How to recursively list all files and directories - linux

Question

Using the tcsh shell on Free BSD, is there a way to recursively list all files and directories including the owner, group and relative path to the file?
ls -alR comes close, but it does not show the relative path in front of every file, it shows the path at the top of a grouping i.e.
owner% ls -alR
total 0
drwxr-xr-x 3 owner group 102 Feb 1 10:50 .
drwx------+ 27 owner group 918 Feb 1 10:49 ..
drwxr-xr-x 5 owner group 170 Feb 1 10:50 subfolder
./subfolder:
total 16
drwxr-xr-x 5 owner group 170 Feb 1 10:50 .
drwxr-xr-x 3 owner group 102 Feb 1 10:50 ..
-rw-r--r-- 1 owner group 0 Feb 1 10:50 file1
-rw-r--r-- 1 owner group 0 Feb 1 10:50 file2
What I would like is output like:
owner group ./relative/path/to/file
The accepted answer to this question shows the relative path to a file, but does not show the owner and group.

Answer 1

How about this:
find . -exec ls -dl \{\} \; | awk '{print $3, $4, $9}'

Answer 2

Use tree. Few linux distributions install it by default (in these dark days of only GUIs :-), but it's always available in the standard repositories. It should be available for *BSD also, see http://mama.indstate.edu/users/ice/tree/
Use:
tree -p -u -g -f -i
or
tree -p -u -g -f
or check the man page for many other useful arguments.

Answer 3

Works in Linux Debian:
find $PWD -type f

Answer 4

find comes close:
find . -printf "%u %g %p\n"
There is also "%P", which removes the prefix from the filename, if you want the paths to be relative to the specified directory.
Note that this is GNU find, I don't know if the BSD find also supports -printf.

Answer 5

You've already got an answer that works, but for reference you should be able to do this on the BSDs (I've tested it on a mac) :
find . -ls

Answer 6

If you fancy using Perl don't use it as a wrapper around shell commands. Doing it in native Perl is faster, more portable, and more resilient. Plus it avoids ad-hoc regexes.
use File::Find;
use File::stat;
find (\&myList, ".");
sub myList {
my $st = lstat($_) or die "No $file: $!";
print getgrnam($st->gid), " ",
getpwuid($st->uid), " ",
$File::Find::name, "\n";
}

Answer 7

Simple way I found was this:
ls -lthr /path_to_directory/*
" * " - represents levels.
Ajiths-MBP:test ajith$ ls -lthr *
test2:
total 0
-rw-r--r-- 1 ajith staff 0B Oct 17 18:22 test2.txt
test3:
total 0
-rw-r--r-- 1 ajith staff 0B Oct 17 18:22 test3.txt
test1:
total 0
-rw-r--r-- 1 ajith staff 0B Oct 17 18:21 test1.txt
drwxr-xr-x 3 ajith staff 96B Oct 17 18:22 test1_sub_dir
Ajiths-MBP:test ajith$ ls -lthr */*
-rw-r--r-- 1 ajith staff 0B Oct 17 18:21 test1/test1.txt
-rw-r--r-- 1 ajith staff 0B Oct 17 18:22 test2/test2.txt
-rw-r--r-- 1 ajith staff 0B Oct 17 18:22 test3/test3.txt
test1/test1_sub_dir:
total 0
-rw-r--r-- 1 ajith staff 0B Oct 17 18:22 test1_sub_file.txt

Answer 8

Use a shell script. Or a Perl script. Example Perl script (because it's easier for me to do):
#!/usr/bin/perl
use strict;
use warnings;
foreach(`find . -name \*`) {
chomp;
my $ls = `ls -l $_`;
# an incomprehensible string of characters because it's Perl
my($owner, $group) = /\S+\s+\S+\s+(\S+)\s+(\S)+/;
printf("%-10s %-10s %s\n", $owner, $group, $_);
}
Perhaps a bit more verbose than the other answers, but should do the trick, and should save you having to remember what to type. (Code untested.)