Using a Macro or Formula, is there a way to achieve the result of the following formula of Office 365?
=FILTER(B:B,A:A = "x")
What it does is get all the values from Column B if Column A on the same row has a value of x.
My PC has office 365 but the one I'm working with only has Office Pro Plus 2019. I had to use my pc when I needed the function and I'm getting tired of it, maybe it can be done on Office Pro Plus 2019 too using a formula or a macro?
Use:
=IFERROR(INDEX($B$1:$B$100,AGGREGATE(15,7,ROW($A$1:$A$100)/($A$1:$A$100="x"),ROW($ZZ1))),"")
Note the use of a set range and not full columns. That is done on purpose, This being an array formula it will do a lot of calculations each cell it is placed. Limiting the range to the data set will speed it up.
Put this in the first cell of the output and copy down till blanks are returned.
I had some spare time and I am recently interested in User defined functions so I decided to make my own version of what I imagine this would be. I'm prefacing this by saying its not good and is excessively long but it works!
Function JOINIF(ByRef IfRange As Range, ByVal Criteria As String, Optional JoinRange As Range, Optional Delimeter As String = ",") As String
'IfRange is the range that will be evaluated by the Criteria
'Criteria is a logical test that can be applied to a cell value.
'Examples of Criteria: "=Steve", ">100", "<>Toronto", "<=-1"
'JoinRange is the range of values that will be concatenated if the corresponding -
'IfRange cell meets the criteria. JoinRange can be left blank if the values to be -
'concatenated are the IfRange values.
'Delimeter is the string that will seperate the concatenated values.
'Default delimeter is a comma.
Dim IfArr() As Variant, JoinArr() As Variant, OutputArr() As String
Dim IfArrDim As Integer, JoinArrDim As Integer
Dim JCount As Long, LoopEnd(1 To 2) As Long
Dim MeetsCriteria As Boolean, Expression As String
Dim i As Long, j As Long
'PARSING THE CRITERIA
Dim Regex As Object
Set Regex = CreateObject("VBScript.RegExp")
Regex.Pattern = "[=<>]+"
'Looking for comparison operators
Dim Matches As Object
Set Matches = Regex.Execute(Criteria)
If Matches.Count = 0 Then
'If no operators found, assume default "Equal to"
If Not IsNumeric(Criteria) Then
'Add quotation marks to allow string comparisons
Criteria = "=""" & Criteria & """"
End If
Else
If Not IsNumeric(Replace(Criteria, Matches(0), "")) Then
Criteria = Matches(0) & """" & Replace(Criteria, Matches(0), "") & """"
End If
'Add quotation marks to allow string comparisons
End If
'Trim IfRange to UsedRange
Set IfRange = Intersect(IfRange, IfRange.Parent.UsedRange)
'Default option for optional JoinRange input
If JoinRange Is Nothing Then
Set JoinRange = IfRange
Else
Set JoinRange = Intersect(JoinRange, JoinRange.Parent.UsedRange)
End If
'DIMENSIONS
'Filling the arrays
If IfRange.Cells.Count > 1 Then
IfArr = IfRange.Value
IfArrDim = Dimensions(IfArr)
Else
ReDim IfArr(1 To 1)
IfArr(1) = IfRange.Value
IfArrDim = 1
End If
If JoinRange.Cells.Count > 1 Then
JoinArr = JoinRange.Value
JoinArrDim = Dimensions(JoinArr)
Else
ReDim JoinArr(1 To 1)
JoinArr(1) = JoinRange.Value
JoinArrDim = 1
End If
'Initialize the Output array to the smaller of the two input arrays.
