An Excel table consists of two columns (e.g., A1:B5):
0 10
1 20
3 30
2 20
1 59
I need to get the minimal value in column B for which the corresponding value in column A is greater than zero. In the above example it should be 20.
I tried using various combinations of INDEX(), MIN(), IF(), ROW(), array formulas, etc. - but I just can't figure out how to do it. :-( Any help would be appreciated.
Grsm almost had it
if you enter the following formula in C1 as an array (Ctrl+Shift+End)
=MIN(IF(A1:A5>0,B1:B5))
That should do the trick.
I think you have to make an extra column..
A B C D
0 10 false 20
1 20 20
3 30 30
2 40 40
1 50 50
column C : =IF(A1>0;B1)
cell D1: =MIN(C1:C5)
You need to do it in 2 stages
First use the MIN function to find the minimum
Then take that answer and use the LOOKUP function to select the row and column that you need.
Check the "Minimum And Maximum Values In A Range" example in http://www.cpearson.com/Excel/excelF.htm (you can download the same as well from the same section)
HTH
This is not identical, but very similar: Excel VBA - Find minimum of list of values?
Related
I have 2 columns:
A B
apple_type1 25
apple_type1 15
apple_type1 5
pears_type1 10
pears_type1 3
apple_type2 5
apple_type2 15
It is posible to Subsum the column B (without deleting the rows, whithout filters, without Pivot table) like:
apple_type1 0
apple_type1 0
apple_type1 45
pears_type1 0
pears_type1 13
apple_type2 0
apple_type2 20
Thank you!
If column A is sorted, then you could also use =IF(A1=A2,0,SUMIF(A:A,A2,B:B)) copied down:
This would be faster than using COUNTIF within the same formula, referring to Error 1004's answer (COUNTIF and SUMIF all need to 'look' at the range, so having two of these in the same formula will consume twice as much resources, but it has the advantage that it doesn't require column A to be sorted).
If you need to refresh the data a lot of times (new information got added for example), then I would advise sorting then using the formula I proposed.
Modify the formula and try:
=IF(COUNTIF(A3:$A$9,A2)>0,0,SUMIF($A$2:$A$8,A2,$B$2:$B$8))
Results:
I'm not sure if I'm over complicating this...
basically I'd like to have a formula which is
if the c column is less than 6, then look up the max value in B but display the value of C
so far I have this but I'd like it to show 2, not 437
{=MAX(IF(C2:C12<6,B2:B12, 0))}
any advice is appreciated. i'm shy, be nice..thanks
A B C
cat 110 3
dog 148 4
rooster 36 7
duck 32 8
pig 437 2
horse 44 6
eagle 215 5
dolphin 21 1
panda 2 9
iguana 257 10
fish 199 11
edit:
maybe something like
{=INDEX(C2:C12,MATCH(MAX(IF(C2:C12<6,C2:C12)),C2:C12,0))}
but I don't see where to put b2:b12
You really need two conditions
1) Column B is equal to =MAX(IF(C2:C12<6,B2:B12))
2) Column C is <6
so you can INDEX column C when those two are met, i.e.
=INDEX(C2:C12,MATCH(1,(B2:B12=MAX(IF(C2:C12<6,B2:B12)))*(C2:C12<6),0))
confirmed with CTRL+SHIFT+ENTER
{=IF(C2<6,INDEX($C$2:$C$12,MATCH(MAX($B$2:$B$12),$B$2:$B$12,0)),0)}
You were almost there..
Basically if C<6 , find max of B , lookup it in B:C and display corresponding C
{=IFERROR(VLOOKUP(MAX(IF(C2:C12<6,B2:B12, 0)),B2:C12,2,FALSE),0)}
Since your question doesn't clarify what if c>=6 I assume you don't want value.
Can answer more precisely if you clarify.
Mark this as answer if that's correct.
Hope this helps!
As I could see you requested a single INDEX formula:
{=INDEX($C$2:$C$12,MATCH(MAX(IF($C$2:$C$12<6,$B$2:$B$12,0),0),IF($C$2:$C$12<6,$B$2:$B$12,0),0))}
This is an array formula, hit Ctrl+Shift+Enter while still in the formula bar.
