I know there's a way to configure a Spark Application based in your cluster resources ("Executor memory" and "number of Executor" and "executor cores") I'm wondering if exist a way to do it considering the data input size?
What would happen if data input size does not fit into all partitions?
Example:
Data input size = 200GB
Number of partitions in cluster = 100
Size of partitions = 128MB
Total size that partitions could handle = 100 * 128MB = 128GB
What about the rest of the data (72GB)?
I guess Spark will wait to have free the resources free due to is designed to process batches of data Is this a correct assumption?
Thank in advance
I recommend for best performance, don't set spark.executor.cores. You want one executor per worker. Also, use ~70% of the executor memory in spark.executor.memory. Finally- if you want real-time application statistics to influence the number of partitions, use Spark 3, since it will come with Adaptive Query Execution (AQE). With AQE, Spark will dynamically coalesce shuffle partitions. SO you set it to an arbitrarily-large number of partitions, such as:
spark.sql.shuffle.partitions=<number of cores * 50>
Then just let AQE do its thing. You can read more about it here:
https://www.databricks.com/blog/2020/05/29/adaptive-query-execution-speeding-up-spark-sql-at-runtime.html
There are 2 aspects to your question. The first is regarding storage of this data, & the second is regarding data execution.
With regards to storage, when you say Size of partitions = 128MB, I assume you use HDFS to store this data & 128M is your default block size. HDFS itself internally decides how to split this 200GB file & store in chunks not exceeding 128M. And your HDFS cluster should have more than 200GB * replication factor of combined storage to persist this data.
Coming to the Spark execution part of the question, once you define spark.default.parallelism=100, it means that Spark will use this value as the default level of parallelism while performing certain operations (like join etc). Please note that the amount of data being processed by each executor is not affected by the block size (128M) in any way. Which means each executor task will work on 200G/100 = 2G of data (provided the executor memory is sufficient for the required operation being performed). In case there isn't enough capacity in the spark cluster to run 100 executors in parallel, then it will launch as many executors it can in batches as and when resources are available.
Related
I have 20TB file and I want to repartition it in spark with each partition = 128MB.
But after calculating n=20TB/128mb= 156250 partitions.
I believe 156250 is a very big number for
df.repartition(156250)
how should I approach repartitiong in this?
or should I increase the block size from 128mb to let's say 128gb.
but 128 gb per task will explode executor.
Please help me with this.
Divide and conquer it. You don’t need to load all the dataset in one place cause it would cost you huge amount resources and also network pressure because of shuffle exchanging.
The block size that you are referring to here is an HDFS concept related to storing the data by breaking it into chunks (say 128M default) & replicating thereafter for fault tolerance. In case you are storing your 20TB file on HDFS, it will automatically be broken into 20TB/128mb=156250 chunks for storage.
Coming to the Spark dataframe repartition, firstly it is a tranformation rather than an action (more information on the differences between the two: https://spark.apache.org/docs/latest/rdd-programming-guide.html#rdd-operations). Which means merely calling this function on the dataframe does nothing unless the dataframe is eventually used in some action.
Further, the repartition value allows you to define the parallelism level of your operation involving the dataframe & should mostly be though upon in those terms rather than the amount of data being processed per executor. The aim should be to maximize parallelism as per the available resources rather than trying to process certain amount of data per executor. The only exception to this rule should be in cases where the executor either needs to persist all this data in memory or collect some information from this data which is proportional to the data size being processed. And the same applies to any executor task running on 128GB of data.
If i have cluster of 5 nodes, each node having 1gb ram, now if my data file is 10gb distributed in all 5 nodes, let say 2gb in each node, now if i trigger
val rdd = sc.textFile("filepath")
rdd.collect
will spark load data into the ram and how spark will deal with this scenario
will it straight away deny or will it process it.
Lets understand the question first #intellect_dp you are asking, you have a cluster of 5 nodes (here the term "node" I am assuming machine which generally includes hard disk,RAM, 4 core cpu etc.), now each node having 1 GB of RAM and you have 10 GB of data file which is distributed in a manner, that 2GB of data is residing in the hard disk of each node. Here lets assume that you are using HDFS and now your block size at each node is 2GB.
now lets break this :
each block size = 2GB
RAM size of each node = 1GB
Due to lazy evaluation in spark, only when "Action API" get triggered, then only it will load your data into the RAM and execute it further.
here you are saying that you are using "collect" as an action api. Now the problem here is that RAM size is less than your block size, and if you process it with all default configuration (1 block = 1 partition ) of spark and considering that no further node will going to add up, then in that case it will give you out of memory exception.
now the question - is there any way spark can handle this kind of large data with the given kind of hardware provisioning?