ReDim OutputArr(IIf(IfRange.Cells.Count < JoinRange.Cells.Count, IfRange.Cells.Count - 1, JoinRange.Cells.Count - 1))
'DEFINING THE LOOP PARAMETERS
'Loop ends on the smaller of the two arrays
If UBound(IfArr) > UBound(JoinArr) Then
LoopEnd(1) = UBound(JoinArr)
Else
LoopEnd(1) = UBound(IfArr)
End If
If IfArrDim = 2 Or JoinArrDim = 2 Then
If Not (IfArrDim = 2 And JoinArrDim = 2) Then
'mismatched dimensions
LoopEnd(2) = 1
ElseIf UBound(IfArr, 2) > UBound(JoinArr, 2) Then
LoopEnd(2) = UBound(JoinArr, 2)
Else
LoopEnd(2) = UBound(IfArr, 2)
End If
End If
'START LOOP
If IfArrDim = 1 Then
For i = 1 To LoopEnd(1)
If IsNumeric(IfArr(i)) And IfArr(i) <> "" Then
Expression = IfArr(i) & Criteria
Else
'Add quotation marks to allow string comparisons
Expression = """" & IfArr(i) & """" & Criteria
End If
MeetsCriteria = Application.Evaluate(Expression)
If MeetsCriteria Then
If JoinArrDim = 1 Then
OutputArr(JCount) = CStr(JoinArr(i))
Else
OutputArr(JCount) = CStr(JoinArr(i, 1))
End If
JCount = JCount + 1
End If
Next i
Else
For i = 1 To LoopEnd(1)
For j = 1 To LoopEnd(2)
If IsNumeric(IfArr(i, j)) And IfArr(i, j) <> "" Then
Expression = IfArr(i, j) & Criteria
Else
'Add quotation marks to allow string comparisons
Expression = """" & IfArr(i, j) & """" & Criteria
End If
MeetsCriteria = Application.Evaluate(Expression)
If MeetsCriteria Then
If JoinArrDim = 1 Then
OutputArr(JCount) = CStr(JoinArr(i))
Else
OutputArr(JCount) = CStr(JoinArr(i, j))
End If
JCount = JCount + 1
End If
Next j
Next i
End If
'END LOOP
ReDim Preserve OutputArr(JCount + 1 * (JCount > 0))
JOINIF = Join(OutputArr, Delimeter)
End Function
Private Function Dimensions(var As Variant) As Long
'Credit goes to the great Chip Pearson, chip#cpearson.com, www.cpearson.com
On Error GoTo Err
Dim i As Long, tmp As Long
While True
i = i + 1
tmp = UBound(var, i)
Wend
Err:
Dimensions = i - 1
End Function
Examples of it in use:
Seperate IfRange and JoinRange
IfRange as the JoinRange
You might try the following udf (example call: FILTER2(A1:A100,B1:B100)) consisting of the following tricky steps:
a) Evaluate the general condition (=If(A1:A100="x",Row(A1:A100),"?") as tabular Excel formula and assign all valid row numbers to array x (marking the rest by "?" strings),
b) Filter out all "?" elements
c) Apply x upon the data column benefitting from the advanced restructuring features of Application.Index()
Public Function Filter2(rng1 As Range, rng2 As Variant, Optional ByVal FilterID As String = "x")
Dim a As String: a = rng1.Address(False, False, External:=True)
'a) get all valid row numbers (rng1)
Dim myformula As String: myformula = "if(" & a & "=""" & FilterID & """,row(" & a & "),""?"")"
Dim x: x = Application.Transpose(Evaluate(myformula))
'b) filter out invalid "?" elements
x = VBA.Filter(x, "?", False)
'c) apply x upon data column (rng2)
If UBound(x) > -1 Then Filter2 = Application.Index(rng2, Application.Transpose(x), 1)
End Function
Note that function calls before versions 2019/MS 365 need to be entered as array formula (Ctrl+Shift+Enter).
The function assumes one-column (range) arguments.
Edit due to comment as of 2022-06-08
The whole example is based on the actual row numbers starting in the first row (OP ranges refer to A:A,B:B. If you want to allow ranges to start at any row, you'd need to change the myFormula definition in section a) by correcting the row indices by subtracting possible offsets (row number + 1 - first row):
Dim myFormula As String
myFormula = "if(" & a & "=""" & FilterID & """,row(" & a & ")+1 -" & rng1.Row & ",""?"")"
Try this UDF for the Filter Function:
Function FILTER_HA(Where, Criteria, Optional If_Empty) As Variant
Dim Data, Result
Dim i As Long, j As Long, k As Long
'Create space for the output (same size as input cells)
With Application.Caller
i = .Rows.Count
j = .Columns.Count
End With
'Clear
ReDim Result(1 To i, 1 To j)
For i = 1 To UBound(Result)
For j = 1 To UBound(Result, 2)
Result(i, j) = ""
Next
Next
'Count the rows to show
For i = 1 To UBound(Criteria)
If Criteria(i, 1) Then j = j + 1
Next
'Empty?
