I have connected to the live database..I want to calculate the count of days between two columns, example start day and end day.
one output of count if start day is greater than end day and
another if end day is greater than start day.
I've tried this:
Count = Calculate(Count ('Table'[Project]),Table[Startday]>Table[endday])
But I cant write Table(enddate) instead it ask for particular date in string format"02/02/2022"
Can anyone help me to solve this issue using measure
Related
I have a 3 column worksheet with columns Date, Time, Value. I need to calculate a fourth column with a running total for each row for all Value where Date+Time is in the past 24 hours. The number of readings vary over the 24 hours, being as little as once a second to once every few minutes.
A SELECT would look something like:
select
ot.dt
, ot.tm
, ot.value
, sum(it.value)
from
readings ot
inner join readings it
on addtime(ot.dt,ot.tm) >= addtime(it.dt,it.tm)
and convert(timediff(addtime(ot.dt, ot.tm), addtime(it.dt, it.tm)), decimal) < 240000
group by
ot.dt
, ot.tm
, ot.value
The screenshot below gives an idea of what the resulting output should look like. Different from actual requirement is that here a reading is provided for every hr and the fourth column (SumPast3Hours) only sums the current Value and the previous two. In actuality the. number of rows to sum will vary.
It seems ungrateful not to use your test data, but I wanted to answer the original question and consider what would happen across different days.
I can think of two possible approaches:
(1) Use sumifs, one for the case where the readings are in the current day and one for the case where they are in the previous day
=SUMIFS(C$2:C2,A$2:A2,A2)+SUMIFS(C$2:C2,A$2:A2,A2-1,B$2:B2,">="&B2)
(2) Use sum (or sumproduct)
=SUM(C2:C$2*((A2:A$2+B2:B$2)>=(A2+B2-1)))
This relies on the fact that dates are consecutive whole numbers, and hours are fractions (1 hour = 1/24th of a day)
You may want to change >= to > to exclude readings which are exactly 24 hours before the current reading.
In assessing how many agents can be added to certain times of day without exceeding the number of seats in the call center, I'm trying to discern how many agents are scheduled for each half hour interval on each day of the week.
Using the =SUMPRODUCT(((A$2:A$1000<=D2)+(B$2:B$1000>D2)+(A$2:A$1000>B$2:B$1000)=2)+0) formula I've been able to identify how many total agents work for each interval, however this doesn't take the day of week into account.
I currently have my spreadsheet setup this way:
K is the start time of the shift, L is the end time of the shift, M to S pulls data from another sheet that shows a 1 if the agent works on that day of the week and 0 if they do not, and then U has all the time intervals listed out. In the example, it's cut off but the columns continue down as needed. U goes to 49 and I've just been using a range from 2 to 500 for the others as we currently do not have that many shifts and I'm leaving space for the moment.
After some Googling, I tried =SUMPRODUCT(--(M2:M500="1"),(((K$2:K$1000<=U2)+(L$2:L$1000>U2)+(K$2:K$1000>L$2:L$1000)=2)+0)) but it only returns #VALUE! so I'm not sure what I'm doing wrong.
Any suggestions of how I can make this work? Please let me know if more information would be useful. Thanks.
=sumproduct(($K$2:$K$1000<=U2)*($L$2:$L$1000>=U2))
That will count the number of occurrences where the start time is less than or equal to the time in U2 AND the end time is greater than or equal to U2. It will check time from row 2 to row 1000. Any time one condition is checked and its true the comparison will result in value of TRUE and FALSE when its not true. The * act like an AND condition while at the same time converts TRUE and FALSE values to 1 and 0. So both conditions have to be true for a value of 1 to result. Sumproduct then totals up all the 1 and 0 to get you a count.
In order to consider the days of the week, you will need one thing to be true. Your headers in M1:S1 will need to be unique (which I believe they are). You will need to either repeat them in adjacent columns to M or in say V1 you have a cell that can change to the header of the day of the week you are interested in. I would assume the former so you can see each day at the same time.
In order to do this you want to add more conditions and pay attention to you reference locks $.
In V2 you could use the following formula and copy down and to the right as needed:
=sumproduct(($K$2:$K$1000<=$U2)*($L$2:$L$1000>=$U2)*(M$2:M$1000))
UPDATE #1
ISSUE 1 Time ranges ending the following day (after midnight)
It is based on the assumption that the ending time is later than the start time. When a shift starts at 22:00 and end at 6:30 as an example, our mind says that the 0630 is later than 22:00 because it is the following day. Excel however has no clue that 0630 is the following day and without extra information assumes it to be the same day. In excel date is stored as an integer and time is stored as a decimal. When you only supply the time during entry it uses 0 for the date.
