Subtracting in excel
to subtract 50 from {20,20 ,20} respectively we get {0,0,10}
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Try in first cell:
=(SUM($A$11:A11)-$A$10)*(SUM($A$11:A11)>$A$10)
and copy to the right.
The following formula can be used to correctly calculate the amount in cases where the initial number is less than the first value of the array:
=MIN((SUM($A$11:A11)-$A$10)*(SUM($A$11:A11)>$A$10);A11)
Because you need to fix the cell to copy. Refer the cell with 50 as e.g. $A$1 for the cell to be fixed.
Related
I want to get the count of cells used in an excel function.
For example say I have a sum function ='CV'!D11+Farmer!D11+'County'!D11+Rt!D11+WT!D11+'Country'!D11
I need a function that will tell me how many cells were used to get the total sum. In this case it is 6. The tricky part is if one of the cells used is blank I do not want it counted. For instance say cell D11 on the Farmer sheet is blank I do not want it counted in the total. So the total should be 5.
Use COUNT:
=COUNT('CV'!D11,Farmer!D11,'County'!D11,Rt!D11,WT!D11,'Country'!D11)
It will only count the cell if it has a number
You should really try to collate all your data in to a single sheet before running calculations. For the sake of example, I'll assume you have it in the range A1:A5, then you can add handling of the various cases using array formulas:
Get the count of non-empty cells (the ISBLANK function is untrustworthy in my experience): {SUM(IF(LEN(A1:A5)>0,1,0))}
Get the sum of those cells: SUM(A1:A5)
(must use Ctrl+Shift+Enter to enter the formula as an array formula, you will know it worked if the formula shows like {IF(...)} with the curly brackets)
Because blank/missing values are treated implicitly as 0 in the SUM function, this case is simple. If you have other validations then you'd have to write an array formula for the summation as well. For example, only including numbers between a min and max threshold (e.g. if you want to exclude outliers):
{SUM(IF(AND(A1:A5 >= yourMinValue, A1:A5 < yourMaxValue), A1:A5, 0)}.
If I understand your question correctly, you want to literately count the number of cells used in a formula which in your example is summing 6 values from 6 different locations.
I used the following example to demonstrate my solution:
The sum of =A1+B1+C1+D1+E1+F1 is 10 where cell C1 has a 0 value in it but cell E1 is blank.
Using the following array formula I was able to count the number of cells that have a value other than 0:
=SUMPRODUCT(IFERROR(ABS(N(INDIRECT(TRIM(MID(SUBSTITUTE(RIGHT(FORMULATEXT(A3),LEN(FORMULATEXT(A3))-1),"+",REPT(" ",100)),100*ROW(INDIRECT("1:"&LEN(FORMULATEXT(A3))))-99,100)))))>0,0)*1)
Please note you MUST press Ctrl+Shift+Enter upon finishing the formula in the formula bar otherwise they will not function correctly.
The logic is to use a combination of TRIM+MID+SUBSTITUTE+RIGHT+FORMULATEXT+REPT+ROW+INDIRECT to extract the cell addresses from the original formula, then use INDIRECT to convert the cell address into the values stored in those cells, then use a combination of IFERROR+ABS+N to find out if any of these values are not 0, and lastly use SUMPRODUCT to add up all the TRUE results.
It is obvious that there are a couple limitations of my solution:
If your actual formula is not strictly in the form of A+B+C+D+E+F, then my SUBSTITUTE part of formula will need further modification;
The formula will treat cells containing 0 as blank and does not include them in the count.
Let me know if you have any questions. Cheers :)
I have a list of 1s and 0s in excel row ranging from B2:K2, I want to calculate the current streak of 1's in cell M2,
example dataset where streak would be 4
1 0 1 0 1 1 1 1 0
Is there a simple way of doing this? I have tried research but not been able to find anything specific.
Any help would be much appreciated.
Here is a way of doing this with just one formula, no helper columns/rows needed:
The formula used translates to:
{=MAX(FREQUENCY(IF(B1:K1=1,COLUMN(B1:K1)),IF(B1:K1=1,0,COLUMN(B1:K1))))}
Note: It's an array formula and should be entered through CtrlShiftEnter
Assuming your data is layed out horizontally like the image below, the following two formulas should do it for you.
The first cell requires a different formula as the is no cell to the left to refer to. so a simple formula to check if the first cell is one or not is entered in B2.
=--(A1=1)
The part in the bracket will either be true or false. A quirk of excel is that if you send a true or false value through a math operation it will be converted to 1 for true and 0 for false. That is why you see the double - in front. could have also done *1, /1, +0,-0 at the end.
In B2 place the following formula and copy right as needed:
=(A2+1)*(B1=1)
Basically it adds 1 to the series, then check if the number in the sequence is 1 or 0. In the event its one, it keeps the value as it is TRUE sent through the math operator *. If it is false it set the sequence back to zero by multiplying False by the math operator *.
Alternate IF
Now the above while it works and may save a few characters is not necessarily intuitive for most. The go to option would be to use an IF function. The above formulas can be replaced with the following:
A3
=IF(A1=1,1,0)
B3 ->Copied right
=IF(B1=1,A3+1,0)
Longest streak
To get the longest streak, the highest value in your helper row is what you want. You can grab this with the following formula in an empty cell.
=MAX(2:2)
=MAX(A2,I2)
If you have no other numbers in your helper row, you can use the first formula which looks in the entire row. If there are other numbers due to calculations off to the left or right as an example, then you will want to restrict your range to you data as in the second formula.
I've put those values in cells B2 to B8.
