I am trying to rename the files and directories using a text file separated by space.
The text file looks like this:
dir1-1 dir1_1
dir2-1 dir223_1
My command is as follows:
xargs -r -a files.txt -L1 mv
This command can rename only folders from dir1-1 to dir1_1 and dir2-1to dir223_1so on but it doesn't rename the files in the subdirectories. The files in the corresponding directories also have these prefix of these directories.
Looking forward for the assistance.
Assuming you don't have special characters(space of tab...) in your file/dir names,
try
perl_script=$(
echo 'chop($_); $orig=$_;'
while read -r src tgt; do
echo 'if (s{(.*)/'"$src"'([^/]*)}{$1/'"$tgt"'\2}) { print "$orig $_\n";next;}'
done < files.txt)
find . -depth | perl -ne "$perl_script" | xargs -r -L1 echo mv
Remove echo once you see it does what you wanted.
Related
I have multiple folders with multiple files. I need to rename those files with the same name like the folder where the file stored with "_partN" prefix.
As example,
I have a folder named as "new_folder_for_upload" which have 2 files. I need to convert the name of these 2 files like,
new_folder_for_upload_part1
new_folder_for_upload_part2
I have so many folders like above which have multiple files. I need to convert all the file names as I describe above.
Can anybody help me to find out for a single linux command or script to do this work automatically?
Assuming bash shell, and assuming you want the file numbering to restart for each subdirectory, and doing the moving of all files to the top directory (leaving empty subdirectories). Formatted as script for easier reading:
find . -type f -print0 | while IFS= read -r -d '' file
do
myfile=$(echo $file | sed "s#./##")
mydir=$(dirname "$myfile")
if [[ $mydir != $lastdir ]]
then
NR=1
fi
lastdir=${mydir}
mv "$myfile" "$(dirname "$myfile")_part${NR}"
((NR++))
done
Or as one-line command:
find . -type f -print0 | while IFS= read -r -d '' file; do myfile=$(echo $file | sed "s#./##"); mydir=$(dirname "$myfile"); if [[ $mydir != $lastdir ]]; then NR=1; fi; lastdir=${mydir}; mv "$myfile" "$(dirname "$myfile")_part${NR}"; ((NR++)); done
Beware. This is armed, and will do a bulk renaming / moving of every file in or below your current work directory. Use at your own risk.
To delete the empty subdirs:
find . -depth -empty -type d -delete
I have an entire directory structure with zip files. I would like to:
Traverse the entire directory structure recursively grabbing all the zip files
I would like to find a specific file "*myLostFile.ext" within one of these zip files.
What I have tried
1. I know that I can list files recursively pretty easily:
find myLostfile -type f
2. I know that I can list files inside zip archives:
unzip -ls myfilename.zip
How do I find a specific file within a directory structure of zip files?
You can omit using find for single-level (or recursive in bash 4 with globstar) searches of .zip files using a for loop approach:
for i in *.zip; do grep -iq "mylostfile" < <( unzip -l $i ) && echo $i; done
for recursive searching in bash 4:
shopt -s globstar
for i in **/*.zip; do grep -iq "mylostfile" < <( unzip -l $i ) && echo $i; done
You can use xargs to process the output of find or you can do something like the following:
find . -type f -name '*zip' -exec sh -c 'unzip -l "{}" | grep -q myLostfile' \; -print
which will start searching in . for files that match *zip then will run unzip -ls on each and search for your filename. If that filename is found it will print the name of the zip file that matched it.
