Prevent exec command running on module unload ibm load sharing facilty - linux

I have a tcl script which is a modulefile within the IBM Load Sharing Facitily (lsf) used to configure some environment variables and launch a python script by using the exec command.
When the module is unloaded normally the opposite of all the commands are run, but also the exec command is run as normal. I would like it so that the exec part is only run on module load and not on module unload.
Here is what I tried so far
if { !(is-loaded mymodule)} {
exec .venv/bin/python mypython.py
}
I also tried this
if { module-info command load } {
exec .venv/bin/python mypython.py
}
For each one I get a similar error
Module ERROR: invalid bareword "module"
in expression " module-info command [load] ";
should be "$module" or "{module}" or "module(...)" or ...
both exceptions complain either about an invalid bareword (either "is" or "module") depending on which snippet I try. Is my snytax invalid?

My syntax was incorrect, in the end I was able to solve the problem with the following:
set is_load_command [module-info command load]
if { $is_load_command == 1 } {
exec .venv/bin/python mypython.py
}
I had two problems, correctly understanding comparisons in tcl and using return values from a called function. Neither really behaved how I am used to.

Related

Execute Python script using Laravel?

I'm trying to execute a python script in a Laravel 5.8 project but I'm having problems with the Symfony/process class.
Basically, I want to run this python script that takes an excel form from the storage folder.
My first try was this
$process = new Process('C:\Python\python.exe C:\Users\"my path"\laravel\storage\app\images\cargaExcel.py');
$process->run();
if (!$process->isSuccessful()) {
throw new ProcessFailedException($process);
}
echo $process->getOutput();
And the error is
Fatal Python error: _Py_HashRandomization_Init: failed to get random numbers to initialize Python
I also tried with shell_exec(), and if the two files (the excel and the python script are in the public path - app/public) it works.
I think the problem is that python only executes on the app/public folder, so I don't know how to run this in another path.
Python output is telling me that:
Working directory: C:\Users\"my path"\laravel\public
Does anyone know how to run this?
You can pass the working directory as the second argument of the process class
So it can be:
$process = new Process('C:\Python\python.exe C:\Users\"my path"\laravel\storage\app\images\cargaExcel.py', "/my/working/path/");
Also you may pass command as array
$process = new Process(['C:\Python\python.exe', 'C:\Users\"my path"\laravel\storage\app\images\cargaExcel.py'], "/my/working/path/");

Using node-cmd module while handling Squirrel Events function

I'm building a desktop app for Windows using electron-packager and electron-squirrel-startup, I would like to execute some Windows cmd commands during the installation of my application. To do so I was planning to use node-cmd node module, but I doesn't really work inside the handleSquirrelEvents function. An example command like this:
function handleSquirrelEvent(application) {
const squirrelEvent = process.argv[1];
switch (squirrelEvent) {
case '--squirrel-install':
case '--squirrel-updated':
var cmd=require('node-cmd');
cmd.run('touch example.created.file');
}
};
Seems to work. A file example.created.file in my_app/node_module/node-cmd/example directory is created.
But any other code does not work. Even if I only change the name of the file to be "touched" nothing happens.
Ok, example.created.file already exists in this directory and I suspect that you can only use update.exe supported commands in case '--squirrel-updated' sections. So this will not work.

Unable to run cucumber feature feature

I am unable to run the feature file. whenever i tried to run the file
i am getting the below stack trace
Exception in thread "main" Usage: java cucumber.api.cli.Main [options] [
[FILE|DIR][:LINE[:LINE]*] ]+
Options:
-g, --glue PATH Where glue code (step definitions and hooks) is loaded from.
-f, --format FORMAT[:PATH_OR_URL] How to format results. Goes to STDOUT unless PATH_OR_URL is specified.
Built-in FORMAT types: junit, html, pretty, progress, json.
FORMAT can also be a fully qualified class name.
-t, --tags TAG_EXPRESSION Only run scenarios tagged with tags matching TAG_EXPRESSION.
-n, --name REGEXP Only run scenarios whose names match REGEXP.
-d, --[no-]-dry-run Skip execution of glue code.
-m, --[no-]-monochrome Don't colour terminal output.
-s, --[no-]-strict Treat undefined and pending steps as errors.
--snippets Snippet name: underscore, camelcase
--dotcucumber PATH_OR_URL Where to write out runtime information. PATH_OR_URL can be a file system
path or a URL.
-v, --version Print version.
-h, --help You're looking at it.
cucumber.runtime.CucumberException: Unknown option: --plugin
at cucumber.runtime.RuntimeOptions.parse(RuntimeOptions.java:119)
at cucumber.runtime.RuntimeOptions.<init>(RuntimeOptions.java:50)
at cucumber.runtime.RuntimeOptions.<init>(RuntimeOptions.java:44)
at cucumber.api.cli.Main.run(Main.java:20)
at cucumber.api.cli.Main.main(Main.java:16)
Please help me to resolve the problem
You normally get this issue if you did not set cucumberOptions correctly on your cukes files.
For example:
#RunWith(Cucumber.class)
#CucumberOptions( dryRun = false, strict = true, features = "src/test/features/com/sample", glue = "com.sample",
tags = { "~#wip", "#executeThis" }, monochrome = true,
format = { "pretty", "html:target/cucumber", "json:target_json/cucumber.json", "junit:taget_junit/cucumber.xml" } )
public class RunCukeTest {
}
Hi I also had this issue as well, and I did the following to resolve it, thanks to the comments of Anusha from video https://youtu.be/pD4B839qfos
-the main trick is to firstly change the jar files you have as follows
cucumber-core-1.2.5.jar
cucumber-java-1.2.5.jar
cucumber-junit-1.2.5.jar
or any of the above, from 1.2.4 upwards
- also update the following selenium-server-standalone-2.42.0.jar and upwards
- also change the format keyword to plugin
Once you make the above changes, this should resolve your problem.

