I have several folders inside a directory called freesurfer like:
freesurfer/sub-001/mri
freesurfer/sub-001/label
freesurfer/sub-001/surf
freesurfer/sub-001/stats
freesurfer/sub-002/mri
freesurfer/sub-002/label
freesurfer/sub-002/surf
freesurfer/sub-002/stats
I would like to rename only 'stats' folder and move it to a different location:
freesurfer/sub-001/mri
freesurfer/sub-001/label
freesurfer/sub-001/surf
freesurfer/sub-001/sub-001_stats
freesurfer/sub-002/mri
freesurfer/sub-002/label
freesurfer/sub-002/surf
freesurfer/sub-002/sub-002_stats
I have managed to write the following code:
while read dir ; do
new_dir=$(rev <<< "$dir" | sed 's~/~_~' | rev);
echo "mv $dir $new_dir";
done < <(find . -type d -name 'stats')
The above code seems to be working fine when I run it with 'echo' before 'mv' command and appends the folder name in front of 'stats' directory but when I take the 'echo' off, it gives an error saying: "No such file or directory".
What am I doing wrong?
Your code to create new_dir isn't correct. It's creating freesurfer/sub-002_stats instead of freesurfer/sub-002/sub-002_stats. But this doesn't explain the error you're getting, since it will just rename the file incorrectly (moving all of them into the parent directory).
Try:
while read dir ; do
new_dir=$(dirname "$dir")/$(basename $(dirname "$dir"))_stats
mv "$dir" "$new_dir"
done < <(find . -type d -name 'stats')
Related
I have a directory with files in the following strcuture:
HomeTransaction1/Date1/transactionfile1.txt
HomeTransaction1/Date1/transactionfile1.xls
HomeTransaction1/Date1/transactionfile2.xls
HomeTransaction1/Date1/transactionfile2.txt
HomeTransaction1/Date1/transactionfile3.txt
HomeTransaction1/Date2/transactionfile1.txt
HomeTransaction1/Date3/transactionfile2.txt
HomeTransaction1/Date3/transactionfile3.txt
HomeTransaction2/Date1/transactionfile1.txt
HomeTransaction2/Date1/transactionfile2.txt
HomeTransaction3/Date1/transactionfile3.txt
I'm trying to get for a specific thing in the transaction files that end in .txt so I'm trying to come up with a bash script to achieve this. Conceptually, this is my thought process.
A - List each folder in the current directory. I this example, it'll be HomeTransaction1, HomeTransaction2 and HomeTransaction3
B - for each folder in B list all the folders(the Date folders)
C - for each folder in step B, run "grep " for files with .txt extension
This is what I have come up with so far:
#!/bin/bash
for FILE in `ls -l`
do
if test -d $FILE && (startswith "HomeTrasaction") //I want to add a condition to check that the directory name and starts with "HomeTrasaction"
then
cd $FILE // example cd to 'HomeTransaction1' directory
echo "In HomeTransaction directory $FILE"
for SUB_FILE in `ls -l`
do
cd $SUB_FILE //example cd to 'Date1'
echo "In Date directory $FILE"
for TS_FILES in ($find . -print | grep .txt)
grep "text-to-search" $SUB_FILE
fi
done
I appreciate any help in finalizing my script. Thank you.
The solution is actually pretty simple
find ./HomeTrasaction* -iname "*.txt" -exec grep -i "phrase" {} \;
find ./HomeTrasaction* - search each directory that start with this phrase, in the current directory.
-iname "*.txt" - for each file that ends with .txt
-exec grep -i "phrase" {} ; - grep for the word "phrase"
If this is still not clear "man find" :)
I have multiple folders with multiple files. I need to rename those files with the same name like the folder where the file stored with "_partN" prefix.
As example,
I have a folder named as "new_folder_for_upload" which have 2 files. I need to convert the name of these 2 files like,
new_folder_for_upload_part1
new_folder_for_upload_part2
I have so many folders like above which have multiple files. I need to convert all the file names as I describe above.
Can anybody help me to find out for a single linux command or script to do this work automatically?
Assuming bash shell, and assuming you want the file numbering to restart for each subdirectory, and doing the moving of all files to the top directory (leaving empty subdirectories). Formatted as script for easier reading:
find . -type f -print0 | while IFS= read -r -d '' file
do
myfile=$(echo $file | sed "s#./##")
mydir=$(dirname "$myfile")
if [[ $mydir != $lastdir ]]
then
NR=1
fi
lastdir=${mydir}
mv "$myfile" "$(dirname "$myfile")_part${NR}"
((NR++))
done
Or as one-line command:
find . -type f -print0 | while IFS= read -r -d '' file; do myfile=$(echo $file | sed "s#./##"); mydir=$(dirname "$myfile"); if [[ $mydir != $lastdir ]]; then NR=1; fi; lastdir=${mydir}; mv "$myfile" "$(dirname "$myfile")_part${NR}"; ((NR++)); done
Beware. This is armed, and will do a bulk renaming / moving of every file in or below your current work directory. Use at your own risk.