Ans - yes, first you need to set default minimum partition :
val rdd = sc.textFile("filepath",n)
here n will be my default minimum partition of block, now as we have only 1gb of RAM, so we need to keep it less than 1gb, so let say we take n = 4,
now as your block size is 2gb and minimum partition of block is 4 :
each partition size will be = 2GB/4 = 500mb;
now spark will process this 500mb first and will convert it into RDD, when next chunk of 500mb will come, the first rdd will get spill to hard disk (given that you have set the storage level "MEMORY_AND_DISK_ONLY").
In this way it will process your whole 10 GB of data file with the given cluster hardware configuration.
Now I personally will not recommend the given hardware provisioning for such case,
as it will definitely process the data, but there are few disadvantages :
firstly it will involve multiple I/O operation making whole process very slow.
secondly if any lag occurs in reading or writing to the hard disk, your whole job will get discarded, you will go frustrated with such hardware configuration. In addition to it you will never be sure that will spark process your data and will be able to give result when data will increase.
So try to keep very less I/O operation, and
Utilize in memory computation power of spark with an adition of few more resources for faster performance.
When you use collect all the data send is collected as array only in driver node.
From this point distribution spark and other nodes does't play part. You can think of it as a pure java application on a single machine.
You can determine driver's memory with spark.driver.memory and ask for 10G.
From this moment if you will not have enough memory for the array you will probably get OutOfMemory exception.
In the otherhand if we do so, Performance will be impacted, we will not get the speed we want.
Also Spark store only results in RDD, so I can say result would not be complete data, any worst case if we are doing select * from tablename, it will give data in chunks , what it can affroad....
I have a Spark SQL that used to execute < 10 mins now running at 3 hours after a cluster migration and need to deep dive on what it's actually doing. I'm new to spark and please don't mind if I'm asking something unrelated.
Increased spark.executor.memory but no luck.
Env: Azure HDInsight Spark 2.4 on Azure Storage
SQL: Read and Join some data and finally write result to a Hive metastore.
The spark.sql script ends with below code:
.write.mode("overwrite").saveAsTable("default.mikemiketable")
Application Behavior:
Within the first 15 mins, it loads and complete most tasks (199/200); left only 1 executor process alive and continually to shuffle read / write data. Because now it only leave 1 executor, we need to wait 3 hours until this application finish.
Left only 1 executor alive
Not sure what's the executor doing:
From time to time, we can tell the shuffle read increased:
Therefore I increased the spark.executor.memory to 20g, but nothing changed. From Ambari and YARN I can tell the cluster has many resources left.
Release of almost all executor
Any guidance is greatly appreciated.
I would like to start with some observations for your case:
From the tasks list you can see that that Shuffle Spill (Disk) and Shuffle Spill (Memory) have both very high values. The max block size for each partition during the exchange of data should not exceed 2GB therefore you should be aware to keep the size of shuffled data as low as possible. As rule of thumb you need to remember that the size of each partition should be ~200-500MB. For instance if the total data is 100GB you need at least 250-500 partitions to keep the partition size within the mentioned limits.
The co-existence of two previous it also means that the executor memory was not sufficient and Spark was forced to spill data to the disk.
The duration of the tasks is too high. A normal task should lasts between 50-200ms.
Too many killed executors is another sign which shows that you are facing OOM problems.
Locality is RACK_LOCAL which is considered one of the lowest values you can achieve within a cluster. Briefly, that means that the task is being executed in a different node than the data is stored.
As solution I would try the next few things:
Increase the number of partitions by using repartition() or via Spark settings with spark.sql.shuffle.partitions to a number that meets the requirements above i.e 1000 or more.
Change the way you store the data and introduce partitioned data i.e day/month/year using partitionBy
My use case is to merge two tables where one table contains 30 million records with 200 cols and another table contains 1 million records with 200 cols.I am using broadcast join for small table.I am loading both the tables as data-frames from hive managed tables on HDFS.
I need the values to set for driver memory and executor memory and other parameters along with it for this use case.
I have this hardware configurations for my yarn cluster :
Spark Version 2.0.0
Hdp version 2.5.3.0-37
1) yarn clients 20
2) Max. virtual cores allocated for a container (yarn.scheduler.maximum.allocation-vcores) 19
3) Max. Memory allocated for a yarn container 216gb
4) Cluster Memory Available 3.1 TB available
Any other info you need I can provide for this cluster.
