I'd like to add an additional condition that uses INDIRECT to the following array that currently works:
=MEDIAN(IF(Signals!$B3:$AOT3=0,IF(Signals!$B3:$AOT3<>"",IF(Signals!$DUI3:$FKA3<>"",Signals!$DUI3:$FKA3))))
Here is the formula I've tried with the additional condition, which I added to the beginning:
=MEDIAN(IF(INDIRECT("Signals!$B"&$Z$2&":$AOT"&$Z$2&"="&$Z$3),IF(Signals!$B3:$AOT3=0,IF(Signals!$B3:$AOT3<>"",IF(Signals!$DUI3:$FKA3<>"",Signals!$DUI3:$FKA3)))))
$Z$2 currently contains the value of 5, and $Z$3 contains 0.
The attempt above results in #REF!
You just want to use INDIRECT on the cell address, not the equal sign. Try instead
=MEDIAN(IF(
INDIRECT("Signals!$B"&$Z$2&":$AOT"&$Z$2)=&$Z$3),
IF(Signals!$B3:$AOT3=0,
IF(Signals!$B3:$AOT3<>"",
IF(Signals!$DUI3:$FKA3<>"",Signals!$DUI3:$FKA3)))))
As a side note, I am not understanding that IF statement, I would double check if it's actually doing what you want.
Related
I am trying to get a sum of column C if A is abc or cba and B is def:
=SUMIFS(C2:C51;A2:A51;{"abc","cba"};B2:B51;"def")
But the formula is not valid, not sure where is my mistake since this was proposed in a quick google search.
Thank you for your suggestions.
The formula is valid for me, but this might be an issue with your delimiter. Depending on your excel, windows or location settings you might need to use a comma , as a delimiter, instead of a semicolon ;.
As for your formula, for completion I've done the same google search and ended up with this reference. It seems your logic in the formula is correct apart from one crucial step, the SUM( wrapping around your formula. This means if your formula works, it will only take the first hit into account, but with the sum, it will count every entry where your logic is True. Syntax:
=SUM(SUMIFS(C2:C51,A2:A51,{"abc","cba"},B2:B51,"def"))
Or semicolon delimited:
=SUM(SUMIFS(C2:C51;A2:A51;{"abc";"cba"};B2:B51;"def"))
Since the {array} option does not seem to be working for you, I propose a workaround as follows:
=SUMIFS(C1:C15;A1:A15;"abc";B1:B15;"def")+SUMIFS(C1:C15;A1:A15;"cba";B1:B15;"def")
This is a more clunky function, but reaches the same result by splitting up the data in two SUMIFS( functions and adding the results together.
Probably I would use #Plutian answer (actually I upvoted), but in case it might work for you, you can use SUMPRODUCT combined with DOUBLE UNARY to get exactly what you want.
DOUBLE UNARY
SUMPRODUCT
I made a fake dataset like this:
As you can see, only the highlighted values meet your requirements ( if A=abc OR cba AND B=def)
My formula in E10 is:
=SUMPRODUCT(--($A$2:$A$7="abc")+--($A$2:$A$7="cba");--($B$2:$B$7="def");$C$2:$C$7)
This is how it works:
($A$2:$A$7="abc") will return an array of True/False values if condition is met.
That array, because it's inside a double unary operator --( your range ), will convert all True/False values into 1 or 0 values. Let's say it works like if you would have selected a range of cells that contains only 1 or 0. So this will return an array like {1,0,1,0,1,0} in this case
--($A$2:$A$7="cba") will do exactly the same than steps 1 or 2 again, but with your second option. It will return another array of values, in this case, {0,1,0,1,0,1}
--($A$2:$A$7="abc")+--($A$2:$A$7="cba") we are just summing up both arrays, so {1,0,1,0,1,0}+{0,1,0,1,0,1}={1,1,1,1,1,1}
--($B$2:$B$7="def") will do like steps 1 and 2 again with your third condition, and will return another array, now it will be {1,0,1,0,0,1}
The array obtained in step 5 then it's multiplied to array obtained in step 4, so we are doing {1,1,1,1,1,1} * {1,0,1,0,0,1}={1,0,1,0,0,1}
Now, that final array obtained in step 7 then it's multiplied by the values of cells $C$2:$C$7, so in this case is {1,0,1,0,0,1} * {10,1,10,1,1,10} = {10,0,10,0,0,10}
And final step, we sum up all values inside array obtained in last step, so we do 10+0+10+0+0+10=30
I've explained every step to make sure everybody can understand, because SUMPRODUCT it's really an useful function if you know how to hanlde (I'm a noob, but I've seen real heroes here on SO using this function).
