I'm trying to use a cronjob to run a ruby script (Using Rails3 runner) with the following Cronjobs:
#!/bin/bash
0-59 * * * * echo 'script test'
# Begin Whenever generated tasks for: test1
* * * * * /bin/bash -l -c '/home/administrator/test1/script/rails runner /home/administrator/test1/app/create_flag.rb >> /home/administrator/test1/test.log 2>&1'
# End Whenever generated tasks for: test1
test1 is the name of the Rails3 project folder.
the "echo 'script test'" was added as a test, but neither seems to be executing. I'm currently using Ubuntu 10.04 LTS.
Have I written the cronjob incorrectly?
Crontab file is not a shell script. So you don't need #!/bin/bash at the beginning of the file. Plus, spaces there are suspicious. Try something like this:
SHELL=/bin/bash
MAILTO=administrator#localhost
BASH_ENV=/home/administrator/.bash_profile
* * * * * /home/administrator/test1/script/rails runner /home/administrator/test1/app/create_flag.rb >> /home/administrator/test1/test.log 2>&1'
Plus, make sure you call crontab -e as administrator to edit the crontab file.
You need to specify the user which runs the commands (you can see the format here. Also the echo will output 'script test' to what? If you want a test try doing a touch on a file, so you can physically see the action of the cron job.
Cron does not use your user environment, so it will not have the same path set that you have. This means that you should use absolute paths for commands.
Related
I have a script that checks if the PPTP VPN is running, and if not it reconnects the PPTP VPN. When I run the script manually it executes fine, but when I make a cron job, it's not running.
* * * * * /bin/bash /var/scripts/vpn-check.sh
Here is the script:
#!/bin/sh
/bin/ping -c3 192.168.17.27 > /tmp/pingreport
result=`grep "0 received" /tmp/pingreport`
truncresult="`echo "$result" | sed 's/^\(.................................\).*$$'`"
if [[ $truncresult == "3 packets transmitted, 0 received" ]]; then
/usr/sbin/pppd call home
fi
finally i found a solution ... instead of entering the cronjob with
crontab -e
i needed to edit the crontab file directly
nano /etc/crontab
adding e.g. something like
*/5 * * * * root /bin/bash /var/scripts/vpn-check.sh
and its fine now!
Thank you all for your help ... hope my solution will help other people as well.
After a long time getting errors, I just did this:
SHELL=/bin/bash
PATH=/bin:/sbin:/usr/bin:/usr/sbin
* * * * * /bin/bash /home/joaovitordeon/Documentos/test.sh
Where test.sh contains:
#!/bin/bash
/usr/bin/python3 /home/joaovitordeon/Documentos/test.py;
In my case, the issue was that the script wasn't marked as executable. To make sure it is, run the following command:
chmod +x your_script.sh
If you're positive the script runs outside of cron, execute
printf "SHELL=$SHELL\nPATH=$PATH\n* * * * * /bin/bash /var/scripts/vpn-check.sh\n"
Do crontab -e for whichever crontab you're using and replace it with output of the above command. This should mirror most of your environment in case there is some missing path issue or something else. Also check logs for any errors it's getting.
Though it definitly looks like the script has an error or you messed something up when copying it here
sed: -e expression #1, char 44: unterminated `s' command
./bad.sh: 5: ./bad.sh: [[: not found
Simple alternate script
#!/bin/bash
if [[ $(ping -c3 192.168.17.27) == *"0 received"* ]]; then
/usr/sbin/pppd call home
fi
Your script can be corrected and simplified like this:
#!/bin/sh
log=/tmp/vpn-check.log
{ date; ping -c3 192.168.17.27; } > $log
if grep -q '0 received' $log; then
/usr/sbin/pppd call home >>$log 2>&1
fi
Through our discussion in comments we confirmed that the script itself works, but pppd doesn't, when running from cron. This is because something must be different in an interactive shell like your terminal window, and in cron. This kind of problem is very common by the way.
The first thing to do is try to remember what configuration is necessary for pppd. I don't use it so I don't know. Maybe you need to set some environment variables? In which case most probably you set something in a startup file, like .bashrc, which is usually not used in a non-interactive shell, and would explain why pppd doesn't work.
