I am using Mudblazor in my Blazor app. I have the following code in a component inside ValidSubmit handler:
public async Task HandleValidSubmit()
{
DialogService.Show<SavingDialog>("Saving Data");
await Http.PostAsJsonAsync("api/Client/AddClient", CModel);
//close the dialog here...
//DialogService.Close(<need reference here>);
}
The DialogService opens the SavingDialog which is also a component.
After the http call, I want to close the dialog. How do I do that? I can see the DialogService.Close(DialogReference dialog) in the documentation. How do I get reference to the dialog box that I opened so I can close it?
Thanks.
Show returns a reference to the opened dialog!
So all you need to do is this:
public async Task HandleValidSubmit()
{
var dialogRef = DialogService.Show<SavingDialog>("Saving Data");
await Http.PostAsJsonAsync("api/Client/AddClient", CModel);
//close the dialog here...
dialogRef.Close();
}
Inside your dialog component, define this:
[CascadingParameter] MudDialogInstance MudDialog { get; set; }
then, you may able to call Close/Cancel methods.
private void Cancel()
{
MudDialog.Cancel();
}
private void Ok()
{
MudDialog.Close(DialogResult.Ok( <any result you need to pass back> ));
}
I found this, on the MudBlazor Dialog "Passing Data" example (check the .razor code)
Related
I have a MainForm class (as you'd expect, it is a form) that has a text box on it. I also have another class called 'Application_Server' That does a load of other stuff (not just form-background related, quite a lot of network based stuff etc.).
The Application_Server class runs in it's own thread, but needs to be able to update the controls on the form, for this question, we will stick with just the textbox.
The problem is that even though I am executing the command to set the text of the textBox control via 'Invoke' I am still getting the following exception during runtime:
Additional information: Cross-thread operation not valid: Control
'DebugTextBox' accessed from a thread other than the thread it was
created on.
What could be causing this? I am definitely invoking a delegate within MainForm.
Here are the relevant code segments (cut down for readability):
MainForm.h:
public ref class MainForm : public System::Windows::Forms::Form {
delegate void del_updateDebugText(String^ msg);
del_updateDebugText^ updateDebugText = gcnew del_updateDebugText(this, &MainForm::postDebugMessage);
private: void postDebugMessage(String^ message);
};
MainForm.cpp:
void EagleEye_Server::MainForm::postDebugMessage(String^ message)
{
Monitor::Enter(DebugTextBox);
if (this->DebugTextBox->InvokeRequired)
{
this->Invoke(updateDebugText, gcnew array<Object^> { message });
}
else
{
this->DebugTextBox->AppendText(message);
}
Monitor::Exit(DebugTextBox);
}
And finally, the code calling it:
void ServerAppManager::postDebugMessage(System::String^ message)
{
mainFormHandle->updateDebugText(message);
}
void ServerAppManager::applicationStep()
{
postDebugMessage("Starting\n");
// This is Run in seperate thread in MainForm.cpp
while (s_appState == ApplicationState::RUN)
{
postDebugMessage("Testing\n");
}
}
Thanks!
From background worker called bwSearch we do the call as following from the DoWork event handler:
private: System::Void bwSearch_DoWork(System::Object^ sender, System::ComponentModel::DoWorkEventArgs^ e) {
//... logic
UpdateTxtOutput("Some message");
//... more logic
}
I have a RitchTextBox called txtOutput, also the windows form control containing this code is called frmMain, the UpdateTxtOutput is defined in three parts as follows:
delegate void UpdateTxtOutputDelegate(String^ text);
void UpdateTxtOutput(String^ text)
{
UpdateTxtOutputDelegate^ action = gcnew UpdateTxtOutputDelegate(this, &frmMain::Worker);
this->BeginInvoke(action, text);
}
void Worker(String^ text)
{
txtOutput->AppendText("\t" + text + "\n");
}
I managed to get it working by simplifying the method within the 'MainForm' class to:
void EagleEye_Server::MainForm::postDebugMessage(String^ message)
{
Monitor::Enter(DebugTextBox);
DebugTextBox->AppendText(message);
Monitor::Exit(DebugTextBox);
}
And then moving the 'Invoke' call to the method calling the delegate, not pretty but it works for now. I think the issue may have been caused by the form getting stuck inside an Invoke loop. I say this as I noticed that the form would lock up and stop responding after it hit the recursive Invoke statement.
