I'm getting a hex string when converting a SPListItem's date.
eg. "0x01c9d2be|0x809a8800"
This question answers it.
However, what's the proper way to convert it, what format is the DateTime object in?
What if I want to set the datetime? Would I have to convert it into hex format and assign it as a hex string?
There has to be a better and ideal way to extract modify the DateTime object.
Any ideas?
Thanks.
I'm able to extract the date and time. That's fine.
So when you are modifying the DateTime of a ListItem, you just simply assign it as a DateTime format and it will interpret it correctly; no need to generate the hex that it returns.
A DateTime value in .NET can also be represented as a 64-bit value. The strange string format on DateTime fields on SharePoint list items is a variant of such a 64-bit value encoded as two 32-bit hex values. I have found no documentation from Microsoft on this format. But by trial and error I found the following conversion method:
string[] words = strVal.Split('|');
int high = int.Parse(words[0].Substring(2), System.Globalization.NumberStyles.HexNumber);
uint low = uint.Parse(words[1].Substring(2), System.Globalization.NumberStyles.HexNumber);
long ticks = high;
ticks = ticks << 32;
ticks += low;
DateTime t = new DateTime(ticks);
t = t.AddYears(1600);
where t holds the result.
Another solution can be found here. It has something to do how Office 2007 stores dates..
SPListItem.Properties DateTime Fields are in weird Hex format
Related
trying to out put a dataframe into txt file (for a feed). a few specific columns are getting automatically converted into float instead of int as intented.
how can i specific those columns to use int as dtype?
i tried to output the whole dataframd as string and that did not work.
the columns i would like to specify are named [CID1] and [CID2]
data = pd.read_sql(sql,conn)
data = data.astype(str)
data.to_csv('data_feed_feed.txt', sep ='\t',index=True)
Based on the code you provided, you turn all of your data to strings just before export.
Thus, you either need to turn some cols back to desired type, such as:
data["CID1"] = data["CID1"].astype(int)
or not convert them in the first place.
It is not clear from what you provided why you'd have issues with ints being converted to floats.
this post provides heaps of info:
stackoverflow.com/a/28648923/9249533
I'm working on a problem which requires to compare the date with other if the selected date is less than given then print Hello.
The date is present In String Format like given in Examaple
Ex:
if('2020-1-13'<'2021-1-5')
{
print(hello);
}
You should try this it should work
````
var date1 = DateTime.parse('2020-01-13').millisecondsSinceEpoch.toInt();
var date2 = DateTime.parse('2021-01-15').millisecondsSinceEpoch.toInt();
if(date1 < date2){
print('true');
}else{
print('false');
}
````
Instead of doing that just use the date's isBefore or isAfter operator
It would look something like the following:
final now = DateTime.now();
final yesterday = DateTime.now().subtract(Duration(days: 1));
print(now.isAfter(yesterday)); //true
Since your dates are in STring format, it you would have to use the DateTime.parse() method to construct your date objects, and then use the operators talked about above
package:basics provides DateTime extensions that can easily compare DateTime objects.
(Disclosure: I contributed those particular extensions.)
As a start, I am extremely new at Python.
I am receiving an Excel file where the date field is incomplete. The value displays as "190808" (YYMMDD) instead of "2019-08-08".
Part of my automation attempt is to move the file to a different location, where the file is renamed. I want to use the date field to change the file name to the file description and date (e.g. "Sales figures 201908").
The code I have only works if the date format is
str(df['Bank date'][0].strftime("%Y%m"))
I have tried dateparser with the following:
dateparser.parse(df['Bank date'][0].strftime("%Y.%m"))
The error I am receiving is 'numpy.int64' object has no attribute 'strftime'
Any help will do.
Thanks.
I modified it slightly and built my own date-string using slicing.
vOldDate = str(df['Bank date'][0])
vNewDate = '20' + vOldDate[:2] + '.' + vOldDate[2:4]
Numpy is interpreting the date as an integer. To use dateparser, you need to convert that value into a string first, then parse that string, and then format the result:
dateparser.parse(str(df['Bank date'][0])).strftime("%Y.%m")
Since the input format is expected, you should specify it to ensure you get the right date:
>>> dateparser.parse(str(190808), date_formats=['%y%m%d']).strftime("%Y.%m")
'2019.08'
I am working with SoupUI a i need to adjust a Date/time (UTC) that i get back in a response to a GMT Date/time. The date that i get back in the respone looks as followes:
2012-11-09T00:00:00+01:00
I would like to convert this to
2012-11-08T23:00:00Z
Unfortunatly i lack Java skils and therefore also Groovy skils to be able to do this on my own. i did a lot o searches on date convertions but until now i was still unable to find what i was looking for. i will keep searching. if i do manage to get the solution then i will post it here.
Assuming there isn't a colon in the timezone portion, I believe this should work:
// Your input String (with no colons in the timezone portion)
String original = '2012-11-09T00:00:00+0100'
// The format to read this input String
def inFormat = new java.text.SimpleDateFormat( "yyyy-MM-dd'T'HH:mm:ssZ" )
// The format we want to output
def outFormat = new java.text.SimpleDateFormat( "yyyy-MM-dd'T'HH:mm:ss'Z'" )
// Set the timezone for the output
outFormat.timeZone = java.util.TimeZone.getTimeZone( 'GMT' )
// Then parse the original String, and format the resultant
// Date back into a new String
String result = outFormat.format( inFormat.parse( original ) )
// Check it's what we wanted
assert result == '2012-11-08T23:00:00Z'
If there is a colon in the TimeZone, you'll need Java 7 for this task (or maybe a date handling framework like JodaTime), and you can change the first two lines to:
// Your input String
String original = '2012-11-09T00:00:00+01:00'
// The format to read this input String (using the X
// placeholder for ISO time difference)
def inFormat = new java.text.SimpleDateFormat( "yyyy-MM-dd'T'HH:mm:ssX" )
I am trying to save data into my database using a vb form. I am using a datetimepicker to insert the date into my database. Here's an example
saveCommand.Parameters.AddWithValue("A_BOOKDATE", abookdatePicker1.Text).DbType = DbType.DateTime
In my database i set its attribute to time ,now the thing is i used the same line of code on another database and it worked but this one is giving this error
'Failed to convert parameter value from string to datetime'
How do i convert this string to datetime.
Many Thanks
Use DateTimePicker.Value instead of DateTimePicker.Text:
saveCommand.Parameters.AddWithValue("A_BOOKDATE", abookdatePicker1.Value) _
.DbType = DbType.DateTime
(If you ever actually have to convert a string to a DateTime, use DateTime.TryParseExact or DateTime.ParseExact, but in this case it's better not to use the string representation at all.)
You could also try to use
Convert.ToDateTime Method (String) (this one will return a datatime object or throw and exception)
DateTime.TryParse Method (String, DateTime) (this one returns the datetime as an output parameter, returns null on failure)