The second thing is to check the logs of pppd. If you cannot find the logs easily, look into its man page, and it's configuration files, and try to find the logs, or how to make it log. Based on the logs, you should be able to find what is missing when running in cron, and resolve your problem.
Was having a similar problem that was resolved when a sh was put before the command in crontab
This did not work :
#reboot ~myhome/mycommand >/tmp/logfile 2>&1
This did :
#reboot sh ~myhome/mycommand >/tmp/logfile 2>&1
my case:
crontab -e
then adding the line:
* * * * * ( cd /directory/of/script/ && /bin/sh /directory/of/script/scriptItself.sh )
in fact, if I added "root" as per the user, it thought "root" was a command, and it didn't work.
As a complement of other's answers, didn't you forget the username in your crontab script ?
Try this :
* * * * * root /bin/bash /var/scripts/vpn-check.sh
EDIT
Here is a patch of your code
#!/bin/sh
/bin/ping -c3 192.168.17.27 > /tmp/pingreport
result=`grep "0 received" /tmp/pingreport`
truncresult=`echo "$result" | /bin/sed 's/^\(.................................\).*$/\1/'`
if [[ $truncresult == "3 packets transmitted, 0 received" ]]; then
/usr/sbin/pppd call home
fi
In my case, it could be solved by using this:
* * * * * root ( cd /directory/of/script/ && /directory/of/script/scriptItself.sh )
I used some ./folder/-references in the script, which didn't work.
The problem statement is script is getting executed when run manually in the shell but when run through cron, it gives "java: command not found" error -
Please try below 2 options and it should fix the issue -
Ensure the script is executable .If it's not, execute below -
chmod a+x your_script_name.sh
The cron job doesn’t run with the same user with which you are executing the script manually - so it doesn't have access to the same $PATH variable as your user which means it can't locate the Java executable to execute the commands in the script. We should first fetch the value of PATH variable as below and then set it(export) in the script -
echo $PATH can be used to fetch the value of PATH variable.
and your script can be modified as below - Please see second line starting with export
#!/bin/sh
export PATH=<provide the value of echo $PATH>
/bin/ping -c3 192.168.17.27 > /tmp/pingreport
result=`grep "0 received" /tmp/pingreport`
truncresult="`echo "$result" | sed 's/^\(.................................\).*$$'`"
if [[ $truncresult == "3 packets transmitted, 0 received" ]]; then
/usr/sbin/pppd call home
fi
First of all, check if cron service is running. You know the first question of the IT helpdesk: "Is the PC plugged in?".
For me, this was happening because the cronjob was executing from /root directory but my shell script (a script to pull the latest code from GitHub and run the tests) were in a different directory. So, I had to edit my script to have a cd to my scripts folder. My debug steps were
Verified that my script run independent of cron job
Checked /var/log/cron to see if the cron jobs are running. Verified that the job is running at the intended time
Added an echo command to the script to log the start and end times to a file. Verified that those were getting logged but not the actual commands
Logged the result of pwd to the same file and saw that the commands were getting executed from /root
Tried adding a cd to my script directory as the first line in the script. When the cron job kicked off this time, the script got executed just like in step 1.
it was timezone in my case. I scheduled cron with my local time but server has different timezone and it does not run at all. so make sure your server has same time by date cmd
first run command env > env.tmp
then run cat env.tmp
copy PATH=.................. Full line and paste into crontab -e, line before your cronjobs.
try this
/home/your site folder name/public_html/gistfile1.sh
set cron path like above
I want to automatically start a program if it crashes (check if the process exists, if not, restart it), so using crontab is a simple solution, but
I creatd a simple crontab task using crontab -e or in /etc/crontab file like this:
* * * * * /usr/bin/gnome-terminal
it doesn't work, it never launches gnome-terminal, I can see it executes the task in /var/log/syslog (Ubuntu) or /var/log/cron (CentOS), the gnome-terminal never comes up.
if you say since gnome-terminal is a gui program, then, this script to create bluetooth service won't work either :
using crontab -e or /etc/crontab:
* * * * * /home/username/run-bt
run-bt:
#!/bin/sh
# find bt pid
/usr/bin/pgrep bluetoothd
# if not running
if [ $? -ne 0 ]
then
/usr/sbin/service bluetooth restart
fi⏎
I already made the run-bt script executable, but bluetooth service won't start even if I stop the bluetooth service manually.
but this:
* * * * * /bin/ls > /tmp/ls.output
works as expected.