To delete the empty subdirs:
find . -depth -empty -type d -delete
I am currently working on an auto grading script for a class project. It has to be able to search any number of given directories lets say
for example
usr/autograder/jdoe/
jdoe contains two files house.c and readme.txt.
I need to create a file in jdoe called jdoe.pdf
Currently i'm using this line of code below to get the path to where i need to create the file. Where $1 is user input of the path containing the projects the auto grader will grade.
find $1 -name "*.txt" -exec sh -c "dirname {}"
When I try adding /somename.pdf to the end of this statement I get readme.txt/somename.pdf
along with another -exec to get the name for the file.
\; -exec sh -c "dirname {} xargs -n 1 basename" \;
I'm having problems combining these two into one working statement.
I'm new to unix programming and would appreciate any advice or help even if it means re-writing the code using different unix tools.
The main question here is how do I create files in a path other than the directory I call my script from. Thanks in advance.
How about this?
find "$1" -name "*.txt" -exec bash -c 'd=$(dirname "$1"); touch $d"/"$(basename "$d").pdf' - {} \;
You can create files in another path using change directory command (cd).
If you start your script in usr/autograder/script and want to change to usr/autograder/jdoe you can change directory with shell command cd ../jdoe (relative) or cd usr/autograder/jdoe (absolute).
Now you are in the directory of usr/autograder/jdoe and you are able to create files in this directory, for example gedit readme.txt will open gedit and creates the file in usr/autograder/jdoe.
The simplest way is to loop over the files returned by find and then do whatever you need to do.
For example:
find "$1" -type f -name "*.txt" -print0 | while IFS= read -r -d $'\0' filename; do
dir=$(dirname "$filename")
# create pdf file
touch "$dir/${dir##*/}.pdf"
done
(Note the use of find -print0 to correctly handle filenames containing whitespace and newline characters.)
Is this what you are looking for?
function process_file {
dir=$(dirname "$1")
name=$(basename "$1")
echo name is $name and dir is $dir;
cd "$dir"
touch "${dir##*/}.pdf" # or anything else
}
# export the function, so that it is known in the child processes
export -f process_file
find . -name '*.txt' -exec bash -c "process_file '{}'" \;
I have a script that changes the file name. It takes a directory name and added to the file name. By the way, using tr replaces a string:
0004 the name of the directory (this directory is a script)
- DSC_1234.jpg
result 0004_1234.jpg
The script works if I am in a particular directory. I wanted to change a name yet in subdirectories
#!/bin/bash
CURRENT=`pwd`
BASENAME=`basename $CURRENT`
echo $BASENAME
for i in ./*DSC*;do mv -- "$i" "${i//DSC/$BASENAME}";done
The following should work in subdirectories:
for i in $(find . -type f); do dir="$(dirname ${i#./})"; mv "$i" "${i//DSC/$(basename $dir)}"; done
You probably want to use find on your bash script (call that script your_script.sh):
find $ROOT_DIR -type d -exec your_script.sh \;
I am working on something and need to solve the following. I am giving a analogous version of mine problem.
Say we have a music directory, in which there are 200 directories corresponding to different movies. In each movie directory there are some music files.
Now, say a file music.mp3 is in folder movie.mp3 . I want to make a shell script such that it renames the file to movie_music.mp3 and put it in some folder that I mention to it. Basically, all the files in the subdirectories are to be renamed and to be put in a new directory.
Any workaround for this?
This script receives two arguments: the source folder and the destination folder. It will move every file under any directory under the source directory to the new directory with the new filename:
#!/bin.sh
echo "Moving from $1 to $2"
for dir in "$1"/*; do
if [ -d "$dir" ]; then
for file in "$dir"/*; do
if [ -f "$file" ]; then
echo "${file} -> $2/`basename "$dir"`_`basename "${file}"`"
mv "${file}" "$2"/`basename "$dir"`_`basename "${file}"`
fi
done
fi
done
Here is a sample:
bash move.sh dir dir2
Moving from dir to dir2
dir/d1/f1 -> dir2/d1_f1
dir/d1/f2 -> dir2/d1_f2
dir/d2/f1 -> dir2/d2_f1
dir/d2/f2 -> dir2/d2_f2
Bash:
newdir=path/to/new_directory;
find . -type d |while read d; do
find "$d" -type f -maxdepth 1 |while read f; do
movie="$(basename "$d" |sed 's/\(\..*\)\?//')"
mv "$f" "$newdir/$movie_$(basename $f)";
done;
done
Assuming the following directory tree:
./movie1:
movie1.mp3
./movie2:
movie2.mp3
The following one-liner will create 'mv' commands you can use:
find ./ | grep "movie.*/" | awk '{print "mv "$1" "$1}' | sed 's/\(.*\)\//\1_/'
EDIT:
If your directory structure contains only the relevant directories, you can expand use the following grep instead:
grep "\/.*\/.*"
Notice it looks file anything with at least one directory and one file. If you have multiple inner directories, it won't be good enough.