Loop on array and delete objects with specific value - node.js

Question

I have an array similar than this one, called websiteproducts:
[{
"memberid": 280,
"state": "AL",
"product": "1",
"deleteProduct": 1,
"waitingDays": 0
},
{
"memberid": 280,
"state": "AL",
"product": "2",
"deleteProduct": 1,
"waitingDays": 0
},
{
"memberid": 280,
"state": "AL",
"product": "3",
"deleteProduct": 1,
"waitingDays": 0
},
{
"memberid": 280,
"state": "AL",
"product": "4",
"deleteProduct": 0,
"waitingDays": 0
}
]
And Im trying to delete all objects that have "deleteProduct" = 1 as follows:
for (let i = 0; i < websiteproducts.length; i++) {
if (websiteproducts[i].deleteProduct == 1) {
websiteproducts.splice(i, 1)
}
}
But only the first object is deleted.
I believe it has to do with the fact that Im deleting the item from the array on the fly.
But this one works, when copying the objects to a new array:
let finalProducts = []
for (let i = 0; i < websiteproducts.length; i++) {
if (websiteproducts[i].deleteProduct != 1) {
finalProducts.push(websiteproducts[i])
}
}
Is there a way to delete the objects straight from the array through a loop, without having to create a second array?
Thanks.

Answer 1

You can use the filter function on the array, it only returns the elements that meet the condition.
let finalProd = websiteproducts.filter(prod => prod.deleteProduct != 1)

Answer 2

You don't have to use a loop at all. You can use Array.prototype.filter().
This returns a new array with the filtered elements removed:
const filtered = websiteproducts.filter(product => product.deleteProduct != 1);

Answer 3

You must decrement the index variable after splice like this :
websiteproducts.splice(i, 1);
i--;