I'm trying to figure out whether a PHP process is running or not using the ps aux command and passing grep to it, for instance:
I need it to return and tell me whether a process ID on php is running or not but whenever I try the following I always seem to get a result where the result is appending 1234 at the end, what am I missing?
ps aux | grep 'php|1234'
Suggesting pgrep command instead of ps aux
pgrep -af "php"
The reason your get always one line:
php process is not matched with grep 'php|123123123'
ps aux list the grep command you submitted and the grep command match itself
maybe you meant grep -E 'php|123123123' to match php or 123123123
The solution I've come across thanks to a user above is to do:
ps aux | grep '123456' | grep 'grep' -v
Where 123456 would be the process ID
Related
I'm trying to tweak a bash script to pull back PID's of the individual application accounts when there are multiple applications running as a masterId. This used to run under individual user accounts, but recent changes have forced the applications to all run under a combined "masterId", but still maintain a unique application Id that I can grep against.
Normally
pgrep -u "appId"
would give me a single PID. Now I have to run:
pgrep -u "masterId"
it returns all of the PID's (each one is it's own application).
1234
2345
3456
I'm trying to come up with a command to bring me back just the PID of the appAccount(n) so I can pipe it into other useful commands. I can do a double grep (which is closer to what I want):
ps aux | grep -i "masterId" | grep -i "appAccount(n)"
and that will get me the entire single process information, but I just want the PID to do something like:
ps aux | grep -i "masterId" | grep -i "appAccount(n)" | xargs sudo -u appAccount(n) kill -9
How do I modify the initial above command to get just the PID? Is there a better way to do this?
pgrep --euid "masterId" --list-full | awk '/appAccount(n)/ {print $1}'
Output the full process command line, then select the one with the desired account and print the first field (pid).
i'm new to bash scripting and i have to determine if a process is running in a linux environment.
Actually i use the follow command to do the job:
#ps -ef | awk '{print substr($0, index($0,$8))}' | grep -v grep | grep -w -F $PROCESSNAME
where
awk '{print substr($0, index($0,$8))}'
allow me to ignore UID PID PPID C STIME TTY TIME fields and
grep -v grep
allow me to ignore the row that contains the command itself. So at this point i have a list of all processes running on the system.
Finally:
grep -w -F $PROCESSNAME
read a variable which contains the name of the process that i want to check.
For what i understand the full command should return only the row that has the exact value of $PROCESSNAME
Actually this doesn't works correctly for processes that follow the pattern "[processname]", and probably also for other patterns.
For example to simplify, if i have a running process named "[vmmemctl]" and i run:
#ps -ef | grep -v grep | grep -w -F "vmmemctl]"
it actually returns a result:
#root 615 2 0 Feb26 ? 00:01:00 [vmmemctl]
but the actual process name in the command is different from the process name in the result.
What is the correct command that doesn't have this behavior?
Thank you
awk to the rescue!
ps -ef | awk '$8=="[command]"{NF=8;print}'
or
ps -ef | awk -v c="vmmemctl]" '$8==c{NF=8;print}'
note that this is for an exact match not pattern.
