Update2,Haskell - haskell

Atom: The Atom is the datatype used to describe Atomic Sentences or propositions. These are basically
represented as a string.
Literal: Literals correspond to either atoms or negations of atoms. In this implementation each literal
is represented as a pair consisting of a boolean value, indicating the polarity of the Atom, and the
actual Atom. Thus, the literal ‘P’ is represented as (True,"P") whereas its negation ‘-P’ as
(False,"P").
2
Clause: A Clause is a disjunction of literals, for example PvQvRv-S. In this implementation this
is represented as a list of Literals. So the last clause would be [(True,"P"), (True,"Q"),
(True,"R"),(False,"S")].
Formula: A Formula is a conjunction of clauses, for example (P vQ)^(RvP v-Q)^(-P v-R).
This is the CNF form of a propositional formula. In this implementation this is represented as a list of
Clauses, so it is a list of lists of Literals. Our above example formula would be [[(True,"P"),
(True,"Q")], [(True,"R"), (True,"P"), (False,"Q")], [(False, "P"),
(False,"P")]].
Model: A (partial) Model is a (partial) assignment of truth values to the Atoms in a Formula. In this
implementation this is a list of (Atom, Bool) pairs, ie. the Atoms with their assignments. So in the
above example of type Formula if we assigned true to P and false to Q then our model would be
[("P", True),("Q", False)]
Ok so I wrote and update function
update :: Node -> [Node]
It takes in a Node and returns a list of the Nodes
that result from assigning True to an unassigned atom in one case and False in the other (ie. a case
split). The list returned has two nodes as elements. One node contains the formula
with an atom assigned True and the model updated with this assignment, and the other contains
the formula with the atom assigned False and the model updated to show this. The lists of unassigned
atoms of each node are also updated accordingly. This function makes use of an
assign function to make the assignments. It also uses the chooseAtom function to
select the literal to assign.
update :: Node -> [Node]
update (formula, (atoms, model)) = [(assign (chooseAtom atoms, True) formula, (remove (chooseAtom atoms) atoms, ((chooseAtom atoms,True)) `insert` model)) , (assign (chooseAtom atoms, False) formula, (remove (chooseAtom atoms) atoms, ((chooseAtom atoms, False) `insert` model)) )]
Now I have to do the same thing but this time I must implement a variable selection heuristic.this should replace the chooseAtom and I'm supposed to write a function update2 using it
type Atom = String
type Literal = (Bool,Atom)
type Clause = [Literal]
type Formula = [Clause]
type Model = [(Atom, Bool)]
type Node = (Formula, ([Atom], Model))
update2 :: Node -> [Node]
update2 = undefined
So my question is how can I create a heurestic and to implement it into the update2 function ,that shoud behave identical to the update function ?

If I understand the question correctly, you're asking how to implement additional selection rules in resolution systems for propositional logic. Presumably, you're constructing a tree of formulas gotten by assigning truth-values to literals until either (a) all possible combinations of assignments to literals have been tried or (b) box (the empty clause) has been derived.
Assuming the function chooseAtom implements a selection rule, you can parameterize the function update over an arbitrary selection rule r by giving update an additional parameter and replacing the occurrence of chooseAtom in update by r. Since chooseAtom implements a selection rule, passing that selection rule to the parameter r gives the desired result. If you provide an implementation of chooseAtom and the function you intend to replace it, it would be easier to verify that your implementation is correct.
Hopefully this is helpful. However, it's unclear exactly what's being asked. In particular, you're asking for a "variable selection rule." However, it looks like you're implementing a resolution system for propositional logic. In general, selection rules and variables are associated with resolution for predicate logic.

Related

Is it possible to pattern match arguments in a function in haskell? [duplicate]

