What's the opposite of od(1)? - linux

Question

Say I have 8b1f 0008 0231 49f6 0300 f1f3 75f4 0c72 f775 0850 7676 720c 560d 75f0 02e5 ce00 0861 1302 0000 0000, how can I easily get a binary file from that without copying+pasting into a hex editor?

Answer 1

Use:
% xxd -r -p in.txt out.bin

Answer 2

See xxd.

Answer 3

This version will work with binary format too:
cat /bin/sh \
| od -A n -v -t x1 \
| tr -d '\r' \
| xxd -r -g 1 -p1 \
| md5sum && md5sum /bin/sh
The extra '\r' is just if you're dealing with DOS text files...
And process byte by byte to prevent endianness difference if running parts of a pipe on different systems.

Answer 4

All the present answers refer to the convenient xxd -r approach, but for situations where xxd is not available or convenient here is a more portable (and more flexible, but more verbose and less efficient) solution, using only POSIX shell syntax (it also compensates for odd-number of digits in input):
un_od() {
printf -- "$(
tr -d '\t\r\n ' | sed -e 's/^(.(.{2})*)$/0\1/' -e 's/\(.\{2\}\)/\\x\1/g'
)"
}
By the way: you don't specify whether your input is big-endian or little-endian, or whether you want big/little-endian output. Usually input such as in your question would be big-endian/network-order (e.g., as created by od -t x1 -An -v), and would be expected to transform to big-endian output. I presume xxd just assumes that default if not told otherwise, and this solution does that too. If byte-swapping is needed, how you do the byte-swapping also depends on the word-size of the system (e.g., 32 bit, 64 bit) and very rarely the byte-size (you can almost always assume 8-bit bytes - octets - though).
The below functions use a more complex version of the binary -> od -> binary trick to portably byteswap binary data, conditional on system endianness, and accounting for system word-size. The algorithm works for anything up to 72-bit word size (because seq -s '' 10 -> 12345678910 doesn't work):
if { sed --version 2>/dev/null || :; } | head -n 1 | grep -q 'GNU sed'; then
_sed() { sed -r "${#}"; }
else
_sed() { sed -E "${#}"; }
fi
sys_bigendian() {
return $(
printf 'I' | od -t o2 | head -n 1 | \
_sed -e 's/^[^ \t]+[ \t]+([^ \t]+)[ \t]*$/\1/' | cut -c 6
)
}
sys_word_size() { expr $(getconf LONG_BIT) / 8; }
byte_swap() {
_wordsize=$1
od -An -v -t o1 | _sed -e 's/^[ \t]+//' | tr -s ' ' '\n' | \
paste -d '\\' $(for _cnt in $(seq $_wordsize); do printf -- '- '; done) | \
_sed -e 's/^/\\/' -e '$ s/\\+$//' | \
while read -r _word; do
_thissize=$(expr $(printf '%s' "$_word" | wc -c) / 4)
printf '%s' "$(seq -s '' $_thissize)" | tr -d '\n' | \
tr "$(seq -s '' $_thissize -1 1)" "$_word"
done
unset _wordsize _prefix _word _thissize
}
You can use the above to output file contents in big-endian format regardless of system endianness:
if sys_bigendian; then
cat /bin/sh
else
cat /bin/sh | byte_swap $(sys_word_size)
fi

Answer 5

Here is the way to reverse "od" output:
echo "test" | od -A x -t x1 | sed -e 's|^[0-f]* ?||g' | xxd -r
test