I have a Hyperlink (www.example.com/bridge/app/job?ID=466145) and I have list of Job ID's (6 digit codes 441256, 324356, 556789..etc) in column A of my worksheet. If I select a particular cell containing Job ID and click any random shortcut key which assigned in macro (example Ctrl+K) the cell value has to replace the part of my hyperlink after "=" and open that hyperlink in default browser.
Sub Test()
Dim url As String
url = "Hyperlink"
ActiveWorkbook.FollowHyperlink url
End Sub
I have tired to open hyperlink but unable to find a way to replace my part of hyperlink with cell value.
Related
I am looking for a Excel VBA code to select the resulting Form address on Sheet 2 from the set of States on Sheet 1, but I need to copy the cell and paste it to retain the existing hyperlink attached to Form.
The only common data is the States.
I used INDEX MATCH but it only gets the word "Link" without the hyperlink itself.
I couldn't actually Select the cell, then copy and paste it.
Sheet 1
Sheet 2
I tried but don't have any idea how. As long when I choose what's selected on Sheet2 State (e.g Sheet2 Cell D2 - Alabama), the corresponding Form Link (e.g Sheet1 Cell B3 - Link) will be selected and copied through the Macro.
Sub test2()
Dim link As Range
Set link = Range("INDEX(Sheet1!B:B,MATCH(Sheet2State,Sheet1State,0),0)))")
Set s1 = Range("D5")
link.Copy
s1.PasteSpecial
End Sub
I have a column of data. I want to select the cells that contain a hyperlink and print just the values of those cells.
I have the following code to extract the hyperlink. I want if there is a link in cell A1 called "hello", it doesn't print the link itself, but prints "hello".
Sub ExtractHL()
Dim HL As Hyperlink
For Each HL In ActiveSheet.Hyperlinks
HL.Range.Offset(0, 1).Value = HL.Address
Next
End Sub
The other idea I just had was to say that if a cell in a row DOESN'T contain a hyperlink, then to delete that row, but I'm not sure how to negate the "for each HL in sheet" line.
Changing the "HL.Address" to HL.Range pastes that range.
I have a document that needs to generate a hyperlink to a cell in the same workbook by getting the address from another cell. Here's what I have right now:
=hyperlink(CELL("address",INDEX('Budget Record'!C3:C105,MATCH(Y73,'Budget Record'!C3:C105,0),1)))
This displays the appropriate location:
'[Calendar Budget.xlsx]Budget Record'!$C$3
However, when clicked, it says that Excel cannot open the specified file.
I have tried manually creating a hyperlink to that value, and it still doesn't appear to work:
=hyperlink('[Calendar Budget.xlsx]Budget Record'!$C$3)
However, if I plug that into the goto dialogue box, it has no problems with it.
Am I missing an extra step?
After looking into all of the built-in hyperlink options that Excel offers, I could not find a way to have Excel link you to a dynamic/ changing cell reference. Naturally, I turned to VBA :)... this is a very simple macro with only a few lines of code. Give it try:
Press Alt + 11 to open the Visual Basic Editor (VBE)
If your project explorer is not already open, click this icon:
Double click the worksheet tab that you want the hyperlink to work on:
Paste the following code into the white space:
Private Sub Worksheet_SelectionChange(ByVal Target As Range)
'check if user is selecting the 'hyperlink' cell
If Target.Address = "$A$1" Then
'run the 'selectCell()' subroutine
Call selectCell
End If
End Sub
Sub selectCell()
Dim goToAddress As String
'get cell address
goToAddress = Range("A2").Value
'send user to this cell
Range(goToAddress).Select
End Sub
Go to your worksheet and test the script by typing G3 in cell B1.
Select cell A1. The macro should have automatically selected cell G3.
Hope this helps!
(Posted on behalf of the OP).
I have identified a solution. Basically it looks like the problem was in the formatting.
Basically I needed three steps. The first one is getting the location of the cell returned as a full address (including the file, sheet, and Cell). I do that with this:
=CELL("address",INDEX('Budget Record'!C3:C105,MATCH(Y73,'Budget Record'!C3:C105,0),1))
Here's a sample of what that results in:
'[Calendar Budget.xlsx]Budget Record'!$C$3
The problem with this is that the apostrophe at the beginning is in the wrong spot. To work as a hyperlink, the string should be this:
[Calendar Budget.xlsx]'Budget Record'!$C$3
So, I have a step where I remove the first 22 characters of the starting string:
=RIGHT(Z73,LEN(Z73)-23)
This results in the following:
Budget Record'!$C$3
Next, I need to add on this to the start of the string:
[Calendar Budget.xlsx]'
I do that with the following:
=HYPERLINK("[Calendar Budget.xlsx]'"&AA73)
The resulting output looks like this:
[Calendar Budget.xlsx]'Budget Record'!$C$3
So, we have a hyperlink to a cell in another sheet that dynamically changes depending on the initial referenced cell.
How should I search a string in a column and then select that cell using button click event?
Just do a for each loop through the range you want to look in. Once you find the cell whose value = search value use ".select" and Exit Sub.
I need to copy a column that has linked text and paste a column that shows all the URL’s for the linked text
Function GetURL(rng As Range) As String
On Error Resume Next
GetURL = rng.Hyperlinks(1).Address
End Function
In this case you can place it where you want. If you want, for example, the URL from a hyperlink in A1 to be listed in cell C25, then in cell C25 you would enter the following formula:
=GetURL(A1)
This post discusses extracting the URL from a cell with a link in it using a custom formula.
This immediately does the job, and add a separate url link column next to the column with the hyperlinked text:
https://howtouseexcel.net/how-to-extract-a-url-from-a-hyperlink-on-excel
Extracting a URL from a hyperlink on Excel -- this worked for me!
If you want to run this operation one time
Open up a new workbook.
Get into VBA (Press Alt+F11)
Insert a new module (Insert > Module)
Copy and Paste the Excel user defined function below (customized function):
Sub ExtractHL()
Dim HL As Hyperlink
For Each HL In ActiveSheet.Hyperlinks
HL.Range.Offset(0, 1).Value = HL.Address
Next
End Sub
Press F5 and click “Run”
Get out of VBA (Press Alt+Q)
You will see a new column with a list of url added to the right.