Thanks so much for looking at my question! I am trying to create a formula that subtracts a specific value from another formula. However, that specific value may change.
Example:
A B C D
1 1 100 =(2000 - ( if A = 1, i want to subtract the C value where B =1))
1 2 250
1 3 310
1 4 .
2 1
2 2 =((2000 - ( if A = 2, i want to subtract the C value where B =1))
2 3
2 4
3 1
3 2
3 3
3 4
(A,B,C,D are the columns)
Hopefully this makes sense! I am trying to subtract the C value that goes along with the B1 value for each different A.
I was thinking an index match of some sort but wasnt exactly sure how to do that when the A's change. Thanks so much in advance for help!
INDIRECT or INDEX functions can help you. See this answer.
Would something like a nested if function work for you here? For example:
=IF(A2=1,IF(B2=1,2000-C2,"Enter calculation if B2<>1"),"Enter calculation if A2"<>1)
If this works, then you can simply copy/paste the function down the rows in column D.
Related
Consider the sheet below:
A
B
1
4
3
5
2
2
5
0
4
1
I want to find if there is a match for each row of column 1 with any row of column 2. So ideally this would give me:
A
B
C
1
4
Yes
3
5
No
2
2
Yes
5
0
Yes
4
1
Yes
As a first and simple step, I am using =MATCH(A2,B2:B6) to get the index of the match and then manually calling this across the rows to get something like this:
A
B
C
1
4
6
3
5
-
2
2
3
5
0
2
4
1
1
I am now having a problem:
I want to apply this for a row of 500 in A and 2000 in B. I was thinking of manually filling in the first few rows and then select and drag over the first 500 rows. This however does not work as for each subsequent cell, it just changes the formula to =MATCH(A(N +1),B2 + N:B6 + N) which gives me wrong values and at worst, just repeats the older pattern ahead.
Can anyone help me with how I can just use the MATCH function to find all the values in A that are present in B?
Let me continue where you arrived:
=MATCH(A2,B2:B6,0)
(You forgot the last zero)
This formula is correct, but it is also wrong.
???
Well, when you drag it down, you get:
=MATCH(A3,B3:B7,0)
This is not what you want: you want the search term (A2) to change into A3 but you want the search array (B2:B6) not to change. In order to get this done, you need to work with absolute references. This looks like this:
=MATCH(A2,B$2:B$6,0)
When you drag this down, this is what you get:
=MATCH(A3,B$2:B$6,0)
=> ok so far.
Problem now: you need to translate your current results (a number or #N/A) into "yes" or "no". This can be done in numerous ways, let me give you an example:
=IF(ISERROR(MATCH(A2,B$2:B$6,0)),"No","Yes")
One remark: there exists an IFERROR() function in Excel, but this does not have an "else"-clause, hence the choice for the IF(ISERROR( combination.
Within Sheets you may try this out:
=index(if(len(A2:A),if(ifna(xmatch(A2:A,B2:B)),"Yes","No"),))
If you want to separate those matching values then could use FILTER() function.
=FILTER(A1:A5,COUNTIFS(B1:B9,A1:A5))
And for YES, NO dynamically, try MAP() function.
=MAP(A1:A5,LAMBDA(x,ISNUMBER(XMATCH(x,B:B))))
I'm not sure if I'm over complicating this...
basically I'd like to have a formula which is
if the c column is less than 6, then look up the max value in B but display the value of C
so far I have this but I'd like it to show 2, not 437
{=MAX(IF(C2:C12<6,B2:B12, 0))}
any advice is appreciated. i'm shy, be nice..thanks
A B C
cat 110 3
dog 148 4
rooster 36 7
duck 32 8
pig 437 2
horse 44 6
eagle 215 5
dolphin 21 1
panda 2 9
iguana 257 10
fish 199 11
edit:
maybe something like
{=INDEX(C2:C12,MATCH(MAX(IF(C2:C12<6,C2:C12)),C2:C12,0))}
but I don't see where to put b2:b12
You really need two conditions
1) Column B is equal to =MAX(IF(C2:C12<6,B2:B12))
2) Column C is <6
so you can INDEX column C when those two are met, i.e.
=INDEX(C2:C12,MATCH(1,(B2:B12=MAX(IF(C2:C12<6,B2:B12)))*(C2:C12<6),0))
confirmed with CTRL+SHIFT+ENTER
{=IF(C2<6,INDEX($C$2:$C$12,MATCH(MAX($B$2:$B$12),$B$2:$B$12,0)),0)}
You were almost there..
