Just a quick one, I want to continuously add digits to a string. The first thing I did is to remove the last character of the string, now digits starting from 1 should be continuously added to it. The snippet is below:
using System;
using System.Collections.Generic;
namespace ConsoleApplication3
{
class Class1
{
public static String source = "#box1";
static string dest;
public static void Main(String[] args)
{
try
{
if (source.Length > 0)
{
dest = source.Substring(0, source.Trim().Length - 1);
}
Console.WriteLine(dest);
Console.ReadLine();
}
catch(Exception e){ e.ToString(); }
}
}
}
The output should look like this:
#box1
#box2
#box3
#box4
#box5
and so on.....
If you have a max :
for (int i = 1; i <= max; i++)
{
Console.WriteLine("#Box" + i);
}
With no maximum, but that is not a good idea:
count = 1
while (1 > 0)
{
Console.WriteLine("#Box" + count);
count++;
}
You can also do no max with the for loop, but I just wanted to give you more options in loops.
Information on loops http://csharp.net-tutorials.com/basics/loops/
Thanks, guys,
I got it solved this way. Sorry that I have to post the real code I'm using it for. I'm much occupied than to edit the pseudo code again.
public static String RegistrationFailedPanels = UserValidations.RegistrationFailedPanels;
public static String CloseFailedPanel = UserValidations.CloseFailedPanel;
static int count = 0;
public void LoginFailed(String InputConstant, String FailedLogin)
{
++count;
InputConstant = RegistrationFailedPanels.Substring(0, RegistrationFailedPanels.Trim().Length-1);
FailedLogin = CloseFailedPanel.Substring(0, CloseFailedPanel.Trim().Length-1);
new LoginValidations(driver).WaitForATime(InputConstant +count);
driver.FindElement(By.CssSelector(FailedLogin +count)).Click();
}
Related
Why this simple program doesn't work?
using System;
namespace ConsoleApp7
{
class Program
{
static void Main(string[] args)
{
string name;
string all;
for (int i = 1; i <= 3; i++)
{
Console.WriteLine("enter name");
name = Console.ReadLine();
Console.WriteLine(name);
all =string.Concat(all, name);
}
Console.WriteLine("all the names are ");
// Console.WriteLine(s1);
}
}
}
It gives an error and does not cascade all strings?
Thanks
You need to initialize the value of variable all. Here's a sample that works:
static void Main(string[] args)
{
string name;
string all = null;
for (int i = 1; i <= 3; i++)
{
Console.WriteLine("enter name");
name = Console.ReadLine();
Console.WriteLine(name);
all = string.Concat(all, name);
}
Console.WriteLine("all the names are ");
Console.WriteLine(all);
}
Note, however, that there are no separators added beween the three names. If someone would enter "one" and "two" and "three", for instance, then the output would be "onetwothree". Maybe you want something different, maybe not.
The code below is giving me the error java.util.NoSuchElementException right after I Ctrl+Z
to indicate that the user input is complete. By the looks of it seems as if it does not know how to just end one method without messing with the other scanner object.
I try the hasNext method and I ended up with an infinite loop, either way is not working. As a requirement for this assignment I need to be able to tell the user to use Ctrl+Z or D depending on the operating system. Also I need to be able to read from a text file and save the final tree to a text file please help.
/* sample input:
CSCI3320
project
personal
1 HW1
1 HW2
1 2 MSS.java
2 p1.java
*/
import java.util.Scanner;
import java.util.StringTokenizer;
public class Directory {
private static TreeNode root = new TreeNode("/", null, null);
public static void main(String[] args) {
userMenu();
System.out.println("The directory is displayed as follows:");
root.listAll(0);
}
private static void userMenu(){ //Displays users menu
Scanner userInput = new Scanner(System.in);//Scanner option
int option = 0;
do{ //I believe the problem is here since I am not using userInput.Next()
System.out.println("\n 1. add files from user inputs ");
System.out.println("\n 2. display the whole directory ");
System.out.println("\n 3. display the size of directory ");
System.out.println("\n 0. exit");
System.out.println("\n Please give a selection [0-3]: ");
option = userInput.nextInt();
switch(option){
case 1: addFileFromUser();
break;
case 2: System.out.println("The directory is displayed as follows:");
root.listAll(0);
break;
case 3: System.out.printf("The size of the directory is %d.\n", root.size());
break;
default:
break;
}
}while( option !=0);
userInput.close();
}
private static void addFileFromUser() {
System.out.println("To terminate inp1ut, type the correct end-of-file indicator ");
System.out.println("when you are prompted to enter input.");
System.out.println("On UNIX/Linux/Mac OS X type <ctrl> d");
System.out.println("On Windows type <ctrl> z");
Scanner input = new Scanner(System.in);
while (input.hasNext()) { //hasNext being used Crtl Z is required to break
addFileIntoDirectory(input); // out of the loop.
