I am using the WP-CLI for updating WooCommerce product_cat terms. When using wp wc product_cat get to retrieve individual fields, a line feed character (a0) seems to get inserted as leading character. Example:
$ echo "»"$(wp wc product_cat --user=4 get 44277 --field="description")"«"
» All widgets for A.-C.«
Another example - Note that the leading character is before the opening "
$ i1=$(wp wc product_cat --user=4 get 18869 --field="name" --format="json")
$ echo "format=json: »"$i1"«"
format=json: » "AEG"«
Additional information:
This happens for all fields
I verified that the added character is a0 by updating the field and checking in the database
Using --format didn't make a difference
Using --context didn't make a difference
I'm working on Linux Mint with Bash version 5.0.17(1).
Did I make a mistake somehwere in my syntaxis that inadvertently inserted this leading character? Or am I missing something in how WP-CLI or Bash works? Thanks in advance! Jeroen
Related
I'm using a shell & TCL script to login to a switch and get the output of certain commands and in some places I can see ^D coming up. I tried to use the dos2unix utility but still it didn't go away.
Eth1/37 NOM: xcvrAbsen routed auto auto --
^DEth1/38 NOM: xcvrAbsen routed auto auto --
Eth1/39 NOM: xcvrAbsen routed auto auto --
Eth101/1/45 eth 1000 NOM:NO_PATCHING CABLE
^DEth101/1/46 eth 1000 NOM:NO_PATCHING CABLE
Eth101/1/47 eth 1000 NOM:NO_PATCHING CABLE
How can this be eliminated, are there any standard tools like dos2unix which can get rid of such data?
What I'm trying to do is to compare two files which are from the same switch and the same command and the same output, but due to these ^D, Vimdiff shows it as different lines.
How to get this eliminated?
Command I'm using is something like this:
$cdir/ciscocmd -Y -u $operator -p $password -s $password -t $switch -r rfc_sa_commands | sed 's/^^D//' > $switch.$NOW
dos2unix removes carriage returns, no other control characters.
The tool to remove all occurrences of an arbitrary character is called tr.
tr -d '\004' <inputfile >outputfile
This assumes you have literal ctrl-D characters, not sequences of caret ^ and D. The tr utility cannot remove a specific sequence; it just processes individual characters. To remove a sequence, you'd need
sed 's/\^D//g' inputfile >outputfile
where the backslash is required because the caret alone has a special meaning in regular expressions (it matches beginning of line). Doubling it does not escape it; ^^ probably still just matches beginning of line, though it's not really well-defined, and could introduce apparently random behavior.
Even if the special character is visible as '^D', it may be NOT catchable like this.
Interesting readings, are:
https://en.wikipedia.org/wiki/ASCII#Character_groups
https://en.wikipedia.org/wiki/End-of-Transmission_character
I think a way to do it would be:
<your command>|sed -e 's/\x04//g'
Does it solve your issue?
I'm currently working on a Unix box and came across this post which I found helpful, in order to learn about cat command in Unix. At the bottom of the page found this line saying: -A = Equivalent to -vET
As I'm new into Unix, I'm unaware of what does this mean actually? For example lets say I've created a file called new using cat and then apply this command to the file:
cat -A new, I tried this command but an error message comes up saying it's and illegal option.
To cut short, wanted to know what does cat -A really mean and how does it effect when I apply it to a file. Any help would be appreciated.
It means show ALL.
Basically its a combination of -vET
E : It will display '$' at the end of every line.
T : It will display tab character as ^I
v : It will use ^ and M-notation
^ and M-notation:
(Display control characters except for LFD(LineFeed or NewLine) and TAB using '^' notation and precede characters that have the high bit set with
'M-') M- notation is a way to display high-bit characters as low bit ones by preceding them with M-
You should read about little-endian and big-endian if you like to know more about M notation.
