I'm looking for a formula that re-arranges values in excel cells.
The cells contain full names (at least one, up to 20) in the format of "last name + name(s)" but this must be convert into the following format:
1.- First letter of first name, follow by a blank space.
2.- Last name
An example can be found below.
I know I could simple use replace function, but it would be great if this might be possible to achieve via excel formulas.
Thanks in advance.
Since the strings can be so long, I would use FILTERXML and LET if you have the newest version of Excel rather than keep having to repeat things like LEFT, LEN, or FIND.
For example, if the data is always seperated by a "|" and only comes in the form "Last_Name First_Name (possible Mid_Initial)|", then you can use something like:
=LET(x, FILTERXML("<t><s>"&SUBSTITUTE(I1, "|", "</s><s>")&"</s></t>", "//s"),
y, TRIM(LEFT(RIGHT(x, LEN(x)-SEARCH(" ",x)),1)),
z, TRIM(LEFT(x, SEARCH(" ",x))),
LEFT(CONCAT(y&" "&z&", "), LEN(CONCAT(y&" "&z&", "))-2))
Try this UDF.
Option Explicit
Function ExtractName(cellRng As Range)
Dim regex As Object, mc As Object, i As Long, str As String, arr
Set regex = CreateObject("VBScript.regexp")
regex.ignorecase = False
regex.Global = True
arr = Split(cellRng.Value, "|")
str = ""
For i = LBound(arr) To UBound(arr)
regex.Pattern = "^[\w-]+\s\b."
Set mc = regex.Execute(arr(i))
str = str & Split(mc(0), " ")(1) & " " & Split(mc(0), " ")(0) & "|"
Next i
ExtractName = Left(str, Len(str) - 1)
End Function
Related
Essentially I have multiple strings within my Excel Spreadsheet that are structured the following way:
JOHN-MD-HOPKINS
REC-PW-RESIN
I would like to use the proper function but exclude the part of the string that is within the dashes (-).
The end result should look like the following:
John-MD-Hopkins
Rec-PW-Resin
Is there an excel formula that is capable of doing this?
You may need to create your own VBA function to do this, that checks if there are two hyphens in the data, and if so converts the first and last words to proper case without touching the middle word, otherwise just converts the string to proper case.
Paste the following into a module within Excel:
Function fProperCase(strData As String) As String
Dim aData() As String
aData() = Split(strData, "-")
If UBound(aData) - LBound(aData) = 2 Then ' has two hyphens in the original data
fProperCase = StrConv(aData(LBound(aData)), vbProperCase) & "-" & aData(LBound(aData) + 1) & "-" & StrConv(aData(UBound(aData)), vbProperCase)
Else ' just do a normal string conversion to proper case
fProperCase = StrConv(strData, vbProperCase)
End If
End Function
Then, in your worksheet, you can use this just as you would any built-in formula, so if "JOHN-MD-HOPKINS" is in cell A1, you would use this as a formula in another cell:
=fProperCase(A1)
Which would display John-MD-Hopkins as required.
EDITED CODE
As the requirement is to leave the second word, then this modified VBA function, which "walks" the array should work instead:
Function fProperCase2(strData As String) As String
Dim aData() As String
Dim lngLoop1 As Long
aData() = Split(strData, "-")
For lngLoop1 = LBound(aData) To UBound(aData)
If (lngLoop1 = LBound(aData) + 1) And (lngLoop1 <> UBound(aData)) Then
aData(lngLoop1) = aData(lngLoop1)
Else
aData(lngLoop1) = StrConv(aData(lngLoop1), vbProperCase)
End If
Next lngLoop1
fProperCase2 = Join(aData, "-")
End Function
It basically looks to see if the array element being dealt with is the second (lngLoop1=LBound(aData)+1) and also not the last (lngLoop1<>UBound(aData)).
Regards,
If I search for the term 'tfo' in the cell value 'TFO_xyz' then the result should be TRUE.
