I would like to add synonyms for the subcommands in my Haskell command line tool. For example summarise and summarize should yield the same result. Of course I could just add an entirely separate command summarize, that appears as an own element in the output of --help. But maybe there is a more elegant way.
Here is a self-contained example in a stack script opt_ex.hs:
#!/usr/bin/env stack
-- stack --resolver lts-18.17 script --package optparse-applicative
import Options.Applicative
import Data.Semigroup ((<>))
data Options = CmdGreet GreetArgs | CmdGroot GreetArgs
newtype GreetArgs = GreetArgs String
main :: IO ()
main = do
cmdOpts <- customExecParser (prefs showHelpOnEmpty) (info optParser fullDesc)
runCmd cmdOpts
optParser :: Parser Options
optParser = subparser (
command "greet" (info (CmdGreet <$> sample) (progDesc "Print greeting 1")) <>
command "groot" (info (CmdGroot <$> sample) (progDesc "Print greeting 2"))
)
runCmd :: Options -> IO ()
runCmd o = case o of
CmdGreet opts -> greet opts
CmdGroot opts -> groot opts
greet :: GreetArgs -> IO ()
greet (GreetArgs h) = putStrLn $ "Hello, " ++ h ++ "!"
groot :: GreetArgs -> IO ()
groot (GreetArgs h) = putStrLn $ "Howdy, " ++ h ++ "!"
sample :: Parser GreetArgs
sample = GreetArgs <$> strArgument ( metavar "TARGET" )
You can run this with ./opt_ex.hs greet John to get Hello, John! and with ./opt_ex.hs groot John to get Howdy, John!. Running ./opt_ex.hs will give you the following overview:
Usage: opt_ex.hs COMMAND
Available commands:
greet Print greeting 1
groot Print greeting 2
What would be the most elegant way, to add a command gruut in this example, which behaves exactly like greet, but produces the least amount of overhead, both in the code and for the user?
Ideally I would like ./opt_ex.hs to yield something like this:
Usage: opt_ex.hs COMMAND
Available commands:
greet|gruut Print greeting 1
groot Print greeting 2
I don't think you can do this. It works fine for options, because the definition of OptField contains a list of OptName, and adds to that list when you use (<>). But the definition of CommandFields, the thing returned by command, is
data CommandFields a = CommandFields
{ cmdCommands :: [(String, ParserInfo a)]
, cmdGroup :: Maybe String }
Each String name is thus associated with a different ParserInfo. Of course, you can define a variable containing any ParserInfo you like, and reuse it across two commands, so you won't have to repeat the ParserInfo. But as far as optparse-applicative is concerned, those two commands are distinct, so it will list them separately in the help text. For your example, this would look like
optParser = let greeting1 = info (CmdGreet <$> sample) (progDesc "Print greeting 1")
in subparser $
command "greet" greeting1 <>
command "gruut" greeting1 <>
command "groot" (info (CmdGroot <$> sample) (progDesc "Print greeting 2"))
and indeed, when run we see both commands listed:
Usage: optparse COMMAND
Available commands:
greet Print greeting 1
gruut Print greeting 1
groot Print greeting 2
Related
I'm trying to learn how to work with IO in Haskell by writing a function that, if there is a flag, will take a list of points from a file, and if there is no flag, it asks the user to enter them.
dispatch :: [String] -> IO ()
dispatch argList = do
if "file" `elem` argList
then do
let (path : otherArgs) = argList
points <- getPointsFile path
else
print "Enter a point in the format: x;y"
input <- getLine
if (input == "exit")
then do
print "The user inputted list:"
print $ reverse xs
else (inputStrings (input:xs))
if "help" `elem` argList
then help
else return ()
dispatch [] = return ()
dispatch _ = error "Error: invalid args"
getPointsFile :: String -> IO ([(Double, Double)])
getPointsFile path = do
handle <- openFile path ReadMode
contents <- hGetContents handle
let points_str = lines contents
let points = foldl (\l d -> l ++ [tuplify2 $ splitOn ";" d]) [] points_str
hClose handle
return points
I get this: do-notation in pattern Possibly caused by a missing 'do'?` after `if "file" `elem` argList.
