For a test I need a string literal with trailing whitespace, like this (dots are spaces).
let expected = "
foo....a
.......b
.......
.......c
.......d
";
Unfortunately editors commonly strip trailing whitespace. Good in general, so I don't want to require people to disable it, but it breaks this code.
Is there a nice way to specify this string in such a way that it has the same value but doesn't have trailing whitespace in the code? By nice I mean it doesn't look too different from the existing code.
This is the best I can come up with:
let expected = "
foo....a
.......b
.......\
\n.......c
.......d
";
It's not great but I can't think of anything better. You could use something like format!(".....{s}", s="...") but that seems worse.
Thanks to Caesar this is a nicer solution!
let expected = "
foo....a
.......b
......\x20
.......c
.......d
";
You could do exactly what you used here on stackoverflow,
and just use dots:
let expected = "
foo....a
.......b
.......
.......c
.......d
".replace(".", " ");
If this weren't test code, and you really needed the string to be constant, you could use the lazy_static crate.
Related
I'm trying to remove all instances of \n, from a string in javascript. Does anyone know the best way to do this?
I tried
mystring = mystring.replace(/\n/g,'');
Did you read MDN?
mystring = mystring.replace(/\n/g, '');
PS. You don't need to put i flag which stands for case insensitive, since there is just one line break sign :)
If you mean you need to get rid of \n\ literally then your regexp should be /\\n/g to remove the string \n.
You need to remove the " from your regex expression. You also do not need the "case insensitive" modifier, but just global (g). Use this instead.
mystring = mystring.replace(/\n/g, '')
And to be very verbose, you can replace all vertical whitespace characters with the following.
mystring = mystring.replace(/[\n\r\v]/g, '')
I'm having issues when trying to remove the first space of a string if that string has 2 spaces in it. For example it should be turning "Fully Functional Method" into "FullyFunctional Method", but "Functional Method" should not be changed because it only has 1 space. I can't really think of a way to remove first space if the string contains 2 spaces.
I don't know exactly what you want to do, but you may search into RegExp and String.replace() to replace some stuff in a String.
Here is another link to understand the Characters, metacharacters, and metasequences.
var myPattern1:RegExp = / /g;
var str1:String = "This is a string that contains double spaces.";
trace(str1.replace(myPattern1, " "));
//this replaces all " " by " "...
//outputs : This is a string that contains double spaces.
Or in your case (I suppose) something like this
var myPattern2:RegExp = / /;
var str2:String = "Fully Functional Method";
trace(str2.replace(myPattern2, ""));
//If you omit the g, only the first space will be replaced by ""
//outputs : FullyFunctional Method
There is so much things you can do by using RegExp, that I will not explain this here...
Just check on the Adobe website...
This is a quick and efficient way to work on Strings.
I hope this will help.
Since you check at those links, you will understand that my example is pure rough and should be modified to have a FullyFunctional Method. :D
Do a linear scan through the string. Count the number of spaces and record the index of the first space, if any. If there are two spaces, return a string that is the concatenation of the characters up to but not including the first space, and the characters after the first space.
Keep it simple. It is possible to solve your problem with regex, but keep in mind that the worst case time complexity of finding a particular character in an unsorted set is always going to be O(N), so it won't be faster.
I have a string in which the data is getting loaded in this format. "float;#123456.0300000" from which i need to extract only 123456.03 and trim all other starting and ending characters. May be it is very basic that i am missing, please let me know how can i do that. Thanks.
If the format is always float;# followed by the bit you want, then it's fairly simple:
// TODO: Validate that it actually starts with "float;#". What do you want
// to do if it doesn't?
string userText = originalText.Substring("float;#".Length);
// We wouldn't want to trim "300" to "3"
if (userText.Contains("."))
{
userText = userText.TrimEnd('0');
// Trim "123.000" to "123" instead of "123."
if (userText.EndsWith("."))
{
userText = userText.Substring(0, userText.Length - 1);
}
}
But you really need to be confident in the format - that there won't be anything else you need to remove, etc.
In particular:
What's the maximum number of decimal places you want to support?
Might there be thousands separators?
Will the decimal separator always be a period?
Can the value be negative?
Is an explicit leading + valid?
Do you need to handle scientific format (1.234e5 etc)?
Might there be trailing characters?
Might the trailing characters include digits?
