How to select a value from another MATCH formula if first MATCH formula returns null in excel - excel

I don't know how possible this is but i want to be able to get a value in a row where the values used to MATCH might not always be on the same column.
Example:
Sheet 1
#
A
B
C
D
1
name
age
work email
personal email
2
dave
20
dave#work.com
3
matt
25
matt#home.com
Sheet 2
#
A
B
1
email
name
2
dave#work.com
fx = dave
3
matt#home.com
fx = N/A
fx
=INDEX('Sheet1'!$A:$A,MATCH(A2,'Sheet1'!$C:$C,0))
the formula works fine but i want to be able to search column D if formula returns N/A when a match can't be found in column C
Please help me out.

You could use IFERROR for this.
=INDEX(Sheet1!$A:$A,IFERROR(MATCH(A2,Sheet1!$C:$C,0),MATCH(A2,Sheet1!$D:$D,0)))

An alternate approach when you don't know what column to find your match is to use SUMPRODUCT combined with ROW:
=INDEX(Sheet1!A:A,SUMPRODUCT((Sheet1!C:D=A2)*ROW(Sheet1!C:D)))
Please note that if there would be two matches within the data, the value returned by SUMPRODUCT is a sum of the matching row numbers. If there's only one match this formula works fine.

Related

Formula returning Column A value for row containing MAX value of a range

Assume I have the following table:
A B C
1 Week 1 Week 2
2 Melissa 114.7 82.8
3 Mike 105.5 122.5
4 Andrew 102.3 87.5
5 Rich 105.3 65.2
The names are in column A, the Week values are in Row 1. (So A1 is blank, B1 = Week 1, and A2 = Melissa.)
I'm trying to build a formula that looks at all the values in a known range (in this example, B2:C5), chooses the highest value of the bunch (here, 122.5) and returns the name of the person from Column A that got that value. If I use this formula, it works for the values in range B2:B5:
=INDEX(A2:A5,MATCH(MAX(B2:B5),B2:B5,0))
That returns Melissa but if I expand the range to include more than just column B's values, I get an #N/A returned:
=INDEX(A2:A5,MATCH(MAX(B2:C5),B2:C5,0))
The weird part (to my simple brain) is that the MATCH portion of the formula works fine, if I just put in this formula, it returns the highest value of 122.5 from C3:
=MAX(B2:C5,B2:C5,0)
So clearly something it going wrong when I'm using either the MATCH or INDEX commands.
Hopefully this makes sense and someone can point out my error?
Try this:
=INDEX(A:A,MAX((B2:C5=MAX(B2:C5))*ROW(B2:C5)))
This is an array formula and must be confirmed with Ctrl+Shift+Enter.
Note: Match can only search one vector at a time. It can be one row or one column or one array. It cannot be two or more rows or columns or a 2D array.
Do it "twice"? Please try:
=INDEX(A2:A5,IFERROR(MATCH(MAX(B2:C5),B2:B5,0),MATCH(MAX(B2:C5),C2:C5,0)))
If you are going to have up to 52/53 weeks to cope with I'd suggest instead inserting a helper column with the MAX for each row. Make that an new (inserted) ColumnA (say =MAX(C2:BC2) etc.) and a simple VLOOKUP should serve, say:
=VLOOKUP(MAX(A:A),A:B,2,0)

Count with criteria for changing column in excel

I have a data looks like this:
a b c
1 3 4
2 3 3
4 1 2
2 4 2
In another worksheet, I want to do the following calculation:
whenever A1 returns a (header of data worksheet), count number of items that are smaller and equal to 2 in column "a". (result will be 2)
if A1 returns b, count number of items that are smaller and equal to 2 in column "b". (result will be 1).
A1 has already been preset with formula such that it will show a or b or c as conditions changed.
I need the formula to be lean... I actually have 6 headers, so if I keep on using if functions, I will probably have to set 6 if functions in one cell...that can be overwhelming. index match cannot provide a range to work on...Any suggestion? thanks
I don't know vba. If you could provide a workable vba code, i don't mind. but i don't know how to read it...>.< please provide user manual for that. lol, thank you~
If your data is found on Sheet1 and the a is found on column a, b is found on column b etc. enter this formula on then next sheet on b1 when a1 is the column value:
=COUNTIF(INDIRECT("Sheet1!"&a1&":"&a1),"<=2")
The Indirect is for adding text to your reference.
If your data sheet is Sheet1, you could try the array formula:-
=SUM((Sheet1!A1:C1=$A$1)*(Sheet1!A2:C5<=2))
Must be entered with CtrlShiftEnter
(actually there are 3 items less than or equal to 2 in column A)
Or you can use the SUMPRODUCT version if you prefer not to use an array formula:-
=SUMPRODUCT((Sheet1!A1:C1=$A$1)*(Sheet1!A2:C5<=2))
Or you can use this INDEX/MATCH method which is probably more efficient:-
=COUNTIF(INDEX(Sheet1!A2:C5,,MATCH(A1,Sheet1!A1:C1,0)),"<="&2)