I'm using Windows Azure Mobile Services to store and retrieve data in my Windows Phone 8 app. This is a bit of a complicated issue so I will do my best to explain it.
Firstly I'm using raw push notifications to receive a message and when it receives the message it updates a listbox in my app. When I open my app, navigate to the page with the ListBox and receive a push notification the ListBox updates fine. If I press back, then navigate to the same page with the ListBox, the push notification is received, the code to update the ListBox executes with no errors yet the ListBox doesn't update. I have checked that the same code runs using the OnNavigatedTo handler in both scenarios, but it seems like the ListBox does not bind correctly in the second instance when I press back and then re-navigate to the same page. Here are some code snippets:
MobileServiceCollection declarations:
public class TodoItem
{
public int Id { get; set; }
[JsonProperty(PropertyName = "text")]
public string Text { get; set; }
}
private MobileServiceCollection<ToDoItem, ToDoItem> TodoItems;
private IMobileServiceTable<TodoItem> todoTable = App.MobileService.GetTable<TodoItem>();
Push Notification Received Handler:
void PushChannel_HttpNotificationReceived(object sender, HttpNotificationEventArgs e)
{
string message;
using (System.IO.StreamReader reader = new System.IO.StreamReader(e.Notification.Body))
{
message = reader.ReadToEnd();
}
Dispatcher.BeginInvoke(() =>
{
var todoItem = new TodoItem
{
Text = message,
};
ToDoItems.Add(todoItem);
}
);
}
I have tried using:
ListItems.UpdateLayout();
and
ListItems.ItemsSource = null;
ListItems.ItemsSource = ToDoItems;
before and after the code in the above procedure that adds the ToDoItem but it didn't help.
The following procedure is called in my OnNavigatedTo event handler, and refreshes the Listbox and assigns ToDoItems as the items source:
private async void RefreshTodoItems()
{
try
{
ToDoItems = await todoTable
.ToCollectionAsync();
}
catch (MobileServiceInvalidOperationException e)
{
MessageBox.Show(e.Message, "Error loading items", MessageBoxButton.OK);
}
ListItems.ItemsSource = ToDoItems;
}
The above procedure is async but I have made sure it completes before receiving any notifications. Even so, as mentioned above when I open the app, navigate to the page that shows the ListBox it updates fine. When I press back, navigate to the same page again, it doesn't work. When I back out of the app, re-open it, navigate to the page with the ListBox, it works again, and then fails if I press back and re-open the page. So it seems the ListBox is not binding to ToDoItems correctly when I press back and navigate to the same page.
Any help appreciated. Thanks.
Can you modify your approach a bit to use Data Binding and the MVVM model to bind your model to your view.
It might look like a bit of effort initially but will save you a lot of debugging hours later on.
Just follow the below steps
Create a new class that implements INotifyPropertyChanged
Add the below method implementation
public event PropertyChangedEventHandler PropertyChanged;
private void NotifyPropertyChanged(String propertyName)
{
PropertyChangedEventHandler handler = PropertyChanged;
if (null != handler)
{
handler(this, new PropertyChangedEventArgs(propertyName));
}
}
Add public ObservableCollection<TodoItem> TodoItems{ get; private set; } and initialize it in the constructor.
Every PhoneApplicationPage has a DataContext member. Assing it to a singleton instance of the above class that you create.
In the XAML, add the property ItemsSource="{Binding TodoItems}" to the list.
In the DataTemplate of the list use ItemsSource="{Binding Text}" for the control you wish to display this value on. ( e.g. TextBlock )
Now whenever you add elements to the collection, it will be reflected in the UI, and vice-versa.
I want to use setOnCloseRequest after my stage has been started but i get almost a NullPointerException although i set the right controller.
I click on a menuitem to open the stage and after the menu is open i want to use the close button. I think the method tries to access until the controller has been initialized.Actually i want to say: Please controller you are just allowed to do something after you are initialized.