If j < 1 Then
If IsMissing(If_Empty) Then
Result(1, 1) = CVErr(xlErrNull)
Else
Result(1, 1) = If_Empty
End If
GoTo ExitPoint
End If
'Get all data
Data = Where.Value
'Copy the rows to show
For i = 1 To UBound(Data)
If Criteria(i, 1) Then
k = k + 1
For j = 1 To UBound(Data, 2)
Result(k, j) = Data(i, j)
Next
End If
Next
'Return the result
ExitPoint:
FILTER_HA = Result
End Function
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My Data is this CSI [40%], CSSEl [50%], LDN [10%] within one cell separated by comma. can any one help me with excel vba code which will sort percentages in descending order and provide me output as this: CSSEl [50%],CSI [40%],LDN [10%].
This will do it for you.
Add the below code into a new Module within VBA and then call the formula in a cell adjacent to your cell with the values.
So in the example below, your original values are in column A and the custom UDF in column B directly adjacent.
Public Function SortByInternalNumber(ByVal strText As String, ByVal strDelimiter As String)
Dim arrValues() As String, strValue As String, i As Long, lngNumber As Long, arrNumbers() As String
Dim strNumber As String, lngMaxNumber As Long, lngMaxIndex As Long, strResult As String
Dim bFound As Boolean, arrMaxValues() As Long, lngIndex As Long, strMaxValue As String
Dim strThisValue As String
Application.Volatile
' Split up the initial string with all of the values.
arrValues = Split(strText, strDelimiter)
For i = 0 To UBound(arrValues)
strValue = Trim(arrValues(i))
strNumber = Replace(Replace(Split(strValue, "[")(1), "%", ""), "]", "")
ReDim Preserve arrNumbers(i)
arrNumbers(i) = strNumber
Next
' Now process all of the numbers in the descending order.
Do While 1 = 1
lngMaxNumber = -1
bFound = False
For i = 0 To UBound(arrNumbers)
If arrNumbers(i) <> "" Then
lngNumber = CLng(arrNumbers(i))
If lngMaxNumber < lngNumber Then
lngMaxNumber = lngNumber
lngMaxIndex = i
End If
bFound = True
End If
Next
If Not bFound Then Exit Do
lngIndex = -1
' Retrieve all of the values that are of the same value as the current max.
For i = 0 To UBound(arrNumbers)
If arrNumbers(i) <> "" Then
If CLng(arrNumbers(i)) = lngMaxNumber Then
lngIndex = lngIndex + 1
ReDim Preserve arrMaxValues(lngIndex)
arrMaxValues(lngIndex) = i
End If
End If
Next
strMaxValue = ""
' Now do the same thing as above but instead of descending, do ascending.
For i = 0 To UBound(arrMaxValues)
strThisValue = Trim(arrValues(arrMaxValues(i)))
If strMaxValue > strThisValue Or strMaxValue = "" Then
strMaxValue = strThisValue
lngMaxIndex = arrMaxValues(i)
End If
Next
strResult = strResult & ", " & strMaxValue
arrNumbers(lngMaxIndex) = ""
Loop
If strResult <> "" Then
strResult = Mid(strResult, 3)
End If
SortByInternalNumber = Trim(strResult)
End Function
It's fairly rigid in but I have demonstrated that you can parameterize more of the relevant options.
I hope that makes sense and I hope it's what you're after.
I think the easiest way is to create a helper column where you extract the numeric value. Assuming your data starts in A1, write a formula in column B like
=MID(A1, FIND("[", A1)+1, FIND("]",A1)-FIND("[", A1)-1)
With this, you can easily sort the data.
May try another alternative
Sub testsort()
Dim txt As String, txt2 As String, Arr As Variant
Dim Nums() As Long, NumSort() As Long, i As Integer, k As Integer
txt = "CSI [40%], CSSEl [50%], LDN [10%], ABC [40%],ZXH[30%]"
Arr = Split(txt, ",")
ReDim Nums(LBound(Arr) To UBound(Arr))
ReDim NumSort(LBound(Arr) To UBound(Arr))
For i = LBound(Arr) To UBound(Arr)
Spos = InStr(1, Arr(i), "[")
Epos = InStr(1, Arr(i), "%")
If Spos > 0 And Epos > Spos Then
Nums(i) = Val(Mid(Arr(i), Spos + 1, Epos - Spos - 1))
Else
Nums(i) = 0
End If
Next i
For i = LBound(Arr) To UBound(Arr)
NumSort(i) = LBound(Arr)
For k = LBound(Arr) To UBound(Arr)
If Nums(i) < Nums(k) Or (Nums(i) = Nums(k) And k < i) Then
NumSort(i) = NumSort(i) + 1
End If
Next
Debug.Print Arr(i), Nums(i), NumSort(i)
Next
For i = LBound(Arr) To UBound(Arr) ' rank
For k = LBound(Arr) To UBound(Arr)
If NumSort(k) = i Then
txt2 = txt2 & Arr(k) & ","
Exit For
End If
Next k
Next i
If Len(txt2) > 0 Then txt2 = Left(txt2, Len(txt2) - 1) 'delete last comma
Debug.Print txt2
End Sub
I've been looking for a while for a code that would give me the digits between without using regex (I want my macro to be used by anyone especially non-computer friendly people). This is a small part of a code creating series for a chart dynamically creating the chart etc.
