I have several strings that I just want to get a subset of like so:
my-bucket-customer-staging-ie-app-data
my-bucket-customer2-longname-prod-uk-app-data
and I just need to get the customers name from the string, so with the above examples I'd be left with
customer
customer2-longname
There's probably a simple way of doing this with regex although I've failed miserably in my attempts.
I'm able to strip the first part of the string using
trimprefix("my-bucket-customer-staging-ie-app-data", "my-bucket-")
trimprefix("my-bucket-customer-longname-prod-uk-app-data", "my-bucket-")
resulting in
customer-staging-ie-app-data
customer-longname-prod-uk-app-data
However Terraform's trimsuffix won't work as there can be several different regions/environments used.
What I'd like to do is slice the string and ignore the last 4 elements, which should then return the customer name regardless of whether it contains an additional delimiter in it.
Something like this captures the customer, however fails for long customer names:
element(split("-",trimprefix("my-bucket-customer-staging-uk-app-data", "my-bucket-")), length(split("-",trimprefix("my-bucket-customer-staging-uk-app-data", "my-bucket-")))-5)
customer
and is also quite messy.
Is there a more obvious solution I'm missing
I believe it's what regex is for.
> try(one(regex("\\w*-\\w*-(\\w*(?:-\\w*)*)-\\w*-\\w*-\\w*-\\w*","my-bucket-customer-staging-ie-app-data")),"")
"customer"
> try(one(regex("\\w*-\\w*-(\\w*(?:-\\w*)*)-\\w*-\\w*-\\w*-\\w*","my-bucket-customer2-longname-prod-uk-app-data")),"")
"customer2-longname"
> try(one(regex("\\w*-\\w*-(\\w*(?:-\\w*)*)-\\w*-\\w*-\\w*-\\w*","my-bucket-customer2-longname-even-longer-prod-uk-app-data")),"")
"customer2-longname-even-longer"
Reference: https://www.terraform.io/language/functions/regex
Related
I am trying to formnulate a regex to get the ids from the below two strings examples:
/drugs/2/drug-19904-5106/magnesium-oxide-tablet/details
/drugs/2/drug-19906/magnesium-moxide-tablet/details
In the first case, I should get 19904-5106 and in the second case 19906.
So far I tried several, the closes I could get is [drugs/2/drug]-.*\d but would return g-19904-5106 and g-19907.
Please any help to get ride of the "g-"?
Thank you in advance.
When writing a regex expression, consider the patterns you see so that you can align it correctly. For example, if you know that your desired IDs always appear in something resembling ABCD-1234-5678 where 1234-5678 is the ID you want, then you can use that. If you also know that your IDs are always digits, then you can refine the search even more
For your example, using a regex string like
.+?-(\d+(?:-\d+)*)
should do the trick. In a python script that would look something like the following:
match = re.search(r'.+?-(\d+(?:-\d+)*)', my_string)
if match:
my_id = match.group(1)
The pattern may vary depending on the depth and complexity of your examples, but that works for both of the ones you provided
This is the closest I could find: \d+|.\d+-.\d+
I'm not fully sure how to word my question, so sorry for the rough title.
I am trying to create a pattern that can identify variable names with the following restraints:
Must begin with a letter
First letter may be followed by any combination of letters, numbers, and hyphens
First letter may be followed with nothing
The variable name must not be entirely X's ([xX]+ is a seperate identifier in this grammar)
So for example, these would all be valid:
Avariable123
Bee-keeper
Y
E-3
But the following would not be valid:
XXXX
X
3variable
5
I am able to meet the first three requirements with my current identifier, but I am really struggling to change it so that it doesn't pick up variables that are entirely the letter X.
Here is what I have so far: [a-z][a-z0-9\-]* {return (NAME);}
Can anyone suggest a way of editing this to avoid variables that are made up of just the letter X?
The easiest way to handle that sort of requirement is to have one pattern which matches the exceptional string and another pattern, which comes afterwards in the file, which matches all the strings:
[xX]+ { /* matches all-x tokens */ }
[[:alpha:]][[:alnum:]-]* { /* handle identifiers */ }
This works because lex (and almost all lex derivatives) select the first match if two patterns match the same longest token.
Of course, you need to know what you want to do with the exceptional symbol. If you just want to accept it as some token type, there's no problem; you just do that. If, on the other hand, the intention was to break it into subtokens, perhaps individual letters, then you'll have to use yyless(), and you might want to switch to a new lexing state in order to avoid repeatedly matching the same long sequence of Xs. But maybe that doesn't matter in your case.
See the flex manual for more details and examples.
