How do I combine something like
[for x in var.variable : { "key" : x , "value" : true}]
and
{ "key" : "*", "value" : true}
Say var.variable is an array/list with values [1,2]
and then I need to perform a jsonencode on the above result in terraform.
I have tried merge, join, concat but somehow nothing seems to work or maybe I dont know how to use them correctly.
I need the final output something like -
[
{
"key" : 1,
"value" : true
},
{
"key" : 2,
"value" : true
},
{
"key" : "*",
"value" : true
},
]
You can do that as follows:
variable "variable" {
default = [1,2]
}
output "test" {
value = jsonencode(concat(
[for x in var.variable : { "key" : x , "value" : true}],
[{ "key" : "*", "value" : true}]))
}
Related
I've a JSON with next structure and data:
[ {
"id" : 716612,
"type" : "ad",
"stats" : [ {
"day" : "2020-06-01",
"impressions" : 1956,
"clicks" : 1,
"reach" : 1782
},
{
"day" : "2020-06-13",
"spent" : "73.32",
"reach" : 1059
} ]
}, {
"id" : 414290,
"type" : "campaign",
"stats" : [ {
"day" : "2020-05-21",
"effective_cost_per_click" : "31.200",
"effective_cost_per_mille" : "108.337"
},
{
"day" : "2020-05-17",
"impressions" : 1,
"reach" : 1,
"ctr" : "0.000",
"uniq_views_count" : 1
} ]
} ]
I need to map id and type from top level with data inside stats to get result like this:
[ {
"id" : 716612,
"type" : "ad",
"day" : "2020-06-01",
"impressions" : 1956,
"clicks" : 1,
"reach" : 1782
},
{
"id" : 716612,
"type" : "ad",
"day" : "2020-06-13",
"spent" : "73.32",
"reach" : 1059
},
...
I tried with:
def json = new JsonSlurper().parseText(text)
def result = json.collectMany{ a ->
a["stats"].collectMany{ b ->
b.collect{
[id: a.id,
type: a.type
]
}
}
}
But it returns only id and type fields without stats. I thought that I'm looping through stat and just adding needed fields from above. I guess I don't get the difference between collectMany and collect?
You were close 😁
You want to collect the stat plus the id and type, so you need:
def result = json.collectMany { a ->
a.stats.collect { b ->
[ id: a.id, type: a.type ] + b
}
}
I have a list of dictionaries and trying to sort by key but couldn't get met requirement.
I'm new to python.
I have tried the following solution
sorted(data, key=itemgetter('key'))
data = [
{
"key" : "NEU",
"value" : 49
},
{
"key" : "POS",
"value" : 30
},
{
"key" : "NEG",
"value" : 39
},
{
"key" : "N/A",
"value" : 10
}
]
I want output like
[ {
"key" : "N/A",
"value" : 10
},
{
"key" : "NEG",
"value" : 39
},
{
"key" : "NEU",
"value" : 49
},
{
"key" : "POS",
"value" : 30
}
]
I think you're looking for this:
sorted(data, key=lambda x: x["key"])
We create an anonymous function via lambda where our argument is x (the values inside of data) and then we return the entry key of the dictionary inside of the lists to sort the data.
I have a document in the below format. The goal is to group the document by student name and sort it by rank in the ascending order. Once that is done, iterate through the rank(within a student) and if each subsequent rank is greater than the previous one, the version field needs to be incremented. As part of a pipeline, student_name will be passed to me so matching by student name should be good instead of grouping.
NOTE: Tried it with python and works to some extent. A python solution would also be great!
{
"_id" : ObjectId("5d389c7907bf860f5cd11220"),
"class" : "I",
"students" : [
{
"student_name" : "AAA",
"Version" : 2,
"scores" : [
{
"value" : "50",
"rank" : 2
},
{
"value" : "70",
"rank" : 1
}
]
},
{
"student_name" : "BBB",
"Version" : 5,
"scores" : [
{
"value" : 80,
"rank" : 2
},
{
"value" : 100,
"rank" : 1
},
{
"value" : 100,
"rank" : 1
}
]
}
]
}
I tried this piece of code to sort
def version(student_name):
db.column.aggregate(
[
{"$unwind": "$students"},
{"$unwind": "$students.scores"},
{"$sort" : {"students.scores.rank" : 1}},
{"$group" : {"students.student_name}
]
)
for i in range(0,(len(students.scores)-1)):
if students.scores[i].rank < students.scores[i+1].rank:
tag.update_many(
{"$inc" : {"students.Version":1}}
)
The expected output for student AAA should be
{
"_id" : ObjectId("5d389c7907bf860f5cd11220"),
"class" : "I",
"students" : [
{
"student_name" : "AAA",
"Version" : 3, #version incremented
"scores" : [
{
"value" : "70",
"rank" : 1
},
{
"value" : "50",
"rank" : 2
}
]
}
I was able to sort the document.
pipeline = [
{"$unwind": "$properties"},
{"$unwind": "$properties.values"},
{"$sort" : {"$properties.values.rank" : -1}},
{"$group": {"_id" : "$properties.property_name", "values" : {"$push" : "$properties.values"}}}
]
import pprint
pprint.pprint(list(db.column.aggregate(pipeline)))
I am trying to remove the lowest homework score.
I tried this,
var a = db.students.find({"scores.type":"homework"}, {"scores.$":1}).sort({"scores.score":1})
but how can I remove this set of data?
I have 200 pieces of similar data below.
{
"_id" : 148,
"name" : "Carli Belvins",
"scores" : [
{
"type" : "exam",
"score" : 84.4361816750119
},
{
"type" : "quiz",
"score" : 1.702113040528119
},
{
"type" : "homework",
"score" : 22.47397850465176
},
{
"type" : "homework",
"score" : 88.48032660881387
}
]
}
you are trying to remove an element but the statement you provided is just to find it.
Use db.students.remove(<query>) instead. Full documentation here
I have a document as below, and I want to pull all the elements in this array without any condition just via one statement. how can I do?
"energy_sent" : [
{
"player_id" : "034010000093",
"_id" : ObjectId("53675b8d251c20490d9679c6"),
"time" : ISODate("2014-05-05T09:36:13.629Z"),
"has_accepted" : 0,
"energy_value" : 2
},
{
"player_id" : "034010000094",
"_id" : ObjectId("53675cfa251c20490d9679cc"),
"time" : ISODate("2014-05-05T09:42:18.015Z"),
"has_accepted" : 0,
"energy_value" : 2
},
{
"player_id" : "034010000116",
"_id" : ObjectId("5367767889f8e3ee137dd239"),
"time" : ISODate("2014-05-05T11:31:04.457Z"),
"has_accepted" : 0,
"energy_value" : 2
}
]
If you are just after emptying the entire array just set it to empty:
db.collection.update(
{ /* query to match document */ },
{ "$set": { "energy_sent": [] }
)
So just use the $set operator