How do I iterate through each line of a text file with Bash?
With this script:
echo "Start!"
for p in (peptides.txt)
do
echo "${p}"
done
I get this output on the screen:
Start!
./runPep.sh: line 3: syntax error near unexpected token `('
./runPep.sh: line 3: `for p in (peptides.txt)'
(Later I want to do something more complicated with $p than just output to the screen.)
The environment variable SHELL is (from env):
SHELL=/bin/bash
/bin/bash --version output:
GNU bash, version 3.1.17(1)-release (x86_64-suse-linux-gnu)
Copyright (C) 2005 Free Software Foundation, Inc.
cat /proc/version output:
Linux version 2.6.18.2-34-default (geeko#buildhost) (gcc version 4.1.2 20061115 (prerelease) (SUSE Linux)) #1 SMP Mon Nov 27 11:46:27 UTC 2006
The file peptides.txt contains:
RKEKNVQ
IPKKLLQK
QYFHQLEKMNVK
IPKKLLQK
GDLSTALEVAIDCYEK
QYFHQLEKMNVKIPENIYR
RKEKNVQ
VLAKHGKLQDAIN
ILGFMK
LEDVALQILL
One way to do it is:
while read p; do
echo "$p"
done <peptides.txt
As pointed out in the comments, this has the side effects of trimming leading whitespace, interpreting backslash sequences, and skipping the last line if it's missing a terminating linefeed. If these are concerns, you can do:
while IFS="" read -r p || [ -n "$p" ]
do
printf '%s\n' "$p"
done < peptides.txt
Exceptionally, if the loop body may read from standard input, you can open the file using a different file descriptor:
while read -u 10 p; do
...
done 10<peptides.txt
Here, 10 is just an arbitrary number (different from 0, 1, 2).
cat peptides.txt | while read line
do
# do something with $line here
done
and the one-liner variant:
cat peptides.txt | while read line; do something_with_$line_here; done
These options will skip the last line of the file if there is no trailing line feed.
You can avoid this by the following:
cat peptides.txt | while read line || [[ -n $line ]];
do
# do something with $line here
done
Option 1a: While loop: Single line at a time: Input redirection
#!/bin/bash
filename='peptides.txt'
echo Start
while read p; do
echo "$p"
done < "$filename"
Option 1b: While loop: Single line at a time:
Open the file, read from a file descriptor (in this case file descriptor #4).
#!/bin/bash
filename='peptides.txt'
exec 4<"$filename"
echo Start
while read -u4 p ; do
echo "$p"
done
This is no better than other answers, but is one more way to get the job done in a file without spaces (see comments). I find that I often need one-liners to dig through lists in text files without the extra step of using separate script files.
for word in $(cat peptides.txt); do echo $word; done
This format allows me to put it all in one command-line. Change the "echo $word" portion to whatever you want and you can issue multiple commands separated by semicolons. The following example uses the file's contents as arguments into two other scripts you may have written.
for word in $(cat peptides.txt); do cmd_a.sh $word; cmd_b.py $word; done
Or if you intend to use this like a stream editor (learn sed) you can dump the output to another file as follows.
for word in $(cat peptides.txt); do cmd_a.sh $word; cmd_b.py $word; done > outfile.txt
I've used these as written above because I have used text files where I've created them with one word per line. (See comments) If you have spaces that you don't want splitting your words/lines, it gets a little uglier, but the same command still works as follows:
OLDIFS=$IFS; IFS=$'\n'; for line in $(cat peptides.txt); do cmd_a.sh $line; cmd_b.py $line; done > outfile.txt; IFS=$OLDIFS
This just tells the shell to split on newlines only, not spaces, then returns the environment back to what it was previously. At this point, you may want to consider putting it all into a shell script rather than squeezing it all into a single line, though.
Best of luck!
A few more things not covered by other answers:
Reading from a delimited file
# ':' is the delimiter here, and there are three fields on each line in the file
# IFS set below is restricted to the context of `read`, it doesn't affect any other code
while IFS=: read -r field1 field2 field3; do
# process the fields
# if the line has less than three fields, the missing fields will be set to an empty string
# if the line has more than three fields, `field3` will get all the values, including the third field plus the delimiter(s)
done < input.txt
Reading from the output of another command, using process substitution
while read -r line; do
# process the line
done < <(command ...)
This approach is better than command ... | while read -r line; do ... because the while loop here runs in the current shell rather than a subshell as in the case of the latter. See the related post A variable modified inside a while loop is not remembered.
