How I can rewrite the code to 1 line without using **do** and **<-**? [duplicate] - haskell

This question already has answers here:
Convert a do block into a code that uses >>= [duplicate]
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Convert a "do" notation with more than two actions to use the bind function
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Converting the do notation to bind notation
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Should do-notation be avoided in Haskell?
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Closed 10 days ago.
How I can rewrite the code?
foo=do
str <− readFile "foo"
writeFile "bar" str
To 1 line without using do and <-?

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Is there a single bit type in Rust?
Something equivalent to C: unsigned x:1;
The "1" represent the size, in this case one bit.
Edit
What should I do then if I want to do/represent the gates logic:
"And" gate two input(bit input) and one output bit
Same for the "Or" gate and so on...
Should I just ignore the size of the memory and work with u8?
Thanks

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Adding 2 numbers in nodejs with 2 decimal places doesn't leads to unexpected results
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Is there any method to find the lowest occurence of an character in a string as like most_common used for maximum occurence? [duplicate]

This question already has answers here:
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(12 answers)
Closed 3 years ago.
string='hhelloo'
output must be 'e' because it is least occurred character in string.
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moc=min([(lst.count(chr),chr) for chr in (lst)])
print(moc)
You could use the last element from Counter.most_common()
from collections import Counter
print(Counter('hhelloo').most_common()[-1][0])
This wouldn't be very efficient however. For a more efficient method, take a look at this answer: https://stackoverflow.com/a/4743286/5946921
It implements a least_common function in a similar way to how Counter.most_common is implemented

Global constant initialized at runtime in Rust? [duplicate]

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if it were possible. static and const declaration requires compile time value (calls in constants are limited to struct and enum constructors) and let can't be put outside function (error: expected item, found `let`).
I think something like lazy_static can help with this.

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