I have to decrease the time to complete this process.
I have been using some configurations but I think its wrong, it took me 4.5 mins to complete it but I think spark has capability to decrease this time.
There are mainly two things to look at when you want to speed up your spark application.
Caching/persistance:
This is not a direct way to speed up the processing. This will be useful when you have multiple actions(reduce, join etc) and you want to avoid the re-computation of the RDDs in the case of failures and hence decrease the application run duration.
Increasing the parallelism:
This is the actual solution to speed up your Spark application. This can be achieved by increasing the number of partitions. Depending on the use case, you might have to increase the partitions
Whenever you create your dataframes/rdds: This is the better way to increase the partitions as you don't have to trigger a costly shuffle operation to increase the partitions.
By calling repartition: This will trigger a shuffle operation.
Note: Once you increase the number of partitions, then increase the executors(may be very large number of small containers with few vcores and few GBs of memory
Increasing the parallelism inside each executor
By adding more cores to each executor, you can increase the parallelism at the partition level. This will also speed up the processing.
To have a better understanding of configurations please refer this post
I have an Spark application that keeps running out of memory, the cluster has two nodes with around 30G of RAM, and the input data size is about few hundreds of GBs.
The application is a Spark SQL job, it reads data from HDFS and create a table and cache it, then do some Spark SQL queries and writes the result back to HDFS.
Initially I split the data into 64 partitions and I got OOM, then I was able to fix the memory issue by using 1024 partitions. But why using more partitions helped me solve the OOM issue?
The solution to big data is partition(divide and conquer). Since not all data could be fit into the memory, and it also could not be processed in a single machine.
Each partition could fit into memory and processed(map) in relative short time. After the data is processed for each partition. It need be merged (reduce). This is tradition map reduce
Splitting data to more partitions means that each partition getting smaller.
[Edit]
Spark using revolution concept called Resilient Distributed DataSet(RDD).
There are two types of operations, transformation and acton
Transformations are mapping from one RDD to another. It is lazy evaluated. Those RDD could be treated as intermediate result we don't wanna get.
Actions is used when you really want get the data. Those RDD/data could be treated as what we want it, like take top failing.
Spark will analysed all the operation and create a DAG(Directed Acyclic Graph) before execution.
Spark start compute from source RDD when actions are fired. Then forget it.
(source: cloudera.com)
I made a small screencast for a presentation on Youtube Spark Makes Big Data Sparking.
Spark's operators spill data to disk if it does not fit in memory,
allowing it to run well on any sized data". The issue with large
partitions generating OOM
Partitions determine the degree of parallelism. Apache Spark doc says that, the partitions size should be atleast equal to the number of cores in the cluster.
Less partitions results in
Less concurrency,
Increase memory pressure for transformation which involves shuffle
More susceptible for data skew.
Many partitions might also have negative impact
Too much time spent in scheduling multiple tasks
Storing your data on HDFS, it will be partitioned already in 64 MB or 128 MB blocks as per your HDFS configuration When reading HDFS files with spark, the number of DataFrame partitions df.rdd.getNumPartitions depends on following properties
spark.default.parallelism (Cores available for the application)
spark.sql.files.maxPartitionBytes (default 128MB)
spark.sql.files.openCostInBytes (default 4MB)
Links :
https://spark.apache.org/docs/latest/tuning.html
https://databricks.com/session/a-deeper-understanding-of-spark-internals
https://spark.apache.org/faq.html
During Spark Summit Aaron Davidson gave some tips about partitions tuning. He also defined a reasonable number of partitions resumed to below 3 points:
Commonly between 100 and 10000 partitions (note: two below points are more reliable because the "commonly" depends here on the sizes of dataset and the cluster)
lower bound = at least 2*the number of cores in the cluster
upper bound = task must finish within 100 ms
Rockie's answer is right, but he does't get the point of your question.
When you cache an RDD, all of his partitions are persisted (in term of storage level) - respecting spark.memory.fraction and spark.memory.storageFraction properties.
Besides that, in an certain moment Spark can automatically drop's out some partitions of memory (or you can do this manually for entire RDD with RDD.unpersist()), according with documentation.
Thus, as you have more partitions, Spark is storing fewer partitions in LRU so that they are not causing OOM (this may have negative impact too, like the need to re-cache partitions).
Another importante point is that when you write result back to HDFS using X partitions, then you have X tasks for all your data - take all the data size and divide by X, this is the memory for each task, that are executed on each (virtual) core. So, that's not difficult to see that X = 64 lead to OOM, but X = 1024 not.