}
input.close();
}
private static void addFileIntoDirectory(Scanner input) {
String line = input.nextLine();
if (line.trim().equals("")) return;
StringTokenizer tokens = new StringTokenizer(line);
int n = tokens.countTokens() - 1;
TreeNode p = root;
while (n > 0 && p.isDirectory()) {
int a = Integer.valueOf( tokens.nextToken() );
p = p.getFirstChild();
while (a > 1 && p != null) {
p = p.getNextSibling();
a--;
}
n--;
}
String name = tokens.nextToken();
TreeNode newNode = new TreeNode(name, null, null);
if (p.getFirstChild() == null) {
p.setFirstChild(newNode);
}
else {
p = p.getFirstChild();
while (p.getNextSibling() != null) {
p = p.getNextSibling();
}
p.setNextSibling(newNode);
}
}
private static class TreeNode {
private String element;
private TreeNode firstChild;
private TreeNode nextSibling;
public TreeNode(String e, TreeNode f, TreeNode s) {
setElement(e);
setFirstChild(f);
setNextSibling(s);
}
public void listAll(int i) {
for (int k = 0; k < i; k++) {
System.out.print('\t');
}
System.out.println(getElement());
if (isDirectory()) {
TreeNode t = getFirstChild();
while (t != null) {
t.listAll(i+1);
t = t.getNextSibling();
}
}
}
public int size() {
int s = 1;
if (isDirectory()) {
TreeNode t = getFirstChild();
while (t != null) {
s += t.size();
t = t.getNextSibling();
}
}
return s;
}
public void setElement(String e) {
element = e;
}
public String getElement() {
return element;
}
public boolean isDirectory() {
return getFirstChild() != null;
}
public void setFirstChild(TreeNode f) {
firstChild = f;
}
public TreeNode getFirstChild() {
return firstChild;
}
public void setNextSibling(TreeNode s) {
nextSibling = s;
}
public TreeNode getNextSibling() {
return nextSibling;
}
}
}
Exception Details:
/*Exception in thread "main" java.util.NoSuchElementException
at java.util.Scanner.throwFor(Scanner.java:907)
at java.util.Scanner.next(Scanner.java:1530)
at java.util.Scanner.nextInt(Scanner.java:2160)
at java.util.Scanner.nextInt(Scanner.java:2119)
at Directory.userMenu(Directory.java:36)
at Directory.main(Directory.java:21)*/
Your problem is this line:
option = userInput.nextInt(); //line 24
If you read the Javadoc, you will find that the nextInt() method can throw a NoSuchElementException if the input is exhausted. In other words, there is no next integer to get. Why is this happening in your code? Because you this line is in a loop once that first iteration completes (on the outer while loop) your initial input selection has been consumed. Since this is a homework, I am not going to write the code. But, if you remove the loop, you know this works at least once. Once you try to loop, it breaks. So I will give you these hints:
Change the do/while to a while loop.
Prompt the user once outside the loop.
Recreate the prompt and recapture the user input inside the loop.
For example, the code below can be used for the basis of your outer loop.
import java.util.Scanner;
public class GuessNumberGame {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Guess the secret number: (Hint: the secret number is 1)");
int guess = input.nextInt();
while (guess != 1) {
System.out.println("Wrong guess. Try again: ");
guess = input.nextInt();
}
System.out.println("Success");
input.close();
}
}
The reason why this works is because I don't reuse the same, exhausted, scanner input object to get the next integer. In your example, the initial input is inside the loop. The second time around, that input has already been consumed. Follow this pattern and you should be able to complete your assignment.
private string GenerateID()
{
}
private void auto()
{
AdmissionNo.Text = "A-" + GenerateID();
}
with prefix of A like below
A-0001
A-0002 and so on .
You can use below code.
private string GenerateId()
{
int lastAddedId = 8; // get this value from database
string demo = Convert.ToString(lastAddedId + 1).PadLeft(4, '0');
return demo;
// it will return 0009
}
private void Auto()
{
AdmissionNo.Text = "A-" + GenerateId();
// here it will set the text as "A-0009"
}
Look at this
public class Program
{
private static int _globalSequence;
static void Main(string[] args)
{
_globalSequence = 0;
for (int i = 0; i < 10; i++)
{
Randomize(i);
Console.WriteLine("----------------------------------------->");
}
Console.ReadLine();
}
static void Randomize(int seed)
{
Random r = new Random();
if (_globalSequence == 0) _globalSequence = r.Next();
Console.WriteLine("Random: {0}", _globalSequence);
int localSequence = Interlocked.Increment(ref _globalSequence);
Console.WriteLine("Increment: {0}, Output: {1}", _globalSequence, localSequence);
}
}
Whether it is an windows application or not is IMHO not relevant. I'd rather care about thread safety. Hence, I would use something like this:
public sealed class Sequence
{
private int value = 0;
public Sequence(string prefix)
{
this.Prefix = prefix;
}
public string Prefix { get; }
public int GetNextValue()
{
return System.Threading.Interlocked.Increment(ref this.value);
}
public string GetNextNumber()
{
return $"{this.Prefix}{this.GetNextValue():0000}";
}
}
This could easily be enhanced to use the a digit count. So the "0000" part could be dynamically specified as well.
