This question already has answers here:
How can I determine size of a type in Haskell?
(2 answers)
Can we write a function in Haskell to measure the number of bytes that a string of n characters occupies?
(2 answers)
Closed 3 years ago.
Is there a way to get the memory size of a datatype in Haskell ?
E.g : I have a list of item a, and I want to limit this list to x bytes in memory... I will reject all the next items to add above that threshold...
Related
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Convert a do block into a code that uses >>= [duplicate]
(1 answer)
Convert a "do" notation with more than two actions to use the bind function
(4 answers)
Converting the do notation to bind notation
(3 answers)
Expressing do block using only monadic bind syntax
(2 answers)
Should do-notation be avoided in Haskell?
(7 answers)
Closed 10 days ago.
How I can rewrite the code?
foo=do
str <− readFile "foo"
writeFile "bar" str
To 1 line without using do and <-?
This question already has answers here:
How do you set, clear and toggle a single bit in Rust?
(3 answers)
What is similar in Rust to the colon operator in C? [duplicate]
(1 answer)
How does a C-style struct with a bitfield get represented in a Rust #[repr(C)] struct?
(1 answer)
Closed 1 year ago.
Is there a single bit type in Rust?
Something equivalent to C: unsigned x:1;
The "1" represent the size, in this case one bit.
Edit
What should I do then if I want to do/represent the gates logic:
"And" gate two input(bit input) and one output bit
Same for the "Or" gate and so on...
Should I just ignore the size of the memory and work with u8?
Thanks
This question already has answers here:
How to get the least common element in a list?
(12 answers)
Closed 3 years ago.
string='hhelloo'
output must be 'e' because it is least occurred character in string.
lst=[1,1,2,3,4,5,5]
moc=min([(lst.count(chr),chr) for chr in (lst)])
print(moc)
You could use the last element from Counter.most_common()
from collections import Counter
print(Counter('hhelloo').most_common()[-1][0])
This wouldn't be very efficient however. For a more efficient method, take a look at this answer: https://stackoverflow.com/a/4743286/5946921
It implements a least_common function in a similar way to how Counter.most_common is implemented
This question already has answers here:
How do I implement Copy and Clone for a type that contains a String (or any type that doesn't implement Copy)?
(2 answers)
What is the difference between Copy and Clone?
(5 answers)
Closed 3 years ago.
An article that I read recently stated that a struct that holds a Box<T> as a field is not Copy.
This confuses me, since I thought that any type whose size is known can be stored on the stack - and is therefore Copy.
Isn't the Box's size always the same? I thought that it was just a reference to a heap allocated memory - and does therefore have always the same size.
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How many objects are created
(4 answers)
Closed 9 years ago.
for this statement
String a="MAM"+"BCD"+"EFG"+"GFE";
How many objects will be created? (I am confused is it created 4 or 5 or 7)
Most smart compilers will realize that concatenated string constants can be concatenated at compile time. If your compiler chooses to make that optimization, the answer is one.
Otherwise, you have each of your literal strings, plus one for each concatenation. Without the optimization, the answer is 7 because you have 4 strings and 3 +es.
If you're talking about Java, the answer is one, at compile time, as specified in the JLS.
If you're not, the question is unanswerable as posed.
Only one object will be created. In this case because the plus sign is used to concatenate "string literals". :)