What's wrong?
Actually crontab does not load all the environment variables of the current user it runs for, just a few of them.
Maybe some of those environment variables are required by the scripts you try to run?
I'm running RHEL and I'm trying to set up a cron job to run a shell script every 5 minutes.
Following the directions here: https://access.redhat.com/documentation/en-US/Red_Hat_Enterprise_Linux/6/html/Deployment_Guide/ch-Automating_System_Tasks.html#s2-configuring-cron-jobs
I have service crond start and chkconfig crond on. Then I edited /etc/crontab and added:
*/5 * * * * my-user /path/to/shell.sh
I did a chmod +x shell.sh. And I made sure to add a new line character at the end.
I'm expecting it to run every 5 minutes but it never executes.
What am I doing wrong?
Simply try to add the cronjob entry and check the script is working fine or not by taking the viewable output in the script.
echo "test time - $(date)" > script.sh
chmod +x script.sh
crontab -e
Then enter the cronjob as below,
*/5 * * * * sh /path/to/script.sh > /path/to/log.file
Check if the log is writing correctly. If its fine, better cross check the script that you are trying to execute via cron. Otherwise it will be a cron issue.
I am trying to make a cron job for the first time but i have some problems making it work.
Here is what i have done so far:
Linux commands:
crontab -e
My cronjob looks like this:
1 * * * * wget -qO /dev/null http://mySite/myController/myView
Now when i look in:
/var/spool/cron/crontabs/
I get the following output:
marc root
if i open the file root
i see my cronjob (the one above)
However it doesnt seem like it is running.
is there a way i can check if its running or make sure that it is running?
By default cron jobs do have a log file. It should be in /var/log/syslog (depends on your system). Vouch for it and you're done. Else you can simply append the output to a log file manually by
1 * * * * wget http://mySite/myController/myView >> ~/my_log_file.txt
and see what's your output. Notice I've changed removed the quiet parameter from wget command so that there is some output.
I have a crontab running every hour. The user running it has environment variabless in the .bash_profile that work when the user runs the job from the terminal, however, obviously these don't get picked up by crontab when it runs.
I've tried setting them in .profile and .bashrc but they still don't seem to get picked up. Does anyone know where I can put environment vars that crontab can pick up?
You can define environment variables in the crontab itself when running crontab -e from the command line.
LANG=nb_NO.UTF-8
LC_ALL=nb_NO.UTF-8
# m h dom mon dow command
* * * * * sleep 5s && echo "yo"
This feature is only available to certain implementations of cron. Ubuntu and Debian currently use vixie-cron which allows these to be declared in the crontab file (also GNU mcron).
Archlinux and RedHat use cronie which does not allow environment variables to be declared and will throw syntax errors in the cron.log. Workaround can be done per-entry:
# m h dom mon dow command
* * * * * export LC_ALL=nb_NO.UTF-8; sleep 5s && echo "yo"
I got one more solution for this problem:
0 5 * * * . $HOME/.profile; /path/to/command/to/run
In this case it will pick all the environment variable defined in your $HOME/.profile file.
Of course $HOME is also not set, you have to replace it with the full path of your $HOME.
Setting vars in /etc/environment also worked for me in Ubuntu. As of 12.04, variables in /etc/environment are loaded for cron.
Have 'cron' run a shell script that sets the environment before running the command.
Always.