This question already has answers here:
Pattern matching identical values
(4 answers)
Closed 10 months ago.
I want the function isValid to return True if the first and second arguments match desPlanet and currPlanet from the 3rd argument. Is there a way I can do this?
Please see -
Not like that.
Patterns can only consist of 3 things:
A constructor, applied to as many sub-patterns as the constructor has arguments. Examples are Nothing, Just (Just x), or [desPlanet, _, currPlanet]:_, etc. The pattern will match values that were constructed with the same constructor, if all of the sub-patterns match the corresponding arguments in the value.
A variable, which will simply match anything and make the matched value available under that variable name. (The variable _ is a special, since it doesn't actually make the matched value available, and can thus be used multiple times across the pattern)
A literal like 123, "foo", 'c', etc; which will be matched by equality checking. (If the literal is polymorphic, like numeric literals with the Num class, then you may need an Eq constraint)
Note that there is no option to match anything against an existing variable (or against one bound elsewhere in the same pattern). The template you're trying to check against must be statically known, it can't be referred to by a variable. You either match against a specific concrete literal, or you match against a specific concrete constructor, or you just accept anything and bind it to a variable name.
However guards do allow you to check arbitrary conditions, and if the guard condition fails then the function will fall through to its next equation (just as if a pattern failed to match). So you can still do exactly what you want ("I want the function isValid to return True if the first and second arguments match desPlanet and currPlanet from the 3rd argument"); you just don't do solely with pattern matching.
For example:
isValid currPlanet desPlanet ([desPlanet', _, curPlanet'] : _) solarSys
| curPlanet == curPlanet' && desPlanet = desPlanet'
= True
isValid ... -- other equations

How do fixpoint, variable, let and tag schema constructors work in Winery?

I had previously asked where the Winery types are indexed. I noticed that in the serialization for the schema for Bool, which is [4,6], the 4 is the version number, and 6 is the index of SBool in SchemaP. I verified the hypothesis using other "primitive" types like Integer (serialization: 16), Double (18), Text (20). Also, [Bool] will be SVector SBool, serialized to [4,2,6], which makes sense: the 2 is for SVector, the 6 is for SBool.
But SchemaP also contains constructors that I don't intuitively see how are used: SFix, SVar, STag and SLet. What are they, and which type would I need to construct the schema for, to see them used? Why is SLet at the end, but SFix at the beginning?
SFix looks like a µ quantifier for a recursive type. The type µx. T is the type T where x refers to the whole type µx. T. For example, a list data List a = Nil | Cons a (List a) can be represented as L(a) = µr. 1 + a × r, where the recursive occurrence of the type is replaced with the variable r. You could probably see this with a recursive user-defined type like data BinTree a = Leaf | Branch a (BinTree a) (BinTree a).
This encoding doesn’t explicitly include a variable name, because the next constructor SVar specifies that “SVar n refers to the nth innermost fixpoint”, where n is an Int in the synonym type Schema = SchemaP Int. This is a De Bruijn index. If you had some nested recursive types like µx. µy. … = SFix (SFix …), then the inner variable would be referenced as SVar 0 and the outer one as SVar 1 within the body …. This “relative” notation means you can freely reorganise terms without worrying about having to rename variables for capture-avoiding substitution.
SLet is a let binding, and since it’s specified as SLet !(SchemaP a) !(SchemaP a), I presume that SLet e1 e2 is akin to let x = e1 in e2, where the variable is again implicit. So I suspect this may be a deficiency of the docs, and SVar can also refer to Let-bound variables. I don’t know how they use this constructor, but it could be used to make sharing explicit in the schema.
Finally, STag appears to be a way to attach extra “tag” metadata within the schema, in some way that’s specific to the library.
The ordering of these constructors might be maintained for compatibility with earlier versions, so adding new constructors at the end would avoid disturbing the encoding, and I figure the STag and SLet constructors at the end were simply added later.

How does Haskell know whether a data type declaration is a variable or a named type?