Reading from a null delimited input, for example find ... -print0
while read -r -d '' line; do
# logic
# use a second 'read ... <<< "$line"' if we need to tokenize the line
done < <(find /path/to/dir -print0)
Related read: BashFAQ/020 - How can I find and safely handle file names containing newlines, spaces or both?
Reading from more than one file at a time
while read -u 3 -r line1 && read -u 4 -r line2; do
# process the lines
# note that the loop will end when we reach EOF on either of the files, because of the `&&`
done 3< input1.txt 4< input2.txt
Based on #chepner's answer here:
-u is a bash extension. For POSIX compatibility, each call would look something like read -r X <&3.
Reading a whole file into an array (Bash versions earlier to 4)
while read -r line; do
my_array+=("$line")
done < my_file
If the file ends with an incomplete line (newline missing at the end), then:
while read -r line || [[ $line ]]; do
my_array+=("$line")
done < my_file
Reading a whole file into an array (Bash versions 4x and later)
readarray -t my_array < my_file
or
mapfile -t my_array < my_file
And then
for line in "${my_array[#]}"; do
# process the lines
done
More about the shell builtins read and readarray commands - GNU
More about IFS - Wikipedia
BashFAQ/001 - How can I read a file (data stream, variable) line-by-line (and/or field-by-field)?
Related posts:
Creating an array from a text file in Bash
What is the difference between thee approaches to reading a file that has just one line?
Bash while read loop extremely slow compared to cat, why?
Use a while loop, like this:
while IFS= read -r line; do
echo "$line"
done <file
Notes:
If you don't set the IFS properly, you will lose indentation.
You should almost always use the -r option with read.
Don't read lines with for
If you don't want your read to be broken by newline character, use -
#!/bin/bash
while IFS='' read -r line || [[ -n "$line" ]]; do
echo "$line"
done < "$1"
Then run the script with file name as parameter.
Suppose you have this file:
$ cat /tmp/test.txt
Line 1
Line 2 has leading space
Line 3 followed by blank line
Line 5 (follows a blank line) and has trailing space
Line 6 has no ending CR
There are four elements that will alter the meaning of the file output read by many Bash solutions:
The blank line 4;
Leading or trailing spaces on two lines;
Maintaining the meaning of individual lines (i.e., each line is a record);
The line 6 not terminated with a CR.
If you want the text file line by line including blank lines and terminating lines without CR, you must use a while loop and you must have an alternate test for the final line.
Here are the methods that may change the file (in comparison to what cat returns):
1) Lose the last line and leading and trailing spaces:
$ while read -r p; do printf "%s\n" "'$p'"; done </tmp/test.txt
'Line 1'
'Line 2 has leading space'
'Line 3 followed by blank line'
''
'Line 5 (follows a blank line) and has trailing space'
(If you do while IFS= read -r p; do printf "%s\n" "'$p'"; done </tmp/test.txt instead, you preserve the leading and trailing spaces but still lose the last line if it is not terminated with CR)
2) Using process substitution with cat will reads the entire file in one gulp and loses the meaning of individual lines:
$ for p in "$(cat /tmp/test.txt)"; do printf "%s\n" "'$p'"; done
'Line 1
Line 2 has leading space
Line 3 followed by blank line
Line 5 (follows a blank line) and has trailing space
Line 6 has no ending CR'
(If you remove the " from $(cat /tmp/test.txt) you read the file word by word rather than one gulp. Also probably not what is intended...)
The most robust and simplest way to read a file line-by-line and preserve all spacing is:
$ while IFS= read -r line || [[ -n $line ]]; do printf "'%s'\n" "$line"; done </tmp/test.txt
'Line 1'
' Line 2 has leading space'
'Line 3 followed by blank line'
''
'Line 5 (follows a blank line) and has trailing space '
'Line 6 has no ending CR'
If you want to strip leading and trading spaces, remove the IFS= part:
$ while read -r line || [[ -n $line ]]; do printf "'%s'\n" "$line"; done </tmp/test.txt
'Line 1'
'Line 2 has leading space'
'Line 3 followed by blank line'
''
'Line 5 (follows a blank line) and has trailing space'
'Line 6 has no ending CR'
(A text file without a terminating \n, while fairly common, is considered broken under POSIX. If you can count on the trailing \n you do not need || [[ -n $line ]] in the while loop.)