In excel the date is the number of days since 1900/01/00. So one way to deal with your time out is to add a day to it. This way excel will know your out time is after your in time when the hour is actually earlier in the day.
See your sample data below.
Using your sample data, I did a straight copy of the value in L and placed it in M (=L3 and copy down). I then changed the cell display format from time to general. This allows you to see how excel sees the time. Note how all the time is less than 1.
In column N I added 1 to the value when the out time was less than the in time to indicate that it was the following day and we had not actually invented time travel. I also used the trick of a math operation will convert a TRUE/FALSE result to 1 or 0 to shorten the equation. I used =M3+(L3<K3) and copied down. You will notice in the green bands that the values are now greater than 1.
In the next column I just copied the values from N over using =N3 copied down, and then I applied just a time display format for the cell. Because it is only time format, the date is ignored and visually your time in column O looks the same as column L. The big difference is excel now knows that it is the following day.
you can quickly fix your out times by using the following formula in a blank column and then copying the results and pasting them back over the source column using paste special values.
=M2+(L2<K2)
The next part is for your time check. When looking at the 12:00 time you need to look at 1200 of the current day incase a shift started at 12:00 and you need to look at the 1200 period of the following day. In order to do that we need to modify the the original formula as follows:
=sumproduct(($K$2:$K$1000<=$U2)*($L$2:$L$1000>=$U2)*(M$2:M$1000)+($K$2:$K$1000<=$U2+1)*($L$2:$L$1000>=$U2+1)*(M$2:M$1000))
Note that the + in the middle of (M$2:M$1000) + ($K$2:$K$1000<=$U2+1)? This + acts like an OR function.
Issue 2 Time In/Out 15 minute increments, range 30 minute increments
You may be able to achieve this with the ROUNDDOWN Function or MROUND. I would combine this with the TIME function. Basically you want to have any quarter hour start time be treated as 15 minutes sooner.
=ROUNDDOWN(E3/TIME(0,30,0),0)*TIME(0,30,0)
Where E3 is your time to be converted
So your formula may wind up looking something like:
=sumproduct((ROUNDDOWN($K$2:$K$1000/TIME(0,30,0),0)*TIME(0,30,0)<=$U2)*($L$2:$L$1000>=$U2)*(M$2:M$1000)+((ROUNDDOWN($K$2:$K$1000/TIME(0,30,0),0)*TIME(0,30,0)<=$U2+1)*($L$2:$L$1000>=$U2+1)*(M$2:M$1000))
similar option could be used for the leaving time and rounding it up to the next 30 minute interval. In which case just use the ROUNDUP function. Though I am not sure it is required.
This task seems easy enough yet I just can't figure a way of doing this without resorting to vba.
All I need is to know the number of hours an employee has used up on annual leave, based on a start and end date, and their hours of work.
To be more clear, this example shows one employees contracted hours from Monday to Sunday i.e. they work only Weds, Thurs, and Friday, for 7.5 hours each day.
Below shows the start and end date that the employee has chosen to take for annual leave. I need to calculate, based on their contracted hours, how much annual leave is used between the two dates. The answer would be 45 hours in this case.
Here's another approach - I've expanded the days between the start and end dates into an array then used the resulting day numbers to offset into the days of work range
=SUMPRODUCT(N(OFFSET(A3,0,WEEKDAY(ROW(INDIRECT(A6&":"&B6)),2)-1)))
If you had a list of holiday dates somewhere (say in I3:N3) you could exclude them as follows
=SUMPRODUCT(N(OFFSET(A3,0,WEEKDAY(ROW(INDIRECT(A6&":"&B6)),2)-1))*ISNA(MATCH(ROW(INDIRECT(A6&":"&B6)),I3:N3,0)))
- it is a bit long-winded but the only way I can think of at the moment.
