There exists a function that is part of a software package (MRICro), and it is called 'dcm2nii.'
When a relative path is used as the output directory, the function works perfectly well.
But, when the absolute path to the exact same folder is used, the function breaks down.
Example (absolute path):
dcm2nii -o /net/user1/project_name/Data/2011_01_10_SVD1/Processed/3_fMRI_rest E2538S3I00*
Example (relative path):
dcm2nii -o ../Processed/3_fMRI_rest E2538S3I00*
Sample error message that occurs when using the absolute path for the output folder (the last line suggests that the output file can not be created):
Validating 52 potential DICOM images.
Found 52 DICOM images.
Converting 52/52 2
E2538S3I0001.MR.dcm->20110110_112950E2538S3I0001MRFPSD1F29OCT2010RCs003a1001.nii
GZip 20110110_112950E2538S3I0001MRFPSD1F29OCT2010RCs003a1001.nii
unable to create /net/user1/project_name/Data/2011_01_10_SVD1/Processed/3_fMRI_rest/20110110_112950E2538S3I0001MRFPSD1F29OCT2010RCs003a1001.nii.gz
I do not know if this problem is due to me doing something wrong in Linux/bash or due to the function actually having a mistake.
But, any input is appreciated.
On a more general level, I am looking for any foreseeable reason for why a function would be able to use a relative folder path and not an absolute one (provided that they resolve to the same location).
EDIT: pwd gives:
/net/user1/project_name/Data/2011_01_10_SVD1/3_fMRI_rest
you would really have to show us the code before we can tell you what the cause of the problem is, however the behaviour you described is possible
This is an example of poor practice but consider the following
#!/bin/bash
....
current_dir = $(pwd)
out_dir = $1
cd ${somewhere}
..... do stuff
#no we want to come back to create the output dir
mkdir ${current_dir}/$out_dir
This appears to be a bug of some kind.. I am experiencing the same issue. If I try to execute this command on data in my home folder, I get the same error.
However, if I move my data to a path that doesn't involve any expansion, i.e. ''/tmp/data'', the program executes fine.
Related
Upon looping a directory to delete txt files ONLY - a message is returned indicating The System cannot find the file specified: 'File.txt'.
I've made sure the txt files that I'm attempting to delete exist in the directory I'm looping. I've also checked my code and to make sure it can see my files by printing them in a list with the print command.
import os
fileLoc = 'c:\\temp\\files'
for files in os.listdir(fileLoc):
if files.endswith('.txt'):
os.unlink(files)
Upon initial execution, I expected to see all txt files deleted except for other non-txt files. The actual result was an error message "FileNotFoundError: [WinError 2] The system cannot find the file specified: 'File.txt'.
Not sure what I'm doing wrong, any help would be appreciated.
It isn't found because the the path you intended to unlink is relative to fileLoc. In fact with your code, the effect is to unlink the file relative to the current working directory. If there were *.txt files
in the cwd then the code would have unfortunate side-effects.
Another way to look at it:
Essentially, by analogy, in the shell what you're trying to do is equivalent to this:
# first the setup
$ mkdir foo
$ touch foo/a.txt
# now your code is equvalent to:
$ rm *.txt
# won't work as intended because it removes the *.txt files in the
# current directory. In fact the bug is also that your code would unlink
# any *.txt files in the current working directory unintentionally.
# what you intended was:
$ rm foo/*.txt
The missing piece was the path to the file in question.
I'll add some editorial: The Old Bard taught us to "when in doubt, print variables". In other words, debug it. I don't see from the OP an attempt to do that. Just a thing to keep in mind.
Anyway the new code:
Revised:
import os
fileLoc = 'c:\\temp\\files'
for file in os.listdir(fileLoc):
if file.endswith('.txt'):
os.unlink(os.path.join(fileLoc,file))
The fix: os.path.join() builds a path for you from parts. One part is the directory (path) where the file exists, aka: fileLoc. The other part is the filename, aka file.
os.path.join() makes a whole valid path from them using whatever OS directory separator is appropriate for your platform.