# #(#)$Id: crontab,v 4.2 2007/09/17 02:41:00 jleffler Exp $
# Crontab file for Home Directory for Jonathan Leffler (JL)
#-----------------------------------------------------------------------------
#Min Hour Day Month Weekday Command
#-----------------------------------------------------------------------------
0 * * * * /usr/bin/ksh /work1/jleffler/bin/Cron/hourly
1 1 * * * /usr/bin/ksh /work1/jleffler/bin/Cron/daily
23 1 * * 1-5 /usr/bin/ksh /work1/jleffler/bin/Cron/weekday
2 3 * * 0 /usr/bin/ksh /work1/jleffler/bin/Cron/weekly
21 3 1 * * /usr/bin/ksh /work1/jleffler/bin/Cron/monthly
The scripts in ~/bin/Cron are all links to a single script, 'runcron', which looks like:
: "$Id: runcron.sh,v 2.1 2001/02/27 00:53:22 jleffler Exp $"
#
# Commands to be performed by Cron (no debugging options)
# Set environment -- not done by cron (usually switches HOME)
. $HOME/.cronfile
base=`basename $0`
cmd=${REAL_HOME:-/real/home}/bin/$base
if [ ! -x $cmd ]
then cmd=${HOME}/bin/$base
fi
exec $cmd ${#:+"$#"}
(Written using an older coding standard - nowadays, I'd use a shebang '#!' at the start.)
The '~/.cronfile' is a variation on my profile for use by cron - rigorously non-interactive and no echoing for the sake of being noisy. You could arrange to execute the .profile and so on instead. (The REAL_HOME stuff is an artefact of my environment - you can pretend it is the same as $HOME.)
So, this code reads the appropriate environment and then executes the non-Cron version of the command from my home directory. So, for example, my 'weekday' command looks like:
: "#(#)$Id: weekday.sh,v 1.10 2007/09/17 02:42:03 jleffler Exp $"
#
# Commands to be done each weekday
# Update ICSCOPE
n.updics
The 'daily' command is simpler:
: "#(#)$Id: daily.sh,v 1.5 1997/06/02 22:04:21 johnl Exp $"
#
# Commands to be done daily
# Nothing -- most things are done on weekdays only
exit 0
If you start the scripts you are executing through cron with:
#!/bin/bash -l
They should pick up your ~/.bash_profile environment variables
Expanding on #carestad example, which I find easier, is to run the script with cron and have the environment in the script.
In crontab -e file:
SHELL=/bin/bash
*/1 * * * * $HOME/cron_job.sh
In cron_job.sh file:
#!/bin/bash
source $HOME/.bash_profile
some_other_cmd
Any command after the source of .bash_profile will have your environment as if you logged in.
Whatever you set in crontab will be available in the cronjobs, both directly and using the variables in the scripts.
Use them in the definition of the cronjob
You can configure crontab so that it sets variables that then the can cronjob use:
$ crontab -l
myvar="hi man"
* * * * * echo "$myvar. date is $(date)" >> /tmp/hello
Now the file /tmp/hello shows things like:
$ cat /tmp/hello
hi man. date is Thu May 12 12:10:01 CEST 2016
hi man. date is Thu May 12 12:11:01 CEST 2016
Use them in the script run by cronjob
You can configure crontab so that it sets variables that then the scripts can use:
$ crontab -l
myvar="hi man"
* * * * * /bin/bash /tmp/myscript.sh
And say script /tmp/myscript.sh is like this:
echo "Now is $(date). myvar=$myvar" >> /tmp/myoutput.res
It generates a file /tmp/myoutput.res showing:
$ cat /tmp/myoutput.res
Now is Thu May 12 12:07:01 CEST 2016. myvar=hi man
Now is Thu May 12 12:08:01 CEST 2016. myvar=hi man
...
For me I had to set the environment variable for a php application. I resolved it by adding the following code to my crontab.
$ sudo crontab -e
crontab:
ENVIRONMENT_VAR=production
* * * * * /home/deploy/my_app/cron/cron.doSomethingWonderful.php
and inside doSomethingWonderful.php I could get the environment value with:
<?php
echo $_SERVER['ENVIRONMENT_VAR']; # => "production"
I hope this helps!
