is a core available, running.
This combination of OS state data, and hardware/software interrupts, effciently matches up threads that can make forward progress with cores avalable to run them, and no CPU is wasted on polling I/O or inter-thread comms flags.
All this complexity, both in the OS and for the developer who has to design multithreaded apps and so put up with locks, synchronization, mutexes etc, has just one vital goal - high performance I/O. Without it, you can forget video streaming, BitTorrent and browsers - they would all be too piss-slow to be useable.
Statements and phrases like 'CPU quantum', 'give up the remainder of their time-slice' and 'round-robin' make me want to throw up.
It's a state-machine. Hardware and software interrupts go in, a set of running threads comes out. The hardware timer interrupt, (the one that can time-out system calls, allow threads to sleep and share out CPU on a box that is overloaded), though valuable, is just one of many.
So I'm on thread 16, and I need to get to thread 1 to modify UI. I
randomly stop it anywhere, "move the stack over to thread 1" then
"take its context and modify it"?
No, time for 'economical with truth' #2...
Thread 1 is running the GUI. To do this, it needs inputs from mouse, keyboard. The classic way for this to happen is that thread 1 waits, blocked, on a GUI input queue - a thread-safe producer-consumer queue, for KB/mouse messages. It's using no CPU - the cores are off running services and BitTorrent downloads. You hit a key on the keyboard, and the keyboard-controller hardware raises an interrupt line on the interrupt controller, causing a core to jump to the keyboard driver code as soon as it has finished its current instruction. The driver reads the KB controller, assembles a KeyPressed message and pushes it onto the input queue of the GUI thread with focus - your thread 1. The driver exits by calling the scheduler interrupt entry point so that a scheduling run can be performed and your GUI thread is assigned a core an run on it. To thread 1, all it has done is make a blocking 'pop' call on a queue and, eventually, it returns with a message to process.
So, thread 1 is performing:
void* HandleGui{
while(true){
GUImessage message=thread1InputQueue.pop();
switch(message.type){
.. // lots of case statements to handle all the possible GUI messages
..
..
};
};
};
If thread 16 wants to interact with the GUI, it cannot do it directly. All it can do is to queue a message to thread 1, in a similar way to the KB/mouse drivers, to instruct it to do stuff.
This may seem a bit restrictive, but the message from thread 16 can contain more than POD. It could have a 'RunMyCode' message type and contain a function pointer to code that thread 16 wants to be run in the context of thread 1. When thread 1 gets around to hadling the message, its 'RunMyCode' case statement calls the function pointer in the message. Note that this 'simple' mechanism is asynchronous - thread 16 has issued the mesage and runs on - it has no idea when thread 1 will get around to running the function it passed. This can be a problem if the function accesses any data in thread 16 - thread 16 may also be accessing it. If this is an issue, (and it may not be - all the data required by the function may be in the message, which can be passed into the function as a parameter when thread 1 calls it), it is possible to make the function call synchronous by making thread 16 wait until thread 1 has run the function. One way would be for the function signal an OS synchronization object as its last line - an object upon which thread 16 will wait immediately after queueing its 'RunMyCode' message:
void* runOnGUI(GUImessage message){
// do stuff with GUI controls
message.notifyCompletion->signal(); // tell thread 16 to run again
};
void* thread16run(){
..
..
GUImessage message;
waitEvent OSkernelWaitObject;
message.type=RunMyCode;
message.function=runOnGUI;
message.notifyCompletion=waitEvent;
thread1InputQueue.push(message); // ask thread 1 to run my function.
waitEvent->wait(); // wait, blocked, until the function is done
..
..
};
So, getting a function to run in the context of another thread requires cooperation. Threads cannot call other threads - only signal them, usually via the OS. Any thread that is expected to run such 'externally signaled' code must have an accessible entry point where the function can be placed and must execute code to retreive the function address and call it.
In UNIX, if a thread calls sleep function, will the entire process not do any work for that time or only the sleep calling thread will not do any work for that time?
In a multi-threaded program, I want a thread to work for certain amount of time, how to achieve this?
man sleep says:
The sleep() function suspends execution of the calling thread until either seconds seconds have elapsed
or a signal is delivered to the thread and its action is to invoke a signal-catching function or to
terminate the thread or process. System activity may lengthen the sleep by an indeterminate amount.
This function is implemented using nanosleep(2) by pausing for seconds seconds or until a signal
occurs. Consequently, in this implementation, sleeping has no effect on the state of process timers,
and there is no special handling for SIGALRM.
so "only the calling thread".