Also, might want to glance through:
https://docs.python.org/2/library/os.path.html
I use a program which create me postscript file before using ps2pdf to make it a readable pdf, i've made a program which add some string to overwrite the company new logo. (The first program can't import image file itself).
I add the string before the before-last line of the file (" showpage").
While running my program to add the logo there is no error.
With the option -dNOSAFER everything is fine, but by default it's set to -dSAFER, and an invalidfileaccess error pop, the files are 6 jpg images alone in their directory.
I don't want to make it run with the -dNOSAFER option on. As it will fully open the file system.
In the documentation I've seen that there is a "permitted path" setting, but i can't find nowhere to set this up. Is it just a command line option to set in the command launching the program ? Or is there a config file for GhostScript / ps2pdf where i can put the path to this directory as permitted path.
in this documentation :
http://www.ghostscript.com/doc/current/Use.htm
I only find
-dTTYPAUSE
Causes Ghostscript to read a character from /dev/tty, rather than
standard input, at the end of each page. This may be useful if input
is coming from a pipe. Note that -dTTYPAUSE overrides -dNOPAUSE. Also
note that -dTTYPAUSE requires opening the terminal device directly,
and may cause problems in combination with -dSAFER. Permission errors
can be avoided by adding the device to the permitted reading list
before invoking safer mode
gs -dTTYPAUSE -dDELAYSAFER -c '<< /PermitFileReading [ (/dev/tty)] >> setuserparams .locksafe' -dSAFER
The quote is just for the context but is this a way to put the permitted path ?
As gs automatically launch with the full system as readOnly there will be no difference ? There is no other find result for PermitFile in this page.
Try adding the required path to the search path with -I (Include) See Use.htm, section 8 How Ghostscript finds files. This should only be a problem if you are using 'run' or similar to read files from another location.
The section on TTYPAUSE is not relevant.
I am trying to zip a file using shell script command. I am using following command:
zip ./test/step1.zip $FILES
where $FILES contain all the input files. But I am getting a warning as follows
zip warning: name not matched: myfile.dat
and one more thing I observed that the file which is at last in the list of files in a folder has the above warning and that file is not getting zipped.
Can anyone explain me why this is happening? I am new to shell script world.
zip warning: name not matched: myfile.dat
This means the file myfile.dat does not exist.
You will get the same error if the file is a symlink pointing to a non-existent file.
As you say, whatever is the last file at the of $FILES, it will not be added to the zip along with the warning. So I think something's wrong with the way you create $FILES. Chances are there is a newline, carriage return, space, tab, or other invisible character at the end of the last filename, resulting in something that doesn't exist. Try this for example:
for f in $FILES; do echo :$f:; done
I bet the last line will be incorrect, for example:
:myfile.dat :
...or something like that instead of :myfile.dat: with no characters before the last :
UPDATE
If you say the script started working after running dos2unix on it, that confirms what everybody suspected already, that somehow there was a carriage-return at the end of your $FILES list.
od -c shows the \r carriage-return. Try echo $FILES | od -c
Another possible cause that can generate a zip warning: name not matched: error is having any of zip's environment variables set incorrectly.
From the man page:
ENVIRONMENT
The following environment variables are read and used by zip as described.
ZIPOPT
contains default options that will be used when running zip. The contents of this environment variable will get added to the command line just after the zip command.
ZIP
[Not on RISC OS and VMS] see ZIPOPT
Zip$Options
[RISC OS] see ZIPOPT
Zip$Exts
[RISC OS] contains extensions separated by a : that will cause native filenames with one of the specified extensions to be added to the zip file with basename and extension swapped.
ZIP_OPTS
[VMS] see ZIPOPT
In my case, I was using zip in a script and had the binary location in an environment variable ZIP so that we could change to a different zip binary easily without making tonnes of changes in the script.
Example:
ZIP=/usr/bin/zip
...
