Consider the sheet below:
A
B
1
4
3
5
2
2
5
0
4
1
I want to find if there is a match for each row of column 1 with any row of column 2. So ideally this would give me:
A
B
C
1
4
Yes
3
5
No
2
2
Yes
5
0
Yes
4
1
Yes
As a first and simple step, I am using =MATCH(A2,B2:B6) to get the index of the match and then manually calling this across the rows to get something like this:
A
B
C
1
4
6
3
5
-
2
2
3
5
0
2
4
1
1
I am now having a problem:
I want to apply this for a row of 500 in A and 2000 in B. I was thinking of manually filling in the first few rows and then select and drag over the first 500 rows. This however does not work as for each subsequent cell, it just changes the formula to =MATCH(A(N +1),B2 + N:B6 + N) which gives me wrong values and at worst, just repeats the older pattern ahead.
Can anyone help me with how I can just use the MATCH function to find all the values in A that are present in B?
Let me continue where you arrived:
=MATCH(A2,B2:B6,0)
(You forgot the last zero)
This formula is correct, but it is also wrong.
???
Well, when you drag it down, you get:
=MATCH(A3,B3:B7,0)
This is not what you want: you want the search term (A2) to change into A3 but you want the search array (B2:B6) not to change. In order to get this done, you need to work with absolute references. This looks like this:
=MATCH(A2,B$2:B$6,0)
When you drag this down, this is what you get:
=MATCH(A3,B$2:B$6,0)
=> ok so far.
Problem now: you need to translate your current results (a number or #N/A) into "yes" or "no". This can be done in numerous ways, let me give you an example:
=IF(ISERROR(MATCH(A2,B$2:B$6,0)),"No","Yes")
One remark: there exists an IFERROR() function in Excel, but this does not have an "else"-clause, hence the choice for the IF(ISERROR( combination.
Within Sheets you may try this out:
=index(if(len(A2:A),if(ifna(xmatch(A2:A,B2:B)),"Yes","No"),))
If you want to separate those matching values then could use FILTER() function.
=FILTER(A1:A5,COUNTIFS(B1:B9,A1:A5))
And for YES, NO dynamically, try MAP() function.
=MAP(A1:A5,LAMBDA(x,ISNUMBER(XMATCH(x,B:B))))
Related
Thanks so much for looking at my question! I am trying to create a formula that subtracts a specific value from another formula. However, that specific value may change.
Example:
A B C D
1 1 100 =(2000 - ( if A = 1, i want to subtract the C value where B =1))
1 2 250
1 3 310
1 4 .
2 1
2 2 =((2000 - ( if A = 2, i want to subtract the C value where B =1))
2 3
2 4
3 1
3 2
3 3
3 4
(A,B,C,D are the columns)
Hopefully this makes sense! I am trying to subtract the C value that goes along with the B1 value for each different A.
I was thinking an index match of some sort but wasnt exactly sure how to do that when the A's change. Thanks so much in advance for help!
INDIRECT or INDEX functions can help you. See this answer.
Would something like a nested if function work for you here? For example:
=IF(A2=1,IF(B2=1,2000-C2,"Enter calculation if B2<>1"),"Enter calculation if A2"<>1)
If this works, then you can simply copy/paste the function down the rows in column D.
So, I have this problem, I would like to find the average of a column by using the OR function to check criteria from adjusted columns, I tried putting OR into AverageIf function, fail, also tried the "Average(IF(OR(" again not the correct return. Thought it is a simple thing could be done easily but don't know why it doesn't work. So my table is something like this:
ID: Rate Check 1 Check 2 Check 3
1 5 1 1 1
2 3 1 1
3 2 1
4 4
5 5 1 1
6 3
7 4 1
I would like to find the average of the rate column by checking if there are any value in either Check 1; Check 2 or Check 3 columns, so in the above case i will get the average of all but row with the id 4 and 6. Is this possible without using a helper column?
You can use SUMPRODUCT()
=SUMPRODUCT(((C2:C8<>"")+(D2:D8<>"")+(E2:E8<>"")>0)*(B2:B8<>"")*B2:B8)/SUMPRODUCT(--((C2:C8<>"")+(D2:D8<>"")+(E2:E8<>"")>0)*(B2:B8<>""))
If your first ID starts in A2, use this formula (edited to handle empty values in the "Rate" column):
=AVERAGE(IF(MMULT(LEN(C2:E8)*LEN(B2:B8),ROW(INDIRECT("1:"&COLUMNS($C$1:$E$1)))),B2:B8))
Suppose I have a dataset:
A B C Final
1 2 3 C
4 5 6 C
I want final to return the column name of the max value. In the example above, 3 and 6 are the highest values, so columns C will be returned in the 'Final' column.Is there an efficient way/formula you can use to get the column names without using VBA? the real dataset containts 60 columns.