Lets break this down.
=INDEX(C:C, - Index column C as these are the values you want returned
MATCH(IF(C:C<6,B:B,0), - Find the largest value from the following array in the array and return it's relative position for INDEX()
IF(C:C<6,B:B,0),0)) - If the value in column c is less than 6 then add the column B value to the array, otherwise add 0
I have a few hundred rows of data, and each has a number between 1 and 200, and I'd like to put them in categories of 1-5 depending on where that number is.
The categories look like this:
Zones Min Max
1 0 35
2 35 60
3 60 85
4 85 110
5 110 200
I want to assign it a Zone if it is greater than the Min, but less than the Max.
I have 2 formulas I've been working with to solve it. One is a nested IF AND statement:
=IF(A1<=35,1,IF(AND(A1<=60,A1>35),2,IF(AND(A1<=85,A1>60),3,IF(AND(A1<=110,A1>85),4,IF(AND(A1<=200,A1>110),2,"TOO BIG")))))
The 2nd formula attempts to use a SUMPRODUCT function:
=INDEX($C$2:$C$6,SUMPRODUCT(--(A1<=$E$2:$E$6),-- (A1>$D2:$D$6),ROW($2:$6)))
Rather than have to continue to adjust the numeric values manually, I set them as absolutes, which is why this formula is slightly different. The E column is the Max value set, and the D is the Min value set.
Any help would be appreciated!
Use this:
=MATCH(A1,{0,35,60,85,110})
Another way is to use VLOOKUP and you just need to set the min number:
=VLOOKUP(D2,$A$2:$B$6,2,1)
The key is the 4th parameter needs to set to 1 which means TRUE. It will find the closest value and return the zone for you.
But noticed that you have overlaps like 35 or 60 etc. that you will need to adjust your value column.
I'm trying to do something that is very simple to do in Excel, but seems very tricky in Spotfire:
Imagine you have the following table:
A
1: 10
2: 15
3: 20
... and you want to produce the following:
A B
1: 10 10
2: 15 25
3: 20 45
In other words, add the current value of A to the previous value of B. If this was Excel, the formula in cell B3 would be = A3 + B2... However, I'm not in Excel, I'm using Spotfire... :) Any thoughts?
NB: If it makes any difference to the answer at all, I will need to use the Intersect() function in conjunction with this, as there is a categorical column to factor in as well.
Hope this helps, I have considered the first column as ID
ID A B
1 10 10
2 15 25
3 20 45
If(Sum([A]) over (AllPrevious([ID])) is null,sum([A]) over ([ID]),Sum([A]) over (AllPrevious([ID])))
I have the following little table. I'd like a formula that finds the number of values where the cumulative total (of column B) is less than some threshold (tx).
I tried
{=MIN((SUM(OFFSET(B1,0,0,A1:A17))>tx)*A1:A17)-1}
but OFFSET doesn't seem to be arrayable like that. Obviously, this would be trivial with a helper column, but for certain reasons that is not possible.
So the correct answer here should be 10.
tx = .8
A B
1 0.112106465
2 0.110981698
3 0.091959216
4 0.082163441
5 0.073292066
6 0.072407529
7 0.071646289
8 0.061646797
9 0.06011448
10 0.057566381
11 0.050341978
12 0.048227061
13 0.043207335
14 0.03940462
15 0.012914194
16 0.007603446
17 0.004417003
You're not really looking for a MIN; rather it should be MAX that follows your condition.
In E7 as a standard (non-array) formula,
=AGGREGATE(14, 6, ROW(1:17)/(SUBTOTAL(9, OFFSET(B1, 0, 0, ROW(1:17), 1))<D7), 1)
I prefer the following array formula** due to its non-volatility:
=MATCH(TRUE,MMULT(0+(ROW(B1:B17)>=TRANSPOSE(ROW(B1:B17))),B1:B17)>=0.8,0)-1
Regards
The most succinct way to do it I've found is
=SUM(--(SUBTOTAL(9,OFFSET(B1,,,A1:A17))<0.8))
entered as an array formula, or, equivalently,
=SUMPRODUCT(--(SUBTOTAL(9,OFFSET(B1,,,A1:A17))<0.8))