${ZIP} -r folder.zip folder
This is then processed as:
/usr/bin/zip /usr/bin/zip -r folder.zip folder
And generates the errors:
zip warning: name not matched: folder.zip
zip I/O error: Operation not permitted
zip error: Could not create output file (/usr/bin/zip.zip)
The first because it's now trying to add folder.zip to the archive instead of using it as the archive. The second and third because it's trying to use the file /usr/bin/zip.zip as the archive which is (fortunately) not writable by a normal user.
Note: This is a really old question, but I didn't find this answer anywhere, so I'm posting it to help future searchers (my future self included).
eebbesen hit the nail in his comment for my case (but i cannot vote for comment).
Another possible reason missed in the other comments is file exceeding the file size limit (4GB).
I converted my script for unix environment using dos2unix command and executed my script as ./myscript.sh instead bash myscript.sh.
I just discovered another potential cause for this. If the permissions of the directory/subdirectory don't allow the zip to find the file, it will report this error. Actually, if you run a chmod -R 444 on the directory, and then try to zip it, you will reproduce this error, and also have a "stored 0%" report, like this:
zip warning: name not matched: borrar/enviar
adding: borrar/ (stored 0%)
Hence, try changing the permissions of the file. If you are trying to send them through email, and those email filters (like Gmail's) invent silly filters of not sending executables, don't forget that making permissions very strict when making zip compression can be the cause of the error you are reporting, of "name not matched".
spaces are not allowed:
it would fail if there are more than one files(s) in $FILES unless you put them in loop
I also encountered this issue. In my case, the line separate is CRLF in my zip shell script which causes the problem. Using LF fixed it.
I'm using ImageMagick to do some image processing from the commandline, and would like to operate on a list of files as specified in foo.txt. From the instructions here: http://www.imagemagick.org/script/command-line-processing.php I see that I can use Filename References from a file prefixed with #. When I run something like:
montage #foo.txt output.jpg
everything works as expected, as long as foo.txt is in the current directory. However, when I try to access bar.txt in a different directory by running:
montage /some_directory/#bar.txt
output2.jpg
I get:
montage: unable to open image
/some_directory/#bar.txt: No such file
or directory # blob.c/OpenBlob/2480.
I believe the issue is my syntax, but I'm not sure what to change it to. Any help would be appreciated.
Quite an old entry but it seems relatively obvious that you need to put the # before the full path:
montage #/some_directory/bar.txt output2.jpg
As of ImageMagick 6.5.4-7 2014-02-10, paths are not supported with # syntax. The # file must be in the current directory and identified by name only.
I haven't tried directing IM to pull the list of files from a file, but I do specify multiple files on the command line like this:
gm -sOutputFile=dest.ext -f file1.ppm file2.ppm file3.ppm
Can you pull the contents of that file into a variable, and then let the shell expand that variable?
I'm trying out CCNetConfig (warning, website a little slow). Great app, one annoyance.
I can see in the documentation and even in the source code (Look at the end of the Initialize method) that I should be able to pass in a command line parameter to automatically load the configuration file.
I have tried:
-f E:\CruiseControl.Net\server\ccnet.config
-file E:\CruiseControl.Net\server\ccnet.config
-f=E:\CruiseControl.Net\server\ccnet.config
-file=E:\CruiseControl.Net\server\ccnet.config
And the same 4 switches with quotes around the file name just in case.
They all produce errors or just don't work. Has anyone had success doing this?
Thanks in advance.
Try moving it to a different path. Try the simplest thing: c:\ccnet.config.
I'm guessing it's the source of the problem because I recall CCNetConfig gave me sh!t early on when I tried to open files in paths that had spaces in them (e..g in Program Files).
According to my version of CCNet the command line flag for using a different config file is -c or --config, so the following should do it...
-c "E:\CruiseControl.Net\server\ccnet.config"
...which works for me.
I don't know why it uses a non-standard flag, but there you go.