Instead of
0 * * * * sh /my/script.sh
Use bash -l -c
0 * * * * bash -l -c 'sh /my/script.sh'
You can also prepend your command with env to inject Environment variables like so:
0 * * * * env VARIABLE=VALUE /usr/bin/mycommand
Expanding on #Robert Brisita has just expand , also if you don't want to set up all the variables of the profile in the script, you can select the variables to export on the top of the script
In crontab -e file:
SHELL=/bin/bash
*/1 * * * * /Path/to/script/script.sh
In script.sh
#!/bin/bash
export JAVA_HOME=/path/to/jdk
some-other-command
I'm using Oh-my-zsh in my macbook so I've tried many things to get the crontab task runs but finally, my solution was prepending the .zshrc before the command to run.
*/30 * * * * . $HOME/.zshrc; node /path/for/my_script.js
This task runs every 30 minutes and uses .zshrc profile to execute my node command.
Don't forget to use the dot before the $HOME var.
I tried most of the provided solutions, but nothing worked at first. It turns out, though, that it wasn't the solutions that failed to work. Apparently, my ~/.bashrc file starts with the following block of code:
case $- in
*i*) ;;
*) return;;
esac
This basically is a case statement that checks the current set of options in the current shell to determine that the shell is running interactively.
If the shell happens to be running interactively, then it moves on to sourcing the ~/.bashrc file.
However, in a shell invoked by cron, the $- variable doesn't contain the i value which indicates interactivity.
Therefore, the ~/.bashrc file never gets sourced fully. As a result, the environment variables never got set.
If this happens to be your issue, feel free to comment out the block of code as follows and try again:
# case $- in
# *i*) ;;
# *) return;;
# esac
I hope this turns out useful
Unfortunately, crontabs have a very limited environment variables scope, thus you need to export them every time the corntab runs.
An easy approach would be the following example, suppose you've your env vars in a file called env, then:
* * * * * . ./env && /path/to_your/command
this part . ./env will export them and then they're used within the same scope of your command
Another way - inspired by this this answer - to "inject" variables is the following (fcron example):
%daily 00 12 \
set -a; \
. /path/to/file/containing/vars; \
set +a; \
/path/to/script/using/vars
From help set:
-a Mark variables which are modified or created for export.
Using + rather than - causes these flags to be turned off.
So everything in between set - and set + gets exported to env and is then available for other scripts, etc. Without using set the variables get sourced but live in set only.
Aside from that it's also useful to pass variables when a program requires a non-root account to run but you'd need some variables inside that other user's environment. Below is an example passing in nullmailer vars to format the e-mail header:
su -s /bin/bash -c "set -a; \
. /path/to/nullmailer-vars; \
set +a; \
/usr/sbin/logcheck" logcheck
All the above solutions work fine.
It will create issues when there are any special characters in your environment variable.
I have found the solution:
eval $(printenv | awk -F= '{print "export " "\""$1"\"""=""\""$2"\"" }' >> /etc/profile)
For me I had to specify path in my NodeJS file.
// did not work!!!!!
require('dotenv').config()
instead
// DID WORK!!
require('dotenv').config({ path: '/full/custom/path/to/your/.env' })
I found this issue while looking at a similar problem that matched the title, but I am stuck with the environment file syntax that systemd or docker use:
FOO=bar
BAZ=qux
This won't work for Vishal's excellent answer because they aren't bash scripts (note the lack of export).
The solution I've used is to read each line into xargs and export them before running the command:
0 5 * * * export $(xargs < $HOME/.env); /path/to/command/to/run
Set Globally env
sudo sh -c "echo MY_GLOBAL_ENV_TO_MY_CURRENT_DIR=$(pwd)" >> /etc/environment"
Add scheduled job to start a script
crontab -e
*/5 * * * * sh -c "$MY_GLOBAL_ENV_TO_MY_CURRENT_DIR/start.sh"
=)
what worked for me (debian based):
create a file with all the needed env var :
#!/bin/bash
env | grep VAR1= > /etc/environment
env | grep VAR2= >> /etc/environment
env | grep VAR3= >> /etc/environment
then build the crontab content, by calling the env file before calling the script that needs it, therefore start the cron service
(crontab -l ; echo '* * * * * . /etc/environment; /usr/local/bin/python /mycode.py >> /var/log/cron-1.log 2>&1') | crontab
service cron start
nb : for python use case, be sure to call the whole python path, else wrong python could be invocated, generating non-sense syntax error