The advantage of using SUMPRODUCT instead of SUMIFS is that you can easily add more conditions to apply same range (case --($A$2:$A$7="abc")+--($A$2:$A$7="cba") or single condition to additional ranges (case --($B$2:$B$7="def")).
With normal SUMIFS probably you would have to add 1 extra complete SUMIF for each condition applied in same range.
Hope this helps
For example =SUMPRODUCT(A2:A10-10) does, but =SUM(A2:A10-10) does not. Specifically in my situation I wish =MEDIAN(ABS(A2:A10-MEDIAN(A2:A10))) did; however sadly it does not, and if I knew which built in functions convert the ranges into arrays before they evaluate then I might be able to reformulate something that gives me what I'm looking for...
there are some natural array type formulas like SUMPRODUCT and some of the options in AGGREGATE, as well as some financial functions.
Many can be "forced" into array mode by simply using Ctrl-Shift-Enter instead of Enter when exiting edit mode.
For example your formula:
=MEDIAN(ABS(A2:A10-MEDIAN(A2:A10)))
If it is confirmed with Ctrl-Shift-Enter instead of Enter when exiting edit mode will "Force" the Array. If done correctly the Excel will put {} around the formula.
The INDEX function has an Array Form.
=SUM(INDEX((A2:A10)-10, , ))
In the above, INDEX is returning an array of values but a wrapping SUM is required to collect a total. The blank parameters represent all rows and all columns in the range (e.g. A2:A10) specified. All rows and all columns in the range can also be represented with zeroes in place of the blank parameters.
With 2 to 10 in A2:A10, your MEDIAN example would return 14 from,
=MEDIAN(INDEX(ABS((A2:A10)-MEDIAN(A2-A10)), , ))
(without CSE)
Use the Evaluate Formula command to see more of the inner workings of this style of INDEX use.
I am adding the values of several cells from two sheets in excel.
I am using the formulas below to calculate this.
My question is why to two formulas aren't giving the same result? As far as I can tell, the only difference is that the 2nd formula has an extra bracket, which shouldn't change anything?
=SUM(SUMIFS('Ark1'!F15:F75;'Ark1'!E15:E75;{"adgangsareal bolig";"fællesrum bolig"}))+SUM(SUMIFS('Ark2'!F11:F126;'Ark2'!E11:E126;"bolig"))
=SUM((SUMIFS('Ark1'!F15:F75;'Ark1'!E15:E75;{"adgangsareal bolig";"fællesrum bolig"}))+SUM(SUMIFS('Ark2'!F11:F126;'Ark2'!E11:E126;"bolig")))
The latter formula has been working perfectly until now through my Work, but for this specific value i needed to remove the extra bracket.
Jacob is right that its the array bit that is causing the problem, but really the problem is caused by the + sign in an expression containing an array which causes the expression to be evaluated as an array formula. You can fix this by changing the + to ; (or whatever the argument separator character is in your locale).
A simpler example (my locale uses , rather than ;):
=SUM({5,10}+20)
results in 55 (the expression evaluater creates (5+20)+(10+20) using the array expansion rules and then passes {25,30} to SUM) but
=SUM({5,10},20)
results in 35
In your first SUMIFS() you have the criteria listed as an array. When using SUM() around the first SUMIFS() alone, it is returning the sum of the range that meets the first criteria being true in the range, then repeats for the second critera, and then it adds the second SUMIF().
When you add the parentheses, you SUM() the first SUMIF() total for the first array value AND the second SUMIF(), and then you are repeating for the second array. So you are getting that second SUMIF() total added twice essentially.
I believe you want something like this:
=SUM(SUMIF('Ark1'!E15:E75;"adgangsareal bolig";'Ark1'!F15:F75);SUMIF('Ark1'!E15:E75;'Ark1'!F15:F75;"fællesrum bolig");SUMIF('Ark2'!E11:E126;"bolig";'Ark2'!F11:F126))
Try this:
=(87,35+464,71-87,35-464,71)
=87,35+464,71-87,35-464,71
2nd formula results correctly in ZERO, while
1st one results in very small number(-0,0000000000000568434)
Add more decimal places to see it.
I think it is a BUG and has something to do with different type of numbers (decimal, floating,...).
Good day,
I am trying to insert this formula into excel to search for specific terms in a cell, and return a value "50" if the term is found.
I have been able to successfully implement this using the below primitive formula:
=IF(C1394<>70,C1394,IF(ISNUMBER(SEARCH("*PD*",B1394)),"50",IF(ISNUMBER(SEARCH("*OD*",B1394)),"50",IF(ISNUMBER(SEARCH("*OC*",B1394)),"50",IF(ISNUMBER(SEARCH("*OF*",B1394)),"50",IF(ISNUMBER(SEARCH("*PC*",B1394)),"50",IF(ISNUMBER(SEARCH("*MS*",B1394)),"50",C1394)))))))
I tried to make my formula more efficient and dynamic using the below approach, however excel only reads the first condition "PD" and ignores the rest
=IF(C8266 =70,IF(--ISNUMBER(SEARCH({"*PD*","*OD*","*OC*","*OF*","*PC*","*MS*"},B8266)),"50",C8266),C8266)
Can someone please advise what am I doing wrong?
