Using rsync, how can I rename files when copying with the --files-from argument? I have about 190,000 files, each of which need to be renamed when copying from source to destination. I plan to have the list of files in a text file to pass to the --files-from argument.
Not entirely true... you CAN rename files enroute with rsync, but only if you rsync one file at a time, and set the --no-R --no-implied-dirs options, then explicitly set the destination name in the destination path.
But at that point, you may just want to use some other tool.
This, for example, would work:
rsync --no-R --no-implied-dirs
1.2.3.4::module/$FILENAME
/$PATH/$TOFILE/$NEWFILENAME
There is no way to arbitrarily rename files with rsync. All rsync can do is move files to a different directory.
You must use a second tool either on the sending or receiving side to rename the files.
Related
I know there has been a huge discussion about this but I have not found something this specific.
Im trying to copy all .key files in /home// directory
This does not work
/usr/bin/rsync -auPA --include="*/*.key" --exclude="*" /home/* /tmp/test
This works but it copies over unwanted empty directories like /home/uname/Documents
/usr/bin/rsync -auPA --include="*/" --include="*.key" --exclude="*" /home /tmp/test
Basically what i need for rsync to do is to copy only files with .key extension and only create necessarily folders that contain .key files
I think you are looking for the -m option. From the man page:
-m, --prune-empty-dirs
This option tells the receiving rsync to get rid of empty directories from the file-list, including nested directories that
have no non-directory children. This is useful for avoiding the creation of a bunch of useless directories when the sending
rsync is recursively scanning a hierarchy of files using include/exclude/filter rules.
Note that the use of transfer rules, such as the --min-size option, does not affect what goes into the file list, and thus
does not leave directories empty, even if none of the files in a directory match the transfer rule.
Because the file-list is actually being pruned, this option also affects what directories get deleted when a delete is active.
However, keep in mind that excluded files and directories can prevent existing items from being deleted due to an exclude both
hiding source files and protecting destination files. See the perishable filter-rule option for how to avoid this.
You can prevent the pruning of certain empty directories from the file-list by using a global "protect" filter. For instance,
this option would ensure that the directory "emptydir" was kept in the file-list:
--filter ’protect emptydir/’
Here’s an example that copies all .pdf files in a hierarchy, only creating the necessary destination directories to hold the
.pdf files, and ensures that any superfluous files and directories in the destination are removed (note the hide filter of
non-directories being used instead of an exclude):
rsync -avm --del --include=’*.pdf’ -f ’hide,! */’ src/ dest
If you didn’t want to remove superfluous destination files, the more time-honored options of "--include='*/' --exclude='*'"
would work fine in place of the hide-filter (if that is more natural to you).
So, I have a list of files in a text file. I believe it's about 100,000 files.
The files in said list are spread across many directories, have different sizes, filenames, extensions, ages, etc.
I am trying to find a way to move those files, and just those, to another drive.
Complicating factor: some of the files have the same name, but are not the same file. They can't just be moved into one folder with an overwriting or ignoring policy towards multiples.
Preferably, I would like them to retain their directory structure, but only have the files that I want inside the destination directory. (the destination drive isn't big enough to simply copy everything).
Below is an example of some lines in the file:
media/dave/xdd/cruzer/F#(NTFS 1)/Raw Files/Portable Network Graphic file/3601-3900/FILE3776.PNG/Windows/winsxs/amd64_microsoft-windows-o..disc-style-memories_31bf3856ad364e35_6.1.7600.16385_none_51190840a935f980/Title_mainImage-mask.png
media/dave/xdd/d1/other/hd1/Program Files/DVD Maker/Shared/DvdStyles/Memories/Title_content-background.png
I have tried to use
rsync -a --files-from=/sourcefile.txt / /media/destinationhdd
However, this just tries to copy my root directory to the destination. Please help, how to I just copy the accursed files that I want to?
cat list | xargs tar cf - | (cd dest; tar xvfp -)
Where list is the file which contains all the file paths.
dest is the target directory
I am looking for a way to compare two folders containing source files and hard links (lets use /media/store/download and /media/store/complete as an example) and then remove orphaned files that don't exist in both folders. These files may have been renamed and may be stored in subdirectories.