How to get an Environment Module modulefile to print a message upon loading the module?

I've just learned the basics on how to make modulefiles for loading software on my cluster. Other environment modules (created by admins) print a message upon loading:
$ module load Name
Welcome to Name/version.1.2.3
How do I add this to the modulefile? I like the quick confirmation that I've indeed loaded the module I intended. I've tried a few things from the man page (ex module-info name) but no luck (or I'm doing it wrong).
Thanks
If you "only" want the message to print when running module load (but not when running module unload or other commands), then you can use a statement like this:
if [ module-info mode load ] {
puts stderr "your text here"
}
Reference: https://sourceforge.net/p/modules/mailman/message/34597600/
You can add puts stderr statements to modulefile, for printing messages to terminal.
puts stderr "** INFO: 'Welcome, Module loaded'"

How do you get the path of the running script in groovy?

I'm writing a groovy script that I want to be controlled via a properties file stored in the same folder. However, I want to be able to call this script from anywhere. When I run the script it always looks for the properties file based on where it is run from, not where the script is.
How can I access the path of the script file from within the script?
You are correct that new File(".").getCanonicalPath() does not work. That returns the working directory.
To get the script directory
scriptDir = new File(getClass().protectionDomain.codeSource.location.path).parent
To get the script file path
scriptFile = getClass().protectionDomain.codeSource.location.path
As of Groovy 2.3.0 the #SourceURI annotation can be used to populate a variable with the URI of the script's location. This URI can then be used to get the path to the script:
import groovy.transform.SourceURI
import java.nio.file.Path
import java.nio.file.Paths
#SourceURI
URI sourceUri
Path scriptLocation = Paths.get(sourceUri)
Note that this will only work if the URI is a file: URI (or another URI scheme type with an installed FileSystemProvider), otherwise a FileSystemNotFoundException will be thrown by the Paths.get(URI) call. In particular, certain Groovy runtimes such as groovyshell and nextflow return a data: URI, which will not typically match an installed FileSystemProvider.
This makes sense if you are running the Groovy code as a script, otherwise the whole idea gets a little confusing, IMO. The workaround is here: https://issues.apache.org/jira/browse/GROOVY-1642
Basically this involves changing startGroovy.sh to pass in the location of the Groovy script as an environment variable.
As long as this information is not provided directly by Groovy, it's possible to modify the groovy.(sh|bat) starter script to make this property available as system property:
For unix boxes just change $GROOVY_HOME/bin/groovy (the sh script) to do
export JAVA_OPTS="$JAVA_OPTS -Dscript.name=$0"
before calling startGroovy
For Windows:
In startGroovy.bat add the following 2 lines right after the line with
the :init label (just before the parameter slurping starts):
#rem get name of script to launch with full path
set GROOVY_SCRIPT_NAME=%~f1
A bit further down in the batch file after the line that says "set
JAVA_OPTS=%JAVA_OPTS% -Dgroovy.starter.conf="%STARTER_CONF%" add the
line
set JAVA_OPTS=%JAVA_OPTS% -Dscript.name="%GROOVY_SCRIPT_NAME%"
For gradle user
I have same issue when I'm starting to work with gradle. I want to compile my thrift by remote thrift compiler (custom by my company).
Below is how I solved my issue:
task compileThrift {
doLast {
def projectLocation = projectDir.getAbsolutePath(); // HERE is what you've been looking for.
ssh.run {
session(remotes.compilerServer) {
// Delete existing thrift file.
cleanGeneratedFiles()
new File("$projectLocation/thrift/").eachFile() { f ->
def fileName=f.getName()
if(f.absolutePath.endsWith(".thrift")){
put from: f, into: "$compilerLocation/$fileName"
}
}
execute "mkdir -p $compilerLocation/gen-java"
def compileResult = execute "bash $compilerLocation/genjar $serviceName", logging: 'stdout', pty: true
assert compileResult.contains('SUCCESSFUL')
get from: "$compilerLocation/$serviceName" + '.jar', into: "$projectLocation/libs/"
}
}
}
}
One more solution. It works perfect even you run the script using GrovyConsole
File getScriptFile(){
new File(this.class.classLoader.getResourceLoader().loadGroovySource(this.class.name).toURI())
}
println getScriptFile()
workaround: for us it was running in an ANT environment and storing some location parent (knowing the subpath) in the Java environment properties (System.setProperty( "dirAncestor", "/foo" )) we could access the dir ancestor via Groovy's properties.get('dirAncestor').
maybe this will help for some scenarios mentioned here.

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