In cell C3, I've put this formula:
=IF(AND(B3=1;B2=1);C2+1;1)
Dragging this downto C8, and then take the maximum of the C column.
The question is slightly confusing, so I will do my best to elaborate. I have a series of cells in a row with all of the cells in the row with a value of 0 and one cell having a value of 1. I want to use the COUNT function to count all of the cells to the right of the cell that contains the value of 1, including that cell. I would then use this number of counted cells in another equation. Does anyone have any suggestions on how to do this? I have tried using a lookup function inside of the count function, but it has not worked. This is my closest guess:
=COUNT(Lookup(1,A1:J1):J1)
This results in an error. Do I need to use VBA to make this work or should I be able to write an equation? I appreciate the help, or if there are any other strategies that I can use to attain the result I am looking for.
Edit: I am adding in some sample data and expected results. I am trying to count all of the cells to the right of the "1" including the cell containing the "1". So in this example, I would expect the formula to return "13" as there are 12 cells to the right of the "1"
You can use OFFSET() and MATCH():
That last "50" is a bit of a guess since I'm not sure how far to the right you want to count...
...and re-reading your question it's not clear if you only want to count values of 1 or if you also need to count other values as long as they're to the right of the first 1.
With data in A1 through J1, consider:
=10-MATCH(1,A1:J1,0)+1
In this case. 4 is the number of cells from G1 through J1, inclusive.
Assuming your range of 0 and 1 values is in row 2, starting from column B, use this formula in B3 and copy it across for as far as you need:
=IFERROR(COUNT($B2:B2)+1-MATCH(1,$B2:B2,0),0)
You could also use a formula of
=IF(A3>0,1+A3,IF(B2=1,1,0))
but that could cause issues if you have something in cell A3 itself.
You can use this formula:
=COUNTA(INDEX($A$1:$J$1,1,MATCH(1,$A$1:$J$1,0)):INDEX($A$1:$J$1,1,10))
The benefit to use this is it is not a volatile function, and it will also work for 1 appears in the last column.
You can use "COUNTIF" formula to count number of occurrences of specific number in a range of cells.
To count no of occurrences in a row.
=COUNTIF(1:1,1)
If it is in a column then
=COUNTIF(A:A,1)
Hope you are looking for a countif function.
COUNTIF(A1:A10, 1)
The above function counts the cell that has value 1 within the range A1:A10
In my Excel worksheet, every 25 rows or so (this number is subject to change), a cell in column C contains a progressive number, identifying a set. Right now, there is a simple formula, e.g. in Cell 34:
= C9 + 1
When The number of rows above C34 changes, the formula updates automatically. No issue with that.
I am now experimenting with a macro that inserts a set in between two existing sets; therefore another number that should fit in the progression, and the following numbers should adapt.
I thought that formulas should change, to find the first number above the current cell and add +1.
Trying a solution from this link, I came up with the following formula:
=LOOKUP("z";$C$9:OFFSET(INDIRECT(ADDRESS(ROW();COLUMN()));-1;0))+1
It seems however that it only searches for text, giving a #N/Awhen there is no text and a #VALUE! when there is text; if I do not add the +1, it works fine.
I also tried
=LOOKUP(2;1/(C$9:C9<>"");C:C)
As explained in the link but all I get is 0
How do I modify these formulas to give me the expected result?
Assuming than the number of the first set is in A1,
enter this formula
=INDEX(A:A,MATCH(1E+100,OFFSET(A$1,,,ROW()-1)))+1
in the counting cells (A5,A10, A16 in the example):
Then you can insert rows for a new inserted set, for example:
When ypu copy the same formula into C10,
the set numbers update accordingly:
And you can fill the text elements of the set:
I am trying to get the max value of a column based on the Left function
What I am doing is the following :
These are the results I get when i write this into column C :
=MAX(LEFT(A:A, 2))
But what I truly want is to get in column C the max value of all column A not for each cell.
So the result should be in this case 90 for all rows.
What should be the formula here?
Just another option that gets entered normally:
=AGGREGATE(14,6,--LEFT($A$1:INDEX(A:A,MATCH("ZZZ",A:A)),2),1)
Array formulas will calculate the enitre referenced array. So care should be taken to limit the number of iterations to only the data set.
The $A$1:INDEX(A:A,MATCH("ZZZ",A:A)) part of the formula does that. It finds the last cell in column A with data in it and sets that as the upper bound. So in this instance the reference range is A1:A3. But, it will grow dynamically as data in Column A is added, so no need to change the formula each time data is added.
Update 2
Here is another solution which I think is better than my original (below)
=INT(SUMPRODUCT(MAX(SUBSTITUTE(A:A,"-",".")*1)))
it can be entered as normal (just Enter)
Orignal Answer
You need numbers and arrays
=MAX(IFERROR(LEFT(A:A,2)*1,0))
Let's break this down. Multiplying by turns your strings into numbers - since Left only returns a string
LEFT(A:A,2)*1
Unfortunately this method returns #Value if you multiply an empty string by 1. You will definitely have some empty strings in the range A:A so we wrap the whole thing with an IFERROR function.
IFERROR(LEFT(A:A,2)*1,0)
Now we still need excel to treat this as an array (i.e. a whole column of numbers, rather than just one number). So we put the MAX formula in and enter it with Ctrl+Shift+Enter rather than just Enter. The result is that the formula looks like this in the formula bar
{=MAX(IFERROR(LEFT(A:A,2)*1,0))}
which would return 90 in your example, as required
Update 1
If you are using Excel 2013 or later, you can also use the NUMBERVALUE function
=MAX(NUMBERVALUE(LEFT(A:A,2)))
again, enter it with Ctrl+Shift+Enter