I'm also worried about the binding issue, assuming that I have another flag that says which method will be used to process the points. Obviously it waits for points, but I don't know how to make points visible not only in if then else, constructs. In imperative languages I would write something like:
init points
if ... { points = a}
else points = b
some actions with points
How I can do something similar in Haskell?
Here's a fairly minimal example that I've done half a dozen times when I'm writing something quick and dirty, don't have a complicated argument structure, and so can't be bothered to do a proper job of setting up one of the usual command-line parsing libraries. It doesn't explain what went wrong with your approach -- there's an existing good answer there -- it's just an attempt to show what this kind of thing looks like when done idiomatically.
import System.Environment
import System.Exit
import System.IO
main :: IO ()
main = do
args <- getArgs
pts <- case args of
["--help"] -> usage stdout ExitSuccess
["--file", f] -> getPointsFile f
[] -> getPointsNoFile
_ -> usage stderr (ExitFailure 1)
print (frobnicate pts)
usage :: Handle -> ExitCode -> IO a
usage h c = do
nm <- getProgName
hPutStrLn h $ "Usage: " ++ nm ++ " [--file FILE]"
hPutStrLn h $ "Frobnicate the points in FILE, or from stdin if no file is supplied."
exitWith c
getPointsFile :: FilePath -> IO [(Double, Double)]
getPointsFile = {- ... -}
getPointsNoFile :: IO [(Double, Double)]
getPointsNoFile = {- ... -}
frobnicate :: [(Double, Double)] -> Double
frobnicate = {- ... -}
if in Haskell doesn't inherently have anything to do with control flow, it just switches between expressions. Which, in Haskell, happen to include do blocks of statements (if we want to call them that), but you still always need to make that explicit, i.e. you need to say both then do and else do if there are multiple statements in each branch.
Also, all the statements in a do block need to be indented to the same level. So in your case
if "file" `elem` argList
...
if "help" `elem` argList
Or alternatively, if the help check should only happen in the else branch, it needs to be indented to the statements in that do block.
Independent of all that, I would recommend to avoid parsing anything in an IO context. It is usually much less hassle and easier testable to first parse the strings into a pure data structure, which can then easily be processed by the part of the code that does IO. There are libraries like cmdargs and optparse-applicative that help with the parsing part.
Haskell newbie here and also first time asking a question here, apologies in advance for anything I may have missed anything.
Im writing a repl function that takes user input, adds the input to a list and uses haskeline to tab complete user input with previously typed words.
So far I can only complete words with a static list defined before run time.
1- How would I add the input word to the list in repl (SOLVED...?)
2- How would I enable the searchFunc to query the list in the repl loop?
My current code:
import Data.List
import System.Console.Haskeline
-- main method
main :: IO ()
main = runInputT mySettings (repl [])
repl :: [String] -> InputT IO ()
repl list =
do
minput <- getInputLine "> "
case minput of
Nothing -> do
outputStrLn "Error"
repl list
Just input ->
do
outputStrLn "Successfully added input to list"
-- < 1- add input word to list ... is this correct?>
repl (input:list)
mySettings :: Settings IO
mySettings = Settings { historyFile = Just "myhist",
complete = completeWord Nothing " \t" $ return . searchFunc,
autoAddHistory = True
}
searchFunc :: String -> [Completion]
-- < 2- complete word using list of words from repl>
searchFunc str = map simpleCompletion $ filter (str `isPrefixOf`) listFromRepl
Any help is appreciated, thanks in advance.
I'm doing my first steps using Haskell. I created a project using stack and changed the Main.hs into
module Main where
my_fkt :: String -> String
my_fkt input = show (length input)
main :: IO ()
main = interact my_fkt
I build the project via stack build, run it via stack exec firststeps-exe, enter "abcd" and finish input via <CTRL>-D. In the console I now see
abcd4%
The %is inverted. If I use a text file containing the "abcd" (without line break) and execute more sample.txt | stack exec firststeps-exe I see
abcd5%
Why do I get one additional character in the second case and what is the inverted percentage sign?
That is because the definition of interact uses putStr instead of putStrLn.
You can take a look at the source code here.
interact :: (String -> String) -> IO ()
interact f = do s <- getContents
putStr (f s)
To remedy your issue I would go on and create a similar function
interact' :: (String -> String) -> IO ()
interact' f = do s <- getContents
putStrLn (f s)
or if you like to mix it up and write a bit terser code
interact' f = putStrLn =<< (f <$> getContents)
I don't know what the % is or why it is showing up, my guess would be that it is the escaped CTRL-D.
