Knowing that i am getting paid $10 000 a year, and that each year my salary increase by 5%.
What is the formula for Excel to know how much i will get in 5 year?
Thank you for any advise
The formula in Excel is:
=VF(5%;5;0;-10000)
Which results in: $12,762.82
If your Office is english version you can use:
=FV(5%;5;0;-10000)
=(10000*((1 + 0.05)^5))
The Compound Interest Equation
P = C (1 + r/n)^nt
Where...
P = Future Value
C = Initial Deposit/Salary
r = Interest Rate/Pay Increase (Expressed as a Fraction: EX = 0.05)
n = Number of Times per Year the Interest/Pay Raise Is Compounded (0 in Your Example)
t = Number of Years to Calculate
The Formula is POWER(B1,C1)*10000, and the cell B1 is (1+5% ), the cell C1 is the number of years
current = 10 000
for each year -1
current = current * 1.05
end for
current now has current salary for the given number of years
Related
this is my first post.
Right now, I have a limited set of data ranging from the beginning of this financial year until now. I'm trying to show what a full year's worth of that data would look like.
For example, if the number is at 10, and the data range is from 1/07/2021 - 30/12/2021 (half the year), then the end output should be 20. Or for example, turn a 12 with 3/4 of the year date range to 16 for a full years' worth.
However, my current formula would end up with 15 (10 + "half") rather than (10 + 10)
Right now this is what I have, but I know there's something off on my logic, as the output is smaller than it should be:
D1+((364-(F1-E1))/365)*D1
where E1 is the start date and F1 is the end date, and d1 is the number for that date range
Thanks in advance
endDate - startDate will give you the number of days the data covers.
(endDate - startDate) / 365 will give you what fraction of a year the sample represents.
Let’s say this works out to be 30%, or 0.30.
annualValue * 0.30 = periodValue and therefore we know that periodValue / 0.30 = annualValue.
So there it is, the cell you want the Annual Value in should be:
= periodValue / ( ( endDate - startDate) / 365 )
I will leave it to you to replace each of the three named values in my example to be the correct cell references. I suspect that’s probably:
=D1/((F1-E1)/365) which is the same as (D1*365)/(F1-E1).
The easy way to remember this is that it’s just cross-multiplication.
periodValue / days is proportionate to annualValue / 365. Thus periodValue / days = annualValue / 365. Cross-multiply and you get periodValue * 365 = annualValue * days. Divide both sides by days and you get `annualValue = (periodValue * 365)/days.
I cannot figure out the approach to this as the principle amount shall change after every year(if calculated annually, which shall be the easiest). Eventual goal is to calculate exact number of years, months and days to earn say 150000 as interest on a deposit of 1000000 at an interest rate of say 6.5%. I have tried but cannot seem to figure out how to increment the year/month/day in the loop. I don't mind if this is down voted because I have not posted any code(Well, they are wrong). This is not as simple as it might seem to beginners here.
It is a pure maths question. Compound interest is calculated as follows:
Ptotal = Pinitial*(1+rate/100)time
where Ptotal is the new total. rate is usually given in percentages so divide by 100; time is in years. You are interested in the difference, though, so use
interest = Pinitial*(1+rate/100)time – Pinitial
instead, which is in Python:
def compound_interest(P,rate,time):
interest = P*(1+rate/100)**time - P
return interest
A basic inversion of this to yield time, given P, r, and target instead, is
time = log((target+Pinitial)/Pinitial)/log(1+rate/100)
and this will immediately return the number of years. Converting the fraction to days is simple – an average year has 365.25 days – but for months you'll have to approximate.
At the bottom, the result is fed back into the standard compound interest formula to show it indeed returns the expected yield.
import math
def reverse_compound_interest(P,rate,target):
time = math.log((target+P)/P)/math.log(1+rate/100)
return time
timespan = reverse_compound_interest(2500000, 6.5, 400000)
print ('time in years',timespan)
years = math.floor(timespan)
months = math.floor(12*(timespan - years))
days = math.floor(365.25*(timespan - years - months/12))
print (years,'y',months,'m',days,'d')
print (compound_interest(2500000, 6.5, timespan))
will output
time in years 2.356815854829652
2 y 4 m 8 d
400000.0
Can we do better? Yes. datetime allows arbitrary numbers added to the current date, so assuming you start earning today (now), you can immediately get your date of $$$:
