How does one yank a function call in vim? - vim

Suppose a line of text reads:
$x = ( frobnicate( foo( bar( $x, $y )[ 1 ]))[ 1 ]);
The cursor is on the 'f' of 'frobnicate' and I want to yank the text which includes the call to frobnicate. (That is, everything up to the 3rd closing parenthesis. I can certainly do:
y3f)
or do it interactively with
vf);;y
but neither of these is appealing. (I don't want to have to count the '3' manually, nor do the repeated find until I hit the end point.) Is there an easy way to accomplish the move from 'f' to the matching closing paren? I'm thinking something like the v_i 'inner word' motion command.

y% seems to work.
From help %:
Find the next item in this line after
or under the cursor and jump to its
match. inclusive motion. Items can
be: ([{}]) parenthesis or
(curly/square) brackets

You could try yel% to position the cursor to the opening parentheses and then jump to the closing one with %, but it does not look much more efficient than your current solution.
The only advantage is that you don't have to count anything, and it works with nested call.
Edit :
as pointed by Peter, y% works and is a superior solution (even if I don't quite understand why it works. Vim is amazing!)

Related

Insert visual vim selection in the line below at the same position

I have a tedious task of converting chords from leadsheets into an inline format.
The format I have
G A
Never gonna give you up
F#m Bm
Never gonna let you down
G A F# Bm
Never gonna run around and desert you
And the format I need would b
Never gonna g[G]ive you [A]up
Never gonna l[F#m]et you do[Bm]wn
Never gonna r[G]un a[A]round and d[F#]esert [Bm]you
The problem with a script in Ruby or Python is, that the format isn't very consistent. So there could be newlines, weird characters, sometimes the chords are seperated with a dash... I haven't looked through all of the files, but I suspect more malformed stuff.
So I thought, if I have to go through of every leadsheet by hand, at least I can save some time using vim. This is the mapping I've come up with so far:
nmap <C-X> viWc[]<ESC>PviWx<down>p
Select the chord: viW
delete it and go into insert mode: c
add brackets
exit insert mode: <ESC>
paste the register to the left: P
select the chord again, including the brackets: viW
delete the selection: x
move cursor down, and paste it: p
But I few things I can't figure out is:
Sometimes the chords already have brackets, then I don't want to surround them with more brackets. Any idea how to only add brackets, if the chord isn't already surrounded with them?
It would be cool to do this with whole lines of chords. Sometimes there are multiple chords on the same line, and selecting them one by one is tedious. Any idea on how to operate the mapping above on a whole line?
well point 1 could be solved by adding the brackets around the chords on every second line:
:g/^/s/\[\=\zs[a-zA-Z#]\+\ze]\=/\[\0\]/g|+t+|-d
Credits: https://vi.stackexchange.com/questions/34785/search-and-replace-on-odd-even-numbered-lines-using-g
This however sucks, because it moves arround the chords, so we have to remove all brackets first and replace them with space
:%s/\[\([a-zA-Z#]\+\)\]/\1 /g
Then we can do the first line again, but remove some space too. Since there are no brackets left, it gets simpler (Note we use other brackets to get ride of some side effect the following code has):
:g/^/s/\([a-zA-Z#]\+\) \{0,3\}/\{\1\} /g|+t+|-d
Also we add a trailing whitespace at the end of the line so that the df} command will not move the cursor to a wrong place
Now that we have curly brackets everywhere, we can use reverse search with ?{ and then create a macro that jumps from results to result and moves it down, replaces the curly brackets with normal brackets and then calls itself (recursive macro):
gg0
qqq
?{<CR>
qq
df}jPr]F{r[n#qq
#q
And nearly all should be done.
The result:
Never gonna g[G]ive you [A]up
Never gonna l[F#m]et you dow[Bm]n
Never gonna r[G]un a[A]round and d[F#]esert [Bm]you
Note, we have to search backwards (? instead of /) so we can delete the chords directly.
If you have problems understanding what I did, feel free to ask.

