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I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)
I am trying to create a formula that gives me the average of the last 12 entries in a given dataset depending on the associated vector.
Let's make an example:
I have in column F2,G2,H2 and I2 dates, Company1, Company2 and Company3 respectively. Then from row3 to row 33 I have months dates starting from May 2016.
Date Company1 Company2 Company3
May-16 2,453,845
Jun-16 13,099,823
Jul-16 14,159,037
Aug-16 38,589,050 8,866,101
Sep-16 63,290,285 13,242,522
Oct-16 94,005,364 14,841,793
Nov-16 123,774,792 7,903,600 41,489,883
Dec-16 93,355,037 12,449,604 69,117,105
Jan-17 47,869,982 13,830,712 83,913,764
Feb-17 77,109,905 10,361,555 68,176,643
The goal is to create a formula that, when I drag it down, correctly calculates the average of the last 12 values for a given company.
So for example i would have, say in table "B2:C5":
Company1 76,856,345
Company2 11,120,859
Company3 65,674,349
And, if a new Company4 is added to the list, then I just have to drag it down the formula, to calculate the average of the last 12 months for Company4.
Until now, I have came up with this formula:
=AVERAGE(LOOKUP(LARGE(IF(ISNUMBER(G:G),ROW(G:G)),ROW(INDIRECT("1:"&MIN(12,COUNT(G:G))))),ROW(G:G),G:G ))
This formula correctly calculates the average of a given column, considering only the last 12 values. The last step would be to come up with a formula that includes all the columns and then calculates the average for the given company.
Thanks!
I recommend that you use a named range to define your data in columns G:I. When a company is added, just modify the named range's specs. I used the name Target. Of course, you can replace it with $G:$I if you feel so inclined but I would rather recommend reducing the number of rows in the range, which is easier to manage when it is named.
Use the formula below to extract the company names from the first row of Target into the first column of your averages table. This is to ensure that the names are spelled identically in both locations.
=INDEX(Target,1,ROW()-2)
The number 2 indicates the number of rows above the row containing the formula. it is copied here from cell M3. There, ROW()-2 creates the number 1, counting sequentially as the formula is copied down.
Now I have the formula below in my cell N3 and copied down.
=SUM(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0)))
The formula simply sums up the columns G, H, and I in 3 consecutive rows.
In the final step I inserted the range definition established above, meaning excluding the SUM() function, into your existing formula.
=AVERAGE(LOOKUP(LARGE(IF(ISNUMBER(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))),ROW(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0)))),ROW(INDIRECT("1:"&MIN(12,COUNT(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))))))),ROW(INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))),INDEX(Target,0,MATCH($M3,INDEX(Target,1,0),0))))
I have simple problem, but I've not be able to get an answer from searching. I require a column to calculate the number of the nth occurrence of a value. It's best explained in this picture
I require a method to calculate column B.
I'd be very grateful for any help.
Are you looking to merely provide a count of the distinct entries of column A in column B? Or merely add a formula to come up with the table in your link?
If the latter, then the formula to write in cell B2 is:
=COUNTIF(A$2:A2,A2)
then copy/paste it down column B. Note - if your data is both a Date and Time, but the cell is formatted to only display a date, you may not get the results you want. You'd need to interject a new column with a "floor" calculation to round the date/time value to a date (Excel date times are decimal, with integer part dictating the date, and remaining 0.0 -> 1.0 dictating the time of day)
If you just want to derive a table of the counts of distinct entries in column A, then a pivot table will do this for you - simple add a pivot table to cover the data in column A, then select column A into the rows category, and then also drag it into the values category, ensuring the field is set to "Count of". You should then have a table with the distinct entries in your data set in one column, and the count of their occurrences in the other column.
You can use the COUNTIF worksheet function, with a relative address.
Eg. In cell B2, enter this formula:
=COUNTIF(A$2:A2,A2)
And then fill-down.
Use the following formula to generate the required series:
=COUNTIF($A$1:A1,A1) and strech(copy) it in all the cells
This will generate result like this:
A 1 COUNTIF($A$1:A1,A1)
A 2 COUNTIF($A$1:A2,A2)
C 1 COUNTIF($A$1:A3,A3)
C 2 COUNTIF($A$1:A4,A4)
B 1 COUNTIF($A$1:A5,A5)
B 2 COUNTIF($A$1:A6,A6)
A 3 COUNTIF($A$1:A7,A7)
C 3 COUNTIF($A$1:A8,A8)
D 1 COUNTIF($A$1:A9,A9)
D 2 COUNTIF($A$1:A10,A10)
D 3 COUNTIF($A$1:A11,A11)
D 4 COUNTIF($A$1:A12,A12)
For example, I need to create a merit list of few student based on total marks (column C), then higher marks in math (column B) -
A B C D
-------------------------
Student1 80 220 1
Student2 88 180 3
Student3 90 180 2
Expected merit position is given in column D.
I can use RANK function but I can only do that for one column (total number). If total number of multiple student is equal, I could not find any solution of this.