More at the BASH FAQ
I like to use xargs instead of while. xargs is powerful and command line friendly
cat peptides.txt | xargs -I % sh -c "echo %"
With xargs, you can also add verbosity with -t and validation with -p
This might be the simplest answer and maybe it don't work in all cases, but it is working great for me:
while read line;do echo "$line";done<peptides.txt
if you need to enclose in parenthesis for spaces:
while read line;do echo \"$line\";done<peptides.txt
Ahhh this is pretty much the same as the answer that got upvoted most, but its all on one line.
#!/bin/bash
#
# Change the file name from "test" to desired input file
# (The comments in bash are prefixed with #'s)
for x in $(cat test.txt)
do
echo $x
done
Here is my real life example how to loop lines of another program output, check for substrings, drop double quotes from variable, use that variable outside of the loop. I guess quite many is asking these questions sooner or later.
##Parse FPS from first video stream, drop quotes from fps variable
## streams.stream.0.codec_type="video"
## streams.stream.0.r_frame_rate="24000/1001"
## streams.stream.0.avg_frame_rate="24000/1001"
FPS=unknown
while read -r line; do
if [[ $FPS == "unknown" ]] && [[ $line == *".codec_type=\"video\""* ]]; then
echo ParseFPS $line
FPS=parse
fi
if [[ $FPS == "parse" ]] && [[ $line == *".r_frame_rate="* ]]; then
echo ParseFPS $line
FPS=${line##*=}
FPS="${FPS%\"}"
FPS="${FPS#\"}"
fi
done <<< "$(ffprobe -v quiet -print_format flat -show_format -show_streams -i "$input")"
if [ "$FPS" == "unknown" ] || [ "$FPS" == "parse" ]; then
echo ParseFPS Unknown frame rate
fi
echo Found $FPS
Declare variable outside of the loop, set value and use it outside of loop requires done <<< "$(...)" syntax. Application need to be run within a context of current console. Quotes around the command keeps newlines of output stream.
Loop match for substrings then reads name=value pair, splits right-side part of last = character, drops first quote, drops last quote, we have a clean value to be used elsewhere.
This is coming rather very late, but with the thought that it may help someone, i am adding the answer. Also this may not be the best way. head command can be used with -n argument to read n lines from start of file and likewise tail command can be used to read from bottom. Now, to fetch nth line from file, we head n lines, pipe the data to tail only 1 line from the piped data.
TOTAL_LINES=`wc -l $USER_FILE | cut -d " " -f1 `
echo $TOTAL_LINES # To validate total lines in the file
for (( i=1 ; i <= $TOTAL_LINES; i++ ))
do
LINE=`head -n$i $USER_FILE | tail -n1`
echo $LINE
done
#Peter: This could work out for you-
echo "Start!";for p in $(cat ./pep); do
echo $p
done
This would return the output-
Start!
RKEKNVQ
IPKKLLQK
QYFHQLEKMNVK
IPKKLLQK
GDLSTALEVAIDCYEK
QYFHQLEKMNVKIPENIYR
RKEKNVQ
VLAKHGKLQDAIN
ILGFMK
LEDVALQILL
Another way to go about using xargs
<file_name | xargs -I {} echo {}
echo can be replaced with other commands or piped further.
for p in `cat peptides.txt`
do
echo "${p}"
done
Related
I am trying to get the script to find the very first character '' backslash and validate if that's the first character of a script otherwise it should not run.
my file is like Test.txt (have lot of starting spaced lines intentionally):
\c
select * from x;
I came up with this and it works:
cut -c -1 test.txt | grep -w '\\'
However if i changed a file a bit suppose like:
select * from x;
\c
it still shows file contains '\' but i want this to fail because i always want the first character to be '\' no matter which line i start.
I have tried using head/cut but not able to validate.Please suggest some ideas.
This uses regex to check if the 1st encountered line contains starts with . If 1st encountered line does not start with \ it exits.
backslash_pat='^\\'
num_lett_pat='[0-9a-Z*]'
while IFS= read -r line; do
if [[ $line =~ $backslash_pat ]]
then
echo "$line"
exit
elif [[ $line =~ $num_lett_pat ]]
then
exit
fi
done < test.txt
You can check if the fitst character is a \ (I understand this is what you want) using dd
if [[ $(dd if=test.txt count=1 bs=1 2>/dev/null| xxd -c1 -ps) == 5c ]]
then
echo 'found'
fi
This works for binary file (i.e. not composed of lines).
Check man dd and man xxd to understand the command line options used.