I'd like to set this up on a cron script to run regularly. I just can't logically figure out myself how work the logic of the script - could anyone be so kind as to help?
Many thanks
rsync can do what you want, using the --existing, --ignore-existing, and --delete options. You'll have to run it twice, once in each "direction" to clean orphans from both source and target directories.
rsync -avn --existing --ignore-existing --delete /media/store/download/ /media/store/complete
rsync -avn --existing --ignore-existing --delete /media/store/complete/ /media/store/download
--existing says don't copy orphan files
--ignore-existing says don't update existing files
--delete says delete orphans on target dir
The trailing slash on the source dir, and no trailing slash on the target dir, are mandatory for your task.
The 'n' in -avn means not to really do anything, and I always do a "dry run" with the -n option to make sure the command is going to do what I want, ESPECIALLY when using --delete. Once you're confident your command is correct, run it with just -av to actually do the work.
Perhaps rsync is of use ?
Rsync is a fast and extraordinarily versatile file copying tool. It
can copy locally, to/from another host over any remote shell, or
to/from a remote rsync daemon. It offers a large number of options
that control every aspect of its behavior and permit very flexible
specification of the set of files to be copied. It is famous for its
delta-transfer algorithm, which reduces the amount of data sent over
the network by sending only the differences between the source files
and the existing files in the destination. Rsync is widely used for
backups and mirroring and as an improved copy command for everyday
use.
Note it has a --delete option
--delete delete extraneous files from dest dirs
which could help with your specific use case above.
You can also use "diff" command to list down all the different files in two folders.
I want to create script that copy my project and make it zip archive. I want to exclude all folder named .svn in all sub directories. Any suggestion?
I'd use rsync's FILTER RULES for this:
Create an .rsync-filter file (in the origin directory) containing, e.g.
-.svn/
Now run rsync like an exalted copy:
rsync -aFF origin/ destination/
You can do this using rsync. Although this is designed to synchronise directories across servers, it can also be used to copy directories on a single machine.
rsync has a --exclude option to exclude files and directories by pattern. See http://www.samba.org/ftp/rsync/rsync.html for help and examples.
Just call the zip utility on your project’s folder and use the -r option for recursive plus the -x option to exclude files / folders by pattern.
zip -r target-filename.zip source-folder -x \*exclude-pattern\*
exclude-pattern in your case would be .svn
See also man zip
I am looking to do a specific copy in Fedora.
I have two folders:
'webroot': holding ALL web files/images etc
'export': folder containing thousands of PHP, CSS, JS documents that are exported from my SVN repo.
The export directory contains many of the same files/folders that the root does, however the root contains additional ones not found in export.
I'd like to merge all of the contents of export with my webroot with the following options:
Overwriting the file in webroot if export's version contains different code than what
is inside of webroot's version (live)
Preserve the permissions/users/groups of the file if it is overwritten (the export
version replacing the live version) *NOTE I would like the webroots permissions/ownership maintained, but with export's contents
No prompting/stopping of the copy
of any kind (ie not verbose)
Recursive copy - obviously I
would like to copy all* files
folders and subfolders found in
export
I've done a bit of research into cp - would this do the job?:
cp -pruf ./export /path/to/webroot
It might, but any time the corresponding files in export and webroot have the same content but different modification times, you'd wind up performing an unnecessary copy operation. You'd probably get slightly smarter behavior from rsync:
rsync -pr ./export /path/to/webroot
Besides, rsync can copy files from one host to another over an SSH connection, if you ever have a need to do that. Plus, it has a zillion options you can specify to tweak its behavior - look in the man page for details.
EDIT: with respect to your clarification about what you mean by preserving permissions: you'd probably want to leave off the -p option.
-u overwrites existing files folder if the destination is older than source
-p perserves the permission and dates
-f turns off verbosity
-r makes the copy recursive
So looks like you got all the correct args to cp
Sounds like a job for cpio (and hence, probably, GNU tar can do it too):
cd export
find . -print | cpio -pvdm /path/to/webroot
If you need owners preserved, you have to do it as root, of course. The -p option is 'pass mode', meaning copy between locations; -v is verbose (but not interactive; there's a difference); -d means create directories as necessary; -m means preserve modification time. By default, without the -u option, cpio won't overwrite files in the target area that are newer than the one from the source area.