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This is a slightly more complicated issue than a simple =COUNTIF(rng,"*"&value&"*"), as found here.
I have a 2D array with cells containing data such as:
abc
def
abc def
ghi
abc,def,ghi
abcdef
ghi; def
..... and several other variations of this. I am trying to count exact matches of "abc", but I want the count to be inclusive of cells containing "abc def" and other like variations, however I can't just use the above simple COUNTIF formula since "abcdef" is not an acceptable match. The target string must stand alone or be separated from other text by an acceptable character in chars.
I think I've got this one 90% done, but the bit I need help with is combining all the possible acceptable variations of a target "name" into a flat range that I can then check my data source against for the COUNTIF. I've tried INDEX(r_1:r_8,idxRow,idxCol) and other familiar solutions that work on the sheet when referencing other ranges, but I'm new to using the =LET function. All of this works well when broken out into separate components on my spreadsheet, but I'm looking for a cleaner solution with =LET. See below for current formula:
=LET(rg, DataTable[[Q14_1]:[Q14_9]],
name, AU38,
chars, {" ",",",";"},
r, 8,
r_1, CONCATENATE(name,chars),
r_2, CONCATENATE(chars,name),
r_3, CONCATENATE(chars,name,chars),
r_4, CONCATENATE(name,chars,"*"),
r_5, CONCATENATE("*",chars,name),
r_6, CONCATENATE(chars,name,chars,"*"),
r_7, CONCATENATE("*",chars,name,chars),
r_8, CONCATENATE("*",chars,name,chars,"*"),
c, COUNTA(chars),
mSeq, SEQUENCE(r*c),
idxRow, 1+MOD(mSeq,r),
idxCol, INT((SEQUENCE(r*c)-1)/r)+1,
X, INDEX(**NeedHelpHere**,idxRow,idxCol),
SUM(COUNTIF(rg,name),COUNTIF(rg,X))
)
Give a try on below formula. If you have more delimiter like space, comma & others then you need to use more SUBSTITUTE() function.
=LET(x,FILTERXML("<t><s>"&SUBSTITUTE(SUBSTITUTE(A1:A7," ","</s><s>"),",","</s><s>")&"</s></t>","//s"),y,FILTER(x,x="abc"),SUM(--(y<>"")))
To learn about FILTERXML() please read this article from JvdV.
I've thought about this again and am posting a solution that fits my needs.
I don't need to index a single column of potential matches to then COUNTIF, I can just COUNTIF multiple times. Additionally, I was not taking into account different combinations of chars, I was only searching for the same chars on either side of the target (e.g. ",abc," when I should have also been looking for ",abc;"). Transposing the chars array on one side is a simple way of fixing this. It also turns out that "*"&target&"*" searches for "*target*" AND "target" (duh!), so I simplified further, removing duplicative possibilities.
My final formula is below, which counts the number of times target (by itself or surrounded by any acceptable chars) is present in a given rng:
=LET(rng, DataTable[Q14_1]:[Q14_9]]),
name, $A6,
chars, {" " , "," , ";"},
r_1, CONCATENATE(name,chars,"*"),
r_2, CONCATENATE("*",chars,name),
r_3, CONCATENATE("*",chars,name,TRANSPOSE(chars),"*"),
SUM(COUNTIF(rng,name),COUNTIF(rng,r_1),COUNTIF(rng,r_2),COUNTIF(rng,r_3))
)
I am not sure where to begin with the formula as I have gotten myself so confused with everything. I have a cell the contains "PON " or "PON: " or "PON = " then the actual PON (Example: PON 123467) I want to formula to return 123467 in the cell.
