How do you map a value to a sub dictionary in python? - python-3.x

I have the following dictionary:
{Jason:{vegetables:{broccoli, carrot}}, Bob:{vegetables:{broccoli}}}
How can I map the value "potato" to Bob so that it appears in vegetables? Like this:
{Jason:{vegetables:{broccoli, carrot}}, Bob:{vegetables:{broccoli, potato}}}
Thanks!

What you posted could be valid Python (if Jason, Bob etc are variables) but you likely are working with strings and lists so I'm going to assume the following structure:
my_dict = {
'Jason': {'vegetables': ['broccoli', 'carrot']},
'Bob': {'vegetables': ['broccoli']}
}
In that case, the vegetables is a list to which you can append items:
my_dict['Bob']['vegetables'].append('potato')
If you really meant the vegetables to be a set (indicated by using curly braces), you would use:
my_dict['Bob']['vegetables'].add('potato')

Related

I need an Integer but its a string with a comma

I'm using sqlite3 and trying to get the oid by using the title of the row and then trying to use that oid to update a column in my table.
allOID is a tuple, and when I print it i get this:
>>> <class 'tuple'>
>>> [(1,)]
I'm trying to get the integer out of this tuple but the comma is throwing it off and I can't seem to get it.
Here is all of the code being used currently:
c.execute("""SELECT oid FROM books
WHERE title = :title""",
{
'title': title
})
allOID = c.fetchall()
print(type(allOID[0]))
print(allOID)
c.execute("SELECT * FROM books")
c.execute("""UPDATE books SET
rented = :rented
WHERE oid = :oid""",
{
'rented': rentedVar,
'oid': allOID[0]
})
any help and comments are greatly appreciated!
The comma just indicates that it is a tuple with a single element.
Access it using allOID[0][0].
allOID[0] gets you the tuple out of the list of results, going one level further with allOID[0][0] gets you the first element of the tuple.
For more info, see the docs:
Empty tuples are constructed by an empty pair of parentheses; a tuple with one item is constructed by following a value with a comma (it is not sufficient to enclose a single value in parentheses). Ugly, but effective.

Check if string is in list with python

I'm new to python, and I'm trying to check if a String is inside a list.
I have these two variables:
new_filename: 'SOLICITUDES2_20201206.DAT' (str type)
and
downloaded_files:
[['SOLICITUDES-20201207.TXT'], ['SOLICITUDES-20201015.TXT'], ['SOLICITUDES2_20201206.DAT']] (list type)
for checking if the string is inside the list, I'm using the following:
if new_filename in downloaded_files:
print(new_filename,'downloaded')
and I never get inside the if.
But if I do the same, but with hard-coded text, it works:
if ['SOLICITUDES2_20201206.DAT'] in downloaded_files_list:
print(new_filename,'downloaded')
What am I doing wrong?
Thanks!
Your downloaded_files is a list of lists. A list can contain anything insider it, numbers, list, dictionaries, strings and etc. If you are trying to find if your string is inside the list, the if statement will only look for identical matches, i.e., strings.
What I suggest you do is get all the strings into a list instead of a list of lists. You can do it using list comprehension:
downloaded_files = [['SOLICITUDES-20201207.TXT'], ['SOLICITUDES-20201015.TXT'], ['SOLICITUDES2_20201206.DAT']]
downloaded_files_list = [file[0] for file in downloaded_files]
Then, your if statement should work:
new_filename = 'SOLICITUDES2_20201206.DAT'
if new_filename in downloaded_files_list:
print(new_filename,'downloaded')
Your code is asking if a string is in a list of lists of a single string each, which is why it doesn't find any.

How do I take a string and turn it into a list using SCALA?

I am brand new to Scala and having a tough time figuring this out.
I have a string like this:
a = "The dog crossed the street"
I want to create a list that looks like below:
a = List("The","dog","crossed","the","street")
I tried doing this using .split(" ") and then returning that, but it seems to do nothing and returns the same string. Could anyone help me out here?
It's safer to split() on one-or-more whitespace characters, just in case there are any tabs or adjacent spaces in the mix.
split() returns an Array so if you want a List you'll need to convert it.
"The dog\tcrossed\nthe street".split("\\s+").toList
//res0: List[String] = List(The, dog, crossed, the, street)

count occurrences of a string in a structure

I have a structure mydata and I need to access one of its fields mydata.myfield, and within that field, access another field mydata.myfield.mysecondfield. In the last field, mydata.myfield.mysecondfield I need to check how many times a particular string ('apple') occurs.
I have tried with:
aaa=unique(mydata.myfield.mysecondfield,'apple')
bbb=cellfun(#(x) sum(ismember(mydata.myfield.mysecondfield,x)),aaa,'un',0)
but I get this error: Attempt to reference field of non-structure array.
The structure contains fields with both strings and numeric values.
The underlying problem may be due to the fact that the structure is a little bit different from how you describe it. Following your question, I created it as follows:
mydata = struct();
mydata.myfield.mysecondfield = {'apple' 'apple' 'orange' 'banana' 'apple' 'kiwi'};
and since I'm not getting the same error you get, I think the underlying types may be slightly mismatching. Anyway, given mydata defined as above, if you change your code as follows, it should work but it will return the count of every unique occurrence within the field:
aaa = unique(mydata.myfield.mysecondfield);
bbb = cellfun(#(x) sum(ismember(mydata.myfield.mysecondfield,x)),aaa,'un',0)
bbb =
4×1 cell array
[3]
[1]
[1]
[1]
If you only want to count the number of apple occurrences, you should use the following approach instead:
apple_count = sum(strcmp(mydata.myfield.mysecondfield,'apple')); % 3

Reading Words for a String

I want to manipulate this string:
"Roger:Rabbit:22:California"
and display the output as follows:
Name: Roger Rabbit
Age: 22
State: California
I am wondering what will be the best approached to this?
For this you may use the String split() method. Mention your delimiter as :. Then you want to make sure you create an array out of the output of your split method with the different strings split. In your System.out.println() you can mention the array index of your newly created array elements as System.out.println("Name" + myIndex[0]).
Resource: https://www.tutorialspoint.com/java/java_string_split.htm

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