Take a data type declaration like
data myType = Null | Container TypeA v
As I understand it, Haskell would read this as myType coming in two different flavors. One of them is Null which Haskell interprets just as some name of a ... I guess you'd call it an instance of the type? Or a subtype? Factor? Level? Anyway, if we changed Null to Nubb it would behave in basically the same way--Haskell doesn't really know anything about null values.
The other flavor is Container and I would expect Haskell to read this as saying that the Container flavor takes two fields, TypeA and v. I expect this is because, when making this type definition, the first word is always read as the name of the flavor and everything that follows is another field.
My question (besides: did I get any of that wrong?) is, how does Haskell know that TypeA is a specific named type rather than an un-typed variable? Am I wrong to assume that it reads v as an un-typed variable, and if that's right, is it because of the lower-case initial letter?
By un-typed I mean how the types appear in the following type-declaration for a function:
func :: a -> a
func a = a
First of all, terminology: "flavors" are called "cases" or "constructors". Your type has two cases - Null and Container.
Second, what you call "untyped" is not really "untyped". That's not the right way to think about it. The a in declaration func :: a -> a does not mean "untyped" the same way variables are "untyped" in JavaScript or Python (though even that is not really true), but rather "whoever calls this function chooses the type". So if I call func "abc", then I have chosen a to be String, and now the compiler knows that the result of this call must also be String, since that's what the func's signature says - "I take any type you choose, and I return the same type". The proper term for this is "generic".
The difference between "untyped" and "generic" is that "untyped" is free-for-all, the type will only be known at runtime, no guarantees whatsoever; whereas generic types, even though not precisely known yet, still have some sort of relationship between them. For example, your func says that it returns the same type it takes, and not something random. Or for another example:
mkList :: a -> [a]
mkList a = [a]
This function says "I take some type that you choose, and I will return a list of that same type - never a list of something else".
Finally, your myType declaration is actually illegal. In Haskell, concrete types have to be Capitalized, while values and type variables are javaCase. So first, you have to change the name of the type to satisfy this:
data MyType = Null | Container TypeA v
If you try to compile this now, you'll still get an error saying that "Type variable v is unknown". See, Haskell has decided that v must be a type variable, and not a concrete type, because it's lower case. That simple.
If you want to use a type variable, you have to declare it somewhere. In function declaration, type variables can just sort of "appear" out of nowhere, and the compiler will consider them "declared". But in a type declaration you have to declare your type variables explicitly, e.g.:
data MyType v = Null | Container TypeA v
This requirement exist to avoid confusion and ambiguity in cases where you have several type variables, or when type variables come from another context, such as a type class instance.
Declared this way, you'll have to specify something in place of v every time you use MyType, for example:
n :: MyType Int
n = Null
mkStringContainer :: TypeA -> String -> MyType String
mkStringContainer ta s = Container ta s
-- Or make the function generic
mkContainer :: TypeA -> a -> MyType a
mkContainer ta a = Container ta a
Haskell uses a critically important distinction between variables and constructors. Variables begin with a lower-case letter; constructors begin with an upper-case letter1.
So data myType = Null | Container TypeA v is actually incorrect; the first symbol after the data keyword is the name of the new type constructor you're introducing, so it must start with a capital letter.
Assuming you've fixed that to data MyType = Null | Container TypeA v, then each of the alternatives separated by | is required to consist of a data constructor name (here you've chosen Null and Container) followed by a type expression for each of the fields of that constructor.
The Null constructor has no fields. The Container constructor has two fields:
TypeA, which starts with a capital letter so it must be a type constructor; therefore the field is of that concrete type.
v, which starts with a lowercase letter and is therefore a type variable. Normally this variable would be defined as a type parameter on the MyType type being defined, like data MyType v = Null | Container TypeA v. You cannot normally use free variables, so this was another error in your original example.2
Your data declaration showed how the distinction between constructors and variables matters at the type level. This distinction between variables and constructors is also present at the value level. It's how the compiler can tell (when you're writing pattern matches) which terms are patterns it should be checking the data against, and which terms are variables that should be bound to whatever the data contains. For example:
lookAtMaybe :: Show a => Maybe a -> String
lookAtMaybe Nothing = "Nothing to see here"
lookAtMaybe (Just x) = "I found: " ++ show x
If Haskell didn't have the first-letter rule, then there would be two possible interpretations of the first clause of the function:
Nothing could be a reference to the externally-defined Nothing constructor, saying I want this function rule to apply when the argument matches that constructor. This is the interpretation the first-letter rule mandates.
Nothing could be a definition of an (unused) variable, representing the function's argument. This would be the equivalent of lookAtMaybe x = "Nothing to see here"
Both of those interpretations are valid Haskell code producing different behaviour (try changing the capital N to a lower case n and see what the function does). So Haskell needs a rule to choose between them. The designers chose the first-letter rule as a way of simply disambiguating constructors from variables (that is simple to both the compiler and to human readers) without requiring any additional syntactic noise.
1 The rule about the case of the first letter applies to alphanumeric names, which can only consist of letters, numbers, and underscores. Haskell also has symbolic names, which consists only of symbol characters like +, *, :, etc. For these, the rule is that names beginning with the : character are constructors, while names beginning with another character are variables. This is how the list constructor : is distinguished from a function name like +.
2 With the ExistentialQuantification extension turned on it is possible to write data MyType = Null | forall v. Container TypeA v, so that the the constructor has a field with a variable type and the variable does not appear as a parameter to the overall type. I'm not going to explain how this works here; it's generally considered an advanced feature, and isn't part of standard Haskell code (which is why it requires an extension)