If I search for the term 'tfo' in the cell value 'TFO systems' then the result should be TRUE.
If I search for the term 'tfo' in the cell value 'spring TFO' then the result should be TRUE.
BUT if I check 'tfo' in the cell value 'Platform' then I want the result as FALSE
I have used the formula =IF(COUNTIF(A2,"*tfo*"),"TRUE","FALSE"), but this wont give result as FALSE when I check 'tfo' in the word 'Platform'
NOTE:
Platform should be false because tfo is coming in between a word. I'm looking result as True for cell values with just the word tfo like in tfo<space>America or TFO_America or <space>TFO systems. But I want FALSE result for the words Platform and portfolio because in these two words the term tfo comes in between alphabets.
Try this:
Dim x As Long: x = 1
With Sheet1
Do While x <= .Cells(.Rows.Count, 1).End(xlUp).Row
If VBA.Left(.Cells(x, 1).Value, 3) = "tfo" Or VBA.Right(.Cells(x, 1).Value, 3) = "tfo" Then
.Cells(x, 2).Value = True
End If
x = x + 1
Loop
End With
Try this formula. This assumes that word tfo will be at the beginning or end
Just make sure to place appropriate cell names where i have 'A2' in the formula
=IF(OR(PROPER(LEFT(A2,3))="tfo",PROPER(RIGHT(A2,3))="tfo"),TRUE,FALSE)
Test Cases Below:
My suggestion is to spend sometime to know your data and create a white-list.
Since there is no easy way to properly do fuzzy search in strings.
Function TFO_Search(strText As String) As Boolean
Dim ArryString As Variant
Dim ArryWhitelist As Variant
' Create a White-List Array
ArryWhitelist = Array("TFO_", "TFO ", "_TFO", " TFO", "tfoAmerica")
For Each ArryString In ArryWhitelist
If InStr(UCase(strText), UCase(ArryString)) > 0 Then 'force to UPPER CASE
TFO_Search = True
Exit Function
Else
TFO_Search = False
End If
Next
End Function
I see two dimensions of complexity in your question:
Where does the key word occur in the text (beginning, middle, end)
What are the characters that separate words.
The first one is fixed size, you need to handle three cases. The second one depends on the number of characters you want to accept as delimiters. Below I assumed that you accept space and underscore, however, you may expand this set by inserting more SUBSTITUTE function calls.
In my table, $A2 is the cell in which you search for the keyword, while B$1 contains the keyword.
To standardize the separator character, you need the formula:
B2=SUBSTITUTE($A2,"_"," ")
To check if the string starts with the keyword:
C2=--(LEFT($B2,LEN(B$1)+1)=B$1&" ")
To check if the string ends with the keyword:
D2=--(RIGHT($B2,LEN(B$1)+1)=" "&B$1)
To check if the keyword is in the middle of the string:
E2=--(LEN(SUBSTITUTE(UPPER($B2)," "&UPPER(B$1)&" ",""))<LEN($B2))
To evaluate the above three cases:
F2=--(0<$C2+$D2+$E2)
If you want to use a single cell, combine the formulas into:
G2=--(0<--(LEFT(SUBSTITUTE($A2,"_"," "),LEN(B$1)+1)=B$1&" ")+--(RIGHT(SUBSTITUTE($A2,"_"," "),LEN(B$1)+1)=" "&B$1)+--(LEN(SUBSTITUTE(UPPER(SUBSTITUTE($A2,"_"," "))," "&UPPER(B$1)&" ",""))<LEN(SUBSTITUTE($A2,"_"," "))))
It is not very readable in the end but I don't think there was an easier solution using Formulas only.
Note: If you want to modify the set of characters accepted as delimiters, add more SUBSTITUTE function calls to B2, then copy the Formula of F2 into notepad and replace $C2 with the formula of C2, etc., then replace $B2 with the updated Formula of B2.