Using COUNTIFS for a series of values at once

Working a step higher then COUNTIFS, I appose a challenge to write a formula without VBA code. The basic data is combined from 1000s of rows with:
Column A: rows with values from 1 to 3
Column B: rows with values from 1 to 250.
For this purpose lets say, we are looking at all cells of value "1" in column A, that suit value "5" in column B. To find all matches, we'd use COUNTIFS command.
1 1
2 5
1 5
1 7
1 10
3 45
2 12
1 2
2 1
=COUNTIFS(A1:A9;1;B1:B9;5)
The answer here is 1.
Next thing, the "5" in column B belongs to a group, e.g. group from 1 to 9. What would the best way be, to count all the matches in this example, so that for all "1"'s in column A, we'd have to find all matches with values from 1 to 9 in column B?! In the upper example that would result in "4". The obvious solution is with a series of IF commands, but that's unefficient and it easy to make a mistake, that get's easily overseen.
=COUNTIFS(A1:A9;1;B1:B9;"<="&9)
Works only as the upper limit. If I give the third criteria range and condition as ">="&1 it does not work - returns 0.
Gasper
Where the data is in A1:B9, using a lookup table in D1:E10 with letters A-J in column D and numbers 0 to 9 in column E and the following formula in B11 referencing letters entered in A11 and A12:
=COUNTIFS(A1:A9,1,B1:B9,">="&VLOOKUP(A11,$D$1:$E$10,2,FALSE),B1:B9,"<="&VLOOKUP(A12,$D$1:$E$10,2,FALSE))
works, changing the letters in A11 and A12 gives the correct count according to what they correspond to in the looku in D1:E10.
When you say give third criteria range do you mean:
=COUNTIFS(A1:A9;1;B1:B9;"<="&9,B1:B9;">=1")
If so then try:
=COUNTIFS(A1:A9;1;B1:B9;AND("<="&9,;">=1"))
ie have two conditional ranges with the second range having both conditions combined with AND()
Maybe what you want(ed) is:
=COUNTIFS(A:A;1;B:B;">=1";B:B;"<=9")
Almost there. I noticed that three criteria ranges and conditions work only if I use "=" sign in a condition. As soon as I use
=COUNTIFS(A1:A9;1;B1:B9;"<="&9,B1:B9;">=1")
it returns 0. My goal is to eventualy replace the number in a condition with a VLOOKUP command, so the final equation should be smth like
=COUNTIFS(A1:A9;1;B1:B9;"<="&VLOOKUP(...),B1:B9;">=VLOOKUP(...)")
But the "<" and ">" signs mess with this. Still looking for a solution.
This is my entire line, if it offers any further indication. The AND() commands is at the end - and it still results in 0
=COUNTIFS(INDIRECT(CONCATENATE("baza!$";SUBSTITUTE(ADDRESS(1;MATCH("card_type_id";baza!$A$1:$AAA$1;0);4);"1";"");"$2:$";SUBSTITUTE(ADDRESS(1;MATCH("card_type_id";baza!$A$1:$AAA$1;0);4);"1";"");"$15000"));IF(C6="računska";1;0);INDIRECT(CONCATENATE("baza!$";SUBSTITUTE(ADDRESS(1;MATCH(IF($C$4="CC_SI_klasifikacija";"building_classification_id";0);baza!$A$1:$AAA$1;0);4);"1";"");"$2:$";SUBSTITUTE(ADDRESS(1;MATCH(IF($C$4="CC_SI_klasifikacija";"building_classification_id";0);baza!$A$1:$AAA$1;0);4);"1";"");"$15000"));AND("<="&VLOOKUP($C$5;$K$203:$N$223;4;FALSE);">="&VLOOKUP($C$5;$K$203:$N$223;3;FALSE)))

How to return a value to the left of a table array with VLOOKUP?