Examples What I want returned
I have PON 123467 for shoes 123467
I have PON: 234567-AB for food 234567-AB
I have PON - 569874-Weird for accessories 569874-Weird
I have PON = DOG-564-987 for dog food DOG-564-987
I am currently using Excel 365
Filterxml() will give you best companion here in this case. Try-
=FILTERXML("<t><s>"&SUBSTITUTE(FILTERXML("<t><s>"&SUBSTITUTE(A1," for","</s><s>")&"</s></t>","//s[1]")," ","</s><s>")&"</s></t>","//s[last()]")
Using FILTERXML, and testing for a substring following PON, you can try:
=FILTERXML("<t><s>"&SUBSTITUTE(TRIM(A1)," ","</s><s>") & "</s></t>","//s[contains(.,'PON')]/following-sibling::*[string-length(.)>2][1]")
Note that FILTERXML solution will cause a PON that is solely numeric, but with a leading zero, to drop the leading zero. Unfortunately, the xPath implementation in that function does not include the string() function
If dropping the leading zero might be a problem, you can add a character to the node that will force the number to be seen as a string. In the modified formula below, I use the unicode zero-width space, but there are others you can use. Note that this will count as a character for the string=length function, so be sure to maintain the >2 parameter:
=FILTERXML("<t><s>"&SUBSTITUTE(TRIM(A1)," ","</s><s>"&UNICHAR(8203)) & "</s></t>","//s[contains(.,'PON')]/following-sibling::*[string-length(.)>2][1]")
Because of the variablity in your data, that sometimes there are extraneous space-separated substrings between PON and your desired extract, the xpath:
locates the substring PON
returns all subsequent siblings that have a string-length of more than two (adjust if necessary)
returns the first sibling that meets that criterion.
You might try this formula.
=TRIM(LEFT(MID(A2,FIND(#{1,2,3,4,5,6,7,8,9},A2),100),FIND(" ",MID(A2,FIND(#{1,2,3,4,5,6,7,8,9},A2),100))))
It extracts the text between the first number and the first space following that number. The size of that extract is limited to 100 characters.
How can I find an entire number between a "#" and a space when that combination could appear anywhere in a given cell?
Example cell contents:
"This is a #123 Test that I 45 like to run"
"This is a #45 Test that I 98 like to run"
I need to return "123" from the first one and "45" from the second one.
Using Mid(), I can return the "1", but the problem is the number between # and space can vary in length, but there will generally be a #, number or numbers, then a space.
As a secondary issue, there may be scenarios where there is no "#", but I need to find the first numeric value in the cell and return them (i.e. "1", "34", "648").
Any advice on either of these challenges is greatly appreciated.
This should work as well:
=MID(A11,(FIND("#",A11,1)+1),FIND(" ",A11,FIND("#",A11,1)+1)-FIND("#",A11,1))
works by looking for the hash and the following space... Not for the secondary question...
Since you've put the excel-vba tag on your question, here's a vba way of doing it using regular expressions that should satisfy both your primary and secondary issues:
Sub tmp()
Dim regEx As New RegExp
regEx.Pattern = "^.*?\#?(\d+)"
Dim i As Integer
For i = 1 To Range("A" & Rows.Count).End(xlUp).Row:
Set mat = regEx.Execute(Cells(i, 1).Value)
If mat.Count = 1 Then
Cells(i, 2).Value = mat(0).SubMatches(0)
End If
Next
End Sub
The regular expression uses a non-greedy character search (ie the "?" on the end of "'.*?" is what does that) to find the first pattern in the cell that matches either "#123" or just "123" where the "123" is any arbitrary sequence of digits.
This will return the first number in a string:
=--LEFT(MID(A1,AGGREGATE(15,6,FIND({1,2,3,4,5,6,7,8,9,0},A1),1),LEN(A1)),FIND(" ",MID(A1,AGGREGATE(15,6,FIND({1,2,3,4,5,6,7,8,9,0},A1),1),LEN(A1))))
AGGREGATE was introduced in 2010 Excel. If you do not ahve that then you will need to use this array formula:
=--LEFT(MID(A1,MIN(IFERROR(FIND({1,2,3,4,5,6,7,8,9,0},A1),1E+99)),LEN(A1)),FIND(" ",MID(A1,MIN(IFERROR(FIND({1,2,3,4,5,6,7,8,9,0},A1),1E+99)),LEN(A1))))
Being an array formula it needs to be confirmed with Ctrl-Shift-Enter instead of Enter when exiting edit mode. If done correctly then excel will put {} around the formula.
I have here some text strings
"16cg-301 -request","16cg-3368 - for review","16cg-3684 - for process"
what i would like to do is to remove all the text and characters except the number and the letters "cg" and - which is within the reference code.
If the string you want to extract is always before the first space in the full string then you can use SEARCH and LEFT to extract your reference code:
=LEFT(A1,SEARCH(" ",A1)-1)
This formula would take 16cg-3368 from 16cg-3368 - for review.