I have the following bash script:
while IFS= read -r line; do
line=$(echo $line | sed "s/\'/\'\'/")
[[ $line =~ ^\<ID\>(.*) ]] && printf "${BASH_REMATCH[1]}"
done < <(dos2unix < file)
EDITED version of script without dos2unix:
while IFS= read -r line && line=${line%$'\r'}; do
[[ $line =~ ^\<ID\>(.*) ]] && printf "${BASH_REMATCH[1]}"
done < file
I want to substitute every apostrophe in "file" with 2 apostrophes BEFORE I loop through it. How can I do this? I'd be grateful for any suggestions concerning any of the 2 versions.
IMPORTANT
Im NOT allowed to modify the original file!!
This is a job for sed alone:
sed 's/\r$//;s/\'/\'\'/g;s/^<ID>\(.*\)/\1/p;d' < file
The steps are:
sed accepts multiple commands separated with newlines, semicolons or given as multiple -e options.
sed 's/\r$//; removes the CR at end of each line like dos2unix.
The g flag added to s/\'/\'\'/ means replace all occurrences in the line; default is to replace just one.
The s/^<ID>\(.*\)/\1/ does the equivalent of that bash regex match and the p flag at the end makes sed print the matching lines now, because
The d command removes the line so it won't get printed by default (you could do that with the -n option instead).
On a side-note, my zsh does not accept \' in ', so I'd probably write it
sed -n -e 's/\r$//' -e "s/'/''/g" -e 's/^<ID>\(.*\)/\1/p'
It should be equivalent, just switching the quote style, separate options and the -n instead of final d.
While this is not a "solution" (your question is not clear on what is not working in your code), you certainly should avoid calling sed for each individual line. It is not "wrong" in the sense of producing an incorrect result, but it is so much slower that it should be avoided. There are ways do it that are both faster and simpler to code.
Do it this way :
while IFS= read -r line; do
[[ $line =~ ^\<ID\>(.*) ]] && printf "${BASH_REMATCH[1]}"
done < <(dos2unix < file | sed "s/\'/\'\'/")
I am trying to parse each line of a file and look for a particular string. The script seems to be doing its intended job, however, in parallel it tries to execute the if command on line 6:
#!/bin/bash
for line in $(cat $1)
do
echo $line | grep -e "Oct/2015"
if($?==0); then
echo "current line is: $line"
fi
done
and I get the following (my script is readlines.sh)
./readlines.sh: line 6: 0==0: command not found
First: As Mr. Llama says, you need more spaces. Right now your script tries to look for a file named something like /usr/bin/0==0 to run. Instead:
[ "$?" -eq 0 ] # POSIX-compliant numeric comparison
[ "$?" = 0 ] # POSIX-compliant string comparison
(( $? == 0 )) # bash-extended numeric comparison
Second: Don't test $? at all in this case. In fact, you don't even have good cause to use grep; the following is both more efficient (because it uses only functionality built into bash and requires no invocation of external commands) and more readable:
if [[ $line = *"Oct/2015"* ]]; then
echo "Current line is: $line"
fi
If you really do need to use grep, write it like so:
if echo "$line" | grep -q "Oct/2015"; then
echo "Current line is: $line"
fi
That way if operates directly on the pipeline's exit status, rather than running a second command testing $? and operating on that command's exit status.
#Charles Duffy has a good answer which I have up-voted as correct (and it is), but here's a detailed, line by line breakdown of your script and the correct thing to do for each part of it.
for line in $(cat $1)
As I noted in my comment elsewhere this should be done as a while read construct instead of a for cat construct.
This construct will wordsplit each line making spaces in the file separate "lines" in the output.
All empty lines will be skipped.
In addition when you cat $1 the variable should be quoted. If it is not quoted spaces and other less-usual characters appearing in the file name will cause the cat to fail and the loop will not process the file.
The complete line would read:
while IFS= read -r line
An illustrative example of the tradeoffs can be found here. The linked test script follows. I tried to include an indication of why IFS= and -r are important.
