not sure if this can even be done, Google search has not been too helpful (mainly due to the fact its just returning how to add a prefix)
Problem:
I have one column in Excel with two comma separated values - for arguments sake, "Bill, Ted" in A1 and I'd like to add a prefix to BOTH of the names, lets just say the word "excellent"
What I have so far looks like this and yields the correct result but only for the first value, so is there a way I can define it to attach the prefix to the next value?
=CONCATENATE("excellent",A1) - "excellentBill, Ted"
So my desired result would be:
"excellentBill, excellentTed"
I'm sure its pretty straighforward but I've been trying different approaches with CONCATENATE and SUBSTITUTE and just can't seem to get the desired result. I was wondering if you can prepend a LEN FUNCTION but wondered if there is a simpler approach?
Any help is appreciated.
Thanks.
Try this. I'm finding the delimiter in the cell then building around that.
="Excellent" & left(A1, Find(",",A1))& "Excellent" & right(A1, len(A1) -Find(",",A1))
=Concat("Excellent",left(A1, Find(",",A1)),"Excellent",right(A1,len(A1) - Find(",",A1)))
Related
I have a string in a cell which is a list of words like this:
a,b,c,d,e,f,g,h,f,c,a,h
I'd like to find and remove all the words which are on this list:
c,f,h
I can use multiple SUBSTITUTE but since my list is long, nested SUBSTITUTE is not convenient.
Here is the example sheet: https://docs.google.com/spreadsheets/d/11ZT3CMJ9vfUcOIvhXYLHUHHQm5tm1Tb1N9hi3LeI0WM/edit#gid=0
There is also a solution here but I'd like to use an existing list instead of manually inserting to the function.
You can use an existing list instead of manually inserting to the function.
Make a list of the words you want replaced in a column eg. A3:A9 and use the following formula to create your expression.
=JOIN("|",A3:A9)
Then use the working solution from your mentioned answer (or whichever formula meets your needs) to get the final result.
=REGEXREPLACE(A1,"\b("&B3&")\b",)
This is a second version based on suggestions from #marikamitsos
, I have added a string ", .. $" to the last partern position because there is no comma at the end of the text in a1.
=RegexReplace(RegexReplace(A1&",","\b(" & SUBSTITUTE(A3&",",",",",|") & ")(\b|$)",""),",$","")
In addition to previous answer, you can also try
=textjoin(",", 1, ArrayFormula(regexreplace(split(A2, ","), textjoin("|",1,A5:A8),)))
I have a dictionary containing lots of words - I want the user to be able to input a list of substrings, and then a filtered list will be updated, containing only words that contain those substrings and nothing else. Any words that contain extra characters the user didn't specify, should not appear. Cell F3 will use a FILTER function to create the list. As in the mock-up below:
What I need is a formula that would generate the TRUE or FALSE flags from the yellow section (B3:B9), but I'm not sure how to go about this.
I'm sure this could be solved by VBA or Regex using Google Sheets, but I want to know if there's a way to do this by formula, as I don't want this to require a button press or script execution, and my spreadsheet can't be hosted on Google sheets due to its size. Any ideas?
You can also use a combination of ISNUMBER and SUMPRODUCT:
=ISNUMBER(SUMPRODUCT(MATCH(MID(A3,ROW(INDEX(A:A,1,1):INDEX(A:A,LEN(A3),1)),1),$D$3:$D$5,0)))
Adjusted formula:
=ISNUMBER(SUMPRODUCT(MATCH(MID(A3,ROW(A$1:INDEX(A:A,LEN(A3))),1),$D$3:$D$5,0)))
The result:
The test being ran below is subtracting each instance of your dictionary from the length of original string. If the result is 0, this returns TRUE. If not, this returns FALSE. This is not case sensitive - a & A will be treated equally here.
=NOT(LEN(A1)-(LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),D1,"")))-(LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),D2,"")))-(LEN(A1)-LEN(SUBSTITUTE(UPPER(A1),D3,""))))
The equation works fine although I don't know if it is an optimal solution for you, but posting as answer in case it is for somebody else. The issue with this approach is the equation gets longer and longer for each character you add to your dictionary. Depending on the size of dictionary and strings to test against, this can get sloppy and calc heavy really quick.