I suggest using something like suggested here
How to use Regular Expressions (Regex) in Microsoft Excel both in-cell and loops
With a replace regex similar to this
[^\dcg]*
or a match regex like this
^([0-9cg- ]+).*
else you could also work with a strange formule similar to this
=CONCATENATE(IF(NOT(ISERROR(SEARCH(MID(A2;1;1);"01234567890cg-")>0));MID(A2;1;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;2;1);"01234567890cg-")>0));MID(A2;2;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;3;1);"01234567890cg-")>0));MID(A2;3;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;4;1);"01234567890cg-")>0));MID(A2;4;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;5;1);"01234567890cg-")>0));MID(A2;5;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;6;1);"01234567890cg-")>0));MID(A2;6;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;7;1);"01234567890cg-")>0));MID(A2;7;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;8;1);"01234567890cg-")>0));MID(A2;8;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;9;1);"01234567890cg-")>0));MID(A2;9;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;10;1);"01234567890cg-")>0));MID(A2;10;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;11;1);"01234567890cg-")>0));MID(A2;11;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;12;1);"01234567890cg-")>0));MID(A2;12;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;13;1);"01234567890cg-")>0));MID(A2;13;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;14;1);"01234567890cg-")>0));MID(A2;14;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;15;1);"01234567890cg-")>0));MID(A2;15;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;16;1);"01234567890cg-")>0));MID(A2;16;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;17;1);"01234567890cg-")>0));MID(A2;17;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;18;1);"01234567890cg-")>0));MID(A2;18;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;19;1);"01234567890cg-")>0));MID(A2;19;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;20;1);"01234567890cg-")>0));MID(A2;20;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;21;1);"01234567890cg-")>0));MID(A2;21;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;22;1);"01234567890cg-")>0));MID(A2;22;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;23;1);"01234567890cg-")>0));MID(A2;23;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;24;1);"01234567890cg-")>0));MID(A2;24;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;25;1);"01234567890cg-")>0));MID(A2;25;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;26;1);"01234567890cg-")>0));MID(A2;26;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;27;1);"01234567890cg-")>0));MID(A2;27;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;28;1);"01234567890cg-")>0));MID(A2;28;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;29;1);"01234567890cg-")>0));MID(A2;29;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;30;1);"01234567890cg-")>0));MID(A2;30;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;31;1);"01234567890cg-")>0));MID(A2;31;1);"");IF(NOT(ISERROR(SEARCH(MID(A2;32;1);"01234567890cg-")>0));MID(A2;32;1);""))
only works by now for less than 33 signs.
problem here will be that you will get unexpected behavior like this:
123cg-123 - Process => 123cg-123-c
after rereading , I think you should try an other approach than described in the question ;-)
If you want to return everything up to and including the last digit, then try:
=LEFT(A1,LOOKUP(2,1/ISNUMBER(-MID(A1,seq,1)),seq))
seq is a named formula: Formula ► Define Name
Name: seq
Refers to: =ROW(INDEX($1:$65535,1,1):INDEX($1:$65535,255,1))
seq returns an array of sequential numbers from 1 to 255.
mid(a1,seq,1)
returns an array consisting of the individual characters in the string in A1. The leading minus sign converts the digits from strings to numbers.
The lookup function will then return the position of the last digit
Is there a way of returning part of a string between certain characters in excel? For example my string looks like this:
`switchrefid` = {switchrefid: }
I need to cut the part of the string between the ' (apostrophes) so it just returns switchrefid
I'm sure there must be a formula for this i just cant think of the one to use.
Thanks in advance.
As long as the ``` characters occur exactly twice in your data, you can do:
=LEFT(RIGHT(A1, LEN(A1)-FIND("`", A1)), FIND("`",RIGHT(A1, LEN(A1)-FIND("`", A1)))-1)
Although it is pretty horrible!
(Edit: this assumes your data is in A1, of course.)
Just two more options, if the word always starts at the second Character and ends just before the last you could simply use :
=MID(A1,2,LEN(A1)-2) ' Minus 2 for the 2 ticks
And the second option would be to substitute the tick with nothing like so:
=SUBSTITUTE(A1,"`","")
With the substitute is also supports a number of substitutes. So if you had `switchrefid`` for some reason and only want to get rid of 2 of the three ticks you could use:
=SUBSTITUTE(A1,"`","",2)
and this would return switchrefid`
although it would not work for ''switchrefid' as it would STILL return switchrefid' because it only removes the 1st 2 instances of the text to remove