You're just missing an OR clause, see this: http://www.mrexcel.com/forum/excel-questions/601195-check-multiple-text-strings-cell.html#post2977162
So you want:
=IF(C8266=70,IF(OR(ISNUMBER(SEARCH({"*PD*","*OD*","*OC*","*OF*","*PC*","*MS*"},B8266))),"50",C8266),C8266)
What you are doing wrong is you are trying to evaluate an array within a formula that doesn't usually evaluate arrays. You evaluate such formulae by pressing and holding Ctrl+Shift and then press Enter.
Otherwise, your formula can be shortened to the below:
=IF(OR(ISNUMBER((C8266=70)*SEARCH({"PD","OD","OC","OF","PC","MS"},B8266))),"50",C8266)
SEARCH does not require wildcards.
A boolean multiplied by a number gives a number. An error multiplied by a number gives an error. So you can safely combine the first and second checks together and drop the --.
OR is then used to check if there is at least 1 number within the array of numbers and/or errors.
Similarly array invoked (with Ctrl+Shift+Enter).
IMO Excel has weird treatment of empty Cells.
I am building a complex array formula. One of the referenced ranges contain cells, that may, or may not be empty, and if not empty, they can contain both numeric values and strings.
What function can I use, to get the value of the cell if the cell is not empty, and "" (or anything other non-numeric, e.g. #N/A) if the cell is empty?
I want to get something like this working:
=MIN(OFFSET(<column vector that contains text, numbers and empty cells>;<row vector of indices>-1;0))
This form of formula returns an #ARG error, as was explained in the answer to Why this array formula doesn't work?.
But when I prefix the OFFSET with N, it transforms any empty cell into 0, so the net result is 0 (unless there are negative numbers in the column vector).
=MIN(L(OFFSET(<column vector>;<row vector of indices>-1;0)))
Is there any formula, that only dereferences the reference returned by OFFSET preserving the "emptyness" of the empty cell? Or maybe there is an alternate way of solving the problem, like
=MIN(IF(OFFSET(<column vector>;<row vector of indices>-1;0)="",L(OFFSET(<column vector>;<row vector of indices>-1;0)),""))
(This example also fails with #ARG, because, as I understand, I need to dereference the array reference for the = test as well).
If it is at all possible, I prefer to keep with Excel 2007 set of built-in functions. And no VBA.
I would accept any solution, that uses constant number of cells irregardless of the size of each input array.
EDIT:
As a side remark I wonder what is wrong with the arrays returned by OFFSET anyway? This simple example works perfectly:
...while the array returned by OFFSET somehow wants to be alone in the formula.
There may be another option but I don't see it at the moment.....
You can filter out zeroes by using an IF like this
=MIN(IF(N(OFFSET(INDIRECT($A$2),$C4:$G4-1,0))<>0,N(OFFSET(INDIRECT($A$2),$C4:$G4-1,0))))
but that won't distinguish between any actual zeroes in your range and those produced when the N function encounters blanks or text
Edit
This version should work
=MIN(IF(COUNTBLANK(OFFSET(INDIRECT($A$2),$C4:$G4-1,0,1))+LEN(T(OFFSET(INDIRECT($A$2),$C4:$G4-1,0,1))),"",N(OFFSET(INDIRECT($A$2),$C4:$G4-1,0,1))))
Perhaps not completely relevant here but the problem is finding functions that can deal with the "array of references" returned by OFFSET with this type of setup - N and T work as shown here and also COUNTBLANK. Other functions that can be used on the OFFSET output are SUBTOTAL and COUNTIF. Note that COUNTBLANK (along with SUBTOTAL and COUNTIF) can work on ranges while T and N will only work with single values - if the latter functions are applied to ranges they simply look at the first value in the range - because of that I was able to use OFFSET without the "height" parameter but you need that with COUNTBLANK (and it's a good habit to get in to so OFFSET should have the final 1 as here
=OFFSET(INDIRECT($A$2),$C4:$G4-1,0,1)
Consider in B1:
=IF(ISBLANK(A1),"nothing there",A1)
So if A1 contains the formula:
=""
Then B1 will also display the null.
Another possibility:
=MIN(CELL("contents",OFFSET(INDIRECT($A$2),N(INDEX($C4:$G4-1,)),0)))
Note: The N(INDEX(...)) part is a trick used to enforce array evaluation.