#!/bin/bash
mkdir -p /tmp/testcase
pushd /tmp/testcase >/dev/null
printf '%s\n' '' two 'three three' '' ' five with leading spaces' 'c:\some\dos\path' '' > testfile
printf '\nwc -l testfile:\n'
wc -l testfile
printf '\n\nfor line in $(cat) ... \n\n'
let n=1
for line in $(cat testfile) ; do
echo line $n: "$line"
let n++
done
printf '\n\nfor line in "$(cat)" ... \n\n'
let n=1
for line in "$(cat testfile)" ; do
echo line $n: "$line"
let n++
done
let n=1
printf '\n\nwhile read ... \n\n'
while read line ; do
echo line $n: "$line"
let n++
done < testfile
printf '\n\nwhile IFS= read ... \n\n'
let n=1
while IFS= read line ; do
echo line $n: "$line"
let n++
done < testfile
printf '\n\nwhile IFS= read -r ... \n\n'
let n=1
while IFS= read -r line ; do
echo line $n: "$line"
let n++
done < testfile
rm -- testfile
popd >/dev/null
rmdir /tmp/testcase
Note that this is a bash-heavy example. Other shells do not tend to support -r for read, for example, nor is let portable. On to the next line of your script.
do
As a matter of style I prefer do on the same line as the for or while declaration, but there's no convention on this.
echo $line | grep -e "Oct/2015"
The variable $line should be quoted here. In general, meaning always unless you specifically know better, you should double-quote all expansion--and that means subshells as well as variables. This insulates you from most unexpected shell weirdness.
You decclared your shell as bash which means you will have there "Here string" operator <<< available to you. When available it can be used to avoid the pipe; each element of a pipeline executes in a subshell, which incurs extra overhead and can lead to unexpected behavior if you try to modify variables. This would be written as
grep -e "Oct/2015" <<<"$line"
Note that I have quoted the line expansion.
You have called grep with -e, which is not incorrect but is needless since your pattern does not begin with -. In addition you have full-quoted a string in shell but you don't attempt to expand a variable or use other shell interpolation inside of it. When you don't expect and don't want the contents of a quoted string to be treated as special by the shell you should single quote them. Furthermore, your use of grep is inefficient: because your pattern is a fixed string and not a regular expression you could have used fgrep or grep -F, which does string contains rather than regular expression matching (and is far faster because of this). So this could be
grep -F 'Oct/2015' <<<"$line"
Without altering the behavior.
if($?==0); then
This is the source of your original problem. In shell scripts commands are separated by whitespace; when you say if($?==0) the $? expands, probably to 0, and bash will try to execute a command called if(0==0) which is a legal command name. What you wanted to do was invoke the if command and give it some parameters, which requires more whitespace. I believe others have covered this sufficiently.
You should never need to test the value of $? in a shell script. The if command exists for branching behavior based on the return code of whatever command you pass to it, so you can inline your grep call and have if check its return code directly, thus:
if grep -F 'Oct/2015` <<<"$line" ; then
Note the generous whitespace around the ; delimiter. I do this because in shell whitespace is usually required and can only sometiems be omitted. Rather than try to remember when you can do which I recommend an extra one space padding around everything. It's never wrong and can make other mistakes easier to notice.
As others have noted this grep will print matched lines to stdout, which is probably not something you want. If you are using GNU grep, which is standard on Linux, you will have the -q switch available to you. This will suppress the output from grep
if grep -q -F 'Oct/2015' <<<"$line" ; then
If you are trying to be strictly standards compliant or are in any environment with a grep that doesn't know -q the standard way to achieve this effect is to redirect stdout to /dev/null/
if printf "$line" | grep -F 'Oct/2015' >/dev/null ; then
In this example I also removed the here string bashism just to show a portable version of this line.
echo "current line is: $line"
There is nothing wrong with this line of your script, except that although echo is standard implementations vary to such an extent that it's not possible to absolutely rely on its behavior. You can use printf anywhere you would use echo and you can be fairly confident of what it will print. Even printf has some caveats: Some uncommon escape sequences are not evenly supported. See mascheck for details.
printf 'current line is: %s\n' "$line"
Note the explicit newline at the end; printf doesn't add one automatically.
fi
No comment on this line.
done
In the case where you did as I recommended and replaced the for line with a while read construct this line would change to:
done < "$1"
This directs the contents of the file in the $1 variable to the stdin of the while loop, which in turn passes the data to read.
In the interests of clarity I recommend copying the value from $1 into another variable first. That way when you read this line the purpose is more clear.
I hope no one takes great offense at the stylistic choices made above, which I have attempted to note; there are many ways to do this (but not a great many correct) ways.
Be sure to always run interesting snippets through the excellent shellcheck and explain shell when you run into difficulties like this in the future.