Update
Building on the idea in Ron Rosenfelds comment to tigeravatar's answer, the formula can be simplified (the beginning, middle, ending cases can be joined):
=--(LEN(SUBSTITUTE(" "&UPPER($B2)&" "," "&UPPER(B$1)&" ",""))<LEN($B2))
After substituting $B2 with its formula:
=--(LEN(SUBSTITUTE(" "&UPPER(SUBSTITUTE($A2,"_"," "))&" "," "&UPPER(B$1)&" ",""))<LEN(SUBSTITUTE($A2,"_"," ")))
This formula will return true if TFO is at the beginning or end of any given word, or by itself, in the text string. It also checks every word in the text string, so TFO can be at beginning, middle, or end. The formula assumes that if a word starts or ends with TFO, then the result should be TRUE (as is the case for tfoAmerica so same rule would apply to tform), else FALSE.
=OR(ISNUMBER(SEARCH({" tfo","tfo "}," "&SUBSTITUTE(A2,"_"," ")&" ")))
Here are its results:
EDIT:
In the event that the result should only be TRUE if TFO is found by itself, then this version of the formula will suffice:
=ISNUMBER(SEARCH(" tfo "," "&SUBSTITUTE(A2,"_"," ")&" "))
Image showing results of second version:
If you can rely on VBA, then regex is a more flexible solution.
There is a good summary, of how to use them in VBA: How to use Regular Expressions (Regex) in Microsoft Excel both in-cell and loops
For your keyword search problem I wrote the following:
Option Explicit
' Include: Tools > References > Microsoft VBScript Regular Expressions 5.5 (C:\Windows\SysWOW64\vbscript.dll\3)
Public Function SearchKeyWord(strHay As String, strNail As String, Optional strDelimiters As String = " _,.;/", Optional lngNthOccurrence As Long = 1) As Long ' Returns 1-based index of nth occurrence or 0 if not found
Dim strPattern As String: strPattern = CreatePattern(strNail, strDelimiters)
Dim rgxKeyWord As RegExp: Set rgxKeyWord = CreateRegex(strPattern, True)
Dim mtcResult As MatchCollection: Set mtcResult = rgxKeyWord.Execute(strHay)
If (0 <= lngNthOccurrence - 1) And (lngNthOccurrence - 1 < mtcResult.Count) Then
Dim mthResult As Match: Set mthResult = mtcResult(lngNthOccurrence - 1)
SearchKeyWord = mthResult.FirstIndex + Len(mthResult.SubMatches(0)) + 1
Else
SearchKeyWord = 0
End If
End Function
Private Function CreateRegex(strPattern As String, Optional blnIgnoreCase As Boolean = False, Optional blnMultiLine As Boolean = True, Optional blnGlobal As Boolean = True) As RegExp
Dim rgxResult As RegExp: Set rgxResult = New RegExp
With rgxResult
.Pattern = strPattern
.IgnoreCase = blnIgnoreCase
.MultiLine = blnMultiLine
.Global = blnGlobal
End With
Set CreateRegex = rgxResult
End Function
Private Function CreatePattern(strNail As String, strDelimiters As String) As String
Dim strDelimitersEscaped As String: strDelimitersEscaped = RegexEscape(strDelimiters)
Dim strPattern As String: strPattern = "(^|[" & strDelimitersEscaped & "]+)(" & RegexEscape(strNail) & ")($|[" & strDelimitersEscaped & "]+)"
CreatePattern = strPattern
End Function
Private Function RegexEscape(strOriginal As String) As String
Dim strEscaped As String: strEscaped = vbNullString
Dim i As Long: For i = 1 To Len(strOriginal)
Dim strChar As String: strChar = Mid(strOriginal, i, 1)
Select Case strChar
Case ".", "$", "^", "{", "[", "(", "|", ")", "*", "+", "?", "\"
strEscaped = strEscaped & "\" & strChar
Case Else
strEscaped = strEscaped & strChar
End Select
Next i
RegexEscape = strEscaped
End Function
Once you have the above in a Module, you can insert formulas like the following:
=SearchKeyWord($A1,"tfo")
where A1 contains e.g. "tfo America".
