20/11/2022 12:00:52 2 X 15.95 15.95 USD 57 5 689 5 689 1 4111 0 Amazing Lego Team
I need to get the position of No 4111 in the above text string, As an excel beginner any help will be greatly appreciated. Thanks.
All of the Text Strings will have a 4 digit number like 4111 which i have to get the position for.
Have tried using this formula to get four digit number in another column, LOOKUP(10^15,MID(A1,ROW(INDIRECT("1:"&LEN(A1))),5)+0) but I am looking to get position instead.
I have tried using lookup but I could only go so far as a beginner.
Use the formula you provided =LOOKUP(10^15,MID(A1,ROW(INDIRECT("1:"&LEN(A1))),5)+0) to identify the number, and use FIND to get the position of the number.
Cell A1="20/11/2022 12:00:52 2 X 15.95 15.95 USD 57 5 689 5 689 1 4111 0 Amazing Lego Team"
=FIND(LOOKUP(10^15,MID(A1,ROW(INDIRECT("1:"&LEN(A1))),5)+0),A1)
=58
This looks to be in a space (or some other character) delimited text string. If you have a bunch of rows of data like this, use the Text to Columns feature on the Data tab. Use the Delimited option and then click the check box next to space (or other if it's something custom not in the available options) and Excel will split the data into columns for you.
For your string example, if you know that your 4 digit is started 58 char from the beginning of the string, use =MID(A1,58,4) A1 is the cell with your string.
MID function returns a specific number of characters from a text string, starting at the position you specify, based on the number of characters you specify.
=LET(t,TEXTSPLIT(A1,," "),
FIND(FILTER(t,(LEN(t)=4)*(ISNUMBER(--(t)))),A1))
It splits the string at every space and filters the result for being of length of 4 characters and not being an error if converted to number.
Related
20/11/2022 12:00:52 2 X 15.95 15.95 USD 57 5 689 5 689 1 4111 0 Amazing Lego Team
I need to get the position of No 4111 in the above text string, As an excel beginner any help will be greatly appreciated. Thanks.
All of the Text Strings will have a 4 digit number like 4111 which i have to get the position for.
Have tried using this formula to get four digit number in another column, LOOKUP(10^15,MID(A1,ROW(INDIRECT("1:"&LEN(A1))),5)+0) but I am looking to get position instead.
I have tried using lookup but I could only go so far as a beginner.
Use the formula you provided =LOOKUP(10^15,MID(A1,ROW(INDIRECT("1:"&LEN(A1))),5)+0) to identify the number, and use FIND to get the position of the number.
Cell A1="20/11/2022 12:00:52 2 X 15.95 15.95 USD 57 5 689 5 689 1 4111 0 Amazing Lego Team"
=FIND(LOOKUP(10^15,MID(A1,ROW(INDIRECT("1:"&LEN(A1))),5)+0),A1)
=58
This looks to be in a space (or some other character) delimited text string. If you have a bunch of rows of data like this, use the Text to Columns feature on the Data tab. Use the Delimited option and then click the check box next to space (or other if it's something custom not in the available options) and Excel will split the data into columns for you.
For your string example, if you know that your 4 digit is started 58 char from the beginning of the string, use =MID(A1,58,4) A1 is the cell with your string.
MID function returns a specific number of characters from a text string, starting at the position you specify, based on the number of characters you specify.
=LET(t,TEXTSPLIT(A1,," "),
FIND(FILTER(t,(LEN(t)=4)*(ISNUMBER(--(t)))),A1))
It splits the string at every space and filters the result for being of length of 4 characters and not being an error if converted to number.
I have to calculate a price by single character. In my example I have 110 parts that are numbered, so this means I have:
9 parts with one character (1 > 9)
90 parts with two characters (10 > 99)
11 parts with three characters (100 > 110)
Thus there are 222 characters for this price.
Is there a way to calculate this with a (nested) formula ? I've been thinking about since a few days and can't come with a solid & modular formula.
See "manual"-Excel calculation here below.
Thanks for your help.
Do you mean:
=SUM(LEN(SEQUENCE(110)))
Or for non-Microsoft 365 versions:
=SUMPRODUCT(LEN(ROW(A1:INDEX(A:A,110))))
If you want to calculate the number of characters of a list of values that is not a continuous sequence starting with 1 up to e.g. 110, then you can do it with the following formula:
=SUM(COUNTIFS(list,">=1",list,"<=9")*1,COUNTIFS(list,">=10",list,"<=99")*2,COUNTIFS(list,">=100",list,"<=999")*3)
Note: the term "list" is just a name that refers to a range of Excel cells.
I have a series of values such as:
10RP
2.5R
5R
7.5R
10R
2.5YR
5YR
I want to convert the string portion to a number based on this table:
0 R
10 YR
20 Y
30 GY
40 G
50 BG
60 B
70 PB
80 P
90 RP
I then want to create two columns so that:
2.5YR
becomes:
2.5 10
In a third column I will add the two numbers together.