And finally, here's everything put together:
#!/bin/bash
input_file="$1"
while IFS= read -r line ; do
if grep -q -F 'Oct/2015' <<<"$line" ; then
printf 'current line is %s\n' "$line"
fi
done < "$input_file"
If you like one-liners, you may use AND operator (&&), for example:
echo "$line" | grep -e "Oct/2015" && echo "current line is: $line"
or:
grep -qe "Oct/2015" <<<"$line" && echo "current line is: $line"
Spacing is important in shell scripting.
Also, double-parens is for numerical comparison, not single-parens.
if (( $? == 0 )); then
I've created a script that accesses a website with the use of a datafile and outputs the sites responses (one line XML) to an output file. I would like the output to start with the query of the datafile and then the response of the website. When I echo the query one one line and write it to an output file and then write the site's response to the same output file it uses two lines but I only want one line because I would like to end up with a comma separated file that I can import in excel.
This works but with having two lines of data:
while read -r line || [[ -n $line ]]
do
datatogather="$line"
echo $datatogather >>outputfile.txt
curl http://login:password#somewebsite.info/application.php?$datatogather >>outputfile.txt
echo >>outputfile.txt
done < datafile.txt
This doesn't work (although it shows the comma in the output file, so that line is being processed):
while read -r line || [[ -n $line ]]
do
datatogather="$line"
echo $datatogather,>>outputfile.txt | curl http://login:password#somewebsite.info/application.php?$datatogather >>outputfile.txt
echo >>outputfile.txt
done < datafile.txt
Stripping the output file of it's garbage data with sed was a breeze to figure out, even reading the input file into the site was very easy compared to figuring out how to use a variable more than once in a single line. Hope you can help me.
Do one echo operation instead of two, and only one redirection instead of many, and use command substitution to capture the output of curl:
while read -r line && [[ -n "$line" ]]
do
echo "$line,$(curl http://login:password#example.com/application.php?$line)"
done < datafile.txt >>outputfile.txt
Note that the test is changed from || to &&, and personally I don't like unquoted variables, though [[ is less problematic in some respects than [ (but introduces other problems, IMO).
The only nasty feature there is that the double quotes mean that newlines in the website response are preserved in the output. If you like living dangerously, you could simply remove the double quotes. It would probably be better to revise it to map the newlines to spaces:
while read -r line && [[ -n "$line" ]]
do
echo "$line,$(curl http://login:password#example.com/application.php?$line | tr '\n' ' ')"
done < datafile.txt >>outputfile.txt
Note that you're liable to have problems if the output from the website includes any commas in its output, but you've not (yet) asked about that.
You do not want to put the tr operation outside the loop; you want a newline at the end of each echo, so this would be bad:
while read -r line && [[ -n "$line" ]]
do
echo "$line,$(curl http://login:password#example.com/application.php?$line)"
done < datafile.txt | tr '\n' ' ' >>outputfile.txt
I have a text file with a list of files with the structure ABC123456A or ABC123456AA. What I would like to do is check whether the files ABC123456ZZP also exists. i.e I want to substitute the letter(s) after ABC123456 with ZZP
Can I do this using sed?
Like this?
X=ABC123456 ; echo ABC123456AA | sed -e "s,\(${X}\).*,\1ZZP,"
You could use sed as wilx suggests but I think a better option would be bash.
while read file; do
base=${file:0:9}
[[ -f ${base}ZZP ]] && echo "${base}ZZP exists!"
done < file
This will loop over each line in file
then base is set to the first 9 characters of the line (excluding whitespace)
then check to see if a file exists with ZZP on the end of base and print a message if it does.
Look:
$ str="ABC123456AA"
$ echo "${str%[[:alpha:]][[:alpha:]]*}"
ABC123456
so do this:
while IFS= read -r tgt; do
tgt="${tgt%[[:alpha:]][[:alpha:]]*}ZZP"
[[ -f "$tgt" ]] && printf "%s exists!\n" "$tgt"
done < file
It will still fail for file names that contain newlines so let us know if you have that situation but unlike the other posted solutions it will work for file names with other than 9 key characters, file names containing spaces, commas, backslashes, globbing characters, etc., etc. and it is efficient.
Since you said now that you only need the first 9 characters of each line and you were happy with piping every line to sed, here's another solution you might like:
cut -c1-9 file |
while IFS= read -r tgt; do
[[ -f "${tgt}ZZP" ]] && printf "%sZZP exists!\n" "$tgt"
done
It'd be MUCH more efficient and more robust than the sed solution, and similar in both contexts to the other shell solutions.