Im try to write the Kozak equation in R, but I dont have experience with this type of equation.
For example, the b could be b1, b2, b3, b4, b5, b6, b7, b8.
Because next it, in want put this formula in one gnls model.
# Kozak
kozak <- gnls(formula)
# Im make this, but is not complete. Im not sure if it well.
d = (
b1*DBH^b2 * (H^b3)[((1-sqrt(RH))/ 1-sqrt(t))]^ b4[((1-sqrt(RH))/1-
sqrt(t))^0.1] + b5*RH^4 + b6*asin(sqrt(1-sqrt(RH))) +
b7[(((1)/(DBH/exp(H))))] + B8*DBH^ ((((1-sqrt(RH))/1-sqrt(t))))
)^2
Tnks!
Related
Here is what I did
=VLOOKUP(M3,P2:Q23,2,FALSE)+VLOOKUP(N3,P2:Q23,2,FALSE)
I want to sum the values with just one formula and not repeat it
Im using Excel Online
I tried =XLOOKUP(M2:N2,P3:P23,Q3:Q23) but I get a value error,does anyone know how to do this ?
Perhaps you can try in Excel Online:
• Formula used in cell C3
=SUM(SCAN(0,M3:N3,LAMBDA(x,y,VLOOKUP(y,P3:Q12,2,0))))
Works for me in Google Sheet as well
• Formula used in cell C3
=SUM(SCAN(0,M3:N3,LAMBDA(x,y,VLOOKUP(y,P3:Q12,2,0))))
This works if, and only if, you are certain the M2 and N2 will not be the same value:
=SUMPRODUCT( ( (P2:P23=M2) + (P2:P23=N2) ) * Q2:Q23 )
If you want N2 = M2 to be valid and result in the number added twice, then:
=SUMPRODUCT( (P2:P23=M2) * Q2:Q23 ) + SUMPRODUCT( (P2:P23=N2) * Q2:Q23 )
But then you are back to repeating the formula.
I used M2 and N2 for the lookup values; your post uses row references 2 and 3 sometimes interchangeably.
I have these values in an excel sheet: A1: 6/15, B1:10/3.
I want to add these cells. I used the following formula, but it doesn't work:
=LEFT (A1, 1) + LEFT(B1, 1) + LEFT (B1, 2)&"/"&RIGHT (A1, 1) +
RIGHT (A1, 2) + RIGHT (B1, 1)
Please help me. What am I doing wrong? How should I change the formula to make it work?
Try this formula, which isolates and then divides the numbers on either side of the slash:
=LEFT(A1, SEARCH("/",A1,1)-1) / RIGHT(A1,LEN(A1) - SEARCH("/", A1, 1))
If you also want a higher level summation or product of multiple such cells, then just use the above formula and then add those cells.
I think you are looking for:
=SUMPRODUCT(LEFT(A1:B1,SEARCH("/",A1:B1)-1)*1)&"/"&SUMPRODUCT(REPLACE(A1:B1,1,SEARCH("/",A1:B1),"")*1)
I have a cell value like 100/20. I mean this text equals "5". I want to calculate each cell and get sum on bottom.
I calculate a cell like this (just for a cell)
=LEFT( V342;FIND( "/"; V342 ) - 1 ) / RIGHT( V342; LEN( V342) - FIND( "/"; V342 ) )
How can i calculate and sum all cells ?
You can use array version of SUM (confirmed with Ctrl+Shift+Enter):
=SUM(LEFT(A1:A6, FIND("/",A1:A6,1)-1) / (MID(A1:A6, FIND("/",A1:A6,1)+1,50000)))
Or SUMPRODUCT confirmed with Enter:
=SUMPRODUCT(LEFT(A1:A6, FIND("/",A1:A6,1)-1) / (MID(A1:A6, FIND("/",A1:A6,1)+1,50000)))
With data like :
In A1 through A3, in another cell enter:
=SUMPRODUCT(--LEFT(A1:A3,FIND("/",A1:A3,1)-1)/(MID(A1:A3,FIND("/",A1:A3,1)+1,9999)))
In your locale use ; rather than ,
Spliiting Words together in a pair like (Head LM) from other word in a cell in Excel
Name Role
John Dowe (Head LM); Moniq Jamese (Lead JK); Larrye Stuarte (Front TR) John Dowe Head LM
I need to be able to split [Head LM] from the rest of the text without the parentesis, just Head LM. I tried several options like:
=TRIM(RIGHT(SUBSTITUTE(S3," ",REPT(" ",100)),300))
=RIGHT(S3, LEN(S3)-FIND(" ", S3,1)-5) =>resule is : (Lead PM); J
In both instances the text isn't clean from the () and other words.