Have you considered a UDF in VBA?
I have a large spreadsheet with column data like:
ABC:1:I.0
ABC:1:I.1
ABC:1:I.2
ABC:1:I.3
ABC:2:I.0
ABC:2:I.1
ABC:2:I.2
ABC:2:I.3
ABC:3:I.0
ABC:3:I.2
ABC:3:I.3
ABC:4:I.0
ABC:4:I.1
ABC:4:I.2
ABC:4:I.3
ABC:5:I.0
ABC:5:I.1
ABC:5:I.2
ABC:5:I.3
ETC.
I need to replace the above with the following:
ABC:I.Data[1].0
ABC:I.Data[1].1
ABC:I.Data[1].2
ABC:I.Data[1].3
ABC:I.Data[2].0
ABC:I.Data[2].1
ABC:I.Data[2].2
ABC:I.Data[2].3
ABC:I.Data[3].0
ABC:I.Data[3].2
ABC:I.Data[3].3
ABC:I.Data[4].0
ABC:I.Data[4].1
ABC:I.Data[4].2
ABC:I.Data[4].3
ABC:I.Data[5].0
ABC:I.Data[5].1
ABC:I.Data[5].2
ABC:I.Data[5].3
ETC.
Here is a sample of the data, most of the data follows a similar format with the exception of the naming "ABC", which can vary in size, so it might be "ABCD" and also with the exception of the letter "I", it can be "O" as well. Also, some might be missing some values such as ABC:3:I.1 which is missing from the data. I am not too familiar with excel formulas or VBA code. Does anyone know how to do this? I have no preference on which method it has to be done in as I don't mind learning some VBA code if someone provides me with a VBA solution.
I was thinking of using some sort of loop along with some conditional statements.
Thanks!
Please try:
=LEFT(F11,FIND(":",F11))&MID(F11,FIND(":",F11,6)+1,1)&".Data["&MID(F11,FIND(":",F11,2)+1,1)&"]."&RIGHT(F11,1)
copied down to suit, assuming placed in Row11 and your data is in ColumnF starting in Row11.
Curiosities:
When this A was first posted it attempted to address only the tabulated example input and output. I temporarily deleted that version while addressing that what was in the table as ABC might at times be ABCD and that what was I might at times be O.
OP has posted an answer that I edited to make no visible change but which shows as the deletion of two characters. A copy of the OP’s formula exhibited a syntax error prior to my edit.
OP suggested an edit to my answer but this was rejected by the review process. As it happens, I think the edit suggestion was incorrect.
I have edited my answer again to include these ‘curiosities’ and to match the cell reference used by the OP in his answer.
=LEFT(A1,SEARCH(":",A1)) & MID(A1, SEARCH(".",A1)-1, 2) &
"Data[" & MID(A1,SEARCH(":",A1)+1,1) & "]" & RIGHT(A1,2)
With the help of pnuts I was able to come up with my own solution:
=LEFT(F11,LEN(F11)-5)&MID(F11,LEN(F11)-2,2)&"Data["&MID(F11,LEN(F11)-4,1)&"]"&RIGHT(F11,2)
My solution works based on the fact that the length of the last six values in the string ABC:1:I:0 will always be the same in size for all the data I have, hence you see LEN(F11)-some number in my code. The only part of the string that changes in size is the first part, in this case ABC which can also be ABCDEF, etc.
If you'd like to use formulas rather than VBA, an easy option is to split the data into 4 columns, using the Text To Columns option - first split using the colon as a delimiter, then using a full-stop / period as a delimiter.
Once you have 4 columns of data (one for each block), you can use the Concatenate function to join them and add in the extra characters: =CONCATENATE(A1,":",C1,".","Data[",B1,"].",D1)
This should still work if you have extra / alternative characters (eg ABCD instead of ABC), as long as you have the same delimiters, but obviously you'd need to test to make sure.
I have the list with like 100,000 site link strings
Each link is unique, but it has consistent ?Item=
Then, it's either nothing or it continues after & symbol.
My question is: How do I pull out the item numbers?