I have different commands my program is reading in (i.e., print, count, min, max, etc.). These words can also include a number at the end of them (i.e., print3, count1, min2, max6, etc.). I'm trying to figure out a way to extract the command and the number so that I can use both in my code.
I'm struggling to figure out a way to find the last element in the string in order to extract it, in Smalltalk.
You didn't told which incarnation of Smalltalk you use, so I will explain what I would do in Pharo, that is the one I'm familiar with.
As someone that is playing with Pharo a few months at most, I can tell you the sheer amount of classes and methods available can feel overpowering at first, but the environment actually makes easy to find things. For example, when you know the exact input and output you want, but doesn't know if a method already exists somewhere, or its name, the Finder actually allow you to search by giving a example. You can open it in the world menu, as shown bellow:
By default it seeks selectors (method names) matching your input terms:
But this default is not what we need right now, so you must change the option in the upper right box to "Examples", and type in the search field a example of the input, followed by the output you want, both separated by a ".". The input example I used was the string 'max6', followed by the desired result, the number 6. Pharo then gives me a list of methods that match that:
To get what would return us the text part, you can make a new search, changing the example output from number 6 to the string 'max':
Fortunately there is several built-in methods matching the description of your problem.
There are more elegant ways, I suppose, but you can make use of the fact that String>>#asNumber only parses the part it can recognize. So you can do
'print31' reversed asNumber asString reversed asNumber
to give you 31. That only works if there actually is a number at the end.
This is one of those cases where we can presume the input data has a specific form, ie, the only numbers appear at the end of the string, and you want all those numbers. In that case it's not too hard to do, really, just:
numText := 'Kalahari78' select: [ :each | each isDigit ].
num := numText asInteger. "78"
To get the rest of the string without the digits, you can just use this:
'Kalahari78' withoutTrailingDigits. "Kalahari"6
As some of the Pharo "OGs" pointed out, you can take a look at the String class (just type CMD-Return, type in String, hit Return) and you will find an amazing number of methods for all kinds of things. Usually you can get some ideas from those. But then there are times when you really just need an answer!
I have an assignment, similar to scrabble. I have to check if a subset is in the set. can only use a letter once. so if subset has 2t and the set has 1t it is false.
My problem is, I used 2 inputs to allow people to enter the subset and set, but that create a string no breaks between the letters which mean split or list won't create a LIST with individual letters. (at least I can't find any way.)
My plan was something like
wordset = word.lower().split()
subset = letters.lower()
for i in range(len(subset)):
if i in subset and in set:
set.remove(i)
I know that properly won't work but until I can get it into a list or someone gives me a hint how to do it with string I can't start testing it. Sorry for so much writing.
If you wish to get a list of characters in a given string you can use a list comprehension:
characters = [x for x in some_string]
I have a parameter called Analyst group in this format :
[Dimension].[Analyst Group].&[Nl.Workplace.Foundation]
I want to pass this parameter to another report, to filter data. Its a multi value parameter. But the other report only accepts it in this format : [KanBan].[Analyst Group].&[Nl.Workplace.Foundation]
So im trying to isolate the "Nl.Workplace.Foundation", so i can do the following thing in the Go To Report parameter expression :="[KanBan].[Analyst Group].&["& --Isolated analyst group-- &"]" to create the desired format.
So what i need is to extract the part between .&[ and ]
But i really have no idea how to isolate that part of the string.
Found a solution! If i just use the Parameter.label instead of Parameter.value it automatically does what i want!
A different solution has been found, but I will still answer the initial question. It could help.
So what i need is to extract the part between .&[ and ]
You could use a regex.
This may not be the fastest way but it can handle most of the situations.
So let's assume you have a string containing:
[Dimension].[Analyst Group].&[Nl.Workplace.Foundation]
And you want to get the following string:
Nl.Workplace.Foundation
Just use the following expression:
=System.Text.RegularExpressions.Regex.Match("[Dimension].[Analyst Group].&[Nl.Workplace.Foundation]", "\.&\[(?<NWF>[^]]+)\]").Groups("NWF").Value
In the expression, replace the input string with your dynamic values, like for example:
=System.Text.RegularExpressions.Regex.Match(Fields!Dimension.Value & "." & Fields!AnalystGroup.Value, "\.&\[(?<NWF>[^]]+)\]").Groups("NWF").Value
I'm keeping the formula as simple as possible so that you can easily adapt it, with, say, handling the case where an input string will not have a match (with the above query it will return #Error).
You could do this by adding an IIF() or better, use a custom function that you can reuse in several places and will reduce the length of your expression.