THis is my code of the controller.
if (KundenDatenController.getInstance() != null) {
((Stage) (KundenDatenController.getInstance().kundenControllerPane.
getScene().getWindow())).setOnCloseRequest(new EventHandler<WindowEvent>() {
#Override
public void handle(WindowEvent t) {
t.consume();
if (generalControler.controlEmptyTextField(pflichtfelder)) {
((Stage) (kundenControllerPane.getScene().getWindow())).close();
} else if (!generalControler.controlEmptyTextField(pflichtfelder)) {
FXOptionPane.showConfirmDialog((Stage) (kundenControllerPane.getScene().getWindow()),
"Sollen die Eingaben wirklich verworfen werden?",
"Programm schliessen");
if (status.equals("Laden")) {
KundenUebersichtController.getInstance().setStatus("Aufnehmen");
}
}
}
});
I just did a dictionary application in blackberry along with a speech to text conversion support .Everything is working fine. Now i wanted to disable the sound when the user needs So how can i do it programmatically .Please help me
Try this
use the flag value as reference
if flag value is true then user click on item then it will play the sound
else sound wont play and display one dialog that Do you want enable sound with two options yes or no
if user click on yes then make flag value as true and item.setText("Voice Disable"); otherwise no action means no changes in flag
in your list item click listener write condition as following
if(flag==true)
{
write your logic to play
}
sample code is
public class app extends UiApplication{
public static void main(String[] args) {
new app().enterEventDispatcher();
}
public app() {
pushScreen(new SampleScreen());
}
}
class SampleScreen extends MainScreen
{
static boolean flag=true;
MenuItem item=null;
public SampleScreen() {
// use the flag value as reference
// if flag value is true then user click on item then it will play the sound
// else sound wont play and display one dialog that Do you want enable sound with two options yes or no
// if user click on yes then make flag value as true and item.setText("Voice Disable"); otherwise no action means no changes in flag
// in your list item click listner write condition as following
// if(flag==true)
// {
// write your logic to play
// }
// you already implement
item=new MenuItem("Voice Disable",0,100) {
public void run() {
if(flag)
{
flag=false;
item.setText("Voice Enable");
UiApplication.getUiApplication().invokeLater(new Runnable() {
public void run() {
Dialog.inform("Voice Disable succesfully");
}
});
}else{
flag=true;
item.setText("Voice Disable");
UiApplication.getUiApplication().invokeLater(new Runnable() {
public void run() {
Dialog.inform("Voice Enable succesfully");
}
});
}
}
};
addMenuItem(item);
}
}
I am working with j2me using lwuit I have one problem is that
when I am startApp() inside midlet I first set Display.init(this)
and run application lwuit work good but when I am using Form inside startApp() event in midlet it good work but in this form actionevent I am call new form and in this new form
I put one back command when I pressed it it does not move on main midlet
please help how know lwuit use
import javax.microedition.MIDlet;
import some lwuit UILibrary
public class mainMiddlet extends MIDlet implement ActionListner
{
public mainMiddlet(){
try{
Display.init(this);
//somthing is here
form=new Form();
form.addActionListener(this);
}catch(Exception e){}
}
public void actionperformed(ActionEven ae){
//here i call new form
//in action event of this form
new form().show();
}
//here some middlet default method
}
public class newForm extends Form {
//in this form I am put one command back and when i am pressed it
// I call mainMiddlet but it throw error internal application java.lang.nullpointer
// can I back on mainmiddlet from on form to another form
// my main problem is I am not move on mainmiddlet for exit middlet because destoryall()
// is method of middlet
}
Its just simple. You can call the show() method inside next form back command. For example,
MainMidlet.java
// create the midlet and write inside of the midlet
final Form form = new Form();
form.addCommand(new Command("Next") {
public void actionPerformed(ActionEvent evt) {
new NewForm(form).show();
}
});
NewForm.java
// create the NewForm class and write inside of the class
public NewForm(final Form form) {
// Constructor
addCommand(new Command("Back") {
public void actionPerformed(ActionEvent evt) {
form.show();
}
});
}