Haskell, stuck on understanding type synonyms

From LYAH book, parameterizing type synonyms:
I would understand:
type MyName = String
But this example I don't get:
type IntMap v = Map Int v -- let alone it can be shortened
'Map' is a function, not a type, right? This got me in loops in the book constantly now. Next to that: Map would require a function and a list to work, correct? If so, and 'v' is the list, what is the 'Int'?
Map is the name of a type. It's an associative array and maps values of type T to values of type K. So IntMap is the type of a Map which has Int keys and v values. Maps are also known as dictionaries in some languages. They're implemented by hash tables, balanced trees or other more exotic data structures.
It's an unfortunate name collision that there's also the map function. They kind of do the same thing, only in different contexts. map transforms values in the input by applying a function to them, whereas Map transforms input keys to output values.
There is a type named Map (with a capital "M"). There is also a function named map (with a lowercase "M"). These are unrelated other than having kind-of similar names. Try not to confuse them. ;-)

How to construct an array with multiple possible lengths using immutability and functional programming practices?

We're in the process of converting our imperative brains to a mostly-functional paradigm. This function is giving me trouble. I want to construct an array that EITHER contains two pairs or three pairs, depending on a condition (whether refreshToken is null). How can I do this cleanly using a FP paradigm? Of course with imperative code and mutation, I would just conditionally .push() the extra value onto the end which looks quite clean.
Is this an example of the "local mutation is ok" FP caveat?
(We're using ReadonlyArray in TypeScript to enforce immutability, which makes this somewhat more ugly.)
const itemsToSet = [
[JWT_KEY, jwt],
[JWT_EXPIRES_KEY, tokenExpireDate.toString()],
[REFRESH_TOKEN_KEY, refreshToken /*could be null*/]]
.filter(item => item[1] != null) as ReadonlyArray<ReadonlyArray<string>>;
AsyncStorage.multiSet(itemsToSet.map(roArray => [...roArray]));
What's wrong with itemsToSet as given in the OP? It looks functional to me, but it may be because of my lack of knowledge of TypeScript.
In Haskell, there's no null, but if we use Maybe for the second element, I think that itemsToSet could be translated to this:
itemsToSet :: [(String, String)]
itemsToSet = foldr folder [] values
where
values = [
(jwt_key, jwt),
(jwt_expires_key, tokenExpireDate),
(refresh_token_key, refreshToken)]
folder (key, Just value) acc = (key, value) : acc
folder _ acc = acc
Here, jwt, tokenExpireDate, and refreshToken are all of the type Maybe String.
itemsToSet performs a right fold over values, pattern-matching the Maye String elements against Just and (implicitly) Nothing. If it's a Just value, it cons the (key, value) pair to the accumulator acc. If not, folder just returns acc.
foldr traverses the values list from right to left, building up the accumulator as it visits each element. The initial accumulator value is the empty list [].
You don't need 'local mutation' in functional programming. In general, you can refactor from 'local mutation' to proper functional style by using recursion and introducing an accumulator value.
While foldr is a built-in function, you could implement it yourself using recursion.
In Haskell, I'd just create an array with three elements and, depending on the condition, pass it on either as-is or pass on just a slice of two elements. Thanks to laziness, no computation effort will be spent on the third element unless it's actually needed. In TypeScript, you probably will get the cost of computing the third element even if it's not needed, but perhaps that doesn't matter.
Alternatively, if you don't need the structure to be an actual array (for String elements, performance probably isn't that critical, and the O (n) direct-access cost isn't an issue if the length is limited to three elements), I'd use a singly-linked list instead. Create the list with two elements and, depending on the condition, append the third. This does not require any mutation: the 3-element list simply contains the unchanged 2-element list as a substructure.
Based on the description, I don't think arrays are the best solution simply because you know ahead of time that they contain either 2 values or 3 values depending on some condition. As such, I would model the problem as follows:
type alias Pair = (String, String)
type TokenState
= WithoutRefresh (Pair, Pair)
| WithRefresh (Pair, Pair, Pair)
itemsToTokenState: String -> Date -> Maybe String -> TokenState
itemsToTokenState jwtKey jwtExpiry maybeRefreshToken =
case maybeRefreshToken of
Some refreshToken ->
WithRefresh (("JWT_KEY", jwtKey), ("JWT_EXPIRES_KEY", toString jwtExpiry), ("REFRESH_TOKEN_KEY", refreshToken))
None ->
WithoutRefresh (("JWT_KEY", jwtKey), ("JWT_EXPIRES_KEY", toString jwtExpiry))
This way you are leveraging the type system more effectively, and could be improved on further by doing something more ergonomic than returning tuples.

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