Extending Sharepoint XSL template - sharepoint

Question

Thanks to this post I've come up with the following template:-
<xsl:variable name="Doc">
<xsl:call-template name="OuterTemplate.GetTitle">
<xsl:with-param name="Title" select="#DocumentLink1"/>
</xsl:call-template>
</xsl:variable>
<a href="{substring-before($Doc,',')}">
<xsl:value-of select="substring-after($Doc,',')" />
</a>
This template is nested in an unorderd list and li tag (see below). Since this code has a physical and visual presence in the html page when no content exists I would like to add the li tags and possibly the ul tags to the template. Can anyone tell me how to accomplish this?
<ul>
<li>
<xsl:variable name="Doc">
<xsl:call-template name="OuterTemplate.GetTitle">
<xsl:with-param name="Title" select="#DocumentLink1"/>
</xsl:call-template>
</xsl:variable>
<a href="{substring-before($Doc,',')}">
<xsl:value-of select="substring-after($Doc,',')"/>
</a>
</li>
<li>
<xsl:variable name="Doc">
<xsl:call-template name="OuterTemplate.GetTitle">
<xsl:with-param name="Title" select="#DocumentLink2"/>
</xsl:call-template>
</xsl:variable>
<a href="{substring-before($Doc,',')}">
<xsl:value-of select="substring-after($Doc,',')"/>
</a>
</li>
<li>
<xsl:variable name="Doc">
<xsl:call-template name="OuterTemplate.GetTitle">
<xsl:with-param name="Title" select="#DocumentLink3"/>
</xsl:call-template>
</xsl:variable>
<a href="{substring-before($Doc,',')}">
<xsl:value-of select="substring-after($Doc,',')"/>
</a>
</li>

Answer 1

I'm assuming from your link to the other post that you are using the Content Query Web Part here.
You need to wrap your call to this variable using XSLT header/footer techniques. Here is one of a few posts I've seen that show how this can be done with the CQWP in particular.

Answer 2

You could try using the xsl:if elements to conditionally output content. You can find more info on how xsl:if works # http://www.w3schools.com/xsl/xsl_if.asp or just use your favorite search engine.