I am trying to convert the string below into a datetime object using datetime.strptime, and I just can't seem to figure out .746Z at the end.
datetime_str = '2022-04-21T08:17:49.746Z'
datetime_object = datetime.strptime(datetime_str, '%Y-%m-%dT%H:%M:%S.%z')
print(datetime_object)
Related
How to remove the time from the csv file in python
I have a csv file in this format: "SSP_Ac_INVOICE_DISTRIBUTIONS_17022023072701.csv"
I am trying to remove the time which is after2023.my expectation was SSP_Ac_INVOICE_DISTRIBUTIONS_17022023.csv
I tried to use strptime but getting below error:
s = "SSP_AP_INVOICE_DISTRIBUTIONS_17022023072701.csv"
temp = dt.datetime.strptime(SSP_AP_INVOICE_DISTRIBUTIONS_17022023072701, '%d%m%Y')
final = temp.strftime('%d-%m-%Y')
print(final)
In the strptime function, you are passing the string 'SSP_AP_INVOICE_DISTRIBUTIONS_17022023072701.csv' instead of the variable s. Also, you are using the wrong format string in strptime. Since the date string in your filename is in the format %d%m%Y%H%M%S, you need to include %H%M%S in the format string to parse the time as well.
The code should look something like this:
import datetime as dt
filename = "SSP_AP_INVOICE_DISTRIBUTIONS_17022023072701.csv"
# Parse the date from the filename
date_str = filename.split('_')[3]
date = dt.datetime.strptime(date_str, '%d%m%Y%H%M%S')
# Format the date as required
new_filename = f"{filename.split('_')[0]}_{filename.split('_')[1]}_{filename.split('_')[2]}_{date.strftime('%d%m%Y')}.csv"
print(new_filename)
This code first splits the filename by the underscore character to extract the date string, and then uses strptime to parse the date and time. Finally, it formats the new filename using the date and the other parts of the original filename that were not changed.
I have a Date time string 2021-12-12T11:11:00. I want to remove the substring T11:11:00, so that I am left with 2021-12-12.
Does anyone have any ideas? Please help me.
import 'package:intl/intl.dart'; //note --->>> import package
DateTime parsedDateTime = DateTime.parse('2021-12-12T11:11:00');
String formatDate = DateFormat("yyyy-MM-dd").format(parsedDateTime);
OUTPUT ->
2021-12-12
String _date_and_time = "2021-12-12T11:11:00";
String date = _date_and_time.split("T")[0];
print("Date is : ${date}");
I am facing issues with a U SQL script. I am trying to get files which were created on current day from a directory. the file name will have the date in yyyyMMdd format. But when i try to extract data instead of taking only one days files i am getting all the files inside the directory. I am using the below script.
DECLARE #file_set_path string ="/XXXX/Sample_{date:yyyy}{date:MM}{date:dd}{*}.csv";
#searchlog =
EXTRACT PART_NUMBER string, date DateTime FROM #file_set_path USING Extractors.Tsv(skipFirstNRows:1);
Can someone please help me on this.
You can use the Date property of the DateTime object to compare dates without including the time component, something like this:
DECLARE #file_set_path string ="/Sample_{date:yyyy}{date:MM}{date:dd}{*}.csv";
DECLARE #now DateTime = DateTime.Now;
#searchlog =
EXTRACT PART_NUMBER string,
date DateTime
FROM #file_set_path
USING Extractors.Csv(skipFirstNRows : 1);
#output =
SELECT *,
#now AS now,
date.Date AS x,
#now.Date AS y
FROM #searchlog
WHERE date.Date == #now.Date;
OUTPUT #output
TO "/output/output.csv"
USING Outputters.Csv();
NB I noticed you are using the Tsv extractor with Csv files. It may not matter when there is only one column or possibly this is a typo?
I need to convert a date/time string to UNIX timestamp including the milliseconds. As the timetuple() does not include milli or microseconds I made a short workaround. But I was wondering, is there a better/nicer way to do this?
import datetime as dt
import time
timestamp = '2018-01-19 10:00:00.019' # example of input time string
tmp = timestamp.split('.')
millisec = tmp[-1] # extracting only milli-seconds
UX_time = time.mktime(dt.datetime.strptime(tmp[0], '%Y-%m-%d %H:%M:%S').timetuple()) + float(millisec)/1e3
print(UX_time)
1516352400.019
I realize my timezone is off by one hour, so you might be getting
print(UX_time)
1516356000.019
you can try this:
timestamp = '2018-01-19 10:00:00.019'
tmp=np.datetime64(timestamp)
print(tmp.view('<i8')/1e3)
output:
1516352400.019
Also possible with your current code:
import datetime as dt
import time
timestamp = '2018-01-19 10:00:00.019' # example of input time string
ts = dt.datetime.strptime(timestamp, '%Y-%m-%d %H:%M:%S.%f')
UX_time = time.mktime(ts.timetuple()) + ts.microsecond/1e6
print "%.3f" %UX_time
So I am trying to scrap a website containing price of a laptop.However it is a srting and for comparison purposes I need to convert it to int.But on using the same I get a none type error: invalid literal for int() with base 10: '56,990'
Below is the code:
from bs4 import BeautifulSoup
import requests
r = requests.get("https://www.flipkart.com/apple-macbook-air-core-i5-5th-gen-8-gb-128-gb-ssd-mac-os-sierra-mqd32hn-a-a1466/p/itmevcpqqhf6azn3?pid=COMEVCPQBXBDFJ8C&srno=s_1_1&otracker=search&lid=LSTCOMEVCPQBXBDFJ8C5XWYJP&fm=SEARCH&iid=2899998f-8606-4b81-a303-46fd62a7882b.COMEVCPQBXBDFJ8C.SEARCH&qH=9e3635d7234e9051")
data = r.text
soup = BeautifulSoup(data,"lxml")
data=soup.find('div',{"class":"_1vC4OE _37U4_g"})
cost=(data.text[1:].strip())
print(int(cost))
PS:I used text[1:] toremove the currency character
I get error in the last line.Basically I need to get the int value of the cost.
The value has a comma in it. So you need to replace the comma with empty character before converting it to integer.
print(int(cost.replace(',','')))
python does not understand , group separators in integers, so you'll need to remove them. Try:
cost = data.text[1:].strip().translate(None,',')
Rather than invent a new solution for every character you don't want (strip() function for whitespace, [1:] index for the currency, something else for the digit separator) consider a single solution to gather what you do want:
>>> import re
>>> text = "\u20B956,990\n"
>>> cost = re.sub(r"\D", "", text)
>>> print(int(cost))
56990
The re.sub() replaces anything that isn't a digit with nothing.