Do you need to handle non-ASCII digits?
You may well want to use a regular expression if you need anything more complicated than the code above, but you'll really want to know as much as you can about your possible inputs before going much further. (I'd strongly recommend writing unit tests for every form of input you can think of.)
Why not just do:
String s = "float;#123456.0300000";
int i = int.Parse(s.Substring(s.IndexOf('#') + 1));
I haven't tested this, but it should be close.
Assuming the format doesn't change, just find the character after the '#' and turn it into an int, so you lose everything after the '.'.
If you need it as a string, then just call the ToString method.
Is there a multiline string literal syntax in Matlab or is it necessary to concatenate multiple lines?
I found the verbatim package, but it only works in an m-file or function and not interactively within editor cells.
EDIT: I am particularly after readbility and ease of modifying the literal in the code (imagine it contains indented blocks of different levels) - it is easy to make multiline strings, but I am looking for the most convenient sytax for doing that.
So far I have
t = {...
'abc'...
'def'};
t = cellfun(#(x) [x sprintf('\n')],t,'Unif',false);
t = horzcat(t{:});
which gives size(t) = 1 8, but is obviously a bit of a mess.
EDIT 2: Basically verbatim does what I want except it doesn't work in Editor cells, but maybe my best bet is to update it so it does. I think it should be possible to get current open file and cursor position from the java interface to the Editor. The problem would be if there were multiple verbatim calls in the same cell how would you distinguish between them.
I'd go for:
multiline = sprintf([ ...
'Line 1\n'...
'Line 2\n'...
]);
Matlab is an oddball in that escape processing in strings is a function of the printf family of functions instead of the string literal syntax. And no multiline literals. Oh well.
I've ended up doing two things. First, make CR() and LF() functions that just return processed \r and \n respectively, so you can use them as pseudo-literals in your code. I prefer doing this way rather than sending entire strings through sprintf(), because there might be other backslashes in there you didn't want processed as escape sequences (e.g. if some of your strings came from function arguments or input read from elsewhere).
function out = CR()
out = char(13); % # sprintf('\r')
function out = LF()
out = char(10); % # sprintf('\n');
Second, make a join(glue, strs) function that works like Perl's join or the cellfun/horzcat code in your example, but without the final trailing separator.
function out = join(glue, strs)
strs = strs(:)';
strs(2,:) = {glue};
strs = strs(:)';
strs(end) = [];
out = cat(2, strs{:});
And then use it with cell literals like you do.
str = join(LF, {
'abc'
'defghi'
'jklm'
});
You don't need the "..." ellipses in cell literals like this; omitting them does a vertical vector construction, and it's fine if the rows have different lengths of char strings because they're each getting stuck inside a cell. That alone should save you some typing.
Bit of an old thread but I got this
multiline = join([
"Line 1"
"Line 2"
], newline)
I think if makes things pretty easy but obviously it depends on what one is looking for :)
I'm embedding JRuby in Java, because I need to call some Ruby methods with Java strings as arguments. The thing is, I'm calling the methods like this:
String text = ""; // this can span over multiple lines, and will contain ruby code
Ruby ruby = Ruby.newInstance();
RubyRuntimeAdapter adapter = JavaEmbedUtils.newRuntimeAdapter();
String rubyCode = "require \"myscript\"\n" +
"str = build_string(%q~"+text+"~)\n"+
"str";
IRubyObject object = adapter.eval(ruby, codeFormat);
The thing is, I don't know what strings I can use as delimiters, because if the ruby code I'm sending to build_string will contain ruby code. Right know I'm using ~,but I think this could break my code. What characters can I use as delimiters to make sure my code will work no matter what the ruby code is?
use the heredoc format:
"require \"myscript\"\n" +
"str = build_string(<<'THISSHOUDLNTBE'\n" + text + "\nTHISSHOULDNTBE\n)\n"+
"str";
this however assumes you won't have "THISSHOULDNTBE" on a separate line in the input.
Since string text contain contain any character, there is no character left to use for quotation escaping like the ~ you're using now. You would still need to escape the tilde in string text in java and append that one to the string you're building.
Something like (untested, not a Java guru):
String rubyCode = "require \"myscript\"\n" +
"str = build_string(%q~" + text.replaceAll("~", "\\~") + "~)\n"+
"str";