I need help searching Column E for value=1 and return the value of column A for the same row. VLOOKUP isn't working because there are many columns being searched and there are several 1's in the lookup, and I couldn't seem to search just 1 column using VLOOKUP. Here's how my spreadsheet looks...
A B C D E
1 Name Weight WeightRank Height HeightRank
2 Mike 170 3 6.3 2
3 Richard 200 1 6.0 3
4 Charles 185 2 7.0 1
So I want to search column E for value=1 and return the corresponding value in column A, which in this example would search "HeightRank" for "value=1" and return "Charles"
I tried using =VLOOKUP(1,E:E,1) but that returns an error.
I tried using =VLOOKUP(1,A1:E3,1) but that returns an error.
INDEX(A:A,MATCH(1,E:E,0))
VLOOKUP doesn't work here -- it always searches in the first column of your table and returns a value of a column a given number of columns to the right.
The INDEX/MATCH combination is more flexible, letting you just choose the two columns you want. It's also easier to read (you don't have to count columns to see what it does) and it doesn't break if you insert or delete columns in between the ones you're using, which VLOOKUP does. If you use the trace-formula features, VLOOKUP also falsely implies that all the columns in between are precedents of your resulting formula. (Can you tell that I don't much like VLOOKUP? I just always use INDEX/MATCH and my life is easier for it.)
The OFFSET solution works but it's volatile, so you'll really bog down your worksheet if many cells depend on the result of your formula.
MATCH(x,E2:E4,0) returns the relative position of x in the range E2:E4. For example, MATCH(1,E2:E4,0) returns 3, because 1 is the value of the third cell in the range E2:E4.
OFFSET(A2,r,c) returns the cell r rows and c columns away from A2.
Thus you can say =OFFSET(A2,MATCH(1,E2:E4,0)-1,0) to return the value from column A corresponding to the cell in column E that contains 1.

Return value of last match

I need a formula to return the value of Data for the last match of "Text". Row number is also acceptable. Macro is NOT acceptable. Name column is unsorted and cannot be sorted!
Only column "Name" is used as lookup value. I would rather use a/multiple helper column(s) instead of an array formula.
Row Name Data
1 Joe 10
2 Tom 20
3 Eva 30
4 Adam 40
5 Tom 21
LARGE only works with numbers, and VLOOKUP only returns the first match. LOOKUP only works sometimes, so its out too.
So if I wanted the last match for "Tom" then it should return "21".
Array formulas could be avoided with a helper column.
Suppose to have in F1 the name to match (i.e. Tom)
In the helper column row C2 enter
=IF(A2<>$F$1,0,row())
Then copy the formulas along your data.
Now the column C contains 0 for the unmatched names and the row number for the matched ones. Maxing the column yield the row of the solution.
Now the result is simple a matter of using the correct offset with the function offset:
=OFFSET(B1,max(C:C)-1,0)
PS: my copy of excel is in italian, so I can't test this english translaction of the formulas.
I think it's the easiest way to make it.
=LOOKUP("Tom";A2:B7)
Create a column with an array formula (enter it with Ctrl+Shift+Enter):
=VLOOKUP(MAX(IF($B$2:$B$6=B2, $A$2:A$6, 0)), $A$2:$C$6, 3, FALSE)
To make sure you did it right, click on the cell, and the formula should be shown encased in curly brackets ({}).
Note: This assumes that "Row" is in A1.
I have come up with a solution, but it requires that numbers in Data are concurrent, like so
Name Data
Joe 1
Tom 1
Eva 1
Adam 1
Tom 2
Tom 3
Eva 2
But thats okay, since that my data looks like that anyway. So if Name is used before then it must be the old highest +1 aka concurrent.
Name is A1 and Data is B1, and this formula goes into C2:
FLOOR(SQRT(2*SUMIF(A2:A7,A2,B2:B7)),1)

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