Vim: % command doesn't move to first parenthesis

I am reading the vim manual. I am having an unexpected result using the % command.
Here is a quote from the manual:
When the cursor is not on a useful character, "%" will search forward to find
one. Thus if the cursor is at the start of the line of the previous example,
"%" will search forward and find the first "(". Then it moves to its match:
if (a == (b * c) / d)
---+---------------->
%
However, when I repeat the same thing (placing the cursor at the start of the line) and press %, the cursor moves the last ) parenthesis instead.
I didn't configure vim, I am using the default settings. I am wondering if my vim is not configured well. Is there a way to configure vim for it to move the cursor the first parenthesis similar to how it is described in the manual?
I am using gVim on Windows.
"it moves to its match", which means that it will move to the matching paranthesis of the one it found (in this case the closing paranthesis). So it does what it should.
To get back to the first paranthesis you will need to press '%' again!
Also you can use f( to move the cursor to the first open parenthesis (if it's not on the same line, you can use search for it like /( just as easily). This is helpful since you could do something like df( (or d/( to target a different line) to delete everything up to and including the open parenthesis. Whereas relying on a double press of % wouldn't allow that.

How to cut/yank half of a Vim "inner" or "block" object

I'm sure there must be some simple way to e.g. yank only the portion of an inner context that starts with the cursor, but haven't found anything.
For example
fcn(arg1, arg2, fcn2(x, y), arg4)
^-cursor here
How do I reduce this to
fcn(arg1, arg2)
in one command, without having to e.g. count intervening parentheses?
Edit:
The accepted answer establishes some good alternate ways of doing what I want to do, by using the "d])" pattern, or repeating "dt]", but there seems to be no way in (vanilla) Vim to leverage the full power of Text objects in combination with a starting cursor position.
Use ]). From :h ]):
])
]) go to [count] next unmatched ')'.
|exclusive| motion.
So y]) to yank and c]) to cut.
Other motion of interest would be [( (previous unmatched (), ]} (next unmatched }), …
Edit: missed the part about sentences and paragraphs.
You can use ) to go to the end of s sentence and ( to go to the beginning of it, so d) deletes from the cursor to the next sentence.
{/} do the same for paragraphs.
As for going to the next square bracket I think you could use matchit.vim, but it's been a while since I last used it. Somehow else might know more about it.

Is there a good Vi(m) command for transposing arguments in a function call? Bonus points for Emacs

For example if I have some code like:
foo = bar("abc", "def", true, callback);
Is there a nice command to move true to the 1st or 2nd position leaving the commas intact?
P.S as a bonus my friend want to know if this works in Emacs too.
In Vim if you place the cursor at the start of the first word and do dWWP then it will have the desired effect. Here is a breakdown:
dW delete the current word, including the comma and the following whitespace
W move to the start of the next word
P insert the deleted text before the cursor
This will work if there are further parameters after the pair to be swapped - it will need to be modified if there are only two parameters or you want to swap the last two parameters, since it will paste the text after the closing bracket.
Alternatively you could use a regex substitution:
:%s/(\([^,]\+\),\s*\([^,)]\+\)/(\2, \1/
This will find the first two arguments after the open bracket and swap them.
update:
A search of vim.org found the swap parameters plugin, which should do exactly what you want and can handle situations that either of the above methods cannot.
I don't know the answer for vi, but in Emacs, transpose-sexps (C-M-t) will swap two arguments either side of the cursor. Actually transpose-words (M-t) was my first guess, but that leaves the quotes behind.
You need a transpose emacs command. But its limited to not guessing that its transposing in lists, it only considers text (it can't guess the 1st, 2nd word of list). Try this.
Keep your cursor at after comma of true. Use M-x transpose-words. By default it will transpose with next word from the point. Shortcut is M-t.
You can use C-u 2 M-t for transpose with next second word.
Now coming to your question. If you want to move true, to backward 1 word, use C-u -1 M-t, and for backward 2 words C-u -2 M-t.
Am not a VIM guy. So sorry bout that.
If you want to do this as a refactoring, not just as text manipulation, I'd suggest looking into Xrefactory, a refactoring tool for Emacsen (free for C/Java, commercial for C++).
Transposing previous (Ctrl-t p) and next (Ctrl-t n) argument ... add the
following into your .vimrc file:
map <C-t>p ?,\\|(<CR>wd/,\\|)<CR>?,\\|(<CR>"_dw?,\\|(<CR>a, <C-c>?,<CR>P/,<CR>w
map <C-t>n ?,\\|(<CR>wv/,<CR>d"_dw/\\,\\|)<CR>i, <C-r>"<C-c>?,<CR>?,\\|(<CR>w