since this is an exact match the command can have spaces and other special chars in it (it's not pattern match but string equality). Using your variable name it will look like this
ps -ef | awk -v c="$PROCESSNAME" '$8==c{NF=8;print}'
Linux command line:
When i execute the following command ps -ef |grep tomcat it shows me the following process
abcapp 28119 1 0 12:53 ? 00:00:19 /usr/java/jdk1.6.0_10//bin/java -Xmx256m -Dabc.log.file=/home/app/apps/rum/logs/dev.log -Dabc.config=dev -Dlog4j.configuration=file:///home/abcapp/env/abc_env/abc_env-1.2/config/log4j-webapp.properties -Djava.util.logging.manager=org.apache.juli.ClassLoaderLogManager -Djava.util.logging.config.file=/home/abcapp/env/tomcat/tomcat-5.5-26-rum/conf/logging.properties -Djava.endorsed.dirs=/home/abcapp/env/tomcat/tomcat-5.5-26-rum/common/endorsed -classpath :/home/abcapp/env/tomcat/tomcat-5.5-26-rum/bin/bootstrap.jar:/home/abcapp/env/tomcat/tomcat-5.5-26-rum/bin/commons-logging-api.jar -Dcatalina.base=/home/abcapp/env/tomcat/tomcat-5.5-26-rum -Dcatalina.home=/home/abcapp/env/tomcat/tomcat-5.5-26-rum -Djava.io.tmpdir=/home/abcapp/env/tomcat/tomcat-5.5-26-rum/temp org.apache.catalina.startup.Bootstrap start
but when i issue following command it shows nothing
pgrep tomcat-5.5-26-rum OR pgrep "*-rum"
can some body help me how can i get tomcat process id by its name regex for "*-rum"
Thanks in advance.
pgrep only search for the process name without the full path (in your case only java) and without arguments.
Since tomcat-5.5-26-rum is part of the latter, i'd search the pid with
ps -ef | grep tomcat-5.5-26-rum | grep java | awk ' { print $2 } '
The double grep is useful to discard the grep pids itself
Just add following line at the start of catalina.sh file
CATALINA_PID="$CATALINA_BASE"/logs/tomcat.pid
OR
CATALINA_PID=/tmp/tomcat.pid
And bounce tomcat. This will create a tomcat.pid file in the given path and put the Tomcat process pid in it.
This worked for me:
This will give the process id of current running tomcat
echo ps aux | grep org.apache.catalina.startup.Bootstrap | grep -v grep | awk '{ print $2 }'
I am trying to use the ps -o command to get just specific info about processes matching a certain name. However, I am having some issues on this, when I try to use this even to just get all processes, like so, it just returns a subset of what a normal ps -ef would return (it doesn't return nearly the same number of results so its not returning all running processes)
ps -ef -o pid,time,comm
I want to try something like this (below) but incorporate the ps -o to just get specific info from it (just the PID)
ps -ef |grep `whoami`| grep firefox-bin
Any advice is appreciated as to how to do this properly, thanks
This will get you the PID of a process by name:
pidof name
Which you can then plug back in to ps for more detail:
ps -p $(pidof name)
This is a bit old, but I guess what you want is: ps -o pid -C PROCESS_NAME, for example:
ps -o pid -C bash
EDIT: Dependening on the sort of output you expect, pgrep would be more elegant. This, in my knowledge, is Linux specific and result in similar output as above. For example:
pgrep bash
ps -fC PROCESSNAME
ps and grep is a dangerous combination -- grep tries to match everything on each line (thus the all too common: grep -v grep hack). ps -C doesn't use grep, it uses the process table for an exact match. Thus, you'll get an accurate list with: ps -fC sh rather finding every process with sh somewhere on the line.
Sometimes you need to grep the process by name - in that case:
ps aux | grep simple-scan
Example output:
simple-scan 1090 0.0 0.1 4248 1432 ? S Jun11 0:00
Sorry, much late to the party, but I'll add here that if you wanted to capture processes with names identical to your search string, you could do
pgrep -x PROCESS_NAME
-x Require an exact match of the process name, or argument list if -f is given.
The default is to match any substring.
This is extremely useful if your original process created child processes (possibly zombie when you query) which prefix the original process' name in their own name and you are trying to exclude them from your results. There are many UNIX daemons which do this. My go-to example is ninja-dev-sync.
When I do the following
ps -aef|grep "asdf"
I get a list of processes that are running. Each one of my process has the following text in the output:
-ProcessName=XXXX
I'd like to be able to format the out put so all I get is:
The following processes are running:
Process A
Process B
etc..
Use sed(1):
... | grep "asdf" | sed -e 's:.*-ProcessName=\([^ ]\+\).*:Process \1:'
you can format your ps output using -o eg
ps -eo args| awk -F"=" '/asdf/{print $2}'