With regards to your second question about the additional "non-existing" character, I am also not sure, but here my guess would be that this is the \EOF.
Btw. you can always check using more testinput | wc -c it should yield the same result as your haskell program.
I have a main like the following:
main :: IO ()
main = do
args <- getArgs
putStrLn $ functionName args
where
functionName args = "problem" ++ (filter (/= '"') $ show (args!!0))
Instead of putting the name to stdout like I do it right now, I want to call the function.
I am aware of the fact, that I could use hint (as mentioned in Haskell: how to evaluate a String like "1+2") but I think that would be pretty overkill for just getting that simple function name.
At the current stage it does not matter if the program crashes if the function does not exist!
Without taking special measures to preserve them, the names of functions will likely be gone completely in a compiled Haskell program.
I would suggest just making a big top-level map:
import Data.Map ( Map )
import qualified Data.Map as Map
functions :: Map String (IO ())
functions = Map.fromList [("problem1", problem1), ...]
call :: String -> IO ()
call name =
case Map.lookup name of
Nothing -> fail $ name + " not found"
Just m -> m
main :: IO ()
main = do
args <- getArgs
call $ functionName args
where
functionName args = "problem" ++ (filter (/= '"') $ show (args!!0))
If you're going to do this, you have a few approaches, but the easiest by far is to just pattern match on it
This method requires that all of your functions you want to call have the same type signature:
problem1 :: Int
problem1 = 1
problem2 :: Int
problem2 = 2
runFunc :: String -> Maybe Int
runFunc "problem1" = Just problem1
runFunc "problem2" = Just problem2
runFunc _ = Nothing
main = do
args <- getArgs
putStrLn $ runFunc $ functionName args
This requires you to add a line to runFunc each time you add a new problemN, but that's pretty manageable.
You can't get a string representation of an identifier, not without fancy non-standard features, because that information isn't retained after compilation. As such, you're going to have to write down those function names as string constants somewhere.
If the function definitions are all in one file anyway, what I would suggest is to use data types and lambdas to avoid having to duplicate those function names altogether:
Data Problem = {
problemName :: String,
evalProblem :: IO () # Or whatever your problem function signatures are
}
problems = [Problem]
problems = [
Problem {
problemName = "problem1",
evalProblem = do ... # Insert code here
},
Problem
problemName = "problem2",
evalProblem = do ... # Insert code here
}
]
main :: IO ()
main = do
args <- getArgs
case find (\x -> problemName x == (args!!0)) problems of
Just x -> evalProblem x
Nothing -> # Handle error
Edit: Just to clarify, I'd say the important takeaway here is that you have an XY Problem.
I'm writing a little shell script in Haskell which can take an optional argument. However, if the argument is not present, I'd like to get a line from stdin in which to ask for a value.
What would be the idiomatic way to do this in Haskell?
#!/usr/bin/env runhaskell
import Control.Applicative ((<$>))
import Data.Char (toLower)
import IO (hFlush, stdout)
import System.Environment (getArgs)
main :: IO ()
main = do args <- getArgs
-- here should be some sort of branching logic that reads
-- the prompt unless `length args == 1`
name <- lowerCase <$> readPrompt "Gimme arg: "
putStrLn name
lowerCase = map toLower
flushString :: String -> IO ()
flushString s = putStr s >> hFlush stdout
readPrompt :: String -> IO String
readPrompt prompt = flushString prompt >> getLine
Oh, and if there's a way to do it with something from Control.Applicative or Control.Arrow I'd like to know. I've become quite keen on these two modules.
Thanks!
main :: IO ()
main = do args <- getArgs
name <- lowerCase <$> case args of
[arg] -> return arg
_ -> readPrompt "Gimme arg: "
putStrLn name
This doesn't fit your specific use case, but the question title made me think immediately of when from Control.Monad. Straight from the docs:
when :: Monad m => Bool -> m () -> m ()
Conditional execution of monadic expressions.
Example:
main = do args <- getArgs
-- arg <- something like what FUZxxl did..
when (length args == 1) (putStrLn $ "Using command line arg: " ++ arg)
-- continue using arg...
You can also use when's cousin unless in similar fashion.