Command to surround a character with spaces in vim

I am trying to use vim properly - to aid me I've mapped my arrow keys to "" so that I am forced to use {hjlk} to move around.
This is causing me a problem when I want to just surround a character with spaces, eg:
"2+3" is better formatted "2 + 3"
Previously I would have put my cursor over the + and typed:
i[space][arrow-right][space][Esc]
That's 5 presses.
To do this without the arrow I seem to need to put the cursor over the + and go:
i[space][Esc]lli[space][Esc]
That's 8 presses.
I can convert the "li" into an "a" which reduces it to 7 presses:
i[space][Esc]la[space][Esc]
Short of writing this into a macro is there a better way of doing it? Is there some magic vim command which will allow me to do it in less than even 5 presses - and some way to generalise it so that I can do it to entire words or symbols, eg if I want to convert 3==4 to 3 == 4?
Personally, I think it makes most sense to destroy what you want to surround, and then repaste it.
c w "" ESC P
Obviously, you can replace both the object and the quotes with whatever you like. To change just one character + to be [space]+[space], you would do
s [space] [space] ESC P
on the +
The first thing that jumps to mind after reading just the title is surround.vim which is an excellent script to do all kinds of useful things along the lines of what you've described.
To solve your specific problem, I would probably position the cursor on the + and:
s[space]+[space][esc]
To change 3==4 into 3 == 4, I might position the cursor on the first =, and:
i[space][esc]ww.
i have been wondering about this as well. i tried with surround.vim, but the naive approach
S<space>
(after making a visual selection) does not work since the space is already taken up as a modifier for adding space to other surrounding character pairs. S<space><cr> adds a ^M in the output. Ss almost works but inserts a space only before.
after asking at tpope/surround.vim on github:
S<space><space>
in visual mode works. alternatively, from normal mode, ysl<space><space> works for a single character
Hah! I've been trying to figure out how to surround a block in spaces for quite a while and I finally found the right combination.
Using surround.vim you say surround selector space space.
So for this specific case I would use visual mode (a good trick for operating on single characters under the cursor BTW) thus: "vs " <- four key presses!
I also have a habit of typing things like argument lists without spaces. With this technique you can just navigate to the second argument using w and say "vws " to visually select a word and surround with spaces.
I prefer visual select mode generally. Also the alternate surround syntax "ysw " excludes the word final comma that is caught by "vw".
You could create a macro with one of the described actions and call it everytime you need it (Like amphetamachine proposed while I was writing) or you could simply search & replace:
:%s/\(\d\)\(+\|-\)\(\d\)/\1 \2 \3/g
You probably have to execute this command two times because it will only find every second occurence of +/-.
EDIT:
This will replace everything without the need to be called twice:
:%s/\d\#<=+\|-\d\#=/ \0 /g
Try positioning your cursor over the '+' and typing this:
q1i[space][right arrow][space][left arrow][esc]q
This will record a quick macro in slot 1 that you can re-use whenever you feel like it, that will surround the character under the cursor with spaces. You can re-call it with #1.
There is also the more versatile one:
q1ea[space][esc]bi[space][right arrow][esc]q
Which will surround the word under the cursor ("==" counts as a word) with spaces when you hit #1.
You could set up a mapping like this (press enter in visual mode to wrap spaces):
:vnoremap <CR> <ESC>`<i<SPACE><ESC>`>la<SPACE><ESC>h
This method allows you to use . to repeat the command at the next +.
Put your cursor over the + and type:
s[SPACE][CTRL-R]"[SPACE][ESC]
I know this is and old thread, but this might be useful to someone. I've found that the map (map it to anything else you want!)
noremap <leader>ss diwi<SPACE><C-R>"<SPACE><ESC>B
works ok both for turning 'a+b' into 'a + b' (when used over the '+' char) and for turning 'a==b' into 'a == b' (when used over either the first or the second '=' sign).
I hope it's useful to someone.

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