For example:
!http://i.imgur.com/0DGET5k.png?1
Check your manual page as below and it will list all options avaialable with your command and check is there -A present, if it is not present it is an illegal option.
man cat
It displays non-printing characters
In Mac OS you need to use -e flag and
-e Display non-printing characters (see the -v option), and display a dollar sign (`$') at the end of each line.
So, im making a small script to do an entire task for me. The task is to get the output of the dmidecode -Fn into a text file and then take a part of the dmidecode output, in my example, the Address (0xE0000) as the file name of the txt.
My script goes as follows and does work, i have tested it. The only little issue that i have, is that the file name of the txt appears as "? 0xE0000.txt"
My question is, why am i getting a question mark followed by a space in the name?
#!/bin/bash
directory=$(pwd)
name=$(dmidecode|grep -i Address|sed 's/Address://')
inxi -Fn > $directory/"$name".txt
The quotes in the "$name".txt is to avoid an "ambiguous redirect" error i got when running the script.
Update #Just Somebody
root#server:/home/user/Desktop# dmidecode | sed -n 's/Address://p'
0xE0000
root#server:/home/user/Desktop#
Solution
The use of |sed -n 's/^.*Address:.*0x/0x/p' got rid of the "? " in 0xE0000.txt
A big thanks to everyone!
You've got a nonprinting char in there. Try:
dmidecode |grep -i Address|sed 's/Address://'| od -c
to see exactly what you're getting.
UPDATE: comments indicate there's a tab char in there that needs to be cleaned out.
UPDATE 2: the leading tab is before the word Address. Try:
name=$(dmidecode |grep -i Address|sed 's/^.*Address:.*0x/0x/')
or as #just_somebody points out:
name=$(dmidecode|sed -n 's/^.*Address:.*0x/0x/p')
UPDATE 3
This changes the substitution regex to replace
^ (start of line) followed by .* (any characters (including tab!)) followed by Address: followed by .* (any characters (including space!)) followed by 0x (which are always at the beginning of the address since it's in hex)
with
0x (because you want that as part of the result)
If you want to learn more, read about sed regular expressions and substitutions.
I'm setting up a logging script with Ruby and am having some difficulties with getting the load averages as a variable. I'm using:
uptime | awk '{print $10}'
to get the current 1 minute time stamp, but I'm having trouble getting it without a trailing comma. I could edit the string later, but that seems less efficient. Is there an edit that will simply remove the , from the return?
How about:
cut -f 1 -d " " /proc/loadavg
The uptime command reads /proc/loadavg and then adds the commas.
In the end, it also works through /proc/loadavg, but the usage is a little more idiomatic, so I thought I'd mention the sys-cpu Gem (which existed even in 2013 :)) as well:
gem install sys-cpu
require 'sys-cpu'
puts Sys::CPU.load_avg
... which will give you a nice array: [0.72, 1.14, 1.11].
I've a progam installed in my linux box called my-scheduler-1.1.0-1112
When I do rpm -qa | grep my, it lists as shown below:
my-scheduler-1.1.0-1112
I want a command which will extract 1.1.0-1112 which is version part in my shell script.
what would be the command to extract it in shell script?
For this question you can try the --queryformat parameter for rpm.
like:
rpm -qa --queryformat '%{NAME}' | grep my
should print
my-scheduler
without the version string... What is much better as mugling it with sed or like. Because you can get something like package-1.0.3-rc2 or soo..
For version-release: use:
--queryformat "%{VERSION}-%{RELEASE}"
and maybe will be useful read http://www.rpm.org/max-rpm/ch-queryformat-tags.html - here is many useful query format tags, so you can directly can get what you want and in what format you want, without scripting...
Not sure what other version strings you may encounter, but you can try:
sed -e 's/^[^0-9]*-//g'
This is a sed replace. It's matching the regular expression ^[^0-9]*-, which is:
starting from the beginning of the String
match as many non-numbers as there are
then the very next character is a -
And it replaces everything that matched with a blank, essentially removing it. This should leave everything after that which is the version string.