from datetime import datetime,timedelta
# ... original script here ...
timespan *= 31556926 # the number of seconds in a year
print ('time in seconds',timespan)
print (datetime.now() + timedelta(seconds=timespan))
which shows for me (your target date will differ):
time in years 2.356815854829652
time in seconds 74373863.52648607
2022-08-08 17:02:54.819492
You could do something like
def how_long_till_i_am_rich(investment, profit_goal, interest_rate):
profit = 0
days = 0
daily_interest = interest_rate / 100 / 365
while profit < profit_goal:
days += 1
profit += (investment + profit) * daily_interest
years = days // 365
months = days % 365 // 30
days = days - (months * 30) - (years * 365)
return years, months, days
years, months, days = how_long_till_i_am_rich(2500000, 400000, 8)
print(f"It would take {years} years, {months} months, and {days} days")
OUTPUT
It would take 1 years, 10 months, and 13 days
Let's say the yearly simple interest is 10% on a principal of $100. At the end of one year, the new principal is $110. I'm trying to calculate the compound interest equivalent so by the end of the 4th quarter, the new principal should still be $110. In the example below, I'm compounding quarterly (which is incorrect) and I'm ending up with $110.38. How do I modify the formula so I end up at $110?
With your current setup:
In B5: =B2*(1+B1)^(1/4)
In B6 and drag down: =B5*(1+B$1)^(1/4).
This is technically maths rather than programming but, since Excel is a crossover, we can possibly let it through :-)
The formula for calculating initial capital plus cumulative interest on an amount of b at r% per period over n periods is:
newb = b * (1 + r/100)n
Hence, the formula for getting 10% per year with quarterly interest over that year is (using 1.1, since newb must be 10% higher than b):
1.1 = (1 + r/100)4
So, let's just give the expression 1 + r/100 the term mult for now, and we can work out the rate from that later:
mult^4 = 1.1
=> mult = ∜(1.1)
=> mult = 1.024113 (roughly)
We can then calculate that the desired interest rate is 2.4113% (by starting with mult, subtracting one, then multiplying by a hundred).
And here's the table to prove it (interest values are rouned):
Current New
Balance Interest Balance
------- -------- -------
100.00 2.41 102.41
102.41 2.47 104.88
104.88 2.53 107.41
107.41 2.59 110.00
-----
10.00
You can see that you reach the 10% increase at the end of the fourth quarter.
In Excel, assuming A1 holds the desired annual interest rate (like 10) and B1 holds the number of periods in a year (like 4), you can calculate the periodic interest rate with:
= 100 * (power (1 + a1 / 100, 1 / b1) - 1)
as per the following screenshot (which also has the four quarterly calculations):
The formulae for the tabular cells are, if you're interested:
+ A + B + C
3 | 100 | =ROUND(a3*$c$1/100,2) | =a3+b3
4 | =c3 | =ROUND(a3*$c$1/100,2) | =a4+b4
5 | =c4 | =ROUND(a3*$c$1/100,2) | =a5+b5
6 | =c5 | =ROUND(a3*$c$1/100,2) | =a6+b6
Feel free to use them as you see fit.
Good afternoon, I have a table of trials that I am trying to average. There are three trials being conducted (trial one = column B, trial 2 = column C, and trial 3 = column D). Each of these trials displays a number, which can be below or above 180. I need to average these three trials, but if the number is greater than 180, then I need the average to be calculated using 180 rather than the original number.
Example:
Trial 1 = 159; Trial 2 = 189; Trial 3 = 73
What I would like to do: (159 + 180 + 73)/3= 137.33
Thank you!
Here's one option (array formula, so use Ctrl+Shift+Enter):
=AVERAGE(IF(B2:B4>180,180,B2:B4))
I'm trying to sum up 12 months of subscriber revenue factoring a 6% monthly churn (assuming no signups) to come up with the one-year value of a subscriber. A simple future value gives me the start and end values, but I'm looking to get the sum of the monthly declining revenues in a single Excel / Google Sheets formula. I can make 11 entries (plus the starting month full value), but is there a better one-liner or formula for this?
This gives me the 12th-month revenue:
=FV(-6%,11,0,100)
I'd like to get the sum without this:
=100 + FV(-6%,1,0,100) + FV(-6%,2,0,100) ... FV(-6%,11,0,100)
You are looking for the sum of a finite geometric series:
1 + r + r^2 + r^3 .... + r^11
And the sum of this series is
(1 - r^12) / (1 - r)
where r = 1 - 6%
So the formula would be
= (1 - (1-6%)^12 ) / (1 - (1-6%) ) * 100
This is assuming the OP meant
=100 + FV(-6%,1,0,-100) + FV(-6%,2,0,-100) ... FV(-6%,11,0,-100)
as FV(-6%,1,0,100) would output a negative number
I don't know much about such math but would the following formula give you the result?
=100+SUMPRODUCT(FV(-6%,ROW(1:11),0,-100))
The formula works in both Excel and Google Spreadsheets