I am doing some work in Excel and am running into a bit of a problem. The instruments I am working with save the date and the time of the measurements and I can read this data into Excel with the following format:
A B
1 Date: Time:
2 12/11/12 2:36:25
3 12/12/12 1:46:14
What I am looking to do is find the difference in the two date/time stamps in mins so that I can create a decay curve from the data. So In Excel, I am looking to Make this (if the number of mins in this example is wrong I just calculated it by hand quickly):
A B C
1 Date: Time: Time Elapsed (Minutes)
2 12/11/12 2:36:25 -
3 12/12/12 1:46:14 1436.82
I Have looked around for a bit and found several methods for the difference in time but they always assume that the dates are the same. I exaggerated the time between my measurements some but that roll over of days is what is causing me grief. Any suggestions or hints as to how to go about this would be great. Even If I could find the difference between the date and times in hrs or days in a decimal format, I could just multiple by a constant to get my answer. Please note, I do have experience with programming and Excel but please explain in details. I sometimes get lost in steps.
time and date are both stored as numerical, decimal values (floating point actually). Dates are the whole numbers and time is the decimal part (1/24 = 1 hour, 1/24*1/60 is one minute etc...)
Date-time difference is calculated as:
date2-date1
time2-time1
which will give you the answer in days, now multiply by 24 (hours in day) and then by 60 (minutes in hour) and you are there:
time elapsed = ((date2-date1) + (time2-time1)) * 24 * 60
or
C3 = ((A3-A2)+(B3-B2))*24*60
To add a bit more perspective, Excel stores date and times as serial numbers.
Here is a Reference material to read up.
I would suggest you to use the following:
Combine date to it's time and then do the difference. So it will not cause you any issues of next day or anything.
Please refer to the image with calculations. You may leave your total minutes cell as general or number format.
MS EXCEL Article: Calculate the difference between two times
Example as per this article
Neat way to do this is:
=MOD(end-start,1)*24
where start and end are formatted as "09:00" and "17:00"
Midnight shift
If start and end time are on the same day the MOD function does not affect anything. If the end time crosses midnight, and the end is earlier then start (say you start 23PM and finish 1AM, so result is 2 hours), the MOD function flips the sign of the difference.
Note that this formula calculates the difference between two times (actually two dates) as decimal value. If you want to see the result as time, display the result as time (ctrl+shift+2).
https://exceljet.net/formula/time-difference-in-hours-as-decimal-value
get n day between two dates, by using days360 function =days360(dateA,dateB)
find minute with this formula using timeA as reference =(timeB-$timeA+n*"24:00")*1440
voila you get minutes between two time and dates
I think =TEXT(<cellA> - <cellB>; "[h]:mm:ss") is a more concise answer. This way, you can have your column as a datetime.
This sounds simple but I have been pulling my hair out trying to figure out a solution. Any help before I go bald would be great.
I need a formula which is able to
calculate the duration in (days, hrs, mins) between two date\time values (eg 05/12/2012 5:30 PM and say 07/12/2012 5:45 PM);
excluding weekends and holidays.
I would like the result of the formula to read as follows "e.g 2 Days 0 Hrs and 15 Mins".
Thanks
Link to sample workbook
You can use NETWORKDAYS and NETWORKDAYS.INTL to achieve this
A bit of manipulation is required as these return net whole days:
Use these functions to calculate the number of non workdays, then subtract from the difference between start and end dates
=E3-D3-(NETWORKDAYS.INTL(D3,E3,"0000000")-NETWORKDAYS(D3,E3,$A$16:$A$24))
This returns the working day difference, where 1.0 = 1 day
NETWORKDAYS.INTL(D3,E3,"0000000") calculates whole days between the two dates (no weekends, no holidays)
NETWORKDAYS(D3,E3,"0000000",$A$16:$A$24) calculates whole working days days between the two dates (Sat/Sun weekends, holidays as per your list in $A$16:$A$24)
Difference in non-working days between the two dates.
E3-D3 is time between start and end date/times (1.0 = 1 day)
Use custom number formatting to display thye result in the format you require
d "Days" h "Hours" mm "Mins"
Note: this format won't work for negative values, you will need an alternative for when end date is before start date.
The following formula works like a treat with no additional formatting or manipulation.
To make it more stable I have turned all the holiday dates for UK 2012/13 into ‘Excel Serial Number’ format and placed them in an array bracket.
Replacing the "D5" in the formula with your cell reference for your course or metric "End Date" and "E5" with your course or Metric for "Completion Date".
=IF(E5<D5,"-"&TEXT(D5-E5,"h:mm"),NETWORKDAYS(D5,E5,({40910,41005,41008,41036,41064,41065,41148,41268,41269,41275,41362,41365,41400,41421,41512,41633,41634}))-1-(MOD(E5,1)<MOD(D5,1))&" days "&TEXT(E5-D5,"h:mm"))