Here is the type of data I am dealing with "C23H120N5O4Cl" so I'd like to save in a variable 23 then in another one 120 the rest should not matter (it could be nothing).
My digits will likely be between single characters (C,H,or else) but I need the numbers after C and H. So at the moment here is my code :
RangeOccupied = Range("C2").End(xlDown).row
For i = 1 To RangeOccupied
If i <> RangeOccupied Then
'Look for digits after C
pos = InStr(1, Cells(i + 1, 2), "C") + 1
pos1 = InStr(pos, Cells(i + 1, 2), "H")
NumC = Mid(Cells(i + 1, 2), pos, pos1 - pos)
'Look for digits after H
pos = InStr(1, Cells(i + 1, 2), "H") + 1
pos1 = InStr(pos, Cells(i + 1, 2), "O")
NumH = Mid(Cells(i + 1, 2), pos, pos1 - pos)
End If
Next
Ideally I'd like the pos1 numbers not to be dependent on a specific character but any character. i.e having pos1=InStr(pos,Cells(i+1,2),"ANY NON-NUMBER CHARACTER").
I do not know if it is possible without using regex.
This function will return an array of the digit strings in a text string
Option Explicit
Function myDigits(str As String) As String()
Dim col As Collection
Dim I As Long, S() As String
I = 0
Set col = New Collection
Do Until I > Len(str)
I = I + 1
If IsNumeric(Mid(str, I, 1)) Then
col.Add Val(Mid(str, I, Len(str)))
I = I + 1
Do Until Not IsNumeric(Mid(str, I, 1))
I = I + 1
Loop
End If
Loop
ReDim S(0 To col.Count - 1)
For I = 1 To col.Count
S(I - 1) = col(I)
Next I
myDigits = S
End Function
Okay, I'm absolutely certain there is a more efficient way of doing this. But I think the following example makes it fairly clear on one way to separate your values.
Option Explicit
Sub test()
Dim testValues() As String
Dim val1 As Long
Dim val2 As Long
testValues = Split("C23H120N5O4Cl,C23O120N5H4Cl,C4H120", ",")
Dim testValue As Variant
For Each testValue In testValues
ExtractValues testValue, val1, val2
Debug.Print "For " & testValue & ": " & val1 & " and " & val2
Next testValue
End Sub
Public Sub ExtractValues(ByVal inString As String, _
ByRef output1 As Long, _
ByRef output2 As Long)
Dim outString1 As String
Dim outString2 As String
Dim stage As String
stage = "Begin"
Dim thisCharacter As String
Dim i As Long
For i = 1 To Len(inString)
thisCharacter = Mid$(inString, i, 1)
Select Case stage
Case "Begin"
If thisCharacter = "C" Then stage = "First Value"
Case "First Value"
If (Asc(thisCharacter) >= Asc("0")) And _
(Asc(thisCharacter) <= Asc("9")) Then
outString1 = outString1 & thisCharacter
Else
'--- if we get here, we're done with this value
output1 = CLng(outString1)
'--- verify the next character is the "H"
If thisCharacter = "H" Then
stage = "Second Value"
Else
stage = "Next Value"
End If
End If
Case "Next Value"
If thisCharacter = "H" Then stage = "Second Value"
Case "Second Value"
If (Asc(thisCharacter) >= Asc("0")) And _
(Asc(thisCharacter) <= Asc("9")) Then
outString2 = outString2 & thisCharacter
Else
'--- if we get here, we're done with this value
output2 = CLng(outString2)
stage = "Finished"
Exit For
End If
End Select
Next i
If Not (stage = "Finished") Then
output2 = CLng(outString2)
End If
End Sub
Here's another method that's more generic and efficient than my first solution. This approach uses a function to extract the number following a given substring -- in this case it's a single letter "C" or "H". The function accounts for the value being at the end of the input value as well.