As a third parameter, you may specify, which characters you want to treat as delimiters, by default they are space, underscore, comma, dot, semicolon and slash.
The return value is the position of the nth occurrence of the keyword, where n is the value of the fourth parameter (default: 1), or 0 if not found.
To check if the keyword is present in A1, compare the result to 0, which means not found:
=--(SearchKeyWord($A1,"tfo")<>0)
I have two columns with data. The first one has some terms and the other one contains single words.
what I have
I'm looking for a way to identify which words from each cell from the first column appear in the second, so the result should look something like this (I don't need the commas):
what I need
My question is somehow similar to Excel find cells from range where search value is within the cell but not exactly, because I need to identify which words are appearing in the second column and there can be more than one word.
I also tried =INDEX($D$2:$D$7;MATCH(1=1;INDEX(ISNUMBER(SEARCH($D$2:$D$7;A2));0);))
but it also returns only one word.
If you are willing to use VBA, then you can define a user defined function:
Public Function SearchForWords(strTerm As String, rngWords As Range) As String
Dim cstrDelimiter As String: cstrDelimiter = Chr(1) ' A rarely used character
strTerm = cstrDelimiter & Replace(strTerm, " ", cstrDelimiter) & cstrDelimiter ' replace any other possible delimiter here
SearchForWords = vbNullString
Dim varWords As Variant: varWords = rngWords.Value
Dim i As Long: For i = LBound(varWords, 1) To UBound(varWords, 1)
Dim j As Long: For j = LBound(varWords, 2) To UBound(varWords, 2)
If InStr(1, strTerm, cstrDelimiter & varWords(i, j) & cstrDelimiter) <> 0 Then
SearchForWords = SearchForWords & varWords(i, j) & ", "
End If
Next j
Next i
Dim iLeft As Long: iLeft = Len(SearchForWords) - 2
If 0 < iLeft Then
SearchForWords = Left(SearchForWords, Len(SearchForWords) - 2)
End If
End Function
And you can use it from the Excel table like this:
=SearchForWords(A2;$D$2:$D$7)
I have a partial solution:
=IF(1-ISERROR(SEARCH(" "&D2:D7&" "," "&A2&" ")),D2:D7&", ","")
This formula returns an array of the words contained in the cell (ranges are according to your picture). This array is sparse: it contains empty strings for each missing word. And it assumes that words are always separated by one space (this may be improved if necessary).
However, native Excel functions are not capable of concatenating an array, so I think the rest is not possible with native formulas only.
You would need VBA but if you use VBA you should not bother with the first part at all, since you can do anything.
You can create a table with the words you want to find across the top and use a formula populate the cells below each word if it's found. See screenshot.
[edit] I've noticed that it's incorrectly picking up "board" in "blackboard" but that should be easily fixed.
=IFERROR(IF(FIND(C$1,$A2,1)>0,C$1 & ", "),"")
Simply concatinate the results
=CONCATENATE(C2,D2,E2,F2,G2,H2)
or
=LEFT(CONCATENATE(C2,D2,E2,F2,G2,H2),LEN(CONCATENATE(C2,D2,E2,F2,G2,H2))-2)
to take off the last comma and space
I've edited this to fix the problem with "blackboard"
new formula for C2
=IF(OR(C$1=$A2,ISNUMBER(SEARCH(" "&C$1&" ",$A2,1)),C$1 & " "=LEFT($A2,LEN(C$1)+1)," " & C$1=RIGHT($A2,LEN(C$1)+1)),C$1 & ", ","")
New formula for B2 to catch the error if there are no words
=IFERROR(LEFT(CONCATENATE(C2,D2,E2,F2,G2,H2,I2),LEN(CONCATENATE(C2,D2,E2,F2,G2,H2,I2))-2),"")
I'm trying to get all the content between multiple parenthesis and comma delimiting them. So for example
A1 contains
thisfile.jpg (/path/to/file.jpg), thisfile2.jpg (/path/to/file2.jpg)
and B1 should look like
/path/to/file.jpg, /path/to/file2.jpg
If it's just one entry I can get what I need with this:
MID(A1,FIND("(",A1)+1,FIND(")",A1)-FIND("(",A1)-1)
But that only returns the first one, I need to be for each parenthesis. The amount of parenthesis in each row will vary.