Basically if C<6 , find max of B , lookup it in B:C and display corresponding C
{=IFERROR(VLOOKUP(MAX(IF(C2:C12<6,B2:B12, 0)),B2:C12,2,FALSE),0)}
Since your question doesn't clarify what if c>=6 I assume you don't want value.
Can answer more precisely if you clarify.
Mark this as answer if that's correct.
Hope this helps!
As I could see you requested a single INDEX formula:
{=INDEX($C$2:$C$12,MATCH(MAX(IF($C$2:$C$12<6,$B$2:$B$12,0),0),IF($C$2:$C$12<6,$B$2:$B$12,0),0))}
This is an array formula, hit Ctrl+Shift+Enter while still in the formula bar.
Lets break this down.
=INDEX(C:C, - Index column C as these are the values you want returned
MATCH(IF(C:C<6,B:B,0), - Find the largest value from the following array in the array and return it's relative position for INDEX()
IF(C:C<6,B:B,0),0)) - If the value in column c is less than 6 then add the column B value to the array, otherwise add 0
i would like to count number for every 7 rows, data are in one column. i use this formula, but it is not working.
from B8 to B14329, for every 7 rows, count number if it is equal to 3. so i know how many 3 in every 7 rows.
=COUNTIFS(B8:B14329, OFFSET($B$7,(ROW()-12)*7,0,7,1),B8:B14329,=3)
Thanks a lot!
i want something like this:
data count
3
2
3
1
3
3
1 4
1
2
2
3
3
1
1 2
.....
....
...
Simple and easy:
=SUMPRODUCT((B8:B14329=3)*(MOD(ROW(B8:B14329),7)=1))
Just change the =1 to your needs. To start with row 1 =1, 2 =2 ... 6 =6, 7 =0. This way, to start count at row 8 it is =1
EDIT: having your exaple now, you want something completely different... lol.
=IF(MOD(ROW(),7)=0,COUNTIF(A8:A14,3),"")
Put this in row 14 and then drag down... change the =0 as you need it.
Here's what I would do
Add a new column with the row index (8 to 14239) in your case
Add Yet another column, with a formula to tell whether the column you just added is a multiple of 7. Put it's value like "TRUE" or "FALSE"
You can use the MOD function to check the remainder of the division.
= MOD ( Number , Divisor )
By now, you should have, aside from the columns you already have, something like:
8-----FALSE
9-----FALSE
10-----FALSE
11-----FALSE
12-----FALSE
13-----FALSE
14-----TRUE
15-----FALSE
Once you have that, just apply a filter on the "TRUE/FALSE" column, select the "TRUE" values and you will be able to count the number of "3"s on the actual value column, by also using a filter on it.
I hope it helps, and it's easier than a really messy formula.
I'm looking for a way to find the first specific value above a certain cell.
Using the example below, in the result column every time I hit a A in COL2, I need to substract the value in COL1 to the first A value above.
The trouble seems finding a way to keep the range dynamic...
I thought of =IF(B5="A";A5-INDIRECT("A"&MATCH("A";B:B;0));"")
But of course that only works for the first one as Match will always pick up the first one.
Any ideas? Thanks!
Example :
COL1 COL2 Result
1 A
2 0
3 0
4 A 4 - 1 = 3
5 0
6 A 6 - 4 = 2
7 0
8 0
9 0
10 A 10 - 6 = 4
Try this:
=IF(AND(ROW(B2)<>2,B2="A"),A2-INDEX($A$1:$A1,AGGREGATE(14,6,ROW($1:1)/($B$1:$B1="A"),1)),"")
The AGGREGATE() Function was introduced in 2010.
In D2 enter =IF(B2="A",A2-INDIRECT("A"&MATCH("A"&(E2-1),F:F,0)),"")
In E2 enter =IF(B2="a",COUNTIFS($B$2:B2,"a"),"")
In F2 enter =B2&E2
Copy formulas from D, E and F down all your rows
Column D is the result you're looking for
Let's say I have this data
4 1
4 0
4 1
3 0
5 1
How do I write a function (using SUM or something like that) to add all the values on the left, if the values on the right are 1, or true
The total should be 13
Assuming columns A and B are used...
Check just for 1:
=SUMIF(B1:B5,"=1",A1:A5)
If you want to check for TRUE also:
=SUMIF(B1:B5,"=1",A1:A5) + SUMIF(B1:B5,"=TRUE",A1:A5)
sort by column b, then auto-sum the values you want in column a. cheap & lazy solution.