Option Explicit
Sub test()
Dim testValues() As String
Dim val1 As Long
Dim val2 As Long
testValues = Split("C23H120N5O4Cl,C23O120N5H4Cl,C4H120", ",")
Dim testValue As Variant
For Each testValue In testValues
val1 = NumberAfter(testValue, "C")
val2 = NumberAfter(testValue, "H")
Debug.Print "For " & testValue & ": " & val1 & " and " & val2
Next testValue
End Sub
Private Function NumberAfter(ByVal inString As String, _
ByVal precedingString As String) As Long
Dim outString As String
Dim thisToken As String
Dim foundThisToken As Boolean
foundThisToken = False
Dim i As Long
For i = 1 To Len(inString)
thisToken = Mid$(inString, i, 1)
If thisToken = precedingString Then
foundThisToken = True
ElseIf foundThisToken Then
If thisToken Like "[0-9]" Then
outString = outString & thisToken
Else
Exit For
End If
End If
Next i
NumberAfter = CLng(outString)
End Function
I found this solution from here Extract numbers from chemical formula
Public Function ElementCount(str As String, element As String) As Long
Dim i As Integer
Dim s As String
For i = 1 To 3
s = Mid(str, InStr(str, element) + 1, i)
On Error Resume Next
ElementCount = CLng(s)
On Error GoTo 0
Next i
End Function
Which works but if simple molecules like CH4 are put in it does not work since no number are shown... but I (we) can probably work that out.
Thanks again for all the solutions !
EDIT:
Here is the function I use that I think takes all possible scenarios into account ! Thanks again for your help !
Public Function ElementCount(str As String, element As String) As Long
Dim k As Integer
Dim s As String
For k = 1 To Len(str)
s = Mid(str, InStr(str, element) + 1, k)
On Error Resume Next
ElementCount = CLng(s)
On Error GoTo 0
If InStr(str, element) > 0 And ElementCount = 0 Then
ElementCount = 1
End If
Next k
End Function
EDIT
Changed the function to use and return dictionaries having keys of "C" and "H" paired with their numbers. Included a screenshot below.
Made sure it handles for tricky situations where multiple letters are packed ontop of each other:
Code:
Sub mainLoop()
Dim numbers As Scripting.Dictionary: Set numbers2 = New Scripting.Dictionary
For i = 1 To 5
Set numbers = returnDict(Cells(i, 1).Value)
printout numbers, i
Next
End Sub
Function returnDict(cellValue As String) As Scripting.Dictionary
Dim i As Integer: i = 1
Dim holder As String: holder = ""
Dim letter As String
Set returnStuff = New Scripting.Dictionary
While i < Len(cellValue)
If Mid(cellValue, i, 1) = "C" Or Mid(cellValue, i, 1) = "H" Then
i = i + 1
If IsNumeric(Mid(cellValue, i, 1)) Then
letter = (Mid(cellValue, i - 1, 1))
Do While IsNumeric(Mid(cellValue, i, 1))
holder = holder & Mid(cellValue, i, 1)
i = i + 1
If i > Len(cellValue) Then Exit Do
Loop
returnStuff.Add letter, holder
holder = ""
ElseIf Mid(cellValue, i, 1) <> LCase(Mid(cellValue, i, 1)) Then
returnStuff.Add Mid(cellValue, i - 1, 1), "1"
End If
Else
i = i + 1
End If
Wend
End Function
And heres a quick little function used to print out the contents of the dictionary
Sub printout(dict As Scripting.Dictionary, row As Integer)
Dim i As Integer: i = 2
For Each Key In dict.Keys
Cells(row, i).Value = Key & ": " & dict.Item(Key)
i = i + 1
Next
End Sub
My 2c:
Sub tester()
Dim r, arr, v
arr = Array("C", "Z", "Na", "N", "O", "Cl", "Br", "F")
For Each v In arr
Debug.Print v, ParseCount("C15H12Na2N5O4ClBr", v)
Next v
End Sub
Function ParseCount(f, s)
Const ALL_SYMBOLS As String = "Ac,Al,Am,Sb,Ar,As,At,Ba,Bk,Be,Bi,Bh,Br,Cd,Ca,Cf,Ce,Cs,Cl," & _
"Cr,Co,Cn,Cu,Cm,Ds,Db,Dy,Es,Er,Eu,Fm,Fl,Fr,Gd,Ga,Ge,Au,Hf,Hs,He,Ho,In,Ir,Fe,Kr,La,Lr," & _
"Pb,Li,Lv,Lu,Mg,Mn,Mt,Md,Hg,Mo,Mc,Nd,Ne,Np,Ni,Nh,Nb,No,Og,Os,Pd,Pt,Pu,Po,Pr,Pm,Pa,Ra," & _
"Rn,Re,Rh,Rg,Rb,Ru,Rf,Sm,Sc,Sg,Se,Si,Ag,Na,Sr,Ta,Tc,Te,Ts,Tb,Tl,Th,Tm,Sn,Ti,Xe,Yb,Zn," & _
"Zr,B,C,F,H,I,N,O,P,K,S,W,U,V,Y"
Dim atoms, rv, pos, i As Long
atoms = Split(ALL_SYMBOLS, ",")
rv = 0 'default return value
If IsError(Application.Match(s, atoms, 0)) Then
rv = -1 'not valid atomic symbol
Else
i = 1
pos = InStr(i, f, s, vbBinaryCompare)
If pos > 0 Then
If Len(s) = 2 Then
'should be a true match...