I am sure there are better solutions out there with formulas only. Yet, I cannot help you there. But the following UDF is surely also a feasible solution. Just copy this code into an empty module:
Option Explicit
Public Function GetPaths(strTMP As String)
Dim i As Long
Dim varArray As Variant
varArray = Split(strTMP, "(")
For i = LBound(varArray) To UBound(varArray)
If InStr(1, varArray(i), ")") > 0 Then
GetPaths = GetPaths & ", " & Mid(varArray(i), 1, InStr(1, varArray(i), ")") - 1)
End If
Next i
GetPaths = Mid(GetPaths, 3)
End Function
Afterwards, you can use this formula in column B as follows: =GetPaths(A1).
I'm trying to prepare a spreadsheet for a report in excel vba. Unforturnately there are some wierd characters here that need to be replaced. Easy enough, except for this chracter:
¦
I can't seem to be able to paste that character into the editor into a string replace function. When I try, the output is _. I then thought to refer to it by it's Chr code. A quick look up said it was Chr(166). http://www.gtwiki.org/mwiki/?title=VB_Chr_Values
Replace(s, "â€" + Chr(166), "...")
But this is not that character at all (at least on Mac excel). I tried:
For i = 1 To 255
Debug.Print Chr(i)
Next i
And I didn't see this character anywhere. Does anyone know how I can reference this character in vba code in order to replace it?
Not sure if regexp is available for vba-mac, but you could simplify your existing code greatly as below.
Uses a sample Strin
Dim strIn As String
strIn = "1â€1â€x123"
Do While InStr(strIn, "â€") > 0
Mid$(strIn, InStr(strIn, "â€"), 3) = "..."
Loop
Click on a cell containing your miscreant character and run this small macro:
Sub WhatIsIt()
Dim s As String, mesage As String
Dim L As Long
s = ActiveCell.Text
L = Len(s)
For i = 1 To L
ch = Mid(s, i, 1)
cd = Asc(ch)
mesage = mesage & ch & " " & cd & vbCrLf
Next i
MsgBox mesage
End Sub
It should reveal the characters in the cell and their codes.
It's dirty, but here's the workaround that I used to solve this problem. I knew that my issue character was always after "â€", so the idea was to replace the character that came after those 2. I don't really know how to replace a character at a position in a string, so my idea was to covert the string to an array of characters and replace the array at those specific indexes. Here's what it looks like:
Do While InStr(s, "â€") > 1
num2 = InStr(s, "â€")
arr = stringToArray(s)
arr(num2 - 1) = "<~>"
arr(num2) = "<~>"
arr(num2 + 1) = "<~>"
s = Replace(arrayToString(arr), "<~><~><~>", "...")
Loop
...
Function stringToArray(ByVal my_string As String) As Variant
Dim buff() As String
ReDim buff(Len(my_string) - 1)
For i = 1 To Len(my_string)
buff(i - 1) = Mid$(my_string, i, 1)
Next
stringToArray = buff
End Function
Function arrayToString(ByVal arr As Variant) As String
Dim s As String
For Each j In arr
s = s & j
Next j
arrayToString = s
End Function
In practice, what I replaced those indexes with is something that had to be unique but recognizable. Then i can replace my unique characters with whatever I want. There are sure to be edge cases, but for now it gets the job done. stringToArray function pulled from: Split string into array of characters?