Can this be done just using formulas? I want to avoid using VBA if I can.
Thanks.
Here's another approach.
seq is a defined name referring to an array constant ={1,2,3,4,5}
If you might have numbers that encompass more than five characters, just extend the constant appropriately.
Number part: =LOOKUP(9E+307,--MID(A1,1,seq))
Letter portion converted to number:
=VLOOKUP(MID(A1,LOOKUP(2,1/ISNUMBER(-MID(A1,1,seq)),seq)+1,9),$F$1:$G$10,2,FALSE)
Where your table is in F1:G10 and reversed so that the letters are in the first column
This might not be the most efficient but should work
=IFERROR((LEFT(F3,LEN(F3)-2)+VLOOKUP(RIGHT(F3,2),$A$3:$B$12,2,0)),
(LEFT(F3,LEN(F3)-1)+VLOOKUP(RIGHT(F3,1),$A$3:$B$12,2,0)))
Where your lookup table is A3:B12 with the letters in the left-most column
Check for the two-letter combinations before the single-letter ones.
I have a data extract that resulted in fields being combined into column A like this:
Sales Figures Report pg 121
Walmart Inc. 001230134 99 Associates Parkway 56.12 20.00 10.00 86.12 00 1
1400.25 262.40 14.50 1677.15 02 9
50.00 100.25 10.00 160.25 00 1
1400.25 262.40 14.50 1677.15 02 9
There are over 50,000 rows in this sort of format, some are a little different as they'll start with vendor information and then have those values after (still all in col. A). In the above example 1677.15 is the combined value of the three numbers before that, i.e. the total amount due.
Originally I wanted to basically separate out each value using things like left(), mid(), right() etc. however at this point all I want is the total figure, i.e. the $1677.15 in the above example. What is the best non-vba method of doing this?
Two issues:
The problem is that the amounts are not always the same number of digits (can range from $xx.xx to $xxx,xxx.xx)
Since There are multiple "." you can't use search() to find the correct character location.
In your example, the Total figure is always the third group from the end. That being the case, you can use the following formula and defined names:
=IFERROR(--INDEX(TRIM(MID(SUBSTITUTE(A1," ",REPT(" ",99)),seq_99,99)),LEN(A1)-LEN(SUBSTITUTE(A1," ",""))-1),"")
Defined Names
seq refers to: =ROW(INDEX($1:$65535,1,1):INDEX($1:$65535,255,1))
seq_99 refers to: =IF(seq=1,1,(seq-1)*99)
In the formula,
SUBSTITUTE: Replace all spaces with a large number (99) of spaces
MID Return an array consisting of each word (space separated)
TRIM the words to remove the extra spaces
INDEX Return the item that is third from the end.
IFERROR handle lines such as your first, which does not contain the relevant pattern.
seq and seq_99 return arrays of {1,2,3,...}and{1,99,198,...}` to be used in the formulas
I have column which consists of text including 13 digit number. How Can I keep 10 digit number and delete all other text?
Please help me I am new to excel..
thanks in advance
Edited:
Cell Format
[6/11/2013 3:26:37 PM] 1234503776599, ksdfl 038ddf63Ksdf)
[6/12/2013 3:26:37 PM] 0234503664599, ksdfadssdfl 038ddf6dfsd3Ksdf)
[6/13/2013 3:26:37 PM] 7234503666099, 45sdsdfadssdfl 03845ddf6dfsd3Ksdf)
Here, In second column I want to keep 13 digit and delete all text after that 13 digit.
Is the number always at the beginning of the cell? If so you can use =LEFT(cell_ref, 10) to extract the first 10 characters, which in this case are numbers and will be treated as such by the spreadsheet.
I'm guessing you will need something like this
=MID(A1,32,FIND(",",A1,32) -32)
MID will get text from the middle of a string
FIND will get the location of the first comma
Thinking that the 13 digit number is in the middle of the string, with 9 spaces to the left and a comma to the right we can use the following formula in a separate cell:
=MID(A1,LEN(LEFT(A1,FIND("]",A1)+1))+9,13)
The LEN function determines the length of the part up to and including ] (big bracket). Then the number 9 is added to include nine spaces. Then the number 13 is the length of the 13 digit number. All these are used as parameters for the MID function.
After you get the result just drag down using the autofill handle to get the mid 13 digit number for all the rows.
=LOOKUP(10^11,MID(A1,ROW(INDIRECT("1:"&LEN(A1)-9)),11)+0)
This works for me.
To extract 6 continuous numeric digits, use the below code:
=LOOKUP(10^6,MID(A1,ROW(INDIRECT("1:"&LEN(A1)-5)),6)+0)
Replace 6 in the above code with the number of digits that are required to be extracted.