if A1 contains:-
John Dowe (Head LM); Moniq Jamese (Lead JK); Larrye Stuarte (Front TR)
This:-
=LEFT(MID(A1,FIND("(",A1)+1,LEN(A1)),FIND(")",MID(A1,FIND("(",A1)+1,LEN(A1)))-1)
returns:-
Head LM
For clarification:-
MID(A1,FIND("(",A1)+1,LEN(A1)) finds the part of A1 that starts after the first (
FIND(")",MID(A1,FIND("(",A1)+1,LEN(A1))) works out the number of characters to the second )
LEFT({...first snippet...},{...second snippet...}-1) trims off the second )
Update to handle all names/titles
A1 your example text
B1 =LEFT(A1,FIND(";",A1))
C1 =LEFT(B1,FIND(" (",B1)-1)
D1 =MID(B1,FIND("(",B1)+1,FIND(")",B1)-(FIND("(",B1)+1))
E1 =MID(A1,LEN(B1)+2,FIND(";",A1)+3)
F1 =LEFT(E1,FIND(" (",E1)-1)
G1 =MID(E1,FIND("(",E1)+1,FIND(")",E1)-(FIND("(",E1)+1))
H1 =MID(A1,LEN(B1)+2+LEN(E1)+1,LEN(A1))
I1 =LEFT(H1,FIND(" (",H1)-1)
J1 =MID(H1,FIND("(",H1)+1,FIND(")",H1)-(FIND("(",H1)+1))
B1 pulls the first name block (up to the first semi-colon)
E1 pulls the second name block (up to the second semi-colon)
H1 pulls the third name block
C1, F1, I1 pull the name from their respective block
D1,G1,J1 pull the title from their respective block
Any columns that are not required can be hidden - leaving just the required ones visible. Breaking out the three blocks into B1, E1 and H1 make the formulae in the other cells simpler - but could be avoided, by substituting (for example) the formula in B1 wherever B1 appears in the other formulae (though this, obviously, makes those formulae even more complex). This would then remove the need to hide any unwanted columns - as you would only calculate the values you require.
This assumes that you want to get ALL of the words in parentheses, not just the first occurrence (this was not really clear in your question, so I assumed you were interested in all of them). To do this, you'll need to split that cell using Text-To-Columns or something of that nature, so that your formula only has to deal with one name/title at a time. Then copy/transpose it so that each name/title is in its own row.
That done, you can use a formula like:
=SUBSTITUTE(SUBSTITUTE(RIGHT(A1,LEN(A1)-FIND("(",A1,1)+1),"(",""),")","")
Here is a picture:
If you don't need ALL of the titles in parentheses, then you could obtain only the first instance without doing any Text-to-Columns/additional steps/etc. as per #dav1dsm1th's answer.
Split this into a number of smaller problems so it makes sense.
To find the beginning of the word, first find the open paren
=FIND( "(", A1 )
To find the end of the word, find the close paren that follows your open paren
=FIND( ")", A1, FIND( "(", A1) )
So with these worked out, you can find your word. It starts 1 character after the open paren and goes for the length between the two minus that 1 character.
= MID( A1, FIND( "(", A1 ) + 1 , ( FIND( ")", A1, FIND( "(", A1) ) - FIND( "(", A1 ) ) - 1 )
I have, on a worksheet, 3 values (C1, C2, C3). C2 and C3 are constant and will not change, but I want C4 to update depending on the value of C1 (anywhere from 1 to 50).
Normally I know how to do these things, but I haven't figured this out. Here's what I want to do for this particular case:
I want C4 to be equal to C3 plus 2.02% * (C2) for every C1... meaning that if C1 = 1 then C4 is equal to C3 * 1.0202.
My problem is for higher than 1, I didn't find a way to "recursively" call the cell value, this is what I have so far:
=IF( $C$1 = 1; C3; C3 * (1+C2))
Obliviously this isn't working and I haven't found a function that'll do what I want. Is there a mathematical way of doing this?
Thanks,
I've tried to make it as clear as possible, don't hesitate to ask me if it's not clear!
EDIT:
Here what the result would look like
C1 = 1: 0.625
C1 = 2: 0.625 * 1.0202 = 0.637625
C1 = 3: 0.637625 * 1.0202 = 0.650505025
C1 = 4: 0.650505025 * 1.0202 = 0.663645226505
...
I want to use the previous result to calculate the new one
What about using the power operator :
= C3 * (1+C2)^C1
This multiplies C3 with (1+C2) for C1 times.
This is how compound interest or a growth rate is applied to grow a value.
Are you thinking of =c3 + c2*c1?
Nope, you're thinking of =c3 * (1+c2)^c1 as #peladao posted.