Some have suggested to use ugrep to search zip files and tarballs. To find the zip files that contain a mylostfile file, specify it as a -g glob pattern like so:
ugrep -z -l -g'myLostfile' ''
With the empty regex pattern '' this this recursively searches all files down the working directory, including any zip, tar, cpio/pax archives for mylostfile. If you only want to search the zip files located in the working directory:
ugrep -z -l -g'myLostfile' '' *.zip
I am on a Linux system and I am trying to rename all .jpg files in many subdirectories to sequential filenames, so all the jpeg files in each subdirectory are renamed 0001.jpg, 0002.jpg, etc. I have a 'rename' command that works in a single directory:
rename -n 's/.*/sprintf("%04d",$::iter++ +1).".jpg"/e' *.jpg
I am trying to use it like this:
for i in ls -D; do rename -n 's/.*/sprintf("%04d",$::iter++ +1).".jpg"/e' *.jpg; done
but for output I get this:
*.jpg renamed as 0001.jpg
for each subdirectory. What am I doing wrong?
You need to put the command in backticks (or use the $( ... ) bash syntax) in order
to iterate over its output. Also use the $i variable together with the *.jpg file
name pattern, e.g.
for i in `ls -D`
do
rename -n 's/.*/sprintf("%04d",$::iter++ +1).".jpg"/e' $i/*.jpg
done
however, for this scenario you want to iterate over all the subdirectories, and you are
better of using the find command:
for i in `find . -type d`; do rename ...
It seems to me you've forgot to change a current working directory so it should looks like
for i in *; do
[ -d "$i" ] || continue
pushd "$i"
# rename is here
popd
done
I have a directory called images
and it contains many images.
For example:
images/
imag001.png
imag002.png
imag003.png
imag004.png
And I have a text file that has the files that I want to copy somewhere else. Say the test.txt file has
img001.png
img003.png
How do I copy the files specified in test.txt from the images folder to some other place?
try this one-liner under your images directory:
awk '{print "cp "$0" /target/path"}' test.txt|sh
There are probably many solutions to this problem. I would do it by using xargs:
cd images/
cat path/to/test.txt | xargs -I FILES cp FILES path/to/dest/
I think in the bash shell you can do:
for image in $(cat copylist.txt); do
cp $image destination
done
You can write:
while IFS= read -r image_filename ; do
cp images/"$image_filename" some_other_place/
done < test.txt
cat copylist.txt | xargs -n1 -I % echo cp % destination/.
# remove echo after testing
I am working on something and need to solve the following. I am giving a analogous version of mine problem.
Say we have a music directory, in which there are 200 directories corresponding to different movies. In each movie directory there are some music files.
Now, say a file music.mp3 is in folder movie.mp3 . I want to make a shell script such that it renames the file to movie_music.mp3 and put it in some folder that I mention to it. Basically, all the files in the subdirectories are to be renamed and to be put in a new directory.
Any workaround for this?
This script receives two arguments: the source folder and the destination folder. It will move every file under any directory under the source directory to the new directory with the new filename:
#!/bin.sh
echo "Moving from $1 to $2"
for dir in "$1"/*; do
if [ -d "$dir" ]; then
for file in "$dir"/*; do
if [ -f "$file" ]; then
echo "${file} -> $2/`basename "$dir"`_`basename "${file}"`"
mv "${file}" "$2"/`basename "$dir"`_`basename "${file}"`
fi
done
fi
done
Here is a sample:
bash move.sh dir dir2
Moving from dir to dir2
dir/d1/f1 -> dir2/d1_f1
dir/d1/f2 -> dir2/d1_f2
dir/d2/f1 -> dir2/d2_f1
dir/d2/f2 -> dir2/d2_f2
Bash:
newdir=path/to/new_directory;
find . -type d |while read d; do
find "$d" -type f -maxdepth 1 |while read f; do
movie="$(basename "$d" |sed 's/\(\..*\)\?//')"
mv "$f" "$newdir/$movie_$(basename $f)";
done;
done
Assuming the following directory tree:
./movie1:
movie1.mp3
./movie2:
movie2.mp3
The following one-liner will create 'mv' commands you can use:
find ./ | grep "movie.*/" | awk '{print "mv "$1" "$1}' | sed 's/\(.*\)\//\1_/'
EDIT:
If your directory structure contains only the relevant directories, you can expand use the following grep instead:
grep "\/.*\/.*"
Notice it looks file anything with at least one directory and one file. If you have multiple inner directories, it won't be good enough.