Whenever I run this code, it works pretty smoothly, until the while loop runs through once. It will go back and ask for the name again, and then skip String b = sc.nextLine();, and print the next line, instead.
static Scanner sc = new Scanner(System.in);
static public void main(String [] argv) {
Name();
}
static public void Name() {
boolean again = false;
do
{
System.out.println("What is your name?");
String b = sc.nextLine();
System.out.println("Ah, so your name is " + b +"?\n" +
"(y//n)");
int a = getYN();
System.out.println(a + "! Good.");
again = askQuestion();
} while(again);
}
static public boolean askQuestion() {
System.out.println("Do you want to try again?");
int answer = sc.nextInt();
if (answer == 1) {
return true;
}
else {
return false;
}
}
static int getYN() {
switch (sc.nextLine().substring(0, 1).toLowerCase()) {
case "y":
return 1;
case "n":
return 0;
default:
return 2;
}
}
}
Also, I'm trying to create this program in a way that I can ask three questions (like someone's Name, Gender, and Age, maybe more like race and whatnot), and then bring all of those answers back. Like, at the very end, say, "So, your name is + name +, you are + gender +, and you are + age + years old? Yes/No." Something along those lines. I know there's a way to do it, but I don't know how to save those responses anywhere, and I can't grab them since they only occur in the instance of the method.
Don't try to scan text with nextLine() AFTER using nextInt() with the same scanner! It may cause problems. Open a scanner method for ints only...it's recommended.
You could always parse the String answer of the scanner.
Also, using scanner this way is not a good practice, you could organize questions in array an choose a loop reading for a unique scanner instantiation like this:
public class a {
private static String InputName;
private static String Sex;
private static String Age;
private static String input;
static Scanner sc ;
static public void main(String [] argv) {
Name();
}
static public void Name() {
sc = new Scanner(System.in);
String[] questions = {"Name?","Age","Sex?"};//
int a = 0;
System.out.println(questions[a]);
while (sc.hasNext()) {
input = sc.next();
setVariable(a, input);
if(input.equalsIgnoreCase("no")){
sc.close();
break;
}
else if(a>questions.length -1)
{
a = 0;
}
else{
a++;
}
if(a>questions.length -1){
System.out.println("Fine " + InputName
+ " so you are " + Age + " years old and " + Sex + "." );
Age = null;
Sex = null;
InputName = null;
System.out.println("Loop again?");
}
if(!input.equalsIgnoreCase("no") && a<questions.length){
System.out.println(questions[a]);
}
}
}
static void setVariable(int a, String Field) {
switch (a) {
case 0:
InputName = Field;
return;
case 1:
Age = Field;
return;
case 2:
Sex = Field;
return;
}
}
}
Pay attention on the global variables, wich stores your info until you set them null or empty...you could use them to the final affirmation.
Hope this helps!
Hope this helps!
using System;
namespace rummykhan
{
class Program
{
static void Main(string[] args)
{
for (int i = 0; i < 100; i++)
{
Test t1 = new Test();
}
}
}
class Test
{
public int first;
public int second;
}
}
im trying to make 100 objects but i wish these objects are named automatically using some random string. im unable to figure out.. thanx for help in advance..
EDIT
Looking at my own question after a year, actually i was looking for a way by which i was able to create object by my own chosen name. e.g.
string tmp = "obj1";
var tmp = new Foo();
i was thinking that someway obj1 value may kick in and i could call my variable using obj1, which is totally moronic.
Just store the objects in a List.
example:
List<Test> tests = new List<Test>();
for (int i = 0; i < 100; i++)
{
tests.Add(new Test());
}
Currently your code will destroy t1 after each iteration of the loop. you could do something like this to preserve 100 coppies of test in memory
using System;
namespace rummykhan
{
class Program
{
static void Main(string[] args)
{
List<Test> lstClasses = new List<Test>();
for (int i = 0; i < 100; i++)
{
lstClasses.Add(new Test());
}
}
}
class Test
{
public int first;
public int second;
}
}
write like this.
Test[] dynamic = new Test[100];
for (int i=0; i< 100; i++)
{
dynamic[i] = new Test();
}