You can try this one in D1
=COUNTIF($C$1:$C$99,">"&C1)+1+SUMPRODUCT(--($C$1:$C$99=C1),--($B$1:$B$99>B1))
and then copy/fill down.
let me know if this helps.
Explanation
Your first criteria sits in column C, and the second criteria sits in Column B.
Basically, first it is counting the number of entries ($C$1:$C$99) that are bigger than the entry itself ($C1). For the first one in the ranking, you will get zero, therefore you need to add 1 to each result (+1).
Until here, you will get duplicate rankings if you have the same value twice. Therefore you need to add another argument to do some extra calculations based on the second criteria:
To resolve the tie situation, you need to sumproduct two array formulas and add the result to the previous argument, the goal is to find the number of entries that are equal to this entry with $C$1:$C$99=C1 and have a bigger value in the second criteria column $B$1:$B$99>B1:
you add -- to convert TRUE and FALSE to 0s and 1s so that you can multiply them:
SUMPRODUCT(--($C$1:$C$99=C1),--($B$1:$B$99>B1))
the first array is to see how many ties you have in the first criteria. And the second array is to find the number of bigger values than the entry itself.
Note you can add as many entries as you like to your columns, but remember to update the ranges in the formula, currently it is set to 99, you can extend it to as many rows as you want.
Sometimes a helper column will provide a quick and calculation-efficient solution. Adding the math marks to the total marks as a decimal should produce a number that will rank according to your criteria. In an unused column to the right, use this formula in row 2,
=C2+B2/1000
Fill down as necessary. You can now use a conventional RANK function on this helper column like =RANK(D2, D$2:D$9) for your ranking ordinals.
Very simple (or, at least, much more simpler that the one provided by the best answer) 'math' solution: do a linear combination with weights.
Do something like
weighted_marks = 10*colC + colB
then sort weighted marks using simple rank function.
It does solve your problem, bulding the ranking you need.
If you don't like to limit the number of rows or the numbers used in the criteria, Jeeped's approach can be extended. You can use the following formulas in cells D2 to L2, assuming that there are three criteria, the first one in column A, the second one in column B, and the third one in column C:
=RANK($A2,$A:$A,1)
=RANK($B2,$B:$B,1)
=D2*2^27+E2
=RANK(F2,F:F,1)
=RANK($C2,$C:$C,1)
=G2*2^27+H2
=RANK(I2,I:I,1)
=J2*2^27-ROW()
=RANK(K2,K:K,0)
The formulas have to be copied down. The result is in column L. Ties are broken using the row number.
If you like to add a fourth criterion, you can do the following after having the formulas above in place:
Add the new criterion between columns C and D.
Insert three new columns between columns I and J.
Copy columns G:I to the new columns J:L.
Copy column G to column M, overwriting its content.
Change the formula in column L to point to the new criterion.
The factor 2^27 used in the formulas balances the precision of 53 bits available in double-precision numbers. This is enough to cover the row limit of current versions of Excel.
I have an excel sheet containing two columns of data that I'd like to rank.
Suppose we have the following:
A B
Franz 58
Daniel 92
Markus 37
Jörg 58
I would like a formula to rank the above data based on column B, and where there are duplicate values (Franz and Jörg) to put the alphabetical name first. What I have at the moment is simply duplicating Franz twice:
=INDEX(Name,MATCH(A2,Points,0))
Can someone advise me of formula / code that will rank the data and arrange duplicate values alphabetically?
Thanks
I would add a helper column in next to your data to help out with ties.
so in column C use
=B1+1/COUNTIF($A$1:$A$4,"<="&A1)/10
This will add on a decimal ranking system based on the name. This assumes that your numbers in column B do not have decimal places, if they do then you will need to increase the 10 on the end of the formula to account for it ie: for 2 decimal places use 1000, 3 : 10000 etc
Use this formula to get the first name
=INDEX(name,MATCH(LARGE(points,1),points,0))
adjust the 1 to 2 for the second name etc
EDIT had the sign around the wrong way
This will rank your data and will not repeat duplicates too:
In C2:
=SUM(1*(b2>$b$2:$b$5))+1+IF(ROW(b2)-ROW($b$2)=0,0,SUM(1*(b2=OFFSET($b$2,0,0,INDEX(ROW(b2)-ROW($b$2)+1,1)-1,1))))
CTRL+SHIFT+ENTER to turn it into an array
Drag these down to C5 and it will not duplicate rank where the name is the same, it will rank them alphabetically if they are the same.
Then if you wanted to order them automatically in order of top performer/score you then do this:
Putting this in E2:
=INDEX(A2:A5,MATCH(LARGE(C2:C5,ROW()-1),C2:C5,0))
...and drag down
Then use a vlookup on your data to return the score putting this in F2:
=vlookup(E2,A2:C5,2,false)
...and drag down
This should give you a table of highest scoring people in score order.
Assuming A2 is the first of the ranked points scores try this version
=INDEX(Name,SMALL(IF(A2=Points,ROW(Points)-MIN(ROW(Points))+1),COUNTIF(A$2:A2,A2)))
confirmed with CTRL+SHIFT+ENTER and copied down
Requires the Name list to be sorted because names with duplicate scores will be listed in the order shown