I would try something like this to get the column letter.
=SUBSTITUTE(ADDRESS(1,MATCH(MAX(A3:C3),A3:C3,0),4),1,"")
If you want the header, I think there's an easier way, but the extension from this would be
=INDIRECT(SUBSTITUTE(ADDRESS(1,MATCH(MAX(A3:C3),A3:C3,0),4),1,"")&1)
For the header, the better way
=INDEX(A1:C1,1,MATCH(MAX(A3:C3),A3:C3,0))
HLOOKUP is a way without VBA, but sadly HLOOKUP does only search in the first row of the array, so you should add the "title column" at the bottom
A B C Final
1 2 3 <formula1>
4 5 6 <formula2>
A B C
If the dataset starts at first corner, Formula1 would be :
=HLOOKUP(MAX(A2:C2);A2:C4;2;FALSE)
Formula2 will be
=HLOOKUP(MAX(A3:C3);A3:C4;1;FALSE)
etc...
=HLOOKUP(MAX($A3:$C3);$A3:$C$4;<manual change here backward>;FALSE)
You can use the vector form of the LOOKUP function.
If your first row, with A B C, are the labels, then:
=LOOKUP(2, 1/(MAX(A2:C2)=A2:C2),$A$1:$C$1)
i would like to count number for every 7 rows, data are in one column. i use this formula, but it is not working.
from B8 to B14329, for every 7 rows, count number if it is equal to 3. so i know how many 3 in every 7 rows.
=COUNTIFS(B8:B14329, OFFSET($B$7,(ROW()-12)*7,0,7,1),B8:B14329,=3)
Thanks a lot!
i want something like this:
data count
3
2
3
1
3
3
1 4
1
2
2
3
3
1
1 2
.....
....
...
Simple and easy:
=SUMPRODUCT((B8:B14329=3)*(MOD(ROW(B8:B14329),7)=1))
Just change the =1 to your needs. To start with row 1 =1, 2 =2 ... 6 =6, 7 =0. This way, to start count at row 8 it is =1
EDIT: having your exaple now, you want something completely different... lol.
=IF(MOD(ROW(),7)=0,COUNTIF(A8:A14,3),"")
Put this in row 14 and then drag down... change the =0 as you need it.
Here's what I would do
Add a new column with the row index (8 to 14239) in your case
Add Yet another column, with a formula to tell whether the column you just added is a multiple of 7. Put it's value like "TRUE" or "FALSE"
You can use the MOD function to check the remainder of the division.
= MOD ( Number , Divisor )
By now, you should have, aside from the columns you already have, something like:
8-----FALSE
9-----FALSE
10-----FALSE
11-----FALSE
12-----FALSE
13-----FALSE
14-----TRUE
15-----FALSE
Once you have that, just apply a filter on the "TRUE/FALSE" column, select the "TRUE" values and you will be able to count the number of "3"s on the actual value column, by also using a filter on it.
I hope it helps, and it's easier than a really messy formula.
I have a list that I'm checking against the main data.
The main data looks like:
1234 1
1235 1
1234 1
1213 2
1231 2
1212 2
1231 3
1231 3
etc
The list I'm checking against the main data is:
1
2
3
etc
For each number in my list, I want to count how many start with 123, so the output looks like:
ID 123
1 3
2 1
3 2
etc
I have each ID in the list already. To drag down for each number, I currently have countifs(a1:a8, a1,b1:b8, "123") and it's obviously producing an error. I know I need to include left somewhere in here but I'm not sure where or how to. Much thanks.
In the Main Data sheet, add a column and enter formula as eg: C1=IF(LEFT(A1,3)="123",1,0). Drag the formula for every C cell. Then use that C cell in your SUMIFS in your list sheet eg: =SUMIFS(C:C,B:B,"="&E1) E col for me is your list.
Please refer screenshots below.
Identify begins with 123
sumifs to get the output
Edit:
Another Solution: =SUMPRODUCT(--(LEFT(Maindata!$A$1:$A$8,3)="123")*(Maindata!$B$1:$B$8=Maindata!D1)). This solution works fine to me.
sumproduct with --left
You can use someproduct to do this:
=sumproduct((Maindata!$A$1:$A$8=A1)*(left(Maindata!$B$1:$B$8)="123"))
Where A1 holds the digit you're determining the amount of "values that start with 123" for, and the main data is in worksheet Maindata, range A1:B8.
Is your data in the form of text or number values? If the former, your criteria should instead be "123*" (using an asterisk for wildcard), if the latter you might be able to get away with using ">1230".