I know replace function can offer similar functionality, but it works with Fixed sizes, in my case string can be different in size.
Link example:
www.site.com?sadfsf?sdfsdf&adfasfd?Item=JGFGGG55555
or
www.site.com?sadfsf?sdfsdf&adfasfd?Item=JGFGGG55555&sdafsdfsdfsdf
In both cases I need to get JGFGGG55555 only
If this always is the last portion of the string, you can use the following:
=MID(A1, FIND("?Item=", A1) + 6, 99)
This assumes:
no item numbers will be over 99 digits.
no additional fields follow the item number.
Edit:
With the update to your question, it is apparent you have some strings with additional data after the ?Item= field. Without using VBA there is not a simple means of using MID and FIND to extract this.
However you could create a column which acts as a placeholder.
For example, create a column using:
=MID(A1,FIND("?Item=",A1)+6,99)
This gets you the following value: JGFGGG55555&sdafsdfsdfsdf
Next, create a column using:
=IF(ISERROR(FIND("&",B2)),B2,LEFT(B2,FIND("&",B2)-1))
This produces: JGFGGG55555 by searching the first value for a & and using the portion before it. If it is not found, the first value is simply repeated.
This formula should work for both the examples given:
=MID(A1,FIND("=",A1),IFERROR(LEN(A1)-FIND("&",A1,FIND("=",A1))-1,LEN(A1)+1-FIND("=",A1)))
Seems like it would be a simple thing really (and it may be), but I'm trying to take the string data of a column and then through a calculated column, replace all the spaces with %20's so that the HTML link in the workflow produced email will actually not break off at the first space.
For example, we have this in our source column:
file:///Z:/data/This is our report.rpt
And would like to end up with this in the calculated column:
file:///Z:/data/This%20is%20our%20report.rpt
Already used the REPLACE, and made up a ghastly super nested REPLACE/SEARCH version, but the problem there is that you have to nest for EACH potential space, and if you don't know how many up front, it doesn't work, or will miss some.
Have any of you come across this scenario and how did you handle it?
Thanks in advance!
As far as I know there is no generic solution using the calculated-column syntax. The standard solution for this situation is using an ItemAdded (/ItemUpdated) event and initializing the field value from code.
I was able to solve this issue for my circumstances by using a series of calculated columns.
In the first calculated column (C1) I entered a formula to remove the first space, something like this:
=IF(ISNUMBER(FIND(" ",[Title])),REPLACE([Title],FIND(" ",[Title]),1,"%20"),[Title])
In the second Calculated column (C2) I used:
=IF(ISNUMBER(FIND(" ",[C1])),REPLACE([C1],FIND(" ",[C1]),1,"%20"),[C1]).
In my case, I wanted to encode upto four spaces, so I used 3 calculated columns (C1, C2, C3) in the same fashion and got the desired result.
This is not as efficient as using a single calculated column, but if SUBSTITUTE will not work in your SharePoint environment, and you cannot use an event handler or workflow, it may offer a workable alternative.
I actually used a slightly different formula, but it was on a work machine to which I don't have access at the moment, so I just grabbed this formula from a similar S.O. question. Any formula that will replace the first occurrence of a space with "%20" will work, the trick is to a) make sure the formula returns the original string unchanged if it does not have more spaces in it, and b) test, test, test. Create a view of your list that has the field you are trying to encode, plus the calculated fields, and see if you are getting the results you want.
so that the HTML link in the workflow produced email will actually not break off at the first space.
The browser only does this if you have not enclosed your link in quotes
If you wrap the link in quotes, it does not cut off at the first space
In a SharePoint Formula it would be:
="""file:///Z:/data/This is our report.rpt"""
becuase two quotes are the SP escape notation to output a quote
You can use this formula (Start trim for 1, in my case was 4):
=IF(ISBLANK([EUR Amount]),"",(TRIM(MID([EUR Amount],4,2))&TRIM(MID([EUR Amount],6,2))&TRIM(MID([EUR Amount],8,2))&TRIM(MID([EUR Amount],10,2))&TRIM(MID([EUR Amount],12,2))&TRIM(MID([EUR Amount],14,2)))*1)