As for your second question: It's mostly beyond your control and most people should rethink their design and leave that to the OS -- your OS controls your threads' execution. You can use conditions and signals to coordinate threads' actions to some extent. It's typically better/easier to use fewer threads and manage tasks, rather than threads directly. Even if you want to time it, there's a lot of work in trying to figure out at runtime how much time your threads are being given.
Can anybody give some information on timer_helper_thread() function of librt.so.1.
I am using posix timer_create() function in my application for timer functionality and i am using SIEV_THREAD for notifiction. When timeout happens, i could see in gdb that two thread are getting created. One is the thread whose start function i have specified and another is the thread whose start function is timer_help_therad() of librt.so.1. Among these two timer_helper_thread() is not exiting even after my thread is exiting. Can anbody tell me when will timer_helper_thread() exit and give some informatin on it?
Short answer: don't worry about it; it's an implementation detail and will clean up after itself when your program exits. But if you're curious...
From glibc's timer_create(2) man page:
SIGEV_THREAD:
Upon timer expiration, invoke sigev_notify_function as if it were the start function of a new thread. (Among the implementation possibilities here are that each timer notification could result in the creation of a new thread, or that a single thread is created to receive all notifications.)
And also:
The functionality for SIGEV_THREAD is implemented within glibc, rather than the kernel.
So glibc (i.e. librt.so) assumes that the kernel cannot create a thread in response to a timer event -- that all it supports is sending a signal. So someone needs to receive that signal and create the handler thread. If you wanted to muck with the details of receiving the signal yourself, you wouldn't have used SIGEV_THREAD, so glibc doesn't bother you and instead creates its own thread just for handling timer events.
This timer helper thread lasts from the fist time you call timer_create() until your program ends. Unless you're doing something unusual, you don't need to worry about it; it will clean up after itself when your program exits. The only thing it does is wait for a timer to expire, so it's not using up any extra processing power. Furthermore, it looks like there will only ever be the one helper thread, no matter how many timers you create.
#jander: Your comment is interesting here "This timer helper thread lasts from the fist time you call timer_create() until your program ends."
There are threads created on everytime a timer is timeout. Is this same as the timer_helper_thread() you mention?
I have a similar post where I observe a separate thread created only for timer_create(). Would this be the timer_helper_thread()?
Ref: New thread on invocation of timer_create()
How do I control the number of threads that my program is working on?
I have a program that is now ready for mutithreading but one problem is that the program is extremely memory intensive and i have to limit the number of threads running so that i don't run out of ram. The main program goes through and creates a whole bunch of handles and associated threads in suspended state.
I want the program to activate a set number of threads and when one thread finishes, it will automatically unsuspended the next thread in line until all the work has been completed. How do i do this?
Someone has once mentioned something about using a thread handler, but I can't seem to find any information about how to write one or exactly how it would work.
If anyone can help, it would be greatly appreciated.
Using windows and visual c++.
Note: i don't need to worry about the traditional problems of access with the threads, each one is completely independent of each other, its more of like batch processing rather than true mutithreading of a program.
Thanks,
-Faken
Don't create threads explicitly. Create a thread pool, see Thread Pools and queue up your work using QueueUserWorkItem. The thread pool size should be determined by the number of hardware threads available (number of cores and ratio of hyperthreading) and the ratio of CPU vs. IO your work items do. By controlling the size of the thread pool you control the number of maximum concurrent threads.
A Suspended thread doesn't use CPU resources, but it still consumes memory, so you really shouldn't be creating more threads than you want to run simultaneously.
It is better to have only as many threads as your maximum number of simultaneous tasks, and to use a queue to pass units of work to the pool of worker threads.
You can give work to the standard pool of threads created by Windows using the Windows Thread Pool API.
Be aware that you will share these threads and the queue used to submit work to them with all of the code in your process. If, for some reason, you don't want to share your worker threads with other code in your process, then you can create a FIFO queue, create as many threads as you want to run simultaneously and have each of them pull work items out of the queue. If the queue is empty they will block until work items are added to the queue.
There is so much to say here.
There are a few ways
You should only create as many thread handles as you plan on running at the same time, then reuse them when they complete. (Look up thread pool).
This guarantees that you can never have too many running at the same time. This raises the question of funding out when a thread completes. You can have a callback be called just before a thread terminates where a parameter in that callback is the thread handle that just finished. Use Boost bind and boost signals for that. When the callback is called, look for another task for that thread handle and restart the thread. That way all you have to do is add to the "tasks to do" list and the callback will remove the tasks for you. No polling needed, and no worries about too many threads.