rv = ExtractNumber(f, pos + 2)
ElseIf Len(s) = 1 Then
'check for false positives eg "N" matches on "Na"
Do While pos > 0 And Mid(f, pos + 1, 1) Like "[a-z]"
i = pos + 1
pos = InStr(i, f, s, vbBinaryCompare)
Loop
If pos > 0 Then rv = ExtractNumber(f, pos + 1)
Else
'exotic chemistry...
End If
End If
End If
ParseCount = rv
End Function
'extract consecutive numeric digits from f starting at pos
' *returns 1 if no number present*
Function ExtractNumber(f, pos)
Dim rv, s, i As Long
Do While (pos + i) <= Len(f)
If Not Mid(f, pos + i, 1) Like "#" Then Exit Do
i = i + 1
Loop
ExtractNumber = IIf(i = 0, 1, Mid(f, pos, i))
End Function
I am looking for a formula to list occurrences of values only if they are greater than 2 times; and the result would be shown as in the image.
For example, if a value repeats 2 times, it's shown by "2", and 3 times by "3". so if there are two numbers repeating in the range, then it would be shown by "32" as in the image below. (There is no need for a comma between the numbers). Thanks.
Here is a simple UDF:
Function mycount(rng As Range) As String
Dim str As String
Dim rngcnt As Range
For Each rngcnt In rng
If InStr("," & str & ",", "," & rngcnt.Value & ",") = 0 Then
If Application.WorksheetFunction.CountIf(rng, rngcnt) > 1 Then
mycount = mycount & Application.WorksheetFunction.CountIf(rng, rngcnt)
str = str & "," & rngcnt
End If
End If
Next rngcnt
End Function
So your call on the sheet would be:
=mycount(A2:H2)
Then copy down.
The way I got it is defining a VBA function.This function uses a dictionary, so it is necessary to add th reference to 'Microsoft Scripting Runtime' (look here). Also, I have used a function to sort the characters in string from here
Function Repetitions(rng As Range)
Dim dict As New Scripting.Dictionary
Dim res() As Integer
For aux = 1 To rng.Count
Dim numero As Integer
numero = rng.Cells(1, aux).Value
If Not dict.Exists(numero) Then
dict.Add numero, 1
Else
dict(numero) = dict(numero) + 1
End If
Next aux
Dim result As String
result = ""
For aux = 0 To UBound(dict.Items)
If dict.Items(aux) > 1 Then result = result & dict.Items(aux)
Next aux
While Len(result)
iTemp = 1
Temp = Left(result, 1)
For I = 2 To Len(result)
If StrComp(Mid(result, I, 1), Temp, vbTextCompare) = 0 Then
If StrComp(Mid(result, I, 1), Temp, vbBinaryCompare) = 1 Then
Temp = Mid(result, I, 1)
iTemp = I
End If
End If
If StrComp(Mid(result, I, 1), Temp, vbTextCompare) = 1 Then
Temp = Mid(result, I, 1)
iTemp = I
End If
Next I
Repetitions = Repetitions & Temp
result = Left(result, iTemp - 1) & _
Mid(result, iTemp + 1)
Wend
End Function
After all, you will be able to